RRB NTPC Graduate CBT 2 2024 PYQs

Concept: Swap the signs first, then solve using BODMAS.

1. After swapping: $26-8÷4+10\times 5$
2. $8÷4=2$, $10\times 5=50$
3. $26-2+50=74$

Trick: Rewrite the whole expression with new signs before any calculation – avoids half-swapped errors.

Answer: (D) 74

Concept: All face the centre, so 'left' means clockwise and 'right' means anticlockwise (seen from above).

1. Place G at a corner (F, second to G's right, must be a corner); F is two seats anticlockwise.
2. E is 4th to G's left (three between); H is third to the left of E, i.e. just right of G.
3. B is 4th to H's left; C is second to B's right; remaining seats go to D and A – D not next to E, so D sits between C and B.
4. Going left (clockwise) from D: D → B → E, so one person (B) sits between.

Trick: In a facing-centre circle/square, left = clockwise; count seats, not people.

Answer: (B) One

Concept: Track each letter position of the clusters separately.

1. 1st letters: H, K, N, Q, T, W → $+3$ each.
2. 2nd letters: Q, N, K, H, E, B → $-3$ each.
3. 3rd letters: K, N, Q, T, W, Z → $+3$ each; so 4th term should be QHT, not QHS.

Trick: Write position numbers under the third letters: 11, 14, 17, 19, 23, 26 – the break is obvious.

Answer: (C) QHS

Concept: Find the differences between consecutive terms.

1. Differences: $18,36,54,72$ → multiples of 18.
2. Next difference $=90$
3. $187+90=277$

Trick: Differences $18\times 1,18\times 2,\dots$ → arithmetic progression of second order.

Answer: (B) 277

Concept: Find the shift for each letter position (cyclic A–Z).

1. MOST → EFKK: $M\to E=-8$, $O\to F=-9$, $S\to K=-8$, $T\to K=-9$
2. Check GEMJ → YVEA: $-8,-9,-8,-9$ ✓
3. IDOI: $I-8=A$, $D-9=U$, $O-8=G$, $I-9=Z$ → AUGZ

Trick: Alternate $-8,-9$; going below A wraps to Z (e.g. $D(4)-9=-5\to 21=U$).

Answer: (C) AUGZ

Concept: Check the ratio of consecutive terms.

1. $12=2\times 6$, $60=12\times 5$, $240=60\times 4$
2. Next: $240\times 3=720$
3. Check: $720\times 2=1440$ ✓

Trick: Multipliers fall by 1: $\times 6,\times 5,\times 4,\times 3,\times 2$.

Answer: (B) 720

Concept: Take A as origin (East = +x, North = +y) and track coordinates after every turn.

1. Samar: east 7 → $(7,0)$; right (south) 9 → $(7,-9)$; right (west) 13 → B $=(-6,-9)$.
2. Wahid: P $=(14,0)$; west 3 → $(11,0)$; left (south) 9 → $(11,-9)$; right (west) 8 → Q $=(3,-9)$.
3. B and Q are on the same horizontal line: $BQ=3-(-6)=9$ km.

Trick: Same y-coordinate → distance is just the difference of x-coordinates.

Answer: (C) 9 km

Concept: Replace letters by operators, then apply BODMAS.

1. $25\times 3-12÷4+10$
2. $25\times 3=75$, $12÷4=3$
3. $75-3+10=82$

Trick: Decode the whole line first: C = ×, B = −, D = ÷, A = +.

Answer: (C) 82

Concept: Check each letter position separately.

1. 1st letters: F, I, L, O, R → $+3$
2. 2nd letters: H, K, N, Q, should be T → $+3$
3. 3rd letters: K, N, Q, T, W → $+3$; so last term should be RTW, not RSW.

Trick: Each cluster is 'x, x+2, x+5' – RSW breaks the gap of 2 between first and second letters.

Answer: (D) RSW

Concept: Interchange the signs first, then apply BODMAS.

1. After swapping: $32+15\times 5-10÷2$
2. $15\times 5=75$, $10÷2=5$
3. $32+75-5=102$

Trick: Rewrite the full expression with new signs before solving.

Answer: (D) 102

Concept: Remove all symbols ($, &, *, %) and then count positions.

1. Remaining: T 1 9 Z 7 A M S 1 D 7 → 11 elements.
2. 7th from right = $(11-7+1)=5$th from left.
3. 5th from left = 7

Trick: $k$th from right $=(n-k+1)$th from left.

