RRB NTPC Undergraduate CBT 1 2025 PYQs

Concept: Relate the 2nd and 3rd letters to the 1st letter.

1. ROS: R(18) → O(15) $=-3$, S(19) $=+1$.
2. MJN: M(13) → J $-3$, N $+1$. LIM: L(12) → I $-3$, M $+1$.
3. JKO: J(10) → K $+1$, O $+5$ – does not follow.

Trick: Pattern “$-3$, $+1$” from the first letter; JKO breaks it.

Answer: (A) JKO

Concept: Split each cluster into 1st, 2nd and 3rd letters.

1. 1st: P, Q, R, S → $+1$ → T.
2. 2nd: C, G, K, O → $+4$ → S.
3. 3rd: O, L, I, F → $-3$ → C.

Trick: The first letter must be T – only one option starts with T.

Answer: (D) TSC

Concept: Decode each symbol from left to right and draw the family tree.

1. V − D: V is the daughter of D. D + Q: D is the sister of Q (D is female).
2. Q × T: Q is the son of T. T ÷ R: T is the husband of R, so R is the mother of Q and D.
3. V is the daughter of D, and D is R’s daughter → V is R’s daughter’s daughter.

Trick: A sister of someone shares the same parents – put D beside Q under T–R.

Answer: (D) Daughter’s daughter

Concept: Find the change in each letter and in the number separately.

1. DI 12 → JE 3: D(4)→J(10) $+6$, I(9)→E(5) $-4$, $12-9=3$.
2. EW 11 → KS 2: E→K $+6$, W(23)→S(19) $-4$, $11-9=2$ ✓.
3. KN 19: K(11)→Q(17), N(14)→J(10), $19-9=10$ → QJ 10.

Trick: Apply “$+6$, $-4$, $-9$” directly; the number 10 alone matches only one option.

Answer: (C) QJ 10

Concept: Find even digits with a perfect square (1, 4 or 9) just before and an odd digit just after.

1. Scan for patterns (1, 4 or 9) – even – odd.
2. Found: 4 8 7, 4 6 3, 9 8 7, 9 8 7, 1 2 5, 9 6 3, 9 8 7, 1 4 5.
3. Total $=8$.

Trick: Search around every 1, 4 and 9 only – each is a possible “preceding” digit.

Answer: (C) 8

Concept: Letters common to both words take the digits common to both codes.

1. JACK = 9621, CALK = 6231.
2. Common letters A, C, K ↔ common digits 6, 2, 1.
3. Remaining: J ↔ 9 (in JACK) and L ↔ 3 (in CALK). So L = 3.

Trick: Eliminate common letters and common digits – the leftover pair is the answer.

Answer: (B) 3

Concept: Look for three consecutive odd digits; the middle one is counted.

1. Scan the series for odd–odd–odd runs.
2. Found: 1 1 9, 9 7 1, 7 1 3, 1 5 3.
3. Total $=4$.

Trick: Mark every even digit as a barrier; only blocks of three or more odd digits give answers.

Answer: (B) Four

Concept: Check the differences between consecutive terms.

1. Differences: $-55,-50,-45,-40,-35$.
2. Next difference $=-30$: $55-30=25$.

Trick: Differences decrease by 5 each time.

Answer: (D) 25

Concept: Draw the least possible Venn diagram for the statements.

1. All jars are boxes → Jars circle lies inside Boxes.
2. Some bottles are jars → those bottles are also boxes, so “Some boxes are bottles” is definitely true – (I) follows.
3. Boxes may contain things that are not jars, so “All boxes are jars” is not certain – (II) does not follow.

Trick: “All A are B” cannot be reversed to “All B are A”.

Answer: (B) Only conclusion (I) follows

Concept: Number seats 1 to 7 from left (all face north) and place definite clues first.

1. Only Q to the left of H → Q = 1, H = 2.
2. Four people between Q and G → G = 6.
3. Only F between L and M needs three consecutive free seats → 3, 4, 5 with F = 4. L is not next to G (6) → L = 3, M = 5.
4. O = 7. Between O (7) and H (2): seats 3–6 → 4 people.

Trick: “Only X to the left of Y” fixes both of them at seats 1 and 2.

Answer: (C) Four

Concept: Find the single operation that turns the first number into the second.

1. $78+10=88$ and $32+10=42$ → rule: add 10.
2. (A) $110+10=120$ ✓; (B) $45+11=56$ ✗; (C) $98-10=88$ ✗; (D) $90+20=110$ ✗.

