RRB NTPC Undergraduate CBT 1 2025 PYQs

Concept: Substitute the operators and solve both sides with BODMAS, then isolate the unknown.

1. $9\text{A}3\text{C}15\text{B}2=9÷3+15\times 2=3+30=33$.
2. Right side: $?\text{D}10=?-10$.
3. $?-10=33\Rightarrow ?=43$.

Trick: When the unknown is on the right, compute the left fully, then undo the operation ($-10$ → add 10).

Answer: (B) 43

Concept: Mark every even digit and check whether both its immediate neighbours are also even.

1. Series: 5 3 8 6 6 3 5 7 9 7 3 4 8 3 9 2 5 5 1 5 6 1 2.
2. Only triple of consecutive even digits is 8 6 6 → the middle 6 (4th digit) qualifies.
3. 4 8 is followed by 3; 2 is preceded by 9; the last 2 has no right neighbour. Total = 1.

Trick: Look for a run of three even digits in a row – the middle one(s) count.

Answer: (B) One

Concept: Each triad uses only three letters: the pairs are formed by rotating them, with the new letter 8 places before the first letter.

1. JS–BJ–SB: letters J, S and B, where B = J$-8$. Pairs: (J,S), (B,J), (S,B).
2. LU–DL–UD: D = L$-8$; pairs (L,U), (D,L), (U,D) – same rotation.
3. NW: F = N$-8$ → pairs (N,W), (F,N), (W,F) → NW–FN–WF.

Trick: Third pair = 2nd letter of 1st pair + 1st letter of 2nd pair. Only option A has WF.

Answer: (A) NW-FN-WF

Concept: A word common to two sentences has a code common to both coded sentences.

1. "hall menu peak" → yy ae wp; "peak boat owner" → mr yy sf.
2. Common word = peak; common code = yy.
3. So peak = yy.

Trick: Match the repeated word with the repeated code – no need to decode anything else.

Answer: (B) yy

Concept: Check the differences between consecutive terms; here they are perfect cubes.

1. $234-109=125=5^3$, $109-45=64=4^3$, $45-18=27=3^3$.
2. So $18-?=2^3=8\Rightarrow ?=10$, and $10-9=1=1^3$ ✓.
3. Series: $9,10,18,45,109,234$ with differences $1^3,2^3,3^3,4^3,5^3$.

Trick: Start from the big end: 125 and 64 are instantly recognisable cubes.

Answer: (B) 10

Concept: Decode symbol by symbol, build the tree, then walk from H upward to S.

1. S × D: S is the wife of D. D + R: D is the brother of R.
2. R @ Y: R is the mother of Y. Y ÷ H: Y is the father of H.
3. From H: father Y → Y's mother R → R's brother D → D's wife S. So S is H's father's mother's brother's wife.

Trick: Build the chain in words from the person asked (H) and read it off: father → mother → brother → wife.

Answer: (A) Father’s mother’s brother’s wife

Concept: Treat the letters and the number as separate series.

1. Letters: RU → QT → PS → OR: each letter moves $-1$ → next NQ.
2. Numbers: 29, 37, 45, 53 → $+8$ each → $53+8=61$.
3. Answer: NQ61.

Trick: Letters step back by 1, numbers step up by 8 – check both parts before choosing.

Answer: (A) NQ61

Concept: Find how each letter changes from pair to pair within the triad.

1. PK–QL–RT: first letters P→Q→R ($+1,+1$); second letters K→L ($+1$), L→T ($+8$).
2. RM–SN–TV: R→S→T ($+1,+1$); M→N ($+1$), N→V ($+8$). Pattern confirmed.
3. LG–MH–NP: L→M→N ✓; G→H ($+1$), H→P ($+8$) ✓.

Trick: Options B and D break the $+1$ step in the first letters (K→M); option C has H→O ($+7$).

Answer: (A) LG - MH - NP

Concept: Draw the Venn diagram: "All A are B" puts circle A inside circle B.

1. All fans are motors → Fans inside Motors. All motors are scooters → Motors inside Scooters.
2. Conclusion I: Some scooters are motors – true, since the whole Motors circle lies inside Scooters.
3. Conclusion II: All fans are scooters – true, Fans ⊂ Motors ⊂ Scooters. Both follow.

Trick: Two "All" statements in a chain give "All first are last" and "Some last are middle" for free.

Answer: (A) Both conclusions (I) and (II) follow

Concept: The word appearing in both sentences takes the code appearing in both coded forms.

1. "queen chin steak" → kc eq rq; "steak arch food" → yg kc mz.
2. Common word = steak; common code = kc.
3. So steak = kc.

Trick: Spot the repeated word and the repeated code – done in five seconds.

Answer: (B) kc

Concept: Apply the rule digit by digit: odd digit $+2$, even digit $-2$, then compare the digits of the new number.

