RRB NTPC Undergraduate CBT 1 2025 PYQs

Concept: Check the gap between consecutive letters of each cluster.

1. KHI: K $\stackrel{-3}{\to }$ H $\stackrel{+1}{\to }$ I
2. ZWX: Z $\stackrel{-3}{\to }$ W $\stackrel{+1}{\to }$ X; FCD: F $\stackrel{-3}{\to }$ C $\stackrel{+1}{\to }$ D
3. PNN: P $\stackrel{-2}{\to }$ N $\stackrel{0}{\to }$ N – different pattern.

Trick: A repeated letter (NN) usually signals the odd cluster – verify quickly.

Answer: (A) PNN

Concept: Facing north, “right” is the east end. Fix the person with a unique position first.

1. Only H is to the right of G → H at the right end (7), G at 6.
2. Two between H and Q → Q = 4. Three between G and F → F = 2.
3. Positions 1, 3, 5 left for M, L, O with M < L < O (left to right) → M = 1, L = 3, O = 5.
4. Between M (1) and O (5): F, L, Q = 3 people.

Trick: “Only X is to the right of Y” → Y is second from the right end.

Answer: (B) Three

Concept: Compare each letter of the first cluster with the corresponding letter of the second.

1. VXW → UWV: each letter $-1$. WYX → VXW: each letter $-1$.
2. BDC → ACB: B→A, D→C, C→B, each $-1$ ✓.
3. BCA → ACB, BDC → ZCA and BCA → ZBA break the $-1$ rule.

Trick: Check only the first letter of each option first (B → A); only (A) and (B) survive, then check the rest.

Answer: (A) BDC−ACB

Concept: A word common to two sentences gets the code common to both coded sentences.

1. salt elbow care → zh pv nf
2. night care jar → ab po zh
3. Only “care” and only “zh” are common → care = zh.

Trick: Common word ↔ common code – no need to decode other words.

Answer: (A) zh

Concept: Write the digits in ascending order and compare place by place with the original number.

1. Original: 7 3 9 1 2 6 8 5
2. Ascending: 1 2 3 5 6 7 8 9
3. Only the 7th place has the same digit (8) in both.

Trick: A digit stays fixed only if exactly (its place − 1) digits are smaller than it: 8 has 6 smaller digits and sits 7th ✓.

Answer: (C) One

Concept: Swap the signs as directed, then solve using BODMAS.

1. After interchange: $39+15\times 3-124÷4$
2. $=39+45-31$
3. $=53$

Trick: Swap carefully in one pass (write the new expression fully) before calculating.

Answer: (C) $53$

Concept: Number positions 1 (bottom) to 7 (top) and place the fixed box first.

1. D = 3. C above A but below D → A = 1, C = 2.
2. Positions 4–7 left for B, E, F, G. E above F and below B → F is the lowest of them.
3. Two between G and F → F = 4, G = 7; then E = 5, B = 6.
4. Between E (5) and D (3): only F → one box.

Trick: When only one pair of slots fits “two between” inside a 4-slot block, it must be the two ends (4 and 7).

Answer: (B) One

Concept: Find a rule linking the three numbers of each set.

1. $(15,12,37)$: $15+12+10=37$
2. $(25,15,50)$: $25+15+10=50$
3. $(2,8,20)$: $2+8+10=20$ ✓; others give $38\ne 40$, $44\ne 40$, $45\ne 42$.

Trick: Third number − (first + second) is constant (10) – test that difference on each option.

Answer: (A) $(2,8,20)$

Concept: Number positions 1 (bottom) to 7 (top); “only X above Y” fixes both at the top.

1. Only G above E → G = 7, E = 6.
2. Only C between E and A → C = 5, A = 4.
3. Only F below B → F = 1, B = 2; remaining D = 3.
4. Between C (5) and F (1): A, D, B → 3 boxes.

Trick: Boxes between positions $p$ and $q$ = $|p-q|-1=5-1-1=3$.

Answer: (B) 3

Concept: Track each letter position of the clusters separately.

1. 1st letters: B, E, H, K → $+3$ → N
2. 2nd letters: M, P, S, V → $+3$ → Y
3. 3rd letters: S, V, Y, B → $+3$ (Y → Z → A → B) → E

Trick: All three positions move $+3$; after Z, wrap around to A.

Answer: (B) NYE

Concept: Look at the differences between consecutive terms.

1. Differences: $27,54,81,108$ = $27\times 1,27\times 2,27\times 3,27\times 4$
2. Next difference $=27\times 5=135$
3. $321+135=456$

Trick: Differences in a table of 27 – recognise multiples quickly.

