SSC CGL 2025 PYQs

Concept: Find one rule that fits both examples.

1. 3 & 3 = $27=3^2\times 3$; 4 & 4 = $48=4^2\times 3$.
2. 5 & 5 = $5^2\times 3=25\times 3=75$.

Trick: a & a = $3a^2$ → the answer must be a multiple of 3 and 25 – only 75.

Answer: (D) 75

Concept: Each term = previous × 2 − 1.

1. 3→5→9→17→33→65 (each = 2×previous − 1).
2. Next = $65\times 2-1=129$.

Trick: Terms are $2^n+1$: 2+1, 4+1, 8+1 … 64+1 → next $128+1=129$.

Answer: (B) 129

Concept: If CP of x items = SP of y items, profit% = $\frac{x-y}{y}\times 100$.

1. Let CP of 1 article = ₹1 → CP of 25 = ₹25 = SP of 20.
2. SP of 1 = $\frac{25}{20}=$ ₹1.25 → profit ₹0.25 per article.
3. Profit% = $\frac{0.25}{1}\times 100=25\%$.

Trick: $\frac{25-20}{20}\times 100=\frac{5}{20}\times 100=25\%$ – divide by the SP count (smaller number).

Answer: (A) 25%

Concept: Find the shift for each position and repeat it on the new word.

1. H→I +1, B→C +1, S→T +1, F→H +2, O→Y +10, O→P +1.
2. Apply the same shifts to ICTHYP: J, D, U, J …
3. 5th letter: Y + 10 = 35 − 26 = 9th letter = I; 6th: Q → JDUJIQ.

Trick: Check just the 4th and 6th letters: H+2 = J and P+1 = Q – only (A) has J at 4th and Q at 6th.

Answer: (A) JDUJIQ

Concept: Write the order from the statements and test each option.

1. Rajesh > Anil > Suresh (70).
2. Anil must be above 70 and Rajesh above Anil.
3. (B) 75 and 80 → 80 > 75 > 70 ✓; others break the order.

Trick: Reject any option where Anil ≤ 70 (A, C) or Rajesh is below Anil (D).

Answer: (B) Anil's marks are 75, Rajesh's marks are 80.

Concept: Compare every part (prefix, spelling, PIN) of each option with the sample.

1. Option B has lost the word “No.” before 38.
2. Option C spells the building as “Residncy” (missing e).
3. Option D shows PIN 600084, the sample has 700084.
4. Option A agrees in every part.

Trick: Check the numbers (house no., PIN) first, then the long words – most changes hide there.

Answer: (A) No. 38, Orchid Residency, Lajpat Nagar, New Delhi, Delhi - 700084

Concept: Two terms can be compared only when the signs between them point the same way.

1. Conclusion I: B ≤ T = E ≥ O → signs ≤ and ≥ face opposite ways, so no relation. I is false.
2. Conclusion II: D < B ≤ T = E and G ≥ E, i.e. E ≤ G.
3. So D < B ≤ E ≤ G → D < G. II is true.

Trick: If one strict sign (<) appears in a same-direction chain, the result is strict.

Answer: (D) Only II

Concept: A conclusion holds only if the path between the two terms has signs in one direction.

1. II: P = Q ≥ R → P ≥ R, i.e. R ≤ P. True.
2. I: Q ≥ R ≤ S > T < U – the direction flips at R and at T.
3. No fixed relation between Q and U, so I is false.

Trick: Look for a “valley” (≥ … ≤) or “peak” (≤ … ≥) in the path – it breaks the comparison.

Answer: (A) Only conclusion II is true

Concept: Count the generation gap between the two people.

1. D → B (son): one generation down.
2. B → C (daughter): another generation down.
3. D is two generations above C, so D is C’s grandparent (gender of D not given).

Trick: Parent of a parent = grandparent; when gender is unknown choose the neutral word.

Answer: (C) Grandparent

Concept: Decode each symbol and join the relations.

1. “×” between P and Q: Q is P’s child, P being female.
2. “+” between Q and R: Q is a male sibling of R.
3. Siblings share parents, so R is also P’s child → P is R’s mother.

Trick: A sibling of my child is also my child – so the parent passes to every sibling.

Answer: (A) P is the mother of R

Concept: A valid action should solve or reduce the stated problem practically.

1. Problem: rise in waterborne diseases.
2. Action 1 removes the cause (unsafe water) – follows.
3. Action 2 is an immediate safety step for people – follows.
4. Both work together, so both follow.

Trick: Long-term fix + short-term precaution for the same problem → usually both follow.

Answer: (A) Both follow

Concept: Letter position and number should move together.

1. x(24)→5, y(25)→6, z(26)→7: next letter, next number.
2. Number = position − 19 in each: 24−19=5, 25−19=6, 26−19=7.
3. w(23)→8 breaks it (23−19 = 4, not 8).

Trick: Find one fixed difference between letter value and number; the item that misses it is odd.

Answer: (D) w8#

Concept: “Some A are B” + “No B is C” ⇒ “Some A are not C”.

1. I says some cycles are cars, but the statement says no cycle is a car – I is false.
2. Some vehicles are cycles, and those cycles are not cars.
3. So some vehicles are not cars – II follows.

Trick: A conclusion that contradicts a given “No” statement can never follow.

Answer: (B) Only II follows

Concept: Convert letters to positions and study the differences.

1. X=24, U=21, Q=17, L=12.
2. Gaps: −3, −4, −5 → next −6.
3. 12 − 6 = 6 → F.

Trick: Remember EJOTY = 5, 10, 15, 20, 25 to convert letters fast.

Answer: (A) F

Concept: Every letter of the new word must be present in the given word.

1. Letters available: C, O, M, B, A, T, I, N, G.
2. DAY – no D, Y; HOUSE – no H, U, S, E; NOTE – no E.
3. COAT – C, O, A, T all present.

Trick: Check a rare letter in each option first (D, H, E) – eliminates quickly.

Answer: (C) COAT

Concept: Each letter skips one letter (+2).

1. C(3), E(5), G(7), I(9).
2. Next: 9 + 2 = 11 → K.

Trick: Odd positions 3, 5, 7, 9, 11 – the series is just odd-numbered letters.

Answer: (B) K

Concept: Find the shift from the example and apply it to the new word.

1. S→T, L→M, A→B, N→O, O→P: each letter +1.
2. SPEED: S→T, P→Q, E→F, E→F, D→E.
3. Code = TQFFE.

Trick: Both E’s must give the same letter – only TQFFE has a doubled middle letter.

Answer: (A) TQFFE

Concept: Three options are individual items; one is the group name.

1. Hindi, Sanskrit, Marathi – each is a single language.
2. “Classical Languages” is a category (a group of languages), not one language.

Yaad rakhein: Sanskrit is one of India’s notified classical languages; Marathi got the status in 2024.

Answer: (A) Classical Languages

Concept: The alphabet is read backwards two letters at a time.

1. Z Y | X W | V U | T S | R Q – continuous reverse alphabet.
2. Next two letters after Q going back: P, O.
3. Answer pair: PO.

Trick: Write the alphabet backwards and simply cut it into pairs.

Answer: (A) PO

Concept: For 3 consecutive evens, the middle one = sum ÷ 3.

1. Middle number = $60÷3=20$.
2. Numbers: 18, 20, 22.
3. Largest = 22.

Trick: Middle = average; largest = middle + 2.

Answer: (A) 22