RRB Technician Grade I (Signal) 2024, 2025 PYQs

Concept: Compare letter positions (A=1 … Z=26); find the shift applied to each letter and apply it to the new word.

1. UDVA → CLDI: U(21)+8=29→C(3), D(4)+8=L(12), V(22)+8=D(4), A(1)+8=I(9). Each letter moves +8.
2. Check AJBG → IRJO: A+8=I, J+8=R, B+8=J, G+8=O ✓.
3. YHZE: Y(25)+8=33→G(7), H(8)+8=P(16), Z(26)+8=34→H(8), E(5)+8=M(13) → GPHM.

Trick: +8 past Z wraps around (subtract 26).

Answer: (A) GPHM

Concept: Build the family tree generation by generation, then read the path from J to D.

1. A (♂) and F (♀) are a couple; S is their daughter. M is S's husband.
2. J is the son of S and M (J has a wife H, so J is male).
3. D is the brother of H, and H is J's wife → D is J's wife's brother (brother-in-law).

Trick: Follow the chain J → wife (H) → her brother (D).

Answer: (A) Wife's brother

Concept: A conclusion "follows" only if it is directly implied by the statement; it must not bring in new information.

1. The statement says book-reading keeps learning alive even after formal education. Conclusion II (students gain knowledge and improve language by reading) is a direct implication → follows.
2. Conclusion I talks about e-books vs hardcovers – nothing in the statement compares formats → does not follow.

Trick: Any conclusion that introduces a new topic (e-books, popularity) is out.

Answer: (C) Only conclusion II follows

Concept: Decode the chain symbol by symbol and draw the tree; N and P are the two people to connect.

1. M # N → M is the sister of N; N + O → N is the mother of O.
2. O % P → O is the father of P; P @ Q → P is the husband of Q; Q # T → Q is the sister of T.
3. N is the mother of O, and O is P's father → N is P's father's mother (grandmother).

Trick: Only the middle part "N + O % P" matters; the ends (M, Q, T) are distractions.

Answer: (D) Father's mother

Concept: Five people face the centre, so "immediate right" means the anticlockwise neighbour. Test each statement alone.

1. Statement I: E is to D's immediate right and one person sits between D and C. A and B can still swap places, so A's right neighbour is not fixed → not sufficient.
2. Statement II: B is to D's immediate left; one person between B and E; one between E and C. Going clockwise this forces D, B, C, A, E (the alternative places E where B and D already sit).
3. Then A's immediate right is C – a unique answer from II alone.

Trick: In data sufficiency, stop as soon as one statement fixes the arrangement uniquely; here II does, I does not.

Answer: (D) Data in Statement II alone is sufficient to answer the question while data in statement I is not.

Concept: Write the alphabet positions and check the gaps between consecutive letters.

1. XBIO: X(24)→B(2)→I(9)→O(15): $+4,+7,+6$ (cyclic after Z)
2. KOVB: 11→15→22→2: $+4,+7,+6$
3. AELR: 1→5→12→18: $+4,+7,+6$
4. EIRV: 5→9→18→22: $+4,+9,+4$ — different pattern

Trick: Use the EJOTY anchors (E=5, J=10, O=15, T=20, Y=25) to find positions fast; count past Z as wrapping to A.

Answer: (A) EIRV

Concept: Find one rule relating the three numbers $(a,b,c)$ of each given set and apply it to the options.

1. $(5,9,52)$: $5\times (9+1)+2=50+2=52$
2. $(11,7,90)$: $11\times (7+1)+2=88+2=90$ → rule: $c=a\times (b+1)+2$
3. $(9,6,65)$: $9\times 7+2=65$ ✓; A: $7\times 14+2=100$, B: $14\times 5+2=72$, C: $8\times 12+2=98$ ✗

Trick: When $c$ is close to $a\times b$, check $a\times b\pm$ something or $a\times (b\pm 1)\pm$ something.

Answer: (D) (9, 6, 65)

Concept: Replace the letters by the given operators and apply BODMAS.

1. $18A6B11C8D6=18÷6\times 11+8-6$
2. $18÷6=3;3\times 11=33$
3. $33+8-6=35$

Trick: Do ÷ and × left to right first, then + and −.

Answer: (A) 35

Concept: Treat the letters and the numbers as separate series.

1. First letters: P, Q, R, S → T; second letters: U, V, W, X → Y.
2. Numbers: 16, 18, 22, 28: differences $+2,+4,+6$ → next $+8$: $28+8=36$.
3. Next term: TY36.

Trick: Check the letter part first — it eliminates two options (TZ) instantly.

Answer: (C) TY36

Concept: Scan each symbol and check its immediate left (must be a letter) and immediate right (must be a number).

1. Symbols with neighbours: 8 # 7 (number–number), 7 \ 2 (number–number), L % 9 (letter–number ✓), 3 \ / , \ / +, / + H, 2 $ S (number–letter), P # H (letter–letter).
2. Only L % 9 satisfies the condition.

Trick: Mark the symbols first, then look only at the two neighbours of each — do not re-read the whole series.

Answer: (A) One

Concept: Fix the most restricted person first (P: floor 2 or 6), then test each case against the remaining clues.

1. Case P = 2 → S = 5 (two between). R–T must be consecutive from {1,3,4,6} → (3,4). Then Q and U take {1,6}; Q ≠ 1 so U = 1, but U must be even. ✗
2. Case P = 6 → S = 3. R–T consecutive from {1,2,4,5}: (4,5) forces Q = 1 ✗; so R = 1, T = 2, U = 4, Q = 5. ✓
3. Floors: 1-R, 2-T, 3-S, 4-U, 5-Q, 6-P. Between Q (5) and S (3): only U → one person.

Trick: 'Only two people between X and Y' in 6 floors means they are at (1,4), (2,5) or (3,6).

Answer: (B) One

Concept: A strong argument is directly related to the statement, realistic, and gives a solid reason for or against it.

1. Argument I: rising night-time thefts/robberies is a direct public-safety reason to close markets early → strengthens (supports) the plan.
2. Argument II: many people can shop only after office hours → closing at 7 pm would hurt them → weakens (opposes) the plan.
3. Both are relevant; one supports, the other opposes.

Trick: Ask of each argument: 'Does this give a reason to do it, or a reason not to?'

Answer: (D) II weakens while I strengthens the statement.