SSC CPO Paper I · 6,600 questions

SSC CPO Paper I 2020, 2022, 2023, 2024 PYQs

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6,600 questions.

Q3941.

The following bar chart shows the trends of foreign direct investment (FDI) into India from all over the world.

For which year is the per cent increase in FDI over the previous year the highest?

निम्नलिखित दंड चार्ट विश्व भर से भारत में आए प्रत्यक्ष विदेशी निवेश (FDI) की प्रवृत्ति दर्शाता है।

किस वर्ष में पिछले वर्ष की तुलना में FDI में प्रतिशत वृद्धि सबसे अधिक है?

A1997
B1994
C1996
D1993

Show answer

Concept: $% increase = \frac{this year - previous}{previous} \times 100$ .

1993: $\frac{4.45}{5.7} \approx 78 %$ ; 1994: $\frac{2.01}{10.15} \approx 20 %$ .
1995: decrease; 1996: $\frac{14.01}{10.22} \approx 137 %$ .
1997: $\frac{7.13}{24.23} \approx 29 %$ .
Highest: 1996.

Trick: Only 1996 more than doubles over the previous year.

Answer: (C) 1996

अवधारणा: $% वृद्धि = \frac{इस वर्ष - पिछला}{पिछला} \times 100$ ।

1993: $\approx 78 %$ ; 1994: $\approx 20 %$ ।
1995: कमी; 1996: $\frac{14.01}{10.22} \approx 137 %$ ।
1997: $\approx 29 %$ ।
सबसे अधिक: 1996।

ट्रिक: केवल 1996 में मान पिछले वर्ष के दोगुने से अधिक है।

उत्तर: (C) 1996

SSC CPO Paper IQuantitative AptitudeData Interpretation – Bar GraphSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3942.

A hemispherical bowl of internal radius 6 cm contains a liquid. This liquid is to be
filled into cylindrical shaped small bottles of diameter 2 cm and height 4 cm. How
many bottles will be needed to empty the bowl?

6 cm आंतरिक त्रिज्या वाले एक अर्धगोलाकार कटोरे में एक द्रव भरा है। इस द्रव को
2 cm व्यास और 4 cm ऊँचाई वाली छोटी बेलनाकार बोतलों में भरना है। कटोरे को खाली करने के लिए
कितनी बोतलों की आवश्यकता होगी?

Show answer

Concept: Number of bottles $= \frac{volume of bowl}{volume of one bottle}$ .

Bowl: $\frac{2}{3} π (6)^{3} = 144 π$ .
Bottle: $r = 1, h = 4$ ⇒ $π (1)^{2} (4) = 4 π$ .
Bottles $= \frac{144 π}{4 π} = 36$ .

Trick: Use radius, not diameter, for the bottle: $r = 1$ .

Answer: (D) 36

अवधारणा: बोतलों की संख्या $= \frac{कटोरे का आयतन}{एक बोतल का आयतन}$ ।

कटोरा: $\frac{2}{3} π (6)^{3} = 144 π$ ।
बोतल: $r = 1, h = 4$ ⇒ $4 π$ ।
बोतलें $= \frac{144 π}{4 π} = 36$ ।

ट्रिक: बोतल के लिए व्यास नहीं, त्रिज्या $r = 1$ लें।

उत्तर: (D) 36

SSC CPO Paper IQuantitative AptitudeMensuration – Hemisphere and CylinderSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3943.

The given chart shows the marks scored by a class X student in different subjects.

If the total marks are 1800, then find the difference between the marks scored in science and mathematics.

दिया गया चार्ट कक्षा X के एक विद्यार्थी द्वारा विभिन्न विषयों में प्राप्त अंक दर्शाता है।

यदि कुल अंक 1800 हैं, तो विज्ञान और गणित में प्राप्त अंकों के बीच का अंतर ज्ञात कीजिए।

Show answer

Concept: Marks for a subject $= \frac{angle}{360^{\circ}} \times total$ .