Answer: (B) 7

Concept: Fix the definite positions first, then fill the rest with the remaining conditions.

1. Only two scored more than A → A is 3rd.
2. Only B scored less than D → B is 6th, D is 5th.
3. Left positions 1, 2, 4 for C, X, Y with C > X > Y → C 1st, X 2nd, Y 4th.
4. Only C scored more than X → one person.

Trick: Place the 'only' clues first – they fix exact ranks.

Answer: (B) One

Concept: Each letter of the first cluster is shifted forward by the same number of places.

1. M→U, P→X, Q→Y, O→W: each letter $+8$.
2. D→L, G→O, H→P, F→N: again each $+8$.
3. K+8 = S, N+8 = V, O+8 = W, M+8 = U → SVWU.

Trick: Check only the first letter of each option: all start with S, so test the second letter N+8 = V.

Answer: (B) SVWU

Concept: Use the fixed day (Q on Thursday) and the gap condition between U and P first.

1. Four people between U and P → they are on (Mon, Sat) or (Tue, Sun); Sunday is not allowed → U, P on Mon and Sat.
2. If U were Saturday, S would have to be Sunday and R Saturday – clash. So U = Mon, P = Sat.
3. R, S consecutive in the free days → R = Tue, S = Wed.
4. T and V take Fri, Sun; V not Friday → T = Fri, V = Sun. After P (Sat) only V → 1.

Trick: With 7 days, "4 between" leaves only two pairs: (1, 6) or (2, 7).

Answer: (C) 1

Concept: Ministers who are Managers but not Engineers = region common to Ministers and Managers only, outside the Engineers circle.

1. Region only in Ministers = 10 (not Managers).
2. Region in Managers and Engineers = 9 (not Ministers).
3. Region common to Ministers and Managers only = 8.

Trick: Read the question as "inside A and B, outside C" and shade just that region.

Answer: (B) 8

Concept: Look at the differences between consecutive terms.

1. Differences: $25-12=13$, $51-25=26$, $90-51=39$, $142-90=52$.
2. They are multiples of 13: $13\times 1,13\times 2,13\times 3,13\times 4$.
3. Next difference $=13\times 5=65$ → $142+65=207$.

Trick: Differences in a table of a number (13, 26, 39…) → just add the next multiple.

Answer: (A) 207

Concept: Decode each option; R must be the brother of a woman who is T's mother.

1. Option (C): P ÷ Q → P is father of Q; Q × R → Q is wife of R.
2. R – S → R is brother of S; S + T → S is mother of T.
3. So S is T's mother and R is her brother → R is T's mother's brother (maternal uncle).
4. In (B), R ÷ S makes R a father, and in (D), R × S makes R a wife – both wrong.

Trick: Look for the pattern "R – S + T" (R brother of S, S mother of T) in the options.

Answer: (C) P ÷ Q x R – S + T

Concept: Each position of the clusters moves forward by the same step.

1. First letters: J, R, Z, H, P, X – each $+8$ (with wrap-around).
2. Second letters: F, N, V, D, L, T – each $+8$.
3. Third letters: B, J, R, Z, ?, P → after Z comes Z+8 = H, so the fifth cluster should be PLH.
4. Given PLK breaks the pattern.

Trick: Check one position at a time; the odd letter shows the wrong cluster at once.

Answer: (C) PLK

Concept: Find the letter-gaps inside each pair: first cluster XY, second cluster PQ.

1. KO−NR: K+4 = O, K+3 = N, N+4 = R.
2. MQ−PT: M+4 = Q, M+3 = P, P+4 = T. AE−DH: A+4 = E, A+3 = D, D+4 = H.
3. GK−IP: G+4 = K but G+2 = I and I+7 = P – pattern broken.

Trick: Pattern is (+4) in each cluster and (+3) between clusters; GK−IP fails at once.

Answer: (D) GK−IP

Concept: Number the letters 1 2 3 4 and find how positions move.

1. WASH → HSWA: order 4 3 1 2. NEST → TSNE: same 4 3 1 2.
2. HSWA → WSAH: order 3 2 4 1 of the second word (NSET from TSNE too).
3. OILS → 4 3 1 2 = SLOI; SLOI → 3 2 4 1 = OLIS. Matches (D).
4. FOGS → 4 3 1 2 would be SGFO ✓, but SGFO → 3 2 4 1 = FGOS, not OGFS.

Trick: Fix the rule on one triad, verify on the second, then test options only.

Answer: (D) OILS - SLOI - OLIS