Trick: Check the difference (second $-$ first) of each option: it must be exactly $+10$.

Answer: (A) 110 - 120

Concept: Compare letters position by position.

1. WTQT → VSPS: W→V, T→S, Q→P, T→S – each letter $-1$.
2. ZWTW → YVSV: each $-1$ ✓.
3. OLIL → N K H K → NKHK.

Trick: Same shift on every letter: just move each letter one step back.

Answer: (B) NKHK

Concept: Number positions 1 (bottom) to 6 (top) and fix definite clues.

1. Three boxes above F → F = 3.
2. One box between H and F → H = 1 or 5. Three boxes between H and I: H = 1 gives I = 5; H = 5 gives I = 1, but I must be above F. So H = 1, I = 5.
3. B immediately below I → B = 4. E below G among 2 and 6 → E = 2, G = 6.
4. Between G (6) and H (1): I, B, F, E → 4 boxes.

Trick: Gap between positions $p$ and $q$ $=|p-q|-1=6-1-1=4$.

Answer: (A) Four

Concept: Apply the rule to every digit: odd $+1$, even $-1$.

1. 7254136: 7→8, 2→1, 5→6, 4→3, 1→2, 3→4, 6→5.
2. New number: 8163245.
3. Digits 8, 1, 6, 3, 2, 4, 5 are all different – no digit repeats.

Trick: Odd $+1$ and even $-1$ just swap pairs (1↔2, 3↔4, 5↔6, 7↔8), so distinct digits stay distinct.

Answer: (A) None

Concept: Common letters of the two words share the common digits of the two codes.

1. GLOW = 3187, WOLF = 1273.
2. Common letters L, O, W ↔ common digits 1, 3, 7.
3. Left over: G ↔ 8 (GLOW) and F ↔ 2 (WOLF). So G = 8.

Trick: Cancel the common part; the unique letter takes the unique digit.

Answer: (B) 8

Concept: Track the change in each letter and the number.

1. LL 22 → JH 6: L(12)→J(10) $-2$, L(12)→H(8) $-4$, $22-16=6$.
2. CR 20 → AN 4: C→A $-2$, R(18)→N(14) $-4$, $20-16=4$ ✓.
3. GN 14: G(7)→E(5), N(14)→J(10), $14-16=-2$ → EJ $-2$.

Trick: Rule “$-2$, $-4$, $-16$”; only EJ has J for N.

Answer: (D) EJ −2

Concept: Apply the rule to each digit: odd $+3$, even $-2$.

1. 8254316: 8→6, 2→0, 5→8, 4→2, 3→6, 1→4, 6→4.
2. New number: 6082644.
3. First from left $=6$; second from right $=4$. Sum $=6+4=10$.

Trick: Only the two required digits need converting: 8→6 and 1→4.

Answer: (B) 10

Concept: When people face the centre, moving to their right means moving anticlockwise.

1. Fix Y; D is third to the right of Y: Y, _, _, D going anticlockwise.
2. Z is second to the right of X and B sits between X and C, so the order (anticlockwise) is C, B, X, _, Z.
3. The only fit: X, Y, Z consecutive (Y is the gap), giving Y, Z, A, D, C, B, X anticlockwise.
4. A is just after Z anticlockwise → A is to the immediate right of Z.

Trick: Facing centre: right = anticlockwise, left = clockwise.

Answer: (A) Immediate right

Concept: Decode each symbol and build the family tree.

1. C ? O: C is the wife of O. O : V: O is the father of V, so C is V’s mother.
2. V @ E: V is the mother of E. E + R: E is the daughter of R, so R is E’s father, i.e. V’s husband.
3. C is the mother of R’s wife (V) → C is R’s wife’s mother.

Trick: Two parents of the same child (V and R for E) are husband and wife.

Answer: (A) Wife's mother

Concept: Draw the minimum Venn diagram; a conclusion follows only if it is true in every possible case.

1. All chairs are trees → Chairs inside Trees. Some leaves are trees → Leaves overlap Trees.
2. The overlap of Leaves may lie outside Chairs, so “Some leaves are chairs” is not certain – (I) does not follow.
3. Trees may include things that are not chairs, so “All trees are chairs” does not follow – (II) fails.

Trick: Two statements linked through the “all” circle’s outer set (Trees) give no definite link between Leaves and Chairs.

Answer: (A) Neither conclusion (I) nor (II) follows