RRB NTPC Graduate CBT 1 2025 PYQs

Concept: Build the family tree generation by generation, marking gender.

1. G is husband of H → G, H are a couple. E is son of G → E is their son.
2. F is sister of E → F is daughter of G and H.
3. C is son of F → C is the son of H's daughter → daughter's son (grandson).

Trick: Start from the oldest couple and hang the others below – the relation of the lowest person to the top one reads straight off the tree.

Answer: (D) Daughter's son

Concept: Decode each symbol pair-wise from left to right and place everyone on a tree.

1. D – F: D is brother of F (D male). F + G: F is daughter of G. G × H: G is wife of H → H is father of F.
2. H ÷ J: H is father of J → J is a child of H and G, hence sibling of F and D.
3. D (male) is a sibling of J → D is J's brother.

Trick: Decode from the end backwards (H ÷ J first) when the asked person is at the right – you reach the common parents fastest.

Answer: (D) Brother

Concept: Find one rule that fits both given pairs, then test the options.

1. $19\times 4+2=78$ ✓, $24\times 4+2=98$ ✓ → rule: $\times 4+2$.
2. $26\times 4+2=106$ (options A, B fail); $27\times 4+2=110$ ✓.

Trick: Multiplier $=\frac{98-78}{24-19}=\frac{20}{5}=4$; then the constant is $78-76=2$.

Answer: (D) 27, 110

Concept: Facing the centre, a person's right is anticlockwise. Fix H and place the others clue by clue.

1. U is 2nd to the right of H → U two seats anticlockwise from H. Only one between U and W (not H's side) → W is between F-side and U; only one between H and F → F is 2nd clockwise from H.
2. Two between V and W → V sits immediately anticlockwise of H; one between G and F → G sits between W and U; I takes the last seat. Clockwise order: H, I, F, W, G, U, V.
3. 4th to the right (anticlockwise) of I: H, V, U, G → G.

Trick: Draw 7 dots, mark H at the top, and count anticlockwise for "right" – never reverse the direction mid-puzzle.

Answer: (C) G

Concept: Check the ratio of each pair; a constant ratio means the rule is multiplication.

1. $\frac{192}{48}=4$ and $\frac{208}{52}=4$ → rule: second number $=$ first $\times 4$.
2. $61\times 4=244$.

Trick: Test $\times k$ first when both outputs are exact multiples of the inputs; it fits here, so no $+c$ is needed.

Answer: (A) 244

Concept: Number positions 1 (top) to 7 (bottom) and fill the definite clues first.

1. Only R above U → R = 1, U = 2. Only two boxes above Q → Q = 3; Q immediately above P → P = 4.
2. Positions 5, 6, 7 remain for S, V, T with S immediately above V. S cannot be at position 5 (3rd from bottom) → S = 6, V = 7, T = 5.
3. Stack: R, U, Q, P, T, S, V. Between R (1) and T (5): U, Q, P = 3 boxes.

Trick: "Only X is above Y" fixes two positions at once – always start there.

Answer: (A) 3

Concept: Compare the two words – the common letters share the common digits; the leftover letter gets the leftover digit.

1. KITE → 5871 and TIME → 7853 share T, I, E; the codes share 5, 7, 8.
2. Letter not common in TIME is M; digit not common in 7853 is 3.
3. So M = 3.

Trick: Elimination coding – cross out common letters and common digits; what remains pairs up.

Answer: (A) 3

Concept: Treat the letter part and the number part as two separate series.

1. Letters: AZA, XWX, UTU, RQR – first/third letter A→X→U→R ($-3$ each) → next O; middle letter Z→W→T→Q ($-3$) → next N. So ONO.
2. Numbers: 27, 36, 45, 54 ($+9$) → 63.
3. Term = ONO 63.

Trick: Each cluster is a palindrome with the middle letter one step behind the outer one (A–Z, X–W…) – O–N fits, so ONO.

Answer: (B) ONO 63

Concept: The only letter common to both words gets the only digit common to both codes.

1. TIME → 3519 and EARS → 6894: common letter = E.
2. Common digit in 3519 and 6894 = 9.
3. So E = 9.

Trick: With one shared letter, just spot the one shared digit – no need to decode the rest.

Answer: (D) 9

Concept: Decode each symbol step by step and build the family tree, starting from the end (E) to reach D.

1. D × N → D is the wife of N. N % P → N is the father of P, so D is P's mother.
2. P + K → P is the mother of K. K # E → K is the daughter of E, so E is K's father and P's husband.
3. D is the mother of P, and P is E's wife → D is E's wife's mother.

Trick: Whenever one person is "mother of X" and another is "father of X", they are husband and wife – that single link solves most coded-relation questions.

Answer: (C) Wife's mother

Concept: Write the place values (A=1 … Z=26) and compare the gaps between consecutive letters.

