RRB NTPC Undergraduate CBT 1 2024 PYQs

Concept: Shifts: $-2,-3,+2,+3$.

1. GBNS → EYPV: G−2, B−3 = Y, N+2, S+3
2. CVRY → ASTB: same (Y+3 = B)
3. YPVE → Y−2 = W, P−3 = M, V+2 = X, E+3 = H
4. WMXH

Trick: Wrap around: before A comes Z, after Z comes A.

Answer: (C) WMXH

Concept: Compare each position before and after sorting.

1. Original: 6 2 4 3 5 1 4
2. Sorted: 1 2 3 4 4 5 6
3. Only the 2nd digit (2) stays the same
4. Count $=1$

Trick: Write both numbers one below the other and tick matches.

Answer: (C) One

Concept: Differences are perfect squares $1^2,2^2,3^2,\dots$

1. $679+1=680$, $+4=684$, $+9=693$, $+16=709$
2. Next: $709+25=734$

Trick: Differences 1, 4, 9, 16 → squares.

Answer: (C) 734

Concept: Decode each symbol step by step and draw the family tree.

1. S ¥ Y: S is father of Y (S male)
2. Y # R: Y is brother of R → S is also R's father
3. R = U: R is wife of U
4. U % P: U is son of P → R is P's son's wife
5. S is P's son's wife's father

Trick: Start from P and walk the chain: son → wife → father.

Answer: (B) Son's wife's father

Concept: All A are B ⇒ Some B are A; No A is C ⇒ No C is A.

1. No lion is a cat ⇒ No cat is a lion, so I (Some cats are lions) is false.
2. All lions are tigers ⇒ Some tigers are lions → II follows.

Yaad rakhein: 'All' statements always give a 'Some' conclusion in reverse.

Answer: (B) Only conclusion (II) follows.

Concept: Common letters share common digits; the leftover letter gets the leftover digit.

1. SAID → 6175, DIMS → 7691
2. Common letters: S, I, D ↔ common digits: 6, 7, 1
3. Leftover in DIMS: M ↔ 9

Trick: Remove common letters and digits; what remains matches.

Answer: (A) 9

Concept: Number the boxes 1 (top) to 7 (bottom) and fix the certain ones first.

1. Only V above Y → V = 1, Y = 2
2. One box between V and T → T = 3; T just above D → D = 4
3. Two between Y and X → X = 5
4. U just above W → U = 6, W = 7
5. Between W (7) and V (1): 5 boxes

Trick: 'Only V above Y' fixes the top two at once.

Answer: (B) Five

Concept: Interchange the signs, then use BODMAS.

1. After swapping: $42÷7+12\times 3-13$
2. $=6+36-13$
3. $=29$

Trick: Do ÷ and × first, then + and −.

Answer: (C) 29

Concept: Add 2 to the first digit and test divisibility by the second digit.

1. 384 → 5 ÷ 8 ✗; 673 → 8 ÷ 7 ✗
2. 543 → 7 ÷ 4 ✗; 236 → 4 ÷ 3 ✗
3. 741 → 9 ÷ 4 ✗
4. No number qualifies → 0

Trick: A smaller number can never be exactly divisible by a larger one (except 0).

Answer: (B) 0

Concept: Place towns on a grid with M as reference.

1. N is south of M; K is west of N; L is south of N.
2. From K: L is towards east (same column as N) and towards south.
3. So L is to the southeast of K.

Trick: East + South combined = Southeast.

Answer: (D) Southeast

Concept: Check each symbol: the element just before it must be a number and the one just after it must be a symbol (pattern: number–SYMBOL–symbol).

1. Scan left to right for “number, symbol, symbol”.
2. 2 $ © ✓; 2 £ @ ✓; 5 £ % ✓.
3. 5 # 6 fails (followed by a number); others are preceded by symbols.
4. Total $=3$.

