RRB NTPC Undergraduate CBT 1 2024 PYQs

Concept: Compare 1st → 3rd letter and 2nd → 4th letter (count backwards, wrapping Z→A).

1. FO-YJ: F(6)→Y(25) is 7 back; O→J is 5 back.
2. BX-US: B→U 7 back; X→S 5 back. WA-PV: W→P 7 back; A→V 5 back (wrap).
3. TJ-LE: T(20)→L(12) is 8 back; J→E 5 back → odd one.

Trick: Wrap-around: going back from A or F continues from Z.

Answer: (D) TJ - LE

Concept: Find the gaps between consecutive letters of each cluster.

1. NRM: 14→18→13: $+4$, $-5$. JNI: 10→14→9: $+4$, $-5$. QUP: 17→21→16: $+4$, $-5$.
2. TXR: 20→24→18: $+4$, $-6$ → odd one.

Trick: In the group the third letter is just before the first (N-M, J-I, Q-P); in TXR it is not (T-R).

Answer: (A) TXR

Concept: Check differences between consecutive terms.

1. Differences: 8, 9, 10, 11.
2. Next difference = 12.
3. Next term $=41+12=53$.

Trick: Differences increasing by 1 → keep adding the next consecutive number.

Answer: (D) 53

Concept: Total $=\text{rank from top}+\text{rank from bottom}-1$.

1. $5+21-1=25$.

Trick: Subtract 1 because Pritam is counted in both ranks.

Answer: (A) 25

Concept: Fix the person with a definite position first, then place the rest.

1. Only two to the right of K → K is 5th; V (immediate left of K) is 4th.
2. Two between K and U → U is 2nd.
3. Two between I and V → I is 1st or 7th; W-L need two adjacent free seats → only 6th-7th, so I is 1st.
4. Remaining seat 3rd → J. Row: I U J V K W L.

Trick: Place the 'W immediately left of L' pair last – it needs two adjacent empty seats, which decides I's position.

Answer: (C) J

Concept: Add the first and third digits of each number and test for primality.

1. 570: $5+0=5$ (prime). 787: $7+7=14$. 488: $4+8=12$.
2. 277: $2+7=9$. 102: $1+2=3$ (prime).
3. Prime sums: 5 and 3 → two numbers.

Yaad rakhein: 1 is not prime; 9 is $3\times 3$ – a common trap.

Answer: (C) Two

Concept: Find the shift for each letter separately; the letter part decides the option.

1. L(12)→G(7) and I(9)→D(4): first letter $-5$.
2. K(11)→G(7) and T(20)→P(16): second letter $-4$.
3. O(15)$-5$ = J(10); V(22)$-4$ = R(18) → letters JR.
4. Number: $19\to 2$ and $29\to 12$ (difference 17); only 'JR 2' carries the letters JR.

Trick: In letter-number analogies, fix the letters first – here only one option starts with JR.

Answer: (A) JR 2

Concept: Rearrange digits in ascending order and compare position-wise.

1. Original: 8 3 5 7 6 9 1.
2. Ascending: 1 3 5 6 7 8 9.
3. Same position: 3 (2nd) and 5 (3rd) → two digits.

Trick: Write both rows one below the other and tick matching columns.

Answer: (A) Two

Concept: Check the differences between consecutive terms.

1. Differences: $-11,-13,-15,-17$.
2. They decrease by 2 → next $-19$.
3. Next term $=-25-19=-44$.

Trick: Differences are consecutive odd numbers (11, 13, 15, 17, 19).

Answer: (B) −44

Concept: Find the shift of each letter position.

1. C→F (+3), H→K (+3), R→X (+6), X→D (+6, wraps).
2. O→R (+3), T→W (+3), P→V (+6), V→B (+6) ✓.
3. X+3 = A, C+3 = F, H+6 = N, N+6 = T → AFNT.

Trick: Pattern +3, +3, +6, +6; after Z, continue from A.

Answer: (D) AFNT

Concept: Replace letters with signs, then apply BODMAS.

1. $18÷3-8\times 2+12$
2. $=6-16+12$
3. $=2$

Trick: Do ÷ and × first ($6$ and $16$), then + and − left to right.