Mathematics $-$ Science $= 84^{\circ} - 82^{\circ} = 2^{\circ}$ .
Difference $= \frac{2}{360} \times 1800 = 10$ .

Trick: $1^{\circ} = \frac{1800}{360} = 5$ marks, so $2^{\circ} = 10$ .

Answer: (B) 10

अवधारणा: किसी विषय के अंक $= \frac{कोण}{360^{\circ}} \times कुल$ ।

Mathematics $-$ Science $= 84^{\circ} - 82^{\circ} = 2^{\circ}$ ।
अंतर $= \frac{2}{360} \times 1800 = 10$ ।

ट्रिक: $1^{\circ} = 5$ अंक, अतः $2^{\circ} = 10$ ।

उत्तर: (B) 10

SSC CPO Paper IQuantitative AptitudeData Interpretation – Pie Chart (Degrees)SSC CPO Paper I 2022 · 11 Nov Shift 2

Q3944.

If sin² θ = cos³ θ, then the value of (cot² θ - cot⁶ θ) is:

यदि sin² θ = cos³ θ है, तो (cot² θ - cot⁶ θ) का मान है:

Show answer

Concept: Express $\cot^{2} θ$ using the given relation $\sin^{2} θ = \cos^{3} θ$ .

$\cot^{2} θ = \frac{\cos^{2} θ}{\sin^{2} θ} = \frac{\cos^{2} θ}{\cos^{3} θ} = \frac{1}{\cos θ}$ .
$\cot^{6} θ = \frac{1}{\cos^{3} θ}$ .
$\cot^{2} θ - \cot^{6} θ = \frac{\cos^{2} θ - 1}{\cos^{3} θ} = \frac{- \sin^{2} θ}{\cos^{3} θ} = - 1$ .

Yaad rakhein: Replace $\cos^{3} θ$ by $\sin^{2} θ$ at the end – they cancel to $- 1$ .

Answer: (A) $- 1$

अवधारणा: दिए गए संबंध $\sin^{2} θ = \cos^{3} θ$ से $\cot^{2} θ$ लिखें।

$\cot^{2} θ = \frac{\cos^{2} θ}{\cos^{3} θ} = \frac{1}{\cos θ}$ ।
$\cot^{6} θ = \frac{1}{\cos^{3} θ}$ ।
$\cot^{2} θ - \cot^{6} θ = \frac{\cos^{2} θ - 1}{\cos^{3} θ} = \frac{- \sin^{2} θ}{\cos^{3} θ} = - 1$ ।

याद रखें: अंत में $\cos^{3} θ$ की जगह $\sin^{2} θ$ रखें – $- 1$ मिलता है।

उत्तर: (A) $- 1$

SSC CPO Paper IQuantitative AptitudeTrigonometrySSC CPO Paper I 2022 · 11 Nov Shift 2

Q3945.

Study the given figure and answer the question that follows.

Find the length of AB in the given triangle, if it is given that the length of BD is 4 unit.

दी गई आकृति का अध्ययन कीजिए और नीचे दिए गए प्रश्न का उत्तर दीजिए।

दिए गए त्रिभुज में AB की लंबाई ज्ञात कीजिए, यदि यह दिया गया है कि BD की लंबाई 4 इकाई है।

A3
B3.5
C2.5
D4

Show answer

Concept: $B C ∥ D E$ (both ⟂ AD), so $△ A B C ~ △ A D E$ and $\frac{A B}{A D} = \frac{B C}{D E}$ .

Let $A B = x$ , then $A D = x + 4$ .
$\frac{x}{x + 4} = \frac{3}{6}$ .
$2 x = x + 4 \Rightarrow x = 4$ .

Trick: $B C$ is half of $D E$ , so B is the midpoint of AD: $A B = B D = 4$ .

