SSC CGL 2025 PYQs

Concept: Test the rule a @ b $=a^2+b^2$.

1. $1^2+2^2=1+4=5$ ✓.
2. $3^2+4^2=9+16=25$ ✓.
3. 4 @ 5 = $4^2+5^2=16+25=41$.

Trick: 5 and 25 are sums of two squares (3-4-5 triangle hint) – think squares when outputs look like this.

Answer: (C) 41

Concept: When only milk is added, the quantity of water stays the same.

1. Milk = $45\times \frac{3}{5}=27$ L; water = $45\times \frac{2}{5}=18$ L.
2. New ratio 4 : 1 with water 18 L → milk needed = $4\times 18=72$ L.
3. Milk to add = $72-27=45$ L.

Trick: Fix the unchanged part: water 2 units = 18 L, so 1 unit = 9 L. New ratio 4 : 1 → make water 1 part: milk must be 8 parts = 72 L; add $72-27=45$ L.

Answer: (C) 45 L

Concept: Replace each symbol with its meaning, then apply BODMAS.

1. ÷ → +, × → −, + → ÷, − → ×.
2. Expression: $10+5-12÷4\times 2$.
3. $12÷4=3$; $3\times 2=6$.
4. $10+5-6=9$.

Trick: Write the converted expression on paper first; most errors come from mixing old and new signs.

Answer: (A) 9

Concept: Break the sentence from the end and move step by step towards the speaker.

1. Woman's husband's sister = her sister-in-law (nanad).
2. That sister-in-law's husband's daughter = the sister-in-law's daughter.
3. The daughter of one's husband's sister is one's niece.

Trick: 'Sister's husband's daughter' = 'sister's daughter' – cancel the husband link to shorten the chain.

Answer: (B) Niece

Concept: Swap each sign as given and simplify using BODMAS.

1. + → ÷, − → ×, × → −, ÷ → +.
2. Expression: $20÷5\times 3-8+4$.
3. $20÷5=4$; $4\times 3=12$.
4. $12-8+4=8$.

Trick: Do ÷ and × left to right before any + or −; then finish the additions/subtractions in order.

Answer: (D) 8

Concept: A, E, I, O, U are vowels; every other first letter is a consonant.

1. Total words in the sentence = 11.
2. Vowel-starting words: is, a, and, is, a = 5.
3. Consonant-starting words = $11-5=6$ (F, l, c, J, t, t).

Trick: Count the short vowel words (is/a/and) and subtract from the total — faster than checking each word.

Answer: (B) 6

Concept: Track each letter position of the clusters as a separate series.

1. Position 1: J→M→P→S, gap +3 ⇒ S+3 = V.
2. Position 2: F→J→N→R, gap +4 ⇒ R+4 = V.
3. Position 3: J→P→V→B, gap +6 (Z wraps to A) ⇒ B+6 = H.
4. Missing term = VVH.

Trick: First two positions already give VV — only options B and C remain; third letter B+6 = H settles it.

Answer: (B) VVH

Concept: Compare the given address part by part — spelling, punctuation and digits.

1. (A): 'Apartment' (no s) and 'Shastree' — wrong.
2. (B): 'Nager' and PIN 302019 — wrong.
3. (C): 'B24' without hyphen and PIN 302105 — wrong.
4. (D) matches every word and number.

Trick: Check the PIN code first — it removes B and C at once.

Answer: (D) B-24, Green Valley Apartments, Shastri Nagar, Jaipur, Rajasthan - 302015

Concept: Each letter position follows its own fixed jump.

1. 1st letter: S stays S.
2. 2nd: C, F, ?, L, O (+3) ⇒ I.
3. 3rd: E, K, ?, W, C (+6) ⇒ Q.
4. 4th: G, P, ?, H, Q (+9, wrapping after Z) ⇒ Y.

Trick: Only option A has I as the second letter — the answer is fixed in 5 seconds.

Answer: (A) SIQY

Concept: A definite relation exists only if all signs on the path point the same way.

1. I: F ≤ H < K ≥ N — the signs flip at K (< then ≥), so F vs N is unknown ⇒ false.
2. II: B = F ≤ H < K ≤ R (R ≥ K read backwards).
3. All signs point one way with a strict '<' ⇒ B < R ⇒ true.

