RRB NTPC Undergraduate CBT 1 2024 PYQs

Concept: Check differences between consecutive terms.

1. Differences: $10,20,30,40$
2. Next difference $=50$
3. $109+50=159$

Trick: Differences in AP ($+10$ each) ⇒ keep adding the next multiple of $10$.

Answer: (D) $159$

Concept: Write alphabet positions and find the gaps between letters.

1. GLH: $G+5=L$, $L-4=H$
2. EJF: $+5,-4$; NSO: $+5,-4$
3. LQN: $+5$, then $Q-3=N$ ⇒ different

Trick: In the group, the 3rd letter is just the next letter after the 1st (G→H, E→F, N→O); LQN breaks it.

Answer: (D) LQN

Concept: Change each digit by the rule, then count repeated digits.

1. $4268953$: even $+1$ → $4\to 5,2\to 3,6\to 7,8\to 9$; odd $-2$ → $9\to 7,5\to 3,3\to 1$
2. New number: $5379731$
3. $3$ appears twice, $7$ appears twice ⇒ two digits repeat

Trick: Write the new digits under the old ones to avoid slips.

Answer: (D) Two

Concept: Constant difference series (multiples of $11$).

1. $11,33,55,77$: each $+22$
2. $77+22=99$; check $99+22=121$ ✓

Trick: Terms are odd multiples of $11$: $11\times 1,3,5,7,9,11$.

Answer: (D) $99$

Concept: Track net North–South and East–West displacement; shortest distance by Pythagoras.

1. North $8$ km, left (West) $6$ km, right (North) $7$ km, right (East) $6$ km
2. East–West: $-6+6=0$
3. North: $8+7=15$ km ⇒ distance $=15$ km

Trick: The two $6$ km moves cancel, so just add the north moves.

Answer: (D) $15$ km

Concept: A left turn rotates direction anticlockwise by ${90}^{\circ }$ (W → S → E).

1. Runs West
2. Turns left ⇒ faces South
3. Turns left again ⇒ faces East – final direction

Trick: Two left turns = U-turn: facing West becomes facing East.

Answer: (A) East

Concept: Find the step between consecutive letters across the pair.

1. TR−PN: $T-2=R$, $R-2=P$, $P-2=N$
2. RP−NL and WU−SQ: also $-2,-2,-2$
3. GE−BC: $-2$, $-3$, $+1$ ⇒ odd

Trick: In the group, the 4 letters are in a $-2$ chain; GE−BC breaks it at once.

Answer: (A) GE−BC

Concept: Drop all symbols, keep the digits in order, then count from the right.

1. Digits only: $851362479$
2. From right: $9(1),7(2),4(3),2(4),6(5),3(6),1(7)$
3. Seventh from right $=1$

Trick: $9$ digits ⇒ 7th from right = 3rd from left $=1$.

Answer: (C) $1$

Concept: Remove all symbols and count among the remaining digits.

1. Digits only: $92315765$
2. From right: $5(1),6(2),7(3),5(4),1(5)$
3. Fifth from right $=1$

Trick: $8$ digits ⇒ 5th from right = 4th from left $=1$.

Answer: (B) $1$

Concept: Treat each letter position and the number separately.

1. 1st letters I, J, K, L → M; 2nd N, O, P, Q → R; 3rd Q, R, S, T → U (each $+1$)
2. Numbers $23,32,41,50$: each $+9$ ⇒ $59$
3. Next: MRU59

Trick: Only options with U and $59$ survive – MRU59.

Answer: (C) MRU59

Concept: Find the change from each pair to the next for both letters.

1. HO → JQ: $+2,+2$; JQ → MP: $+3,-1$
2. KR → MT: $+2,+2$; MT → PS: $+3,-1$
3. NU → PW ($+2,+2$) → SV ($+3,-1$) ✓

Trick: Check the last step first: $P+3=S$ eliminates RV options quickly.

Answer: (D) NU-PW-SV

Concept: Work backward from the known end: each term $=(\text{next term}\times 2)-2$.

1. $7\times 2-2=12$, $12\times 2-2=22$, $22\times 2-2=42$
2. $42\times 2-2=82$
3. Check: $82\times 2-2=162$ ✓

Trick: Forward rule: next $=\frac{\text{term}+2}{2}$: $\frac{162+2}{2}=82$.

Answer: (A) $82$

Concept: Position from right $=$ total $-$ position from left $+1$.

1. Ajeet from left $=20+16=36$th
2. From right $=59-36+1=24$th

Trick: "$16$th to the right" means add $16$ to the left position.

Answer: (D) ${24}^{th}$

Concept: A word common to two sentences has the code common to both.

1. "has" is in both sentences
2. Codes common to "bs kr ni" and "ud ni gy" ⇒ ni

Trick: Match common word ↔ common code.

Answer: (B) ni

Concept: Swap the signs first, then apply BODMAS.

1. After swapping: $11\times 2-48÷6+15$
2. $=22-8+15$
3. $=29$

Trick: Rewrite the whole expression before calculating – most mistakes come from swapping in the head.

Answer: (D) $29$

Concept: Find the position change at each step.

1. JUNE → UJNE: first two letters swap
2. UJNE → EUJN: last letter moves to the front
3. FROG → RFOG → GRFO ✓

Trick: Final cluster must start with the last letter of the word: only FROG → G… fits.

Answer: (B) FROG - RFOG - GRFO

Concept: Total $=$ rank from top $+$ rank from bottom $-1$.

1. $29+15-1=43$

Yaad rakhein: Subtract $1$ because Kunal is counted twice.

Answer: (C) $43$

Concept: Facing the centre: right = anticlockwise, left = clockwise.

1. Q is immediate right of N; counting left from Q, S comes after $3$ people
2. M is $4$ places from N on the other side of S
3. L sits immediately right of R ⇒ R and L fill the two seats beside N on its left; O takes the last seat
4. From R going left: R → S → M → O ⇒ two people (S, M)

Trick: Same skeleton as a twin question: fix N, Q, S, M first, then the adjacent pair.

Answer: (C) Two

Concept: Find a rule linking the outer numbers to the middle number.

1. $(26,96,22)$: $(26+22)\times 2=96$
2. $(46,108,8)$: $(46+8)\times 2=108$
3. $(24,84,18)$: $(24+18)\times 2=84$ ✓
4. Others: $(7+1)\times 2=16\ne 15$, $(1+19)\times 2=40\ne 39$, $(30+2)\times 2=64\ne 63$

Trick: Middle number is even in the given sets; (A), (B), (C) have odd middles – only (D) is possible.

Answer: (D) $(24,84,18)$

Concept: Write letter positions and check the steps across the pair.

1. CE-FH: $C+2=E$, $E+1=F$, $F+2=H$
2. SU-VX and AC-DF: also $+2,+1,+2$
3. KM-NO: $+2,+1,+1$ ⇒ odd

Trick: In each pair the second cluster also has a gap of one letter (F_H, V_X, D_F); NO has none.

Answer: (C) KM-NO