SSC CGL 2025 PYQs

Concept: Both letters of each pair move +2.

1. 1st letters: E, G, I → K.
2. 2nd letters: G, I, K → M.
3. Next pair = KM.

Trick: Each pair's 2nd letter becomes the next pair's 1st letter: IK → K_ , and K + 2 = M.

Answer: (D) KM

Concept: Replace the signs as told, then apply BODMAS.

1. Rule: × → +, + → −, − → ×.
2. After conversion (C) reads: $10+2\times 6-4$.
3. Multiply first: 12; then $10+12=22$, $22-4=18$ ✓

Trick: For checking, (A) gives $6-2+3\times 4=16\ne 14$, so move on quickly.

Answer: (C) 10 × 2 − 6 + 4 = 18

Concept: Each term = previous × 2 + 1.

1. 3→7→15→31→63 follows ×2 + 1.
2. $63\times 2+1=127$.

Trick: Terms are $2^n-1$: 3, 7, 15, 31, 63, 127 (one less than 4, 8, 16, 32, 64, 128).

Answer: (C) 127

Concept: Each handshake is a pair of people: total = ${}^n{C}_2=\frac{n(n-1)}{2}$.

1. $n=8$.
2. $\frac{8\times 7}{2}=\frac{56}{2}=28$.

Trick: Handshakes among n people = sum $1+2+\dots +(n-1)=1+2+\dots +7=28$.

Answer: (C) 28

Concept: Each letter is shifted one place forward.

1. TRAIN → USBJO (each +1).
2. Apply again: U→V, S→T, B→C, J→K, O→P.
3. USBJO → VTCKP.

Trick: Coding twice = +2 on the original: T+2 = V, N+2 = P – only (A) ends in KP.

Answer: (A) VTCKP

Concept: Compare every part (flat no., name, sector, city, PIN) character by character.

1. Flat number: (b) shows B-205 instead of B-204 – rejected.
2. Sector: (c) shows Sector-13 instead of 12 – rejected.
3. Spelling: (d) writes 'Residancy' for 'Residency' – rejected.
4. (a) agrees in every part.

Trick: Check numbers first (flat, sector, PIN), then spellings – most fakes differ in one digit or one letter.

Answer: (A) B-204, Lakeview Residency, Sector-12, Gurugram - 122001

Concept: Swap the two signs given in each option and test with BODMAS until LHS = RHS.

1. Try (d) − ↔ ×: $8÷2+6\times 4-3$
2. Division/multiplication first: $8÷2=4$, $6\times 4=24$
3. $4+24-3=25=\text{RHS}$ ✓

Trick: Original value is $8÷2+6-12=-2$, far below 25 – so a swap that creates a big product $(6\times 4)$ is needed; test that option first.

Answer: (D) − and ×

Concept: Rewrite the expression with the real operations, then apply BODMAS.

1. Replace: $36+12÷4-6\times 8$
2. $12÷4=3$; $6\times 8=48$
3. $36+3-48=-9$

Trick: Only one option is negative; since $6\times 8=48$ exceeds $36+3$, the answer must be negative – pick −9 at once.

Answer: (B) −9

Concept: Children of the same parent are siblings; a female child is a daughter.

1. P, Q, R are siblings (P sister, Q brother).
2. R is W's son ⇒ W is the parent of all three.
3. P is female ⇒ P is W's daughter.

Trick: Gender of the person asked about (P = sister ⇒ female) settles it: child + female = daughter.

Answer: (A) Daughter

Concept: Two sons of the same mother are brothers; father's brother = uncle.

1. W is mother of X; Z is also W's son ⇒ X and Z are brothers.
2. X is Y's father.
3. Z = brother of Y's father ⇒ uncle (chacha).

Trick: Draw a 2-generation tree: W on top, X and Z below, Y under X – Z sits beside Y's father.

Answer: (C) Uncle

Concept: A responsible person owns up to a mistake and shows care.