Trick: First mark every symbol followed by a symbol, then keep only those with a number before them.

Answer: (B) 3

Concept: Facing the centre, a person’s left is clockwise and right is anticlockwise.

1. Fix D; L is immediately right (anticlockwise) of D.
2. Going left (clockwise) from L, three people sit before C: D and two more seats, then C.
3. Three between D and J places J next to C (other side is C’s seat).
4. A is immediate right of K → only possible in the two seats after D: D, A, K, C; B fills the last seat.
5. From the right of K (anticlockwise): K → A → D, so 1 person.

Trick: In circular puzzles, place the most fixed pair (D–L) first and read “from the right/left” as anticlockwise/clockwise.

Answer: (D) One

Concept: Compare the letter gaps in each pair using positions (A = 1 … Z = 26).

1. KP-LI: $K+1=L$, $P(16)-7=I(9)$.
2. MR-NK: $M+1=N$, $R(18)-7=K(11)$; IN-JG: $I+1=J$, $N(14)-7=G(7)$.
3. GL-HF: $G+1=H$ but $L(12)-6=F(6)$ — gap 6, not 7.

Trick: First letters all move $+1$, so the odd one hides in the second letter.

Answer: (A) GL-HF

Concept: Apply the rule digit-wise: odd digit $+3$, even digit $-1$.

1. 6 2 4 3 5 1 4 → 5 1 3 6 8 4 3.
2. Highest digit $=8$, lowest $=1$.
3. Difference $=8-1=7$.

Trick: Only the extremes matter: largest odd (5) gives 8, smallest result comes from 2 → 1.

Answer: (B) 7

Concept: Differences doubling: $+1,+2,+4,+8,\dots$

1. $84+1=85$, $85+2=87$, $87+4=91$, $91+8=99$.
2. Next: $99+16=115$.

Trick: Differences are powers of 2: $2^0,2^1,2^2,2^3,2^4$.

Answer: (B) 115

Concept: Replace letters by signs (A = $÷$, B = $\times$, C = $+$, D = $-$) and solve using BODMAS.

1. $(117÷3)+(119÷7)+24-6+(117÷13)\times 2$.
2. $=39+17+24-6+9\times 2$.
3. $=39+17+24-6+18=92$.

Trick: Finish all brackets and $\times$ first: $39,17,18$; then add/subtract.

Answer: (B) 92

Concept: Swap $+\leftrightarrow -$ and $\times \leftrightarrow ÷$, then apply BODMAS.

1. $25÷6-8+20\times 4$ becomes $25\times 6+8-20÷4$.
2. $=150+8-5$.
3. $=153$.

Trick: Rewrite the whole expression first, then calculate — avoid swapping mid-way.

Answer: (B) 153

Concept: A letter common to both words takes the digit common to both codes (codes may be jumbled).

1. LEFT → 5427, EARS → 6153.
2. Common letter: E.
3. Common digit: 5. So E = 5.

Trick: Intersect letters and intersect digits — one common each means a direct match.

Answer: (A) 5

Concept: Track the position with coordinates (east and north positive).

1. A $(0,0)$ → east 8: $(8,0)$ → left (north) 4: $(8,4)$.
2. Left (west) 4: $(4,4)$ → left (south) 11: $(4,-7)$.
3. Right while facing south = west, 4 km: P $(0,-7)$.
4. A is 7 km straight north of P.

Trick: Net east $=8-4-4=0$, net north $=4-11=-7$ → go 7 km north.

Answer: (C) 7 km towards north

Concept: Treat each letter position and the number as separate series.

1. 1st letters: C, E, G, I → $+2$ → K.
2. 2nd letters: O, Q, S, U → $+2$ → W; 3rd: B, D, F, H → $+2$ → J.
3. Numbers: 5, 10, 15, 20 → $+5$ → 25.

Trick: All three letters jump $+2$ — option with K…W…J and 25.

Answer: (C) KWJ 25