RRB NTPC Undergraduate CBT 1 2024 PYQs

Concept: Replace letters by signs (A = ÷, B = ×, C = +, D = −) and apply BODMAS.

1. $25÷5-10\times 3+42$.
2. $=5-30+42$.
3. $=17$.

Trick: Do ÷ and × first, then + and − from left to right.

Answer: (D) 17

Concept: A letter common to both words must have the digit common to both codes.

1. GLUE → 2475 and UNIT → 1536.
2. Common letter: U. Common digit: 5.
3. So U = 5.

Trick: Match the common letter with the common digit.

Answer: (C) 5

Concept: Each letter of a term is 4 positions behind the corresponding letter of the previous term.

1. XSW → TOS → PKO → LGK: every letter $-4$.
2. LGK − 4: L→H, G→C, K→G ⇒ HCG.

Trick: Within each term, 3rd letter $=$ 1st letter $-1$ (X/W, T/S, P/O, L/K) ⇒ H/G.

Answer: (A) HCG

Concept: Place Q at the origin and plot each town relative to it.

1. P is north of Q; R is west of Q; T is north of P.
2. S is east of P ⇒ S is to the north (via P) and east of Q.
3. North + East ⇒ S is northeast of Q.

Trick: Combine the two moves from Q: up (north) then right (east) ⇒ northeast.

Answer: (A) Northeast

Concept: For each number, compare (1st digit + 3rd digit) with the 2nd digit.

1. 731: $7+1=8>3$ ✓; 890: $8+0=8<9$ ✗.
2. 923: $9+3=12>2$ ✓; 286: $2+6=8$, not greater than 8 ✗.
3. 378: $3+8=11>7$ ✓ ⇒ three numbers.

Trick: "Greater than" is strict – an equal sum (286) does not count.

Answer: (B) Three

Concept: Track east–west and north–south displacements separately.

1. East 17 → left (north) 6 → right (east) 11 → right (south) 6 → right (west) 2.
2. North–south: $6-6=0$, so P is on the same line as A.
3. East–west: $17+11-2=26\text{km}$ east of A.
4. To return, drive $26\text{km}$ towards west.

Trick: The two 6 km legs cancel; only the east–west total remains.

Answer: (D) 26 km towards West

Concept: Facing the centre, moving to the right means going anticlockwise. Fix C first.

1. B is immediately right of C ⇒ B = 1st right of C.
2. Three people between C and A counted from C’s right ⇒ A = 4th right of C.
3. Two people between Q and B counted from Q’s right ⇒ B = 3rd right of Q ⇒ Q = 5th right of C.
4. Free seats: 2nd, 3rd, 6th right of C. R immediately right of S ⇒ S = 2nd, R = 3rd, D = 6th.
5. 4th right of D: C, B, S, R ⇒ R.

Trick: With 7 seats, "4th to the right" $=$ "3rd to the left".

Answer: (D) R

Concept: Number positions 1 (top) to 7 (bottom) and place fixed boxes first.

1. No box above W ⇒ W = 1. Three boxes between W and F ⇒ F = 5; V immediately above F ⇒ V = 4.
2. One box between E and V ⇒ E = 2 or 6. Four boxes between E and X ⇒ E = 2, X = 7 (E = 6 would need X = 1, taken).
3. Left: 3 and 6 for G and U; G above U ⇒ G = 3, U = 6.
4. Second below G (3) is position 5 ⇒ F.

Trick: "n boxes between" means a gap of $n+1$ positions.

Answer: (A) F

Concept: The word common to both sentences has the code common to both coded forms.

1. ‘are you hungry’ → ‘mk tk jb’; ‘you came early’ → ‘cd ab mk’.
2. Common word: you; common code: mk.
3. So ‘you’ = mk.

Trick: Match common word with common code.

Answer: (C) mk

Concept: Odd digit $+1$, even digit $-1$, then count digits that appear more than once.