1. LPU: 12, 16, 21 → +4, +5. WAF: 23, 1, 6 → +4 (W→A cyclic), +5. DHM: 4, 8, 13 → +4, +5.
2. JNT: 10, 14, 20 → +4, +6 – the second gap breaks the pattern.

Trick: Check the first gap of all four; if all match, the odd one hides in the second gap. Remember that after Z the alphabet wraps to A.

Answer: (A) JNT

Concept: Scan each symbol and check the element just before it (must be a letter) and just after it (must be a number).

1. Symbols in the series: & (G, R), % (K, 7), @ (7, 2), & (S, 6), # (T, 3), * (Y, D).
2. Letter before and number after: K % 7, S & 6, T # 3 → three.

Trick: Underline only the symbols first (there are just six), then test neighbours – far faster than reading the whole series.

Answer: (C) Three

Concept: Treat the letters and the numbers as two separate series.

1. Letters: each position moves +5. T→Y→D→I→N; W→B→G→L→Q; U→Z→E→J→O.
2. Numbers: 89, 81, 73, 65 → each −8 → 57.
3. Next term: NQO 57.

Trick: Decide the number first (57 → options C or D), then check just the first letter: I+5 = N in both, so check the second letter L+5 = Q → NQO.

Answer: (D) NQO 57

Concept: Compare the two words: letters common to both must share the common digits; the leftover letter gets the leftover digit.

1. SEMI → 3615, TIME → 1523. Common letters: E, M, I. Common digits: 1, 5, 3.
2. So in SEMI the uncommon letter S ↔ uncommon digit 6; in TIME the uncommon letter T ↔ uncommon digit 2.

Trick: In such questions the codes are jumbled – never match by position, always by "common vs uncommon" elimination.

Answer: (D) 2

Concept: Find one rule connecting the three numbers of each given set, then test it on the options.

1. (19, 24, 7): $2\times (19-7)=24$ ✓. (12, 14, 5): $2\times (12-5)=14$ ✓. Rule: second = 2 × (first − third).
2. (3, 4, 1): $2\times (3-1)=4$ ✓. Others fail: (7,5,3) → 8; (12,5,3) → 18; (12,5,4) → 16.

Trick: When the middle number is the largest, try "middle = (first ± third) × k" – here $2\times (a-c)$ fits both sets at once.

Answer: (C) (3, 4, 1)

Concept: Find the position-wise shift from the first word to the second and apply the same shift.

1. DMKZ → EKNV: D+1=E, M−2=K, K+3=N, Z−4=V. Pattern: +1, −2, +3, −4.
2. Check LOJT → MMMP: L+1=M, O−2=M, J+3=M, T−4=P ✓.
3. SRLQ: S+1=T, R−2=P, L+3=O, Q−4=M → TPOM.

Trick: Alternating signs with increasing magnitude (+1, −2, +3, −4) is a very common RRB pattern – verify with the second pair, then apply.

Answer: (C) TPOM

Concept: Change each digit as instructed, then pick the greatest and smallest digits of the new number.

1. 48572613 → 4−1=3, 8−1=7, 5+1=6, 7+1=8, 2−1=1, 6−1=5, 1+1=2, 3+1=4 → new number 37681524.
2. Greatest digit 8, smallest digit 1 → product $8\times 1=8$.

Trick: Odd +1 and even −1 just swaps each digit with its neighbour pair (1↔2, 3↔4, 5↔6, 7↔8); only 9 would become 10 and 0 would become −1 – neither occurs here.

Answer: (A) 8

Concept: Start with the definite clue (top floor), then fix the rest using "only two between" constraints.

1. No one above D → D on floor 6. Only two between D and C → C on floor 3.
2. Q below C but above N → Q = 2, N = 1. Only two between O and Q → O = 5. Remaining P = 4.
3. Between P (4) and N (1) are floors 3 and 2 → two people (C and Q).

Trick: Draw the 6 boxes first; "only two between X and Y" means X and Y are exactly 3 floors apart.

Answer: (D) Two

Concept: Decode each symbol and draw the family tree; the gender of D is given by "brother".

1. D − F → D is the brother of F. F + G → F is the daughter of G, so D is also G's son.
2. G ÷ H → G is the father of H, so D, F and H are siblings. H × J → H is the wife of J.
3. D is the brother of J's wife → wife's brother.

Trick: Siblings of a parent's other children are your own siblings – once D and H share father G, D is H's brother, hence J's brother-in-law.

Answer: (A) Wife's brother

Concept: For people facing the centre, "left" is clockwise and "right" is anticlockwise. Fix E first and place the others.

1. A is immediately right of E. G is third to the left of E. A is second to the left of F → F is second to the right of A.
2. Two people between F and B counted from B's left → B is third to the right of F. D is the neighbour of G, and the remaining seat goes to C.
3. Order (clockwise): E, B, D, G, F, C, A. From G's right: D, B, E, then A → 3 people between.

Trick: Use the clue with two fixed names (E and A) first, then clues connecting a placed person to a new one; D's "neighbour of G" is decided last by elimination.

Answer: (C) 3