Answer: (D) 4

अवधारणा: $B C ∥ D E$ (दोनों AD पर लंब), अतः $△ A B C ~ △ A D E$ और $\frac{A B}{A D} = \frac{B C}{D E}$ ।

माना $A B = x$ , तब $A D = x + 4$ ।
$\frac{x}{x + 4} = \frac{3}{6}$ ।
$2 x = x + 4 \Rightarrow x = 4$ ।

ट्रिक: $B C$ , $D E$ का आधा है, अतः B, AD का मध्यबिंदु: $A B = B D = 4$ ।

उत्तर: (D) 4

SSC CPO Paper IQuantitative AptitudeSimilar TrianglesSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3946.

What is the value of

12 - 8 \div 2 - {16 of (- 2) + (3 \times 5 - 4)}

12 - 8 \div 2 - {16 of (- 2) + (3 \times 5 - 4)}

का मान क्या है?

Show answer

Concept: Brackets → "of" → ÷ → × → + → −.

$16 of (- 2) = - 32$ ; $(3 \times 5 - 4) = 11$ ; brace $= - 32 + 11 = - 21$ .
$8 \div 2 = 4$ .
$12 - 4 - (- 21) = 8 + 21 = 29$ .

Yaad rakhein: Minus before a negative bracket becomes plus.

Answer: (A) 29

अवधारणा: कोष्ठक → "of" → ÷ → × → + → −।

$16 of (- 2) = - 32$ ; $(3 \times 5 - 4) = 11$ ; कोष्ठक $= - 21$ ।
$8 \div 2 = 4$ ।
$12 - 4 - (- 21) = 8 + 21 = 29$ ।

याद रखें: ऋणात्मक कोष्ठक से पहले का ऋण चिह्न धन बन जाता है।

उत्तर: (A) 29

SSC CPO Paper IQuantitative AptitudeSimplification – BODMASSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3947.

What is the positive value of the following expression?

\sqrt{36 \div 15 of 2 of [25 \times 4 \div 4 of {29 - (8 - 11) \div (9 \times 5 \div 5 of 3)}]}

निम्नलिखित व्यंजक का धनात्मक मान क्या है?

\sqrt{36 \div 15 of 2 of [25 \times 4 \div 4 of {29 - (8 - 11) \div (9 \times 5 \div 5 of 3)}]}

A $1 \frac{5}{6}$
B $1 \frac{1}{5}$
C $2 \frac{4}{5}$
D $2 \frac{3}{5}$

Show answer

Concept: Solve innermost bracket first; "of" means multiply and is done before ÷.

$9 \times 5 \div 5 of 3 = 45 \div 15 = 3$ ; $(8 - 11) \div 3 = - 1$ ; brace $= 29 + 1 = 30$ .
$25 \times 4 \div 4 of 30 = 100 \div 120 = \frac{5}{6}$ .
$36 \div 15 of 2 of \frac{5}{6} = 36 \div 25 = \frac{36}{25}$ .
$\sqrt{\frac{36}{25}} = \frac{6}{5} = 1 \frac{1}{5}$ .

Yaad rakhein: Chain of "of": $15 \times 2 \times \frac{5}{6} = 25$ is computed as one block.

Answer: (B) $1 \frac{1}{5}$

अवधारणा: सबसे भीतर का कोष्ठक पहले; "of" का अर्थ गुणा है और ÷ से पहले होता है।

$45 \div 15 = 3$ ; $(8 - 11) \div 3 = - 1$ ; कोष्ठक $= 30$ ।
$100 \div 120 = \frac{5}{6}$ ।
$36 \div (15 \times 2 \times \frac{5}{6}) = \frac{36}{25}$ ।
$\sqrt{\frac{36}{25}} = \frac{6}{5} = 1 \frac{1}{5}$ ।

याद रखें: "of" की श्रृंखला $15 \times 2 \times \frac{5}{6} = 25$ एक साथ हल करें।

उत्तर: (B) $1 \frac{1}{5}$

SSC CPO Paper IQuantitative AptitudeSimplification – BODMASSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3948.

The following bar graph describes the population of a town (in lakhs) from 2001 to 2007.

Find the percentage increase in population from 2006 to 2007.

