RRB NTPC Undergraduate CBT 1 2024 PYQs

Concept: Check each number's left and right neighbours: both must be symbols.

1. > 3 @ ✓; @ 8 * ✓.
2. @ 7 1 ✗ and 7 1 (symbol) ✗ (number beside).
3. @ 4 ? ✓; ? 4 5 ✗; 4 5 < ✗; first 6 has nothing before it.
4. Total = 3 (the numbers 3, 8, 4).

Trick: Skip numbers that sit next to another number – they can never qualify.

Answer: (C) Three

Concept: Chain of 'All' statements gives a nested Venn diagram.

1. Gardens ⊂ Forests ⊂ Meadows.
2. So all gardens are meadows: I follows.
3. Meadows can exist outside forests: II ('All meadows are forests') fails.

Trick: All A are B + All B are C ⇒ All A are C; the reverse 'All C are B' never follows.

Answer: (A) Only conclusion (I) follows.

Concept: Total = rank from top + rank from bottom − 1.

1. $65+94-1=158$.

Trick: Subtract 1 because the person is counted twice.

Answer: (D) 158

Concept: Look at the differences, then at the differences of those.

1. Differences: 23, 36, 44, 57.
2. Second differences: 13, 8, 13 → next 8.
3. Next difference $=57+8=65$; next term $=179+65=244$.

Trick: If first differences look random, check their differences – here an alternating +13, +8.

Answer: (B) 244

Concept: Find the gaps between letter positions.

1. KFM: K(11)−5 = F(6), F+7 = M(13).
2. TOV: −5, +7; QLS: −5, +7.
3. NIO: N(14)−5 = I(9), but I+6 = O(15) → odd one.

Trick: Remember positions with EJOTY = 5, 10, 15, 20, 25.

Answer: (A) NIO

Concept: Constant difference of 27.

1. 181 − 154 = 27, 208 − 181 = 27.
2. $208+27=235$; check $235+27=262$ ✓.

Trick: Verify with the term after the blank.

Answer: (B) 235

Concept: Split into four series: 1st letter, 2nd letter, 3rd letter, number.

1. 1st: L, O, R, U → +3 → X.
2. 2nd: S, O, K, G → −4 → C.
3. 3rd: P, O, N, M → −1 → L.
4. Number: 15, 12, 9, 6 → −3 → 3. Answer XCL 3.

Trick: The number part alone (−3 each time) already leaves only XCL 3.

Answer: (B) XCL 3

Concept: In each pair XY-ZW: Y = X+4, Z = X+7, W = Y+7.

1. IM-PT: I+4 = M, I+7 = P, M+7 = T ✓.
2. MQ-TX ✓ and FJ-MQ ✓ similarly.
3. KO-RW: K+4 = O, K+7 = R, but O+8 = W ✗ → odd one.

Trick: Equivalently Z−X and W−Y must both be 7.

Answer: (A) KO-RW

Concept: Interchange the signs first, then apply BODMAS.

1. $14÷4+78\times 13-13$ becomes $14\times 4-78÷13+13$.
2. $=56-6+13$.
3. $=63$.

Trick: Rewrite the whole expression with new signs before calculating.

Answer: (C) 63

Concept: Total = rank from top + rank from bottom − 1.

1. $35+27-1=61$.

Trick: Subtract 1 because the person is counted twice.

Answer: (D) 61

Concept: Write the alphabet positions and check the gaps between the letters.

1. HPJ: H(8) → P(16) is +8, P → J(10) is −6
2. KSM: 11 → 19 (+8) → 13 (−6); NVP: 14 → 22 (+8) → 16 (−6)
3. QYR: 17 → 25 (+8) → 18 (−7) — breaks the pattern

Trick: Pattern +8, −6 also means 3rd letter = 1st + 2; Q + 2 = S, not R.

Answer: (B) QYR

Concept: Facing the centre, a person’s right is anticlockwise. Fix Q and count seats to Q’s right as positions 1–6.

1. Two between Q and K from Q’s right ⇒ K at 3. Three between Q and P ⇒ P at 4 (3 is taken).
2. Two between K and O ⇒ O at 6.
3. Left seats 1, 2, 5; I immediately left of L ⇒ I = 1, L = 2, J = 5.
4. Third to the left of J: P, K, L ⇒ L.

Trick: In a 7-seat circle, “n between” on one side = “5 − n between” on the other side.

Answer: (B) L

Concept: Facing north, the right end is the east end. Number positions 1–7 from the left.

1. Two people to the right of K ⇒ K = 5; Q immediately left ⇒ Q = 4.
2. Two between K and R ⇒ R = 2.
3. Two between I and Q ⇒ I = 1 or 7. P–L must be adjacent: only I = 1 leaves 6, 7 free ⇒ P = 6, L = 7.
4. Remaining J = 3.

Trick: Test both cases for I quickly — the adjacent-pair condition (P, L) usually rejects one.

Answer: (A) J

Concept: Swap the signs first, then apply BODMAS.

1. $100\times 4+11÷2-18$ becomes $100÷4-11\times 2+18$
2. $=25-22+18=21$

Trick: Rewrite the whole expression with new signs before calculating — never swap mentally.

Answer: (C) 21

Concept: Check the differences between consecutive terms.

1. 22 → 25 (+3) → 36 (+11) → 39 (+3) → 50 (+11)
2. Next: 50 + 3 = 53

Trick: Alternating differences (+3, +11) repeat — continue the cycle.

Answer: (B) 53

Concept: Track each letter position of the cluster separately.

1. 1st: E, H, K, N → +3 → Q
2. 2nd: L, O, R, U → +3 → X
3. 3rd: J, M, P, S → +3 → V
4. Answer: QXV

Trick: If one letter shows a constant jump, check the others first with the same jump.

Answer: (C) QXV

Concept: Find the gaps between consecutive letters.

1. FIM: F → I (+3) → M (+4)
2. ORV: +3, +4; PSW: +3, +4
3. ZBF: Z → B (+2) → F (+4) — different

Trick: For wrap-around letters (Z → A …) count carefully: Z + 3 = C, not B.

Answer: (C) ZBF

Concept: Letters and numbers follow separate rules.

1. Each letter moves −4: N→J→F→B→X→T, U→Q→M→I→E→A, B→X→T→P→L→H
2. Numbers: 1, 4, 10, 22, 46 — each = previous × 2 + 2
3. Next number $=46imes2+2=94$; cluster = TAH 94

Trick: Options share 94, so only the letters decide: −4 from X, E, L gives T, A, H.

Answer: (B) TAH 94

Concept: Draw the least-overlap Venn diagram and test each conclusion.

1. All Melons lie inside Grapefruits; some Blueberries are Melons.
2. So those Blueberries are also Grapefruits ⇒ “Some Grapefruits are Blueberries” is definite — II follows.
3. I (“No Blueberries are Grapefruits”) contradicts this — does not follow.

Trick: Some A are B + All B are C ⇒ Some A are C (and its converse Some C are A).

Answer: (D) Only conclusion (II) follows.

Concept: Sort the numbers and compare each position with the original.

1. Original: 869, 509, 779, 491, 863
2. Ascending: 491, 509, 779, 863, 869
3. Same position: 509 (2nd) and 779 (3rd) ⇒ 2 numbers

Trick: Write both rows one under the other and tick matching columns.

Answer: (B) 2