RRB NTPC Undergraduate CBT 1 2024 PYQs

Concept: Look at the differences between consecutive terms.

1. $561\stackrel{+1}{\to }562\stackrel{+2}{\to }564\stackrel{+3}{\to }?$
2. $564+3=567$; check $567+4=571$, $571+5=576$ ✔

Trick: Differences 1, 2, 3, 4, 5 – a simple increasing pattern.

Answer: (C) 567

Concept: Use 'only X above / below' clues to fix the ends first.

1. Only C above D $\Rightarrow$ C = 1st, D = 2nd (from top)
2. Two boxes between D and E $\Rightarrow$ E = 5th
3. Only A below B $\Rightarrow$ A = 7th, B = 6th
4. F not immediately above E $\Rightarrow$ F = 3rd, G = 4th. Between B and F: G, E

Trick: Two 'only' clues fix four boxes at once – start there.

Answer: (B) Two

Concept: Swap the signs as instructed, then apply BODMAS.

1. $7÷4+20-72\times 6$ becomes $7\times 4-20+72÷6$
2. $=28-20+12$
3. $=20$

Trick: Rewrite the whole expression first; swapping mentally while calculating causes errors.

Answer: (D) 20

Concept: Treat the letters and the numbers as separate series.

1. First letters: Z, V, R, N ($-4$ each) → J; last letters Y, U, Q, M ($-4$) → I
2. Numbers: $122={11}^2+1$, $101={10}^2+1$, $82=9^2+1$, $65=8^2+1$
3. Next number $=7^2+1=50$ → J50I

Trick: The last letter is always the letter just before the first one (Z-Y, V-U …), so J…I.

Answer: (C) J50I

Concept: Facing north, left and right are the viewer's left and right; number the seats 1–7 from the left.

1. No one right of H $\Rightarrow$ H = 7; two between H and M $\Rightarrow$ M = 4
2. M immediately left of S $\Rightarrow$ S = 5; three between I and S $\Rightarrow$ I = 1
3. L, K together (K right of L) in seats 2, 3 $\Rightarrow$ L = 2, K = 3; G = 6
4. Between G (6) and K (3): M, S

Trick: Anchor the end person (H) first; the chain H → M → S → I then fills almost the whole row.

Answer: (D) Two

Concept: Compare 2nd and 3rd letters with the 1st letter's position.

1. MHN: M13, H8 ($-5$), N14 ($+1$)
2. PKQ: P16, K11 ($-5$), Q17 ($+1$); IDJ: I9, D4 ($-5$), J10 ($+1$)
3. SNU: S19, N14 ($-5$), U21 ($+2$) – odd

Trick: In the group, the 3rd letter is just the next letter after the 1st (M-N, P-Q, I-J); S-U breaks it.

Answer: (B) SNU

Concept: Find the shift of each letter in the example pairs.

1. CHRX → HMXD: $+5,+5,+6,+6$
2. WBPV → BGVB: W $+5$ = B, B $+5$ = G, P $+6$ = V, V $+6$ = B ✔
3. LQHN: L $+5$ = Q, Q $+5$ = V, H $+6$ = N, N $+6$ = T → QVNT

Trick: Option elimination: 2nd letter must be Q $+5$ = V, leaving QVTN and QVNT; 3rd letter H $+6$ = N decides.

Answer: (D) QVNT

Concept: Check the differences with alternating signs.

1. $18\stackrel{+5}{\to }23\stackrel{-6}{\to }17\stackrel{+7}{\to }24\stackrel{-8}{\to }16$
2. Next: $16+9=25$

Trick: Alternate terms also work: 18, 17, 16 (down by 1) and 23, 24, 25 (up by 1).

Answer: (C) 25

Concept: Fix the top and bottom boxes using the 'only' clues.

1. Only D above C $\Rightarrow$ D = 1st, C = 2nd (from top)
2. Only E between C and M $\Rightarrow$ E = 3rd, M = 4th
3. Only P below N $\Rightarrow$ P = 7th, N = 6th; O = 5th
4. Between O (5th) and P (7th): N only

Trick: Once both ends are fixed, the single leftover box (O) drops into the only empty slot.

Answer: (D) One

Concept: Plot the path on axes, taking A as the origin; each right turn rotates the direction clockwise.

1. 7 km south: $(0,-7)$; right → west 8 km: $(-8,-7)$
2. Right → north 9 km: $(-8,2)$; right → east 9 km: $(1,2)$
3. Right → south 2 km: P $=(1,0)$
4. A $(0,0)$ is 1 km to the west of P

Trick: Net N–S: $-7+9-2=0$; net E–W: $-8+9=+1$ (east). So go back 1 km west.