Trick: Opposite-facing signs (< and >) on the route = no conclusion.

Answer: (A) Only II

Concept: Terms are of the form $n^2\times (n+1)$.

1. $12=4\times 3,36=9\times 4,80=16\times 5$.
2. $150=25\times 6,252=36\times 7$.
3. Next: $49\times 8=392$.

Trick: Differences 24, 44, 70, 102 have second differences 20, 26, 32 (+6). Next difference = $102+38=140\Rightarrow 252+140=392$.

Answer: (C) 392

Concept: Find the common rule a # b = c, then spot the option that breaks it.

1. $12÷2=6,24÷4=6,18÷3=6$ — rule is $a÷b$.
2. $30÷5=6$, but the option shows 5.
3. So (A) breaks the rule.

Trick: Three options give the same result 6 — the one with a different result is usually the odd one.

Answer: (A) 30 # 5 = 5

Concept: An assumption is implicit only if the statement takes it for granted; added judgements are not implicit.

1. I: The statement directly assumes AI can improve diagnosis and care — implicit.
2. II: The statement says AI use raises privacy/data-security questions — implicit.
3. III: Nothing says benefits are greater than the risks; the statement only lists both — not implicit.

Trick: Words like 'outweigh', 'better than', 'only' add a comparison the author never made — reject them.

Answer: (A) Only I and II are Implicit

Concept: A conclusion must follow logically from the statement, without outside assumptions.

1. I: Fingerprint login is a security tool, so the bank clearly wants better security — follows.
2. II: A fingerprint system needs no card; 'special ID cards' is unsupported — does not follow.

Trick: Ask 'why would someone do this?' — the obvious purpose follows; extra rules (cards, fees) do not.

Answer: (A) Only Conclusion I follows

Concept: Each letter is changed to its opposite letter (positions add to 27).

1. Check first pair: 2 + 25 = 27 (B↔Y), 4 + 23 = 27 (D↔W), 5 + 22 = 27 (E↔V), 13 + 14 = 27 (M↔N).
2. Apply to ACFL: 27 − 1 = 26 → Z, 27 − 3 = 24 → X.
3. 27 − 6 = 21 → U, 27 − 12 = 15 → O.
4. Result: ZXUO.

Trick: Opposite pairs mnemonic 'FU' (F↔U) and 'LO' (L↔O) give the last two letters instantly.

Answer: (C) ZXUO

Concept: Some + Some gives no definite conclusion.

1. Animals and wild are linked only through omnivores, and both links are 'some'.
2. The wild omnivores may lie outside the animal group, so I is not certain.
3. II ('All wild are animals') is never stated — false.

Trick: I + I = no conclusion. Draw the 'some' circles touching different parts of the middle circle to test.

Answer: (D) Neither I nor II follows

Concept: A new word can use each letter only as many times as it appears in the given word.

1. CONSERVATION letters: C, O×2, N×2, S×1, E, R, V, A, T, I.
2. SESSION needs S three times, but there is only one S ⇒ cannot be formed.
3. CARTON, NATION (N×2, O×1) and RAVEN all fit.

Trick: Look for a repeated letter in the options first — SESSION's triple S fails at a glance.

Answer: (A) SESSION

Concept: nth term of a GP: $T_n=a\times r^{n-1}$.

1. $T_5=2\times r^4=162$.
2. $r^4=162÷2=81$.
3. $81=3^4\Rightarrow r=3$.

Trick: Check options: $2\times 3^4=2\times 81=162$ ✓ — no algebra needed.

Answer: (A) 3.0

Concept: Group the names by their field.

1. Bhagat Singh, Chandrashekhar Azad and Rajguru — revolutionaries of India's freedom struggle (HSRA).
2. Sachin Tendulkar — cricketer, not a freedom fighter.

Yaad rakhein: Bhagat Singh, Rajguru and Sukhdev were hanged on 23 March 1931 (observed as Shaheed Diwas).

Answer: (D) Sachin Tendulkar

Concept: Siblings have the same mother.

1. N is O's sister ⇒ N and O are siblings.
2. M is N's mother ⇒ M is also O's mother.

Trick: Mother of my sibling = my mother (O's gender does not matter here).

Answer: (B) Mother