1. Hurting someone by accident still needs an apology.
2. Apologising (and helping) shows responsibility and empathy.
3. Laughing, running away or blaming others are irresponsible responses.

Trick: In such questions pick the option that shows responsibility + empathy; drop anything rude, evasive or blame-shifting.

Answer: (B) Apologize

Concept: Find the common operation in three pairs; the pair that breaks it is odd.

1. 4 $ 6: (4+6)² = 100 ✓
2. 7 $ 5: 12² = 144 ✓; 3 $ 2: 5² = 25 ✓
3. 2 $ 4: 6² = 36 ≠ 42 ✗

Trick: Results 100, 144, 25 are perfect squares; 42 is not a square at all – odd one spotted instantly.

Answer: (A) 2 $ 4 = 42

Concept: 'Some A are B' + 'All B are C' ⇒ 'Some A are C'.

1. Some erasers are sharp + all sharp are pointed ⇒ some erasers are pointed: I follows.
2. Pencils are inside erasers, but the sharp erasers may not be pencils.
3. So 'some pencils are pointed' is only possible, not certain: II fails.

Trick: Some + All = Some (valid). All + Some gives no definite link for the inner set (pencils).

Answer: (A) Only I follows

Concept: A word can be formed only if each of its letters is available (in enough number) in the given word.

1. Letters of INVESTIGATE: I×2, N, V, E×2, S, T×2, G, A.
2. GIVE, GATE, SAVING – all letters available ✓
3. TEAMS needs M – not present ✗

Trick: Scan options for a letter not in the base word at all – here M in TEAMS.

Answer: (B) TEAMS

Concept: First term is a jumble of a meaningful word; second term is that word.

1. MOPUTERC rearranged = COMPUTER.
2. RETNIGAL has R, E, T, N, I, G, A, L.
3. Meaningful arrangement = INTEGRAL.

Trick: Reject options that are not real words (INETRGAL, LERTNIGA, INTEGRLA) – only INTEGRAL is a dictionary word.

Answer: (D) INTEGRAL

Concept: Find the shift from word to code and apply it letter by letter.

1. H→I, K→L, U→V, J→K: each +1.
2. Shift YQTO one step forward: Y→Z, Q→R, T→U, O→P.
3. Code = ZRUP.

Trick: Only the first letter of each option needs checking first: Y+1 = Z removes (d); then Q+1 = R removes (c).

Answer: (A) ZRUP

Concept: Track each letter position separately.

1. 1st letters F, I, L: +3 ⇒ O
2. 2nd letters T, R, P: −2 ⇒ N
3. 3rd letters X, V, T: −2 ⇒ R

Trick: Find only the first letter (O) – options (b) and (d); second letter N picks ONR.

Answer: (B) ONR

Concept: Classify taxes by who levies them: Union or local body.

1. Income Tax and (former) Service Tax – levied by the Union.
2. GST – levied jointly by Centre and States under the GST system, not by local bodies.
3. Property Tax – levied by municipalities/panchayats (local bodies).

Trick: Ask 'who collects it from me?' – property tax bill comes from the Nagar Nigam, the rest from Centre/State.

Answer: (D) Property Tax

Concept: Each letter of a group moves +2 in the next group.

1. DFHJ → FHJL → HJLN: every letter +2.
2. H+2 = J, J+2 = L, L+2 = N, N+2 = P.
3. Next = JLNP.

Trick: Next group simply starts with the 2nd letter of the previous one: HJLN ⇒ JLN_, then add 2 to N = P.

Answer: (B) JLNP

Concept: Rate per machine stays fixed; machines and work rising in the same ratio keeps time unchanged.

1. 10 machines, 10 boxes, 10 min ⇒ 1 machine makes 1 box in 10 min.
2. 100 machines work in parallel, one box each.
3. Time = 10 minutes.

Trick: $\frac{M_1{T}_1}{W_1}=\frac{M_2{T}_2}{W_2}\Rightarrow \frac{10\times 10}{10}=\frac{100\times T}{100}\Rightarrow T=10$.

Answer: (A) 10 minutes