SSC CHSL 2025 PYQs

Concept: Compare symbol by symbol – dots, hyphens and spaces count.

1. (A) 'M.G. Road' has extra dots (master: MG Road).
2. (B) 'H.No.21' uses a dot instead of a hyphen.
3. (C) 'Sector B 4' has a space instead of a hyphen.
4. (D) matches exactly.

Trick: Check the punctuation-heavy parts first (H.No-21, B-4, MG) – differences hide there.

Answer: (D) H.No-21, Sector B-4, Green Valley, MG Road, Jaipur - 302015

Concept: Second differences are constant.

1. Differences: 12, 18, 24, 30 (each +6).
2. Next difference = 36.
3. $90+36=126$.

Trick: Divide by 6: 1, 3, 6, 10, 15 → triangular numbers; next $21\times 6=126$.

Answer: (A) 126

Concept: In each row the last number = product of the first three.

1. Row 1: $4\times 6\times 5=120$ ✓
2. Row 2: $3\times 5\times 6=90$ ✓
3. Row 3: $5\times 8\times ?=200\to 40\times ?=200\to ?=5$.

Trick: When the last number is large compared to the others, test multiplication first.

Answer: (C) 5

Concept: Find one rule that links the four numbers in every box.

1. Multiply the two upper numbers and add the lower-right one; the result is the lower-left number.
2. 1st box: $20+9=29$ ✓   2nd box: $35+5=40$ ✓
3. 3rd box: $18+?=25\to ?=7$.

Trick: Verify any rule on two boxes before applying it to the third.

Answer: (A) 7

Concept: Count single regions first, then combinations of 2, 3… regions.

1. Single small triangles: 6.
2. Triangles made of two parts: 3.
3. One large triangle formed by the top edge, the long slant line and the vertical line: 1.
4. Total = 6 + 3 + 1 = 10.

Trick: Label each small region with a number and list combinations – nothing gets double counted.

Answer: (B) 10

Concept: Label the points and count group by group (top part, middle crossing lines, base part, side flaps).

1. Top small section near apex: 3.
2. Whole figure and its two halves split by the central line: 3.
3. Triangles from the two long crossing lines: 10.
4. Lower part (inner line + base): 6; side flaps: 2.
5. Total = 3 + 3 + 10 + 6 + 2 = 24.

Trick: For symmetric figures, count one half carefully, double it, then add triangles that cross the axis.

Answer: (C) 24

Concept: Facing the centre, 'right' = anticlockwise.

1. Anticlockwise: S, _, Q, _, P (Q 2nd right of S, P 2nd right of Q).
2. R can't sit next to P → R between S and Q; T between Q and P.
3. Order (anticlockwise): S, R, Q, T, P → next after P is S.

Trick: With 5 seats, 'second to the right' twice = 4 steps = 1 step left. So P is just left of S, i.e. S is immediately right of P.

Answer: (D) S

Concept: Build the same arrangement; facing the centre, count right = anticlockwise.

1. Q is 2nd right of S, P is 2nd right of Q → S, _, Q, _, P.
2. R not next to P → S, R, Q, T, P (anticlockwise).
3. From R to the right: Q (1), T (2), P (3).

Trick: In 5 seats, 3rd to the right = 2nd to the left: from R going clockwise 2 seats → S, then P.

Answer: (B) P

Concept: Every Right or Left is a 90° turn; only the net turn (Lefts − Rights) matters.

1. North → West needs a net of one Left turn.
2. (B) R, L, R, L, L: 2 Rights, 3 Lefts → net 1 Left → West ✓ (N→E→N→E→N→W).
3. (A), (C) and (D) each have 3 Rights, 2 Lefts → net 1 Right → East.

Trick: Don't trace each turn – just count: net = L − R. Net 1 L = West, net 1 R = East.

Answer: (B) Right, Left, Right, Left, Left

Concept: The square is split by its diagonals into 4 identical triangular parts, each carrying the same design from its edge to the centre.

1. Design in each part (edge → centre): one thick bar, two thin parallel lines, small arcs at the tip.
2. The missing part is the bottom triangle: thick bar along the bottom edge, arcs at the top tip near the centre.
3. Without rotation, only option (C) shows this orientation.

Trick: Read the opposite (top) part and flip it top-to-bottom – that is exactly the missing piece.

