RRB NTPC Graduate CBT 1 2025 PYQs

Concept: Number the places 1 (bottom) to 7 (top) and fix the definite clues first.

1. No box below B → B = 1. Two boxes between D and B → D = 4.
2. Only E above G → G = 6, E = 7.
3. Order C > A > F fills 5, 3, 2: C = 5, A = 3, F = 2.
4. Between B (1) and G (6): F, A, D, C = 4 boxes.

Trick: Clues like "no box below" or "only one above" fix ends of the stack — start there.

Answer: (D) 4

Concept: Find one operation that works for both given pairs.

1. $18\times 4+1=73$ and $23\times 4+1=93$ – rule: second $=4\times$first$+1$.
2. $26\times 4+1=105$ ✓; $25\times 4+1=101$ ✗.

Trick: When the second number is roughly 4 times the first, test $4n\pm 1$ or $4n\pm 2$ first.

Answer: (C) 26, 105

Concept: Replace the symbols by their real meaning, then apply BODMAS.

1. $316-2÷37+436\times 4$ becomes $316\times 2+37-436÷4$.
2. $436÷4=109$; $316\times 2=632$.
3. $632+37-109=560$.

Trick: Write the converted equation on paper first; most mistakes happen while converting in the head.

Answer: (D) 560

Concept: Number places 1 (bottom) to 7 (top); use "only" clues to fix the ends.

1. Only R above A → R = 7, A = 6. Two boxes between A and S → S = 3.
2. Only E below N → N = 2, E = 1.
3. Places 4 and 5 remain for P and T; T is not immediately above S (place 4) → T = 5, P = 4.
4. Between P (4) and E (1): S and N = two boxes.

Trick: "Only X is above/below Y" fixes two positions at once — always use it first.

Answer: (C) Two

Concept: A word common to two sentences has the code common to both.

1. 'repair the mobile' → gf ed ls; 'mobile is lost' → sq gf tf.
2. Only 'mobile' is common to both sentences and only 'gf' is common to both codes.
3. So mobile = gf.

Trick: Match common words with common codes – no need to decode the rest.

Answer: (D) gf

Concept: Letters common to both words get the digits common to both codes.

1. MILE → 9, 5, 7, 4 and TIME → 5, 4, 2, 9.
2. Common letters I, M, E ↔ common digits 9, 5, 4.
3. The extra letter in TIME is T and the extra digit is 2 → T = 2.

Trick: Cancel the common part; what is left on each side matches.

Answer: (C) 2

Concept: Look for the pattern Letter – Symbol – Symbol and count the middle symbol.

1. Series: K C © C V € @ € # U © & Y £ © I $ N W # & Q.
2. V € @ ✓, U © & ✓, Y £ © ✓, W # & ✓.
3. C © C and I $ N fail (followed by a letter). Total = 4.

Trick: Scan every symbol once and check only its left and right neighbours – mark ticks under the series.

Answer: (C) 4

Concept: Test each statement alone, then together.

1. (I) alone: Alpha < Bravo < Cargo – Delta and Echo unknown, so the lightest is not fixed.
2. (II) alone: Bravo < Delta < Echo – Alpha and Cargo unknown.
3. Together: Alpha < Bravo and Bravo is lighter than Cargo, Delta, Echo → Alpha is the lightest.

Trick: In ordering questions, a statement is sufficient only if every parcel is placed relative to the extreme asked.

Answer: (B) Both statements I and II together are sufficient

Concept: Facing the centre, 'left' is clockwise and 'right' is anticlockwise. Number the seats 1–7 clockwise.

1. X = 1 → G second to the left = 3 → V third to the left of G = 6.
2. Two people between H and I counted from the right of I: I = 7, H = 4 works (I = 5, H = 2 leaves no vacant seat beside H for F).
3. F next to H → F = 5; W takes the last seat 2.
4. Fourth to the right (anticlockwise) of W: 1, 7, 6, 5 → F.

Trick: Draw the circle, mark 'left = clockwise' once, and test both cases of a two-way clue quickly.

Answer: (D) F

Concept: Look for the pattern Letter – Letter – Symbol and count the middle letter.

1. Series: B T # A M @ * * # € © * C H # N £ H Q £ T O.
2. B T # ✓, A M @ ✓, C H # ✓, H Q £ ✓.
3. £ T O and N £ H do not fit. Total = 4.

Trick: Only letters that have a letter on the left can qualify – check just those.

Answer: (A) 4

Concept: Each step moves the first letter to the end (left rotation by one).

