RRB Technician Grade I (Signal) 2024, 2025 PYQs

Concept: Row 1 faces north (its right = east); Row 2 faces south (its left = east). Test each statement separately.

1. Statement I: R is to the immediate left of Q → R is east of Q, so Q is west or middle. Q faces A, and B is to A's immediate left (west). If Q were at the west end, A would be at the west end and B could not be west of it. Hence Q and A are in the middle, R and C at the east ends, B and P at the west ends.
2. Right extreme of Row 1 (east) = C. Statement I alone is sufficient.
3. Statement II: one person between B and C → B and C occupy the two ends, A in the middle; B faces a neighbour of Q – true for either end. B or C can be at the east end → not sufficient.

Trick: For south-facing people, "left" is east. Fix one certain position first, then try to place the others.

Answer: (B) Data in Statement I alone is sufficient to answer the question while data in statement II is not.

Concept: Use the strongest clues first ("only three between", parity conditions), then fit the rest.

1. Three people between A and B → (A, B) on floors (1, 5) or (2, 6). A is even → A = 2, B = 6 (B ≠ 2 rules out A = 6, B = 2).
2. F even and F immediately above E: F = 4 (6 is taken by B) → E = 3.
3. Two people between F and D → D = 1. The remaining floor 5 → C.
4. Final: 6-B, 5-C, 4-F, 3-E, 2-A, 1-D. Floor 3 = E.

Trick: "Exactly $n$ between" means a gap of $n+1$ floors – list the only possible pairs and apply the even/odd condition.

Answer: (A) E

Concept: Find a single operation (on the whole number) linking the first number to the second and apply it to both pairs.

1. Rule: second $=2\times$ first $+3$.
2. Option A: $23\times 2+3=49$ ✓ and $17\times 2+3=37=Y$ ✓.
3. Other options: B $25\times 2-1=49$ but $17\times 2-1=33\ne 39$; C $21\times 2+7=49$ but $17\times 2+7=41$; D fails similarly.

Trick: Compute $17\to Y$ for the common rules ($\times 2\pm k$) and match with the options.

Answer: (A) X = 23, Y = 37

Concept: Plot the path on a grid with Y at the origin; the final position relative to Y gives the shortest return distance and direction.

1. Y(0, 0) → 11 km N → (0, 11) → right (E) 25 km → (25, 11) → right (S) 27 km → (25, −16).
2. Right (W) 11 km → (14, −16) → right (N) 41 km → (14, 25) → left (W) 14 km → Z(0, 25).
3. Z is directly 25 km north of Y, so he must drive 25 km towards South.

Trick: Net E–W: $+25-11-14=0$; net N–S: $+11-27+41=+25$ (north). Return = 25 km south.

Answer: (D) 25 km towards South

Concept: Build the family tree step by step from the given relations and then read off the required relation.

1. K is the husband of S, and S is the mother of B → K is the father of B.
2. B is the sister of T → T is also a child of S and K.
3. T is the brother of E → T is male.
4. So T is the male child of K, i.e. T is the son of K. (E and Q are not needed for the answer.)

Trick: First find the gender of the person asked about (brother → male), then find the parent link; "male child of a man" = son.

Answer: (C) Son

Concept: Replace the signs as instructed, then apply BODMAS (division and multiplication before addition and subtraction, left to right).

1. Interchange $+\leftrightarrow -$ and $\times \leftrightarrow ÷$: $15÷5\times 7+8-9$.
2. $15÷5=3$; $3\times 7=21$.
3. $21+8-9=20$.

Trick: Rewrite the whole expression with new signs first, then solve – never mix the two steps.

Answer: (B) 20

Concept: The same operation must convert X into 40 and 60 into Y. Test each option with the whole number.

1. Option C: $32\times \frac{5}{4}=40$ and $60\times \frac{5}{4}=75$ → same operation (multiply by $1.25$) ✓.
2. Option A: $32+8=40$ but $60+10=70$ – different additions.
3. Option B: $36+4=40$, $60+8=68$ – no common rule; Option D: $30+10=40$, $60+15=75$ – different additions/ratios ($\frac{4}{3}$ vs $\frac{5}{4}$).

