SSC CGL 2025 PYQs

Concept: Each letter keeps the same digit in every word.

1. Match HOUSE with 52691 letter by letter; the last three letters U, S, E sit under the digits 6, 9, 1.
2. So USE → 691.

Trick: USE is the last three letters of HOUSE, so take the last three digits: 691. CAT is a distractor.

Answer: (B) 691

Concept: The expression is $\sqrt{121}+\sqrt[3]{8}$.

1. $\sqrt{121}=11$ (${11}^2=121$).
2. $\sqrt[3]{8}=2$ ($2^3=8$).
3. $11+2=13$.

Yaad rakhein: Squares up to 30 and cubes up to 15 should be on your fingertips for such questions.

Answer: (B) 13

Concept: a # b $=a^b$.

1. 6 # 2 = $6^2=36$ ✓.
2. 5 # 3 = $5^3=125$ ✓.
3. 4 # 2 = $4^2=16$.

Trick: 36 and 125 are a perfect square and a perfect cube — a strong hint that a power is involved.

Answer: (D) 16

Concept: Find the shift applied at each position and repeat it.

1. CHAIR → DKBJS: C+1, H+3, A+1, I+1, R+1.
2. Pattern: +1, +3, +1, +1, +1.
3. Apply to TABLE letter by letter: T→U, A→D (three steps), B→C, L→M, E→F ⇒ UDCMF.

Trick: Third letter B+1 = C — only option A has C in the 3rd place.

Answer: (A) UDCMF

Concept: Total cost = Σ (quantity × rate).

1. 5 pens × ₹8 = ₹40.
2. 3 notebooks × ₹25 = ₹75.
3. Total = ₹40 + ₹75 = ₹115.

Trick: Notebooks alone cost ₹75; adding ₹40 must end in 5 — only ₹115 fits.

Answer: (B) ₹115

Concept: Decode each symbol, then link the relations step by step.

1. X ÷ Y ⇒ X is Y's father.
2. Y − Z ⇒ Y is Z's sister ⇒ Y and Z are siblings.
3. Siblings share parents, so Y's father X is Z's father too.

Trick: A sibling link never changes the generation — the parent of one sibling is the parent of the other.

Answer: (C) X is Z's father

Concept: Replace symbols as per the code, then apply BODMAS.

1. (A) 10+5−3×2 → $10÷5+3-2=2+3-2=3$ ✓.
2. (B) 15÷3+2×1 → $15\times 3÷2-1=21.5$ ✗.
3. (C) 8×4−2+6 → $8-4+2÷6\approx 4.33$ ✗; (D) 9−3+6÷2 → $9+3÷6\times 2=10$ ✗.

Trick: Write the swap table once (× ↔ −, + → ÷, ÷ → ×) and test options from (A); stop at the first one that balances.

Answer: (A) 10+5−3×2=3

Concept: Convert letters to operators and solve by BODMAS.

1. 35 B 7 C 4 D 3 A 5 → $35÷7+4\times 3-5$.
2. $35÷7=5$; $4\times 3=12$.
3. $5+12-5=12$.

Trick: +5 and −5 cancel out, so the answer is just $4\times 3=12$.

Answer: (A) 12

Concept: After substitution, powers are solved first, then ×, then −.

1. 7 − 2 × 4 + 1 → $7^2-4\times 1$.
2. $7^2=49$; $4\times 1=4$.
3. $49-4=45$.

Trick: Swap only the given symbols — here '−' becomes power, so 7 − 2 is simply $7^2$.

Answer: (A) 45

Concept: Follow the order in the sentence: $(13+27)\times 4$.

1. $13+27=40$.
2. $40\times 4=160$.

Trick: $13+27$ makes a round 40 — multiply mentally: $4\times 4=16$, add a zero.

Answer: (B) 160

Concept: Only letters strictly between positions 1 and 7 are counted; then remove vowels.

1. In EXAMINATION, the 7th letter is the second A.
2. Letters in positions 2 to 6 read X-A-M-I-N.
3. Remove the vowels (A, I): left with X, M, N → 3 consonants.

Trick: 'Between' means exclude both end letters – count only positions 2 to 6.

Answer: (A) 3

Concept: Find the option identical to the given address, character by character.

1. Check the number: (D) has 41/B – rejected.
2. Check 'Silver Oaks Apartment': (A) writes 'Oak', (B) writes 'Apartments' – rejected.
3. (C) matches every word, comma and PIN 400050.

Trick: Scan for small changes first – digit swaps and an extra/missing 's' are the usual traps.

Answer: (C) 14/B, Silver Oaks Apartment, Linking Road, Mumbai, Maharashtra - 400050

Concept: Track each letter position separately; each has its own fixed jump.

1. 1st letters L→P→T→X: +4 each, so X+4 = B (after Z restart at A).
2. 2nd letters G→J→M→P: +3, so P+3 = S.
3. 3rd letters B→D→F→H: +2, so H+2 = J.
4. Next term = BSJ.

Trick: Positional values: X = 24, 24 + 4 = 28 → 28 − 26 = 2 = B.

Answer: (D) BSJ

Concept: A brother of someone's child is also that person's child.

1. Q is R's daughter → R is a parent of Q.
2. P is Q's brother → P is male and has the same parent R.
3. So P is R's son.

Trick: Gender of the answer comes from P himself: 'brother' → male → son.

Answer: (B) Son

Concept: Find P's relation to S first, then go one generation up.

1. R is S's daughter; P is R's brother → P is S's son.
2. S's mother is P's grandmother.
3. A male grandchild = grandson.

Trick: Q is extra information – it does not change the answer.

Answer: (D) Grandson

Concept: Terms sit next to perfect squares, alternately 1 less and 1 more.

1. $3=2^2-1,10=3^2+1,15=4^2-1,26=5^2+1$.
2. $35=6^2-1,50=7^2+1$.
3. Next: $8^2-1=64-1=63$.

Trick: If terms are close to 4, 9, 16, 25…, check $n^2\pm 1$ immediately.

Answer: (A) 63

Concept: Pick the group whose numbers share one special property.

1. 4, 9, 16, 25 = $2^2,3^2,4^2,5^2$ – all perfect squares.
2. Other groups are only equal-gap sequences (gap 2, 3, 4) with no common special type.
3. 1, 3, 5, 7 contains 1, which is not prime – not a prime group either.

Trick: Common difference alone is weak; a named property (squares, primes, cubes) wins.

Answer: (C) 4, 9, 16, 25

Concept: Each term = previous term × 2 + 2.

1. 2 → 6 → 14 → 30 → 62 (check $30\times 2+2=62$).
2. Next = $62\times 2+2=126$.

Trick: Differences 4, 8, 16, 32 double each time → next difference 64; $62+64=126$.

Answer: (A) 126

Concept: An assumption is what the speaker must take for granted for the advice to make sense.

1. Calling for a tax 'immediately' implies present voluntary efforts are not enough → I is implicit.
2. A tax works only if a cost changes how industries behave → II is implicit.
3. If carbon-neutral energy were already cheap and everywhere, no tax would be needed – III is not assumed.

Trick: Extreme words like 'completely' and 'universally' usually make an assumption invalid.

Answer: (A) Only I and II are implicit

Concept: A conclusion must follow directly from the statement, not from guesswork about the past.

1. Airbags are now compulsory for every manufacturer → all new cars will have them: I follows.
2. The rule says nothing about earlier practice; some makers may already have fitted airbags → II does not follow.

Trick: Statements about the future rule rarely prove anything about the past.

Answer: (A) Only Conclusion I follows