Answer: (C) $2$

Concept: Decode each symbol from left to right and build a family tree.

1. W $ A: W is the brother of A
2. A = C: A is the mother of C
3. C @ D: C is the wife of D; D * R: D is the father of R, so C is R's mother
4. A is R's mother's mother; W (A's brother) is R's mother's mother's brother

Trick: Climb the chain from R upward: mother (C) → her mother (A) → her brother (W).

Answer: (C) Mother's mother's brother

Concept: Letters common to both words share the common digits; the leftover letter gets the leftover digit.

1. DELT → {1, 4, 7, 3}; BLED → {7, 2, 3, 4}
2. Common letters D, E, L ↔ common digits 3, 4, 7
3. DELT has extra T ↔ extra 1; BLED has extra B ↔ extra 2

Trick: Cancel the common part; what remains in BLED's code (2) is B.

Answer: (D) 2

Concept: Fix the definite positions first, then place the pairs.

1. Only S above I $\Rightarrow$ S = 1st, I = 2nd from top
2. Four boxes between I and K $\Rightarrow$ K = 7th
3. M and G (two between) must take 3rd and 6th; H, L (H just above L) take 4th, 5th
4. G not immediately above H $\Rightarrow$ G = 6th, M = 3rd. Order: S, I, M, H, L, G, K

Trick: Only the pair 3–6 has exactly two gaps among the free slots 3, 4, 5, 6.

Answer: (B) H

Concept: Facing the centre: left = clockwise, right = anticlockwise.

1. Fix S; O is second to the left of S; R is third to the left of O
2. Q is third to the right of L. L must sit immediately to the right of S, which puts Q immediately to the left of O
3. N is a neighbour of Q, M takes the last seat: clockwise S, M, O, Q, N, R, L
4. Third to the right of M (anticlockwise): S, L, R

Trick: The other placement of L–Q leaves no free seat beside Q for N, so it is rejected.

Answer: (C) R

Concept: Track each letter position of the clusters separately.

1. 1st letters: F → A → V → Q, each $-5$ (A $-5$ wraps to V); next Q $-5$ = L
2. 2nd letters: I → D → Y → T, each $-5$; next O
3. 3rd letters: L → G → B → W, each $-5$; next R

Trick: Each cluster is the previous one shifted back by 5 letters: QTW → LOR.

Answer: (B) LOR

Concept: Find the letter-wise shifts in the given pairs.

1. MUV → QPZ: M $+4$ = Q, U $-5$ = P, V $+4$ = Z
2. UKD → YFH: U $+4$ = Y, K $-5$ = F, D $+4$ = H
3. CAL: C $+4$ = G, A $-5$ = V (wrap), L $+4$ = P → GVP ✔

Trick: Check the middle letter ($-5$) first – it rejects TLW (L → Q) and SLU at once.

Answer: (C) CAL : GVP

Concept: A letter common to both words is coded by the digit common to both codes.

1. LOAN → {4, 2, 5, 7}; NIKE → {1, 3, 4, 6}
2. Only common letter: N; only common digit: 4
3. So N = 4

Trick: One common letter ↔ one common digit.

Answer: (D) 4

Concept: Rearrange the digits and read positions carefully from each end.

1. Ascending order: 1 2 3 4 5 6 7 9
2. Third from left = 3
3. Fourth from right (8 digits) = 5th from left = 5
4. Sum $=3+5=8$

Trick: $k$th from right $=(n-k+1)$th from left; here $8-4+1=5$.

Answer: (C) 8

Concept: Use positions: in each pair XY-ZW, compare Y, Z, W with X.

1. NQ-SL: N14 → Q17 ($+3$), S19 ($+5$ from N), L12 ($-7$ from S)
2. JM-OH: J10 → M13 ($+3$), O15 ($+5$), H8 ($-7$)
3. FI-KD: F6 → I9, K11, D4 – same pattern
4. CF-HB: C3 → F6, H8, but B2 is H $-6$ – odd

Trick: Only the last letter breaks the pattern, so compare 4th letter with 3rd first.

Answer: (C) CF-HB