SSC CHSL 2025 PYQs

Concept: Treat 1st, 2nd and 3rd letters as three separate series.

1. 1st: E, G, I (+2) → K
2. 2nd: N, O, P (+1) → Q
3. 3rd: S, R, P (−1, −2) → next −3 → M
4. Answer: KQM

Trick: All options start with KQ, so only the 3rd letter matters – find its gap pattern.

Answer: (B) KQM

Concept: The correct candidate must match every word, full stop, comma and number.

1. A drops the full stop after 'No'.
2. B shortens 'Extension' to 'Extn.'.
3. D matches the master address exactly.

Trick: Compare in chunks (Flat No. / Block / locality / city - PIN) and strike off an option at its first mismatch.

Answer: (D) Flat No. 12B, Block A, Green Park Extension, New Delhi - 110016

Concept: Look for small changes: hyphens, full stops and abbreviations.

1. A: 'Sector 5' – hyphen missing.
2. B: 'Flat No 18A' – full stop missing.
3. D: 'Hosp.' – word shortened.
4. C is an exact copy.

Trick: Typical traps are punctuation (- and .) and short forms – scan those spots first.

Answer: (C) Sector-5, Flat No. 18A, Shanti Nagar, Near City Hospital, Bhopal - 462003

Concept: Every row of the grid follows the same operation; find it from a complete row.

1. Try a rule (sum, product, difference, square etc.) on Row 1.
2. Confirm the same rule on Row 3.
3. Apply it to Row 2 → missing number = 24.

Trick: Always verify the rule on a second complete row before applying it – one row can fit many rules.

Answer: (A) 24

Concept: The same row-rule holds for all rows of the grid.

1. Frame the rule from the first complete row.
2. Check it on the other complete row.
3. Applying it to the row with '?' gives 34.

Trick: If a sum rule fails, try $(a\times b)\pm c$ or $a^2\pm b$ – these are the most common matrix rules in SSC.

Answer: (C) 34

Concept: Ask for each pair: can one person be both?

1. Sister and aunt: a woman can be both, but not always → overlapping circles.
2. Uncle is male → no overlap with sister or aunt → separate circle.
3. Two intersecting circles + one separate circle = option C.

Trick: Gender splits classes fast: male relations (uncle) never overlap female ones (sister, aunt).

Answer: (C) (figure option)

Concept: Add all region numbers inside the required shape(s).

1. Spirit (circle) = 15 + 8 + 12 + 18 = 53 → I true.
2. Tea not water = triangle outside rectangle = 18 + 50 = 68 → II true.
3. Both statements are correct.

Trick: 'X but not Y' = part of X lying outside Y – shade it mentally before adding.

Answer: (C) Both I and II

Concept: One right and one left turn cancel; only the net turns matter.

1. Net = 10 right − 9 left = 1 right turn (90° clockwise).
2. North + 90° clockwise = East.

Trick: Net right turns mod 4: 0 → same, 1 → right, 2 → opposite, 3 → left of start.

Answer: (A) East

Concept: 'Either P or Q' + 'not P' ⟹ Q must be true.

1. P = exam cancelled, Q = exam online.
2. Exam is not cancelled → it will definitely be held online.
3. 'May be online' is too weak; offline was never an option.

Trick: In either/or, removing one choice makes the other certain – look for the word 'definitely'.

Answer: (C) The examination will definitely be conducted online

Concept: The figure is symmetric about its centre lines; the missing quarter completes the half-drawn shapes.

1. The diamond on the right side lacks its lower half; the one on the bottom side lacks its right half.
2. Both missing halves, plus the inner square's bottom-right corner, lie in the '?' quarter.
3. Option D supplies exactly these pieces.

Trick: Extend every line that reaches the edge of the '?' box – the correct piece must continue each of them.

Answer: (D) (figure option)

Concept: Fig 1 → Fig 2 is a top–bottom flip (water image): top ↔ bottom, left/right unchanged, shapes inverted.

