RRB NTPC Undergraduate CBT 1 2024 PYQs

Concept: Look at the differences between consecutive terms.

1. Differences: 4, 9, 16, 25 = $2^2,3^2,4^2,5^2$
2. Next difference $=6^2=36$
3. $81+36=117$

Trick: Slowly growing gaps that are perfect squares → add the next square.

Answer: (D) 117

Concept: Decode each symbol and draw the family tree.

1. E @ F: E is the wife of F
2. F $ G: F is the son of G (F is male)
3. G ÷ M: G is the father of M; M + N: M is the brother of N
4. So F and N are both children of G – F is N's brother; E is F's wife

Trick: Wife of a sibling's brother = brother's wife (bhabhi).

Answer: (B) Brother's wife

Concept: Compare letters at the same position in successive clusters.

1. W→B, B→G, G→L: +5 each time
2. V→A→F→K: +5; H→M→R→W: +5
3. Next: L+5=Q, K+5=P, W+5=B → QPB

Trick: First two letters are always consecutive in reverse (WV, BA, GF, LK → QP).

Answer: (A) QPB

Concept: Compare the first letter of each cluster with the first letter of the pair, and second with second.

1. PT-KQ: P−5=K, T−3=Q
2. JN-EK: J−5=E, N−3=K; MQ-HN: M−5=H, Q−3=N
3. SW-NU: S−5=N but W−2=U ✘

Trick: Write positions (P16, T20, K11, Q17) – the pattern $-5,-3$ shows up quickly.

Answer: (D) SW-NU

Concept: Two 'All' statements with a common predicate give no definite link between the subjects.

1. Letters and Schedules are both inside Mails but need not overlap → (I) does not follow.
2. All schedules are mails, so some mails are schedules → (II) follows.

Yaad rakhein: 'All A are B' always implies 'Some B are A'.

Answer: (B) Only conclusion (II) follows.

Concept: Find the rule linking the middle number to the outer numbers: here middle $=3\times \text{first}+\text{third}-1$.

1. (16, 63, 16): $3\times 16+16-1=63$ ✔; (36, 111, 4): $108+4-1=111$ ✔
2. (47, 144, 4): $141+4-1=144$ ✔
3. Others: $144+15-1=158\ne 162$, $132+20-1=151\ne 155$, $3+6-1=8\ne 12$

Trick: Test the rule on both given sets before checking options.

Answer: (A) (47, 144, 4)

Concept: Replace letters by signs, then use BODMAS.

1. $48-14\times 3+27÷3$
2. $=48-42+9$
3. $=15$

Trick: Do × and ÷ first: 42 and 9; then $48-42+9$.

Answer: (C) 15

Concept: Check the gaps between consecutive letters (wrap Z→A).

1. RXCJ: R+6=X, X+5=C, C+7=J
2. OUZG: +6, +5, +7; KQVC: +6, +5, +7
3. NTYE: N+6=T, T+5=Y, Y+6=E ✘ (should be F)

Trick: Use positions R18, X24, C3(=29), J10(=36) to see the gaps.

Answer: (D) NTYE

Concept: Find the shift for each position from the given pair.

1. BGLY→DJNB: +2, +3, +2, +3
2. Check JSTK→LVVN: +2, +3, +2, +3 ✔
3. PBZT: P+2=R, B+3=E, Z+2=B, T+3=W → REBW

Trick: Alternate +2, +3 pattern; remember Z+2 wraps to B.

Answer: (C) REBW

Concept: Facing north, left = west end. Fix the certain positions first.

1. Only J is left of O → J at 1, O at 2
2. Four people between J and I → I at 6
3. M-K-N block in 3–5; M not next to I → M 3, K 4, N 5
4. L takes the last seat 7

Trick: 'Only X sits to the left of Y' instantly fixes X at the extreme left and Y second.

Answer: (B) L

Concept: Remove all symbols, then count from the right.

1. Digits left: 8 1 2 3 9 6 4 5 7
2. From right: 7 (1st), 5 (2nd), 4 (3rd), 6 (4th)

Trick: Write the digits from the right end only up to the required count – saves time.

Answer: (C) 6

Concept: Track coordinates with Y at (0, 0); east and north are positive.

1. North 14 → (0, 14); right (east) 6 → (6, 14)
2. Right (south) 20 → (6, −6); right (west) 12 → (−6, −6)
3. Right (north) 6 → Z = (−6, 0)
4. Z is 6 km west of Y → drive 6 km east

Trick: Net E–W: $6-12=-6$; net N–S: $14-20+6=0$.

Answer: (C) 6 km towards the east

Concept: Each letter moves forward by the same number.

1. RUWU→YBDB: R+7=Y, U+7=B, W+7=D
2. JMOM→QTVT: +7 each ✔
3. TWYW: T+7=A, W+7=D, Y+7=F, W+7=D → ADFD

Trick: The 2nd and 4th letters must be equal – only ADFD and ADED keep that; Y+7 = F decides.

Answer: (C) ADFD

Concept: A word common to two sentences takes the code common to both.

1. 'is' appears in both sentences.
2. Common code in 'pb mk lo' and 'jo mt pb' is 'pb'.

Yaad rakhein: Common word ↔ common code.

Answer: (D) pb

Concept: Number positions 1 (bottom) to 7 (top) and place definite boxes first.

1. Two below Z → Z at 3; one above W → W at 6
2. One box between W and Q → Q at 4
3. V just above Y: only free pair is 1–2 → Y 1, V 2
4. R below X: R 5, X 7 → between X and V: W, R, Q, Z

Trick: Boxes between positions 7 and 2 $=7-2-1=4$.

Answer: (B) Four

Concept: Facing north; fix the extreme positions first.

1. Only J left of P → J 1, P 2
2. Four between J and I → I 6
3. R-K-Q block in 3–5; R not next to I → R 3, K 4, Q 5
4. L is left for seat 7 – extreme right

Trick: Same structure as the M-K-N question: the leftover person goes to the open end.

Answer: (B) L

Concept: Track each letter position and the number separately.

1. 1st letters J, K, L, M → N; 2nd M, N, O, P → Q; 3rd R, S, T, U → V
2. Numbers 11, 20, 29, 38 (+9) → 47
3. Answer: NQV47

Trick: All letters move +1, the number moves +9.

Answer: (B) NQV47

Concept: Odd digit +1, even digit −2; then count repeated digits.

1. 7453186 → 7→8, 4→2, 5→6, 3→4, 1→2, 8→6, 6→4
2. New number: 8264264
3. 2, 6 and 4 each appear twice → three digits

Trick: Count digits that repeat, not how many times they repeat.

Answer: (B) Three

Concept: Interchange the signs first, then apply BODMAS.

1. $57÷3+11\times 7-42$
2. $=19+77-42$
3. $=54$

Trick: Rewrite the whole expression with new signs before solving – avoids sign slips.

Answer: (A) 54

Concept: Letters are coded by digits in jumbled order; a common letter takes the common digit.

1. Common letter in BLUE and UNIT: U
2. Common digit in 7524 and 1356: 5
3. So U = 5

Yaad rakhein: Common letter ↔ common digit.

Answer: (C) 5