SSC CHSL 2025 PYQs

Concept: Position from one end + position from other end = Total + 1.

1. Rank from bottom = 42 − 15 + 1.
2. = 28.

Trick: Top + Bottom = Total + 1 → 15 + 28 = 43 = 42 + 1 ✔. Forgetting '+1' gives the trap 27.

Answer: (C) 28th

Concept: Decode the statement from the end that is closest to the speaker.

1. Only son of Rakhi's grandmother = Rakhi's father.
2. Man's brother's father = the man's own father.
3. Same father → man and Rakhi are siblings; Rakhi is female → sister.

Trick: 'Only son of my grandmother/grandfather' = my father (in such questions). Spot it instantly.

Answer: (B) Sister

Concept: Parents of one set of siblings are husband and wife.

1. P, Q, R are siblings (P brother of Q, Q sister of R).
2. S = mother of P → mother of all; T = father of R → father of all.
3. Mother and father of the same children → S is T's wife.

Trick: Gender of S comes from 'mother' — so the answer must be a female relation; Wife is the only fit.

Answer: (B) Wife

Concept: Replace 'my father's son' with 'me' when the speaker has no brother.

1. No brother → my father's son = Trump himself.
2. So: that man's father = Trump.
3. Hence the man is Trump's son.

Trick: No brother + 'my father's son' = 'I'. Then read the sentence again — answer pops out.

Answer: (A) His Son

Concept: Divide both terms of a ratio by their HCF.

1. Orange : Black = 54 : 36.
2. HCF(54, 36) = 18.
3. $\frac{54}{18}:\frac{36}{18}$ = 3 : 2.

Trick: Keep the asked order (orange first); 2 : 3 is the reversed trap.

Answer: (A) 3 : 2

Concept: $\text{Distance}=\text{Speed}\times \text{Time}$ (time in hours when speed is in km/hr).

1. 15 min $=\frac{15}{60}=\frac{1}{4}$ hr.
2. Distance = $160\times \frac{1}{4}=$ 40 km.

Trick: 15 min is a quarter hour → just divide speed by 4.

Answer: (C) 40 km

Concept: If x% of a number is known, any other % is found by scaling.

1. $10\%=60$ → $100\%=600$.
2. 50% of 600 = 300.

Trick: 50% is 5 times 10% → $60\times 5=300$ in one step.

Answer: (C) 300

Concept: Split the total in the ratio of ages.

1. Shyam : Gita = 2 : 1, total parts = 3.
2. 1 part = $90÷3=30$.
3. Shyam = $2\times 30=$ 60 years.

Trick: Shyam's share = $\frac{2}{3}$ of $90=60$.

Answer: (D) 60 years

Concept: Fast-growing terms usually follow a constant multiplier.

1. $6\times 3=18,18\times 3=54,54\times 3=162$.
2. Next = $162\times 3=$ 486.

Trick: Unit digit check: $2\times 3$ ends in 6 → only 486 ends in 6.

Answer: (A) 486

Concept: $\text{Profit}\%=(\text{Profit}÷\text{CP})\times 100$.

1. Profit = $1600-1200=$ ₹400.
2. $\text{Profit}\%=\frac{400}{1200}\times 100=\frac{1}{3}\times 100=$ 33.33%.

Trick: $\frac{400}{1200}=\frac{1}{3}$ → $33\frac{1}{3}\%$. Fraction-to-% memory saves time.

Answer: (D) 33.33%

Concept: $\text{Sum}=\text{Average}\times \text{Count}$.

1. Total of 5 = $30\times 5=150$.
2. Known three = $22+26+34=82$.
3. Other two = $150-82=68$ → average = $\frac{68}{2}=$ 34.

Trick: Deviation method: 22, 26, 34 differ from 30 by $-8,-4,+4=-8$, so the other two must total +8 → each $30+4=34$.

Answer: (C) 34

Concept: $\text{New value}=\text{Original}\times \frac{100+r}{100}$.

1. 25% increase → multiply by $\frac{5}{4}$.
2. $\text{Original}\times \frac{5}{4}=750$ → $\text{Original}=750\times \frac{4}{5}=$ ₹600.

Trick: $25\%=\frac{1}{4}$ → new = 5 parts = 750 → 1 part = 150 → original (4 parts) = 600.

Answer: (B) ₹600

Concept: Equal moves in opposite directions cancel out.

1. 10 km south and 10 km north cancel.
2. Only 14 km east remains.
3. Shortest distance = 14 km.

Trick: Net N–S and net E–W first; if one is zero, the other is the answer.

Answer: (A) 14 km

Concept: $\text{Distance}=\sqrt{{\text{net E–W}}^2+{\text{net N–S}}^2}$.

1. Net east = $16-8=8$ km; net north = 15 km.
2. Distance = $\sqrt{8^2+{15}^2}=\sqrt{64+225}=\sqrt{289}=$ 17 km.

Trick: 8–15–17 is a Pythagorean triplet — no need to square.

Answer: (B) 17 km

Concept: After cancelling opposite moves, the leftover move gives the direction.

1. 9 km north and 9 km south cancel.
2. Remaining: 6 km west.
3. So he is West of the start.

Trick: Only the un-cancelled leg decides the direction.

Answer: (D) West

Concept: Net displacement = combine moves on each axis.

1. East 10 and West 10 cancel → E–W = 0.
2. North = 17 km.
3. Distance from start = 17 km.

Trick: Same-length opposite legs → answer is simply the middle leg.

Answer: (B) 17 km

Concept: Fill fixed facts first, then use 'does not' clues to settle the rest.

1. Fixed: Ankush–Cricket, Sita–Hockey, Deepak–Football.
2. Left: Badminton, Tennis for Meena and Mohan.
3. Meena does not play Tennis → Meena–Badminton, Mohan–Tennis.

Trick: Direct clues remove 3 of 5 items; one negative clue finishes the last pair.

Answer: (A) Meena

Concept: Place fixed people, then use 'before/after' chains to fix the rest.

1. P = Tuesday. S cannot be Wed, Fri, Sat → S is Mon or Thu.
2. Q before R before S → S needs two days before it → S = Thursday; Q = Monday, R = Wednesday.
3. Fri, Sat left for T and U; T not Friday → T = Saturday, U = Friday.

Trick: Chains like Q→R→S push the last person late — test the latest allowed day first.

Answer: (B) T - Saturday

Concept: Find the common link in most pairs, then spot the pair that breaks it.

1. Sun–Shine, Moon–Glow, Star–Twinkle: second word = how the body gives light.
2. A cloud gives no light, and 'fall' describes rain, not the cloud.
3. Odd pair: Cloud – Fall.

Trick: Turn each pair into a sentence: 'The ___ ___s.' — 'The cloud falls' sounds wrong.

Answer: (D) Cloud - Fall

Concept: Check the gap between letters in each option.

1. A-D-G-J, B-E-H-K, C-F-I-L: each step +3.
2. D-G-I-L: +3, +2, +3 → breaks the rule.

Trick: Use position values (D4 G7 I9 L12) — the uneven jump shows immediately.

Answer: (D) $D-G-I-L$