1. Circle top → bottom, pentagon bottom → top, triangle turns upside down.
2. Apply to Fig 3: 'p' at top → 'b' at bottom; '=' bottom → top.
3. '+' and the letter on the sides keep their side but the letter appears inverted → option D.

Trick: Water image: p ↔ b, d ↔ q; symmetric symbols (=, +) look unchanged.

Answer: (D) (figure option)

Concept: Track each symbol's position (top/right/bottom/left) and its shading separately.

1. Plus: bottom → right → top → next left (anticlockwise).
2. Circle: top → left → bottom → next right (anticlockwise).
3. Diamond: left → top → right → next bottom (clockwise).
4. Shading alternates circle/diamond → in Fig 4 the diamond is solid. Option D.

Trick: Fix one symbol's movement first; usually it alone removes two options.

Answer: (D) (figure option)

Concept: Follow each element's corner and orientation step by step.

1. Arrow: top-left → top-right → bottom-right → bottom-left (clockwise), turning 90° clockwise each step → points right.
2. Hexagon: top-right → top-left → bottom-left → bottom-right; shading top/bottom alternates → lower half shaded.
3. Star appears only in odd figures → absent in Fig 4. Option B.

Trick: Elements that appear/disappear alternately are a quick filter: no star in the 4th figure.

Answer: (B) (figure option)

Concept: Replace letters with signs, then apply BODMAS.

1. P = +, R = −, Q = ÷, S = × → $30+40-20÷10\times 4$
2. $20÷10=2$, $2\times 4=8$
3. $30+40-8=$ 62

Trick: Do ÷ and × first as one block ($20÷10\times 4=8$), then the rest is easy addition/subtraction.

Answer: (D) 62

Concept: Swap × and ÷ everywhere, then solve by BODMAS.

1. $90\times 10÷12-96+20\to 90÷10\times 12-96+20$
2. $90÷10=9$, $9\times 12=108$
3. $108-96+20=$ 32

Trick: After swapping, ÷ and × of equal priority go strictly left to right.

Answer: (B) 32

Concept: $\text{Path area}=\text{outer rectangle area}-\text{inner field area}$.

1. Outer length = $24+2\times 3=30$ m; outer width = $18+2\times 3=24$ m.
2. Outer area = $30\times 24=720{\text{m}}^2$; field = $24\times 18=432{\text{m}}^2$.
3. Path = $720-432=288{\text{m}}^2$.

Trick: Outside path: Area = $2w(l+b+2w)=2\times 3\times (24+18+6)=6\times 48=288$.

Answer: (C) 288 sq m

Concept: Perimeter of square $=4a$, Area $=a^2$.

1. $4a=24\Rightarrow a=\frac{24}{4}=6$ m.
2. Area = $6^2=36{\text{m}}^2$.

Trick: Area = ${\left(\frac{\text{Perimeter}}{4}\right)}^2={\left(\frac{24}{4}\right)}^2=36$ – one step.

Answer: (B) 36 sq m

Concept: In situational questions, pick the calm, helpful and respectful response.

1. It was an accident – nobody needs to be blamed.
2. Helping collect the files and speaking politely solves the problem and keeps good relations.
3. Blaming, laughing or walking away are rude and unprofessional.

Trick: Choose the option that is both helpful and polite; drop any option showing anger, mockery or indifference.

Answer: (A) Help gather the files and respond politely

Concept: Replace the coded signs with real ones, then solve by BODMAS.

1. Here $ stands for ÷ and ∧ for × (& = −).
2. $12÷3-18\times 6$.
3. $=4-108=-104$.

Trick: Since $18\times 6=108$ is far bigger than $12÷3$, the answer must be negative and end in 4 → only −104.

Answer: (B) -104

Concept: Find the shift from the example word, apply it to the new word.

1. BALL → CBMM: every letter moves one step ahead (+1).
2. CROW: C+1 = D, R+1 = S, O+1 = P, W+1 = X.
3. Code = DSPX.

Trick: Check only one letter that differs among options: R+1 = S removes (B) and (D); O+1 = P removes (C).

Answer: (A) DSPX