1. 8 6 4 3 5 6 2 1 → 7 5 3 4 6 5 1 2.
2. Count: 5 appears twice; 7, 3, 4, 6, 1, 2 appear once.
3. Only one digit (5) repeats.

Trick: The two 6s in the original both become 5, so only that pair repeats.

Answer: (C) One

Concept: Two 'All' statements chain: All A are B + All B are C ⇒ All A are C. 'All' cannot be reversed.

1. Lakes ⊂ Ponds ⊂ Rivers, so all lakes are rivers → I follows
2. Rivers may be outside ponds, so 'All rivers are ponds' is not certain → II does not follow

Trick: 'All A are B' never gives 'All B are A' — only 'Some B are A'.

Answer: (C) Only Conclusion I follows

Concept: Compare gaps inside each cluster using letter positions (A = 1 … Z = 26).

1. JM-DH: J(10)→M(13) +3, D(4)→H(8) +4
2. HK-BF: +3, +4; MP-GK: +3, +4
3. OR-IN: O(15)→R(18) +3, but I(9)→N(14) +5 ✗

Trick: Pattern '+3 then +4' (and first letters −6) breaks only in OR-IN.

Answer: (C) OR-IN

Concept: Find the position shift for each letter (A = 1 … Z = 26), wrapping around after A.

1. R(18)→K(11), B(2)→U(21), N(14)→G(7), H(8)→A(1): each −7
2. Check PZLF→ISEY: −7 each ✓
3. UEQK: U(21)→N(14), E(5)→X(24), Q(17)→J(10), K(11)→D(4)

Trick: −7 is the same as +19; for letters before H, go back around from Z.

Answer: (A) NXJD

Concept: Check differences between consecutive terms.

1. Differences: 10, 20, 30, 40
2. Next difference $=50$
3. $102+50=152$

Trick: Differences in an AP (+10 each time) → add the next multiple of 10.

Answer: (C) 152

Concept: Check differences between consecutive terms.

1. Differences: 0, 1, 2, 3
2. Next difference $=4$
3. $9+4=13$

Trick: Differences 0, 1, 2, 3, 4 — consecutive whole numbers.

Answer: (C) 13

Concept: Apply the rule digit by digit: odd → +2, even → −1.

1. 7 2 5 1 8 6 4 3 → 9 1 7 3 7 5 3 5
2. First digit = 9, last digit = 5
3. Difference $=9-5=4$

Trick: Only the first and last digits matter: 7 → 9 and 3 → 5.

Answer: (D) 4

Concept: Track each letter position separately.

1. 1st letters: C, E, G, I → K (+2)
2. 2nd letters: N, P, R, T → V (+2)
3. 3rd letters: Q, S, U, W → Y (+2)

Trick: Every letter moves +2: ITW → KVY.

Answer: (A) KVY

Concept: Each term is double the previous one.

1. $15\times 2=30$, $30\times 2=60$, $60\times 2=120$
2. $120\times 2=240$
3. Check: $240\times 2=480$ ✓

Trick: Always verify the missing term with the term after it.

Answer: (B) 240

Concept: Use letter positions (A = 1 … Z = 26) within each pair.

1. PT-WR: P(16)→T(20) +4, W(23)→R(18) −5
2. RV-YT and KO-RM: +4 and −5 as well
3. BF-IC: B(2)→F(6) +4, but I(9)→C(3) −6 ✗

Trick: Pattern '+4, then −5' (first letters +7) fails only in BF-IC.

Answer: (D) BF-IC

Concept: Plot the path on axes (East = +x, North = +y); each left turn rotates 90° anticlockwise.

1. A(0, 0) → 9 E → (9, 0) → left, 4 N → (9, 4)
2. Left, 11 W → (−2, 4) → left, 6 S → (−2, −2)
3. Left, 2 E → P(0, −2)
4. A is 2 km straight north of P

Trick: Net E–W: $9-11+2=0$; net N–S: $4-6=-2$ → P is 2 km south of A, so go 2 km North.

Answer: (B) 2 km to North