1. 7 2 1 3 5 4 6 → $7+2=9$, $2-2=0$, $1+2=3$, $3+2=5$, $5+2=7$, $4-2=2$, $6-2=4$.
2. New number: 9 0 3 5 7 2 4.
3. Highest digit 9, lowest digit 0 → difference $9-0=9$.

Trick: Write the new digits directly under the old ones – the lone even digit 2 becomes 0, which usually becomes the minimum.

Answer: (A) 9

Concept: Sort the digits in ascending order and compare position by position with the original.

1. Original: 9 3 4 2 1 5 6; ascending: 1 2 3 4 5 6 9.
2. Compare pairs (old, new): (9, 1), (3, 2), (4, 3), (2, 4), (1, 5), (5, 6), (6, 9) – no position has the same digit in both.
3. Hence no digit keeps its place.

Trick: Write both numbers one below the other and tick only columns where the digits match.

Answer: (A) None

Concept: Take successive differences; if they grow by a constant, extend the pattern.

1. $57-37=20$, $81-57=24$, $109-81=28$, $141-109=32$, $177-141=36$.
2. Differences increase by 4 each time, so the next difference is $40$.
3. $177+40=217$.

Trick: Differences 20, 24, 28 … (multiples of 4) – a second-level arithmetic progression.

Answer: (C) 217

Concept: Compare corresponding letters of each pair using alphabet positions.

1. ON → QP: $O+2=Q$, $N+2=P$.
2. SR → UT: $S+2=U$, $R+2=T$; LK → NM: $L+2=N$, $K+2=M$.
3. UT → WX: $U+2=W$ but $T+4=X$ – breaks the $(+2,+2)$ pattern.

Trick: In the three alike pairs the second cluster is also two consecutive letters in reverse (QP, UT, NM); WX is forward order – spot it at a glance.

Answer: (B) UT - WX

Concept: Look for the pattern vowel – consonant – vowel in the series (vowels: A, E, I, O, U).

1. Series: O K I Y C R L U K V I E H L Y V O N Q O S Z.
2. Vowel-consonant-vowel triplets: O-K-I ✓; I-Y-C ✗; U-K-V ✗; I-E-H (E is a vowel, H followed by L) ✗; O-N-Q ✗; O-S-Z ✗.
3. Only K (2nd letter) qualifies.

Trick: Underline the vowels first; then check only the single letters sandwiched between two underlined ones.

Answer: (D) 1

Concept: Arrange digits in ascending order, then pick the required positions.

1. Digits of 3164857: 3, 1, 6, 4, 8, 5, 7 → ascending: 1 3 4 5 6 7 8.
2. Third from left = 4; third from right = 6.
3. Sum $=4+6=10$.

Trick: In a 7-digit sorted number, 3rd from left and 3rd from right are symmetric about the middle digit (5) – here $4+6=2\times 5=10$.

Answer: (C) 10

Concept: Number the seats 1–7 from left to right (all face north, so left/right are the same as ours) and fix the definite positions first.

1. Only one person left of R → R at seat 2. G fourth from right → seat 4. Two between R and E → E at seat 5.
2. D is immediately left of N, so D–N must occupy consecutive free seats: only 6–7 fit → D at 6, N at 7.
3. H and C take seats 1 and 3; H is not to the left of C → C at 1, H at 3.
4. Between C (1) and D (6): R, H, G, E = four people.

Trick: Place the "from the end" and "only one" clues first; the adjacent pair (D–N) then has a single slot.

Answer: (B) Four

Concept: Build the family tree generation by generation, then trace the path from Kunal up to Chetna.

1. Bablu (husband) – Chetna (wife); Anita and Ekam are their children.
2. Manu is Anita's son; Kunal is Manu's brother → Kunal is also Anita's son.
3. Kunal → mother Anita → her mother Chetna. So Chetna is Kunal's mother's mother (maternal grandmother).

Trick: Always start from the person asked about (Kunal) and climb upward; "mother's mother" = nani.

Answer: (A) Mother's mother

Concept: Number positions 1 (bottom) to 7 (top) and use the "only" clues to pin the ends.

1. Only G is above A → G at 7, A at 6.
2. Two boxes between A and C → C at 3. Only D is below E → D at 1, E at 2.
3. Positions 4 and 5 remain for B and F; F is not immediately above C (position 4) → F at 5, B at 4.
4. Between E (2) and F (5): C and B = 2 boxes.

Trick: "Only X is above/below Y" fixes two boxes at an end at once – start there.

Answer: (B) 2

Concept: Track each letter position separately and the number separately.

1. 1st letters H → M → R → W: $+5$ each; next $W+5=B$ (wrap after Z).
2. 2nd letters E → C → A → Y: $-2$ each; next $Y-2=W$. 3rd letters P → N → L → J: $-2$; next $J-2=H$.
3. Numbers 27, 41, 55, 69: $+14$; next $69+14=83$.

Trick: Check the number first – only options A and C end in 83; then the first letter ($W+5=B$) settles it.

Answer: (C) BWH 83