1. DASH → ASHD → SHDA; GAME → AMEG → MEGA.
2. BALD → ALDB → LDBA follows the same rotation.
3. IRON → RONI → ONIR (not ONRI); FADE and JAIL do not rotate at all.

Trick: Check the third word with the second, not only the second with the first.

Answer: (B) BALD-ALDB-LDBA

Concept: Number places 1 (bottom) to 7 (top); start from the clue that fixes an exact place.

1. Three boxes above N → N = 4. One box between H and N, and A above N with three boxes between H and A → H = 2, A = 6.
2. R immediately below A → R = 5.
3. Places 1, 3, 7 remain for C, G, J. J is not adjacent to H (2) → J = 7; C above G → C = 3, G = 1.
4. Boxes above H: C, N, R, A, J = 5.

Trick: 'Exactly three above' pins the middle box of seven – build outward from it.

Answer: (D) 5

Concept: Use letter positions (A=1 … Z=26) and compare the gaps.

1. MQO: M(13) +4 → Q(17) −2 → O(15).
2. SWU: S(19) +4 → W(23) −2 → U(21); ZDB: Z(26) +4 → D(4) −2 → B(2) (cyclic).
3. CHE: C(3) +5 → H(8) −3 → E(5) – different gaps, so it is the odd one.

Trick: Write the gaps as a pattern (+4, −2) and the odd cluster shows itself.

Answer: (C) CHE

Concept: Compare how each letter of the first cluster moves to the second.

1. CG → FJ: C+3 = F, G+3 = J. WA → ZD: W+3 = Z, A+3 = D. AE → DH: A+3 = D, E+3 = H.
2. YC → BE: Y+3 = B (cyclic) but C+2 = E – the second letter breaks the +3 rule.

Trick: Check both letters of every pair; the odd one usually hides the error in the second letter.

Answer: (C) YC-BE

Concept: Apply the rule digit by digit: odd → +1, even → −2.

1. 8 1 3 4 5 7 6 → 6 2 4 2 6 8 4.
2. New number 6242684; second digit from the left is 2.

Trick: Only the asked position matters – the second digit 1 is odd → 1 + 1 = 2. Done in one step.

Answer: (A) 2

Concept: Find the operation linking the first number to the second in both pairs.

1. $108÷9=12$ and $234÷9=26$ – rule: second $=$ first $÷9$.
2. $198÷9=22$.

Trick: When the first number is much larger, try division first; 108, 234, 198 are all multiples of 9 (digit sums 9, 9, 18).

Answer: (D) 22

Concept: Decode each symbol step by step and build the family tree.

1. G # N: G is daughter of N. N # V: N is daughter of V. V + K: V is mother of K. K # T: K is daughter of T.
2. V and T are both parents of K, so T is the father (V is female). Hence T is also the father of N.
3. N is G's mother → T is G's mother's father.

Trick: Start decoding from the person asked about (G) and move link by link; fix genders from 'mother/daughter' words.

Answer: (B) Mother's father

Concept: 'All A are B' and 'All B are C' give 'All A are C'; a 'Some' statement passes nothing definite backwards.

1. All liquid is water, all water is juice → All liquid is juice. Conclusion I follows.
2. Some juices are syrup: the syrup part of juice may lie entirely outside water and liquid, so 'Some syrups are liquid' is not certain. Conclusion II does not follow.

Trick: Draw the smallest possible Venn: nested circles for 'All', and put the 'Some' overlap as far from the inner circle as you can.

Answer: (C) Only conclusion (I) follows.

Concept: Find the uniform letter shift that links the given pair, then apply it to the other pair.

1. Try option A: DNV : KUC $\to$ D$+7=$K, N$+7=$U, V$+7=$C. Each letter moves $+7$.
2. Apply $+7$ to VFN: V$+7=$C, F$+7=$M, N$+7=$U $\Rightarrow$ CMU.
3. Only option A has both # = DNV and % = CMU.

Trick: Check the second pair first – VFN $+7$ = CMU eliminates B and D at once; then DNV vs DUV decides A.

Answer: (A) # = DNV % = CMU

Concept: Build the family tree generation by generation.

1. Lg is Dv's daughter; Qb is Lg's brother $\Rightarrow$ Qb is Dv's son.
2. Jq is Qb's daughter $\Rightarrow$ Jq is the daughter of Dv's son.
3. So Jq is Dv's son's daughter (granddaughter).

Trick: Brother of a daughter = son of the same parent. Sibling links always share the parent.

Answer: (D) Son's daughter