Trick: Check ratios first: $\frac{40}{32}=\frac{75}{60}=\frac{5}{4}$.

Answer: (C) X=32, Y=75

Concept: Find one rule that maps X → 35 and 8 → Y; test the options with whole numbers.

1. Option B: $7\times 5=35$ and $8\times 6=48$, i.e. $n\times (n-2)$ or $n^2-2n$: $49-14=35$, $64-16=48$ ✓.
2. Option A: $10\to 35$ ($+25$ or $\times 3.5$) but $8\to 20$ ($+12$ or $\times 2.5$) – no common rule.
3. Options C and D: $3\to 35$ and $6\to 35$ have no natural rule that also gives $8\to 74$ or $8\to 68$.

Trick: $n(n-2)$ pairs: $7\to 35$, $8\to 48$, $9\to 63$ – a common pattern in these questions.

Answer: (B) X = 7, Y = 48

Concept: Look at the differences between consecutive terms.

1. $1024-1023=1$, $1027-1024=3$, $1032-1027=5$, $1039-1032=7$.
2. Differences are consecutive odd numbers $1,3,5,7,\dots$; the next difference is $9$.
3. $1039+9=1048$.

Trick: Differences $1,3,5,7,9$ – term $n$ equals $1023+(n-1{)}^2$; for $n=6$: $1023+25=1048$.

Answer: (B) 1048

Concept: Draw the Venn diagram of the statements and accept a conclusion only if it is true in every possible diagram.

1. "All parks are grounds" – parks circle lies inside grounds. "Some grounds are museums" – museums overlaps grounds. "No museum is a theatre" – museums and theatre are separate.
2. Conclusion I "All museums are parks": museums only partly overlap grounds and need not touch parks at all → does not follow.
3. Conclusion II "No ground is a theatre": only museums are separated from theatre; the part of grounds that is not museum can still overlap theatre → does not follow.

Trick: "Some A are B" + "No B is C" gives only "Some A are not C" – never "No A is C".

Answer: (B) Neither conclusion I nor II follows.

Concept: Test each statement alone, then together; the question is "answerable" only when the arrangement fixes the required person uniquely.

1. Statement I alone: V at an end with Y, X next → V Y X _ _ (or mirror). Positions of Z and W are not fixed → not sufficient.
2. Statement II alone: W at an end and Z immediately left of W → W at the right end, Z at 4th place. The 3rd place could be V, X or Y → not sufficient.
3. Together: Places 4, 5 = Z, W, so V Y X occupy 1–3: V Y X Z W. Immediate left of Z is X → answer found.

Trick: "Immediate left" of someone facing north = the position with the smaller number from the left end.

Answer: (C) Data in statements I and II together are sufficient to answer the question.

Concept: An argument strengthens a statement if it gives a sound reason that supports the action recommended in it.

1. Statement: the government urges citizens to invest in rainwater harvesting (with subsidies).
2. Argument I: ground water is depleting → harvested rainwater recharges ground water and reduces dependence on it → strong reason to harvest → strengthens.
3. Argument II: heavy monsoon rain causes flooding → plenty of rainwater is available to collect, and capturing it reduces run-off and flooding → also supports harvesting → strengthens.

Trick: Ask "does this fact make the recommended action more sensible?" Both facts (scarcity below, abundance above) say yes.

Answer: (B) Both I and II strengthen the statement.

Concept: Locate every number in the series and check its left neighbour (must be a symbol) and right neighbour (must be a letter).

1. Series: + 2 $ Q = Y L A S S X L / % 9 T \ = X H 6 ?
2. 2: left "+", right "$" (symbol) → fails the "followed by a letter" condition.
3. 9: left "%" (symbol), right "T" (letter) → ✓.
4. 6: left "H" (letter) → fails. So only one such number.

Trick: Mark the numbers first (here 2, 9, 6), then check neighbours – it takes seconds.

Answer: (B) One

Concept: Start from the fixed clue, place the people with "immediately before/after" clues, then use the counting clues.