Answer: (C) Figure (C)

Concept: Track each element separately: star, big corner dot and small inner dot.

1. Star alternates: slanted (×) → upright (+) → slanted → next upright.
2. Big dot moves 90° clockwise: top-left → top-right → bottom-right → next bottom-left.
3. Small dot moves 45° anticlockwise along the arms → next on the left arm.
4. Only (D) has all three.

Trick: Eliminate with the easiest element first (big dot position), then confirm with the star.

Answer: (D) Figure (D)

Concept: Each figure's bottom-left symbol is the upside-down (water) image of the previous figure's top-right symbol.

1. Fig 1 top-right 'Y' appears inverted at bottom-left of fig 2; same pattern continues.
2. So the answer must show, at bottom-left, the water image of fig 5's top-right symbol (the stem with cross-bars and flag), flipped top-to-bottom.
3. A new symbol sits at the top-right. Option (A) fits.

Trick: Water image = flip top ↔ bottom only; left and right stay the same.

Answer: (A) Figure (A)

Concept: Swap letters for signs, then BODMAS (÷, × left to right, then +, −).

1. 36 A 4 B 2 C 8 D 5 → $36÷4\times 2+8-5$.
2. $36÷4=9$; $9\times 2=18$.
3. $18+8-5=21$.

Trick: ÷ and × have equal priority – go left to right (don't do 4 × 2 first).

Answer: (B) 21

Concept: Swap every 5 with 9 (and 9 with 5), then evaluate both sides.

1. Equation I after swap: 20 ($5\times 4$) plus 9 minus 3 ($6÷2$) gives 26, not 20 ✗
2. Equation II after swap: 27 ($3\times 9$) plus 5 minus 3 ($12÷4$) gives 29, not 34 ✗
3. Both fail → Both I and II are NOT correct.

Trick: Swap carefully in one pass and circle each changed number to avoid missing one.

Answer: (C) Both I and II

Concept: Right number = square of the left number.

1. ${17}^2=289$ ✓, ${16}^2=256$ ✓, ${15}^2=225$ ✓
2. ${14}^2=196$, but the pair shows 197 ✗
3. So 14-197 is the odd one.

Trick: Squares ending check: ${14}^2$ must end in 6 ($4^2=16$) – 197 ends in 7, out instantly.

Answer: (D) 14-197

Concept: Find the backward shift of each letter (A = 1 … Z = 26).

1. GOLD → BIGX: −5, −6, −5, −6 (D − 6 wraps to X).
2. Check FISH → ACNB: same −5, −6, −5, −6 ✓
3. TASK: T−5 = O, A−6 = U (wrap), S−5 = N, K−6 = E → OUNE.

Trick: Backward wrap: A − 6 = 27 − 6 = 21 = U (add 26 when you go below 1).

Answer: (B) OUNE

Concept: A word common to two sentences gets the code common to those two codes.

1. Sentences 1 & 3 share only 'work'; codes share only 'ka' → work = ka.
2. Sentences 2 & 3 share only 'growth'; codes share only 'pa' → growth = pa.
3. So 'work growth' = ka pa.

Trick: Only the third sentence holds both words – the answer must come from its codes (ka, pa, ra, va), so (B) is the only fit.

Answer: (B) ka pa

Concept: A word can be formed only if every letter (with its count) is in the given word.

1. DEMOCRATIC: D, E, M, O, C×2, R, A, T, I.
2. COMRADE, CREDIT, METRIC – all letters available.
3. ACTION needs N – not present.

Trick: Scan options for a letter absent from the main word – N in ACTION stands out.

Answer: (C) ACTION

Concept: Check each option's letters against COMMUNICATION.

1. COMMUNICATION: C×2, O×2, M×2, U, N×2, I×2, A, T.
2. ACTION, UNION (2 N), MOTION (2 O) – possible.
3. MUSIC needs S – not in the word.

Trick: Look for the 'foreign' letter first; S is missing → MUSIC.

Answer: (C) MUSIC

Concept: Treat the first letter, second letter and number as three separate series.

1. 1st letter: M, K, I, G (−2) → E.
2. 2nd letter: Z, V, R, N (−4) → J.
3. Number: +45 each → 335 + 45 = 380 → EJ380.

Trick: Solve the number part first: 380 leaves (C) and (D); first letter E picks (C).

Answer: (C) EJ380