Answer: (C) 1 km to west

Concept: Find what happens to the letters and to the number separately.

1. FI 11 → KN 8: F $+5$ = K, I $+5$ = N, $11-3=8$
2. NQ 25 → SV 22: $+5$, $+5$, $-3$ ✔
3. OR 17 → O $+5$ = T, R $+5$ = W, $17-3=14$ → TW 14

Trick: Number part alone ($17-3=14$) leaves UW 14 and TW 14; O $+5$ = T settles it.

Answer: (D) TW 14

Concept: Draw the least-overlap Venn diagram; a conclusion follows only if it is true in every possible diagram.

1. All bricks are spoons: Bricks circle inside Spoons
2. No brick is a cricket: Crickets lie outside Bricks, but may or may not touch Spoons
3. (I) Some crickets are spoons – not certain (Crickets can be fully outside Spoons)
4. (II) All spoons are crickets – false (bricks are spoons but not crickets)

Trick: A 'No' statement never guarantees a 'Some' link with a third set.

Answer: (C) Neither conclusion (I) nor (II) follows.

Concept: With two 'Some' statements through a middle term, the end terms have no definite relation.

1. Homestays overlap Resorts; Resorts overlap Palaces
2. Homestays and Palaces may not meet at all → (I) not certain
3. Palaces may lie partly outside Resorts → (II) not certain

Yaad rakhein: Some + Some = no conclusion between the two end terms.

Answer: (B) Neither conclusion (I) nor (II) follows.

Concept: Swap the signs as instructed, then apply BODMAS.

1. $32+8\times 2-12÷5$ becomes $32-8÷2+12\times 5$
2. $=32-4+60$
3. $=88$

Trick: Write the new expression completely before solving.

Answer: (B) 88

Concept: Find the gaps between consecutive letters using their positions.

1. BIL: B2 → I9 ($+7$) → L12 ($+3$)
2. PWZ: P16 → W23 ($+7$) → Z26 ($+3$); OVY: O15 → V22 ($+7$) → Y25 ($+3$)
3. YEI: Y25 → E5 ($+6$, wrapping) → I9 ($+4$) – odd

Trick: Pattern $+7,+3$ in three clusters; YEI gives $+6,+4$.

Answer: (A) YEI

Concept: A number is even when its last (third) digit is even.

1. Third digits: 5, 8, 7, 1, 2
2. After adding 1: 6, 9, 8, 2, 3
3. Even: 476, 858, 592 → three numbers

Trick: Adding 1 flips parity: the numbers that were odd (475, 857, 591) become even.

Answer: (C) Three

Concept: Differences are perfect squares.

1. $6\stackrel{+0}{\to }6\stackrel{+1}{\to }7\stackrel{+4}{\to }11\stackrel{+9}{\to }20$
2. Differences $0^2,1^2,2^2,3^2$; next $4^2=16$
3. $20+16=36$

Trick: Differences 0, 1, 4, 9 are squares of 0, 1, 2, 3.

Answer: (C) 36

Concept: Check each number: the term just before must be a number and the term just after must be a symbol (pattern number–NUMBER–symbol).

1. 1 7 %: 7 is preceded by 1 and followed by % ✔
2. 4 9 &: 9 is preceded by 4 and followed by & ✔
3. Others fail, e.g. @ 2 ©, © 1 ©, 4 4 9, 5 5 (end)

Trick: Scan only for symbols; look at the two terms just before each symbol.

Answer: (D) 2

Concept: Find one rule that fits both given pairs.

1. $24\times 3-6=66$; $18\times 3-6=48$ ✔
2. (B) $30\times 3-6=84$ ✔
3. (A) $22\to 60$, (C) $20\to 54$, (D) $28\to 78$ – do not match

Trick: Second number $=3\times$ first $-6$, i.e. $3(\text{first}-2)$: $3\times 28=84$ for 30.

Answer: (B) 30, 84

Concept: Plot the path with Y at the origin; net displacement gives the answer.

1. 23 km north: $(0,23)$; right → east 12 km: $(12,23)$
2. Right → south 27 km: $(12,-4)$; right → west 12 km: Z $=(0,-4)$
3. Z is 4 km south of Y, so drive 4 km north

Trick: East 12 and west 12 cancel; net N–S $=23-27=-4$ (south). Return 4 km north.

Answer: (C) 4 km towards north