1. E = Friday; J immediately after E → J = Saturday.
2. Exactly one person between E and D → D = Wednesday or Sunday. H is immediately after D, so D cannot be Sunday → D = Wednesday, H = Thursday.
3. F immediately before D → F = Tuesday.
4. Two people between H (Thu) and G → G = Monday or Sunday. I is not on Monday → I = Sunday, G = Monday.
5. Order: G(Mon) F(Tue) D(Wed) H(Thu) E(Fri) J(Sat) I(Sun). Between J (Sat) and F (Tue): Wed, Thu, Fri → three people.

Trick: Draw the 7 boxes Mon–Sun and fill the definite clue (E = Fri) first; chains like F-D-H then drop in place.

Answer: (C) Three

Concept: Treat each part of the term separately – first letter, second letter and number.

1. First letters: L, M, N, O → next P (+1 each).
2. Second letters: Q, R, S, T → next U (+1 each).
3. Numbers: 13, 20, 27, 34 → $34+7=41$.
4. Next term = PU41.

Trick: Options PV41/PV42 break the +1 letter pattern (T→U, not V) – eliminate them at once.

Answer: (D) PU41

Concept: A conclusion follows only if it is a definite, logical consequence of the statement. (Statement: a father tells his children, 'Today is a bright sunny day, so let us have breakfast on the beach and then visit the museum you all wanted to see.' Conclusions: (i) all family outings should be planned only on bright sunny days; (ii) science museums are very useful for children's education and also fun.)

1. Conclusion (i) generalises one outing to all outings and adds 'only' – not implied.
2. Conclusion (ii) talks about science museums being educational and fun; the statement says nothing about education or the type of museum.
3. Hence neither conclusion follows.

Trick: Words like 'all', 'only', 'always' in a conclusion are usually a sign that it does NOT follow.

Answer: (A) Neither conclusion (I) nor (II) follows

Concept: Compare the position shift of each letter in the pair.

1. SL-RX: S→R $(-1)$, L→X $(+12)$.
2. RK-QW: R→Q $(-1)$, K→W $(+12)$.
3. LE-KQ: L→K $(-1)$, E→Q $(+12)$.
4. OH-MT: O→M $(-2)$, H→T $(+12)$ – the first shift is $-2$ instead of $-1$, so it is the odd one.

Trick: Check the first letters only: S→R, R→Q, L→K are all previous letters; O→M skips one.

Answer: (A) OH-MT

Concept: Find how the positions 1-2-3-4 of the first word are rearranged in the second and third words.

1. LIVE → IVLE: positions 2,3,1,4 (first letter moves to third place). REST → ESRT: same, 2,3,1,4.
2. LIVE → EVIL and REST → TSER: the third word is the first word reversed (4,3,2,1).
3. MUTE → UTME (2,3,1,4 ✓) → ETUM (MUTE reversed ✓). Others fail: WIND→INWD ✓ but INDW is not DNIW; WEST→WSET ✗; YORK→OYRK ✗.

Trick: Check the third word first – it must be the exact reverse of the first; only C satisfies it.

Answer: (C) MUTE - UTME - ETUM

Concept: Check the differences between consecutive terms; here they form an even-number pattern.

1. $903-901=2$, $913-?$, $921-913=8$, $931-921=10$.
2. Differences should be $2,4,6,8,10$, so $?=903+4=907$ (check: $913-907=6$ ✓).

Trick: Known differences 2 … 8, 10 → the missing ones are 4 and 6.

Answer: (C) 907

Concept: The same operation must take $X\to 16.2$ and $23\to Y$. Test each option.

1. Option B: $17-0.8=16.2$ and $23-0.8=22.2$ ✓ (same rule: subtract $0.8$).
2. Option A: $19\to 16.2$ is $-2.8$ but $23\to 22.2$ is $-0.8$ ✗. Option D: $17\to 16.2$ is $-0.8$ but $23\to 21.2$ is $-1.8$ ✗. Option C fails both ways.

Trick: In X : Y analogies, plug the options and keep the one where both pairs share one rule.

Answer: (B) X=17, Y=22.2