Answer: (A) $456$

Concept: Treat each letter position and the number separately.

1. Every letter moves $-3$: G→D→A→X→U, C→Z→W→T→Q, H→E→B→Y→V.
2. Numbers: 10, 21, 32, 43 → $+11$ → 54.
3. Next term: UQV 54.

Trick: Numbers alone (+11 → 54) cut options to (B); confirm letters.

Answer: (B) UQV 54

Concept: Number positions 1 (bottom) to 7 (top).

1. No box below B → B = 1. Two between G and B → G = 4.
2. Only D above C → D = 7, C = 6.
3. Positions 2, 3, 5 for A, F, E with A above F above E → E = 2, F = 3, A = 5.
4. Between D (7) and E (2): C, A, G, F → 4 boxes.

Trick: “No box below B” = B at the bottom; “only D above C” = D top, C second.

Answer: (C) 4

Concept: Compare the change from the first cluster to the second, letter by letter.

1. PS → OR: $-1,-1$; FI → EH: $-1,-1$; LO → KN: $-1,-1$.
2. KN → JL: K→J is $-1$ but N→L is $-2$.
3. So KN − JL is the odd pair.

Trick: In the three alike pairs both clusters have the same internal gap (+3): PS/OR, FI/EH, LO/KN; JL has gap +2.

Answer: (C) KN - JL

Concept: Take A as origin $(0,0)$, East = $+x$, North = $+y$, and track each move.

1. E 29 → $(29,0)$; right → S 16 → $(29,-16)$; right → W 39 → $(-10,-16)$.
2. Right → N 9 → $(-10,-7)$; right → E 6 → $(-4,-7)$; left → N 3 → $(-4,-4)$.
3. Right → E 4 → P $=(0,-4)$.
4. P is 4 km directly south of A, so he must drive 4 km towards North.

Trick: Net E–W: $29-39+6+4=0$; net N–S: $-16+9+3=-4$ → P is 4 km south of A.

Answer: (C) 4 km to the North

Concept: Look for the pattern Odd – Odd – Even and count the middle odd numbers.

1. … 3 1 6 … → ✓
2. … 7 7 4 … (the third 7 of “7 7 7”) → ✓
3. … 3 9 2 … near the end → ✓
4. No other odd number has an odd number before and an even number after it → total 3.

Trick: First mark every even number; then check only the number just before it (must be odd) and the one before that (must be odd).

Answer: (D) 3

Concept: Find the shift applied to each letter position.

1. DIOR → AEJL: D$-3$=A, I$-4$=E, O$-5$=J, R$-6$=L.
2. RSUT → OOPN: R$-3$=O, S$-4$=O, U$-5$=P, T$-6$=N ✓.
3. IGFB: I$-3$=F, G$-4$=C, F$-5$=A, B$-6$=V (B → A → Z → Y → X → W → V).

Trick: Shifts −3, −4, −5, −6 – an increasing backward step; wrap around after A.

Answer: (A) FCAV

Concept: For people facing the centre, “left” is clockwise and “right” is anticlockwise. Seven seats → “four between” means the two are 2 seats apart the other way.

1. Four between B and D from B’s right → D is 2nd to the left of B: B, _, D.
2. Four between A and Z from A’s left → Z is 2nd to the right of A.
3. O–J–T block fills three seats. If Z sits beside B and D, it violates the condition, so: B, A, D, O, J, T, Z (going left/clockwise), with Z next to T (not O).
4. From D’s left: O, J, T, then Z → 3 people.

Trick: In a 7-seat circle, “4 between” one way = “1 between” the other way – draw the short side first.

Answer: (B) Three

Concept: Each term has the form X Y X where Y is two letters before X.

1. First (and third) letters: L, M, N, O → P.
2. Middle letters: J, K, L, M → N.
3. Next term: P N P.

Trick: Terms are palindromes (first = last letter); among the options only PNP is of this form with N in the middle.

Answer: (C) PNP

Concept: Two “Some” statements sharing only the middle term (Petals) give no definite link between Doors and Flowers.

1. Draw Doors and Flowers each overlapping Petals but not each other – both statements still hold.
2. In this drawing no flower is a door → Conclusion I need not be true.
3. Some petals lie outside Flowers → “All petals are flowers” need not be true → II does not follow.

Trick: Some + Some → no conclusion between the end terms.

Answer: (C) Neither conclusion (I) nor (II) follows