निम्नलिखित दंड आलेख 2001 से 2007 तक एक कस्बे की जनसंख्या (लाख में) दर्शाता है।

2006 से 2007 तक जनसंख्या में प्रतिशत वृद्धि ज्ञात कीजिए।

A15%
B20%
C16%
D18%

Show answer

Concept: $% increase = \frac{New - Old}{Old} \times 100$ .

2006 $= 9.5$ lakh, 2007 $= 11.4$ lakh.
Increase $= 1.9$ .
$\frac{1.9}{9.5} \times 100 = 20 %$ .

Trick: $1.9$ is exactly $\frac{1}{5}$ of $9.5$ .

Answer: (B) $20 %$

अवधारणा: $% वृद्धि = \frac{नया - पुराना}{पुराना} \times 100$ ।

2006 $= 9.5$ लाख, 2007 $= 11.4$ लाख।
वृद्धि $= 1.9$ ।
$\frac{1.9}{9.5} \times 100 = 20 %$ ।

ट्रिक: $1.9$ , $9.5$ का ठीक $\frac{1}{5}$ है।

उत्तर: (B) $20 %$

SSC CPO Paper IQuantitative AptitudeData Interpretation – Bar GraphSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3949.

On a certain sum of money lent out at 16% per annum, the difference between the
compound interest for 1 year, payable half-yearly, and the simple interest for 1 year is Rs. 60. The sum is:

16% वार्षिक दर पर उधार दी गई एक निश्चित धनराशि पर, अर्धवार्षिक रूप से देय 1 वर्ष के चक्रवृद्धि ब्याज और 1 वर्ष के साधारण ब्याज के बीच का
अंतर Rs. 60 है। धनराशि है:

ARs. 937.5
BRs. 9,000
CRs. 9,365
DRs. 9,375

Show answer

Concept: Half-yearly: rate $= \frac{16}{2} = 8 %$ , time $= 2$ periods; CI − SI for 2 periods $= P {(\frac{r}{100})}^{2}$ .

CI $= P ({1.08}^{2} - 1) = 0.1664 P$ ; SI $= 0.16 P$ .
Difference $= 0.0064 P = 60$ .
$P = \frac{60}{0.0064} = 9375$ .

Trick: $P \times {(\frac{8}{100})}^{2} = 60 \Rightarrow P = 60 \times \frac{10000}{64}$ .

Answer: (D) Rs. 9,375

अवधारणा: अर्धवार्षिक: दर $= 8 %$ , अवधि $= 2$ ; दो अवधियों का CI − SI $= P {(\frac{r}{100})}^{2}$ ।

CI $= 0.1664 P$ ; SI $= 0.16 P$ ।
अंतर $= 0.0064 P = 60$ ।
$P = \frac{60}{0.0064} = 9375$ ।

ट्रिक: $P \times {(\frac{8}{100})}^{2} = 60 \Rightarrow P = 60 \times \frac{10000}{64}$ ।

उत्तर: (D) Rs. 9,375

SSC CPO Paper IQuantitative AptitudeCompound Interest – Half-yearlySSC CPO Paper I 2022 · 11 Nov Shift 2

Q3950.

\sin A = \frac{1}{2}

, then the value of

(\tan A + \cos A)

is:

यदि

\sin A = \frac{1}{2}

है, तो

(\tan A + \cos A)

का मान है:

A $\frac{2}{3 \sqrt{3}}$
B $\frac{3}{2 \sqrt{3}}$
C $\frac{5}{2 \sqrt{3}}$
D $\frac{5}{3 \sqrt{3}}$

Show answer

Concept: $\sin A = \frac{1}{2} \Rightarrow A = 30^{\circ}$ .

$\tan 30^{\circ} = \frac{1}{\sqrt{3}}$ , $\cos 30^{\circ} = \frac{\sqrt{3}}{2}$ .
Sum $= \frac{1}{\sqrt{3}} + \frac{\sqrt{3}}{2} = \frac{2 + 3}{2 \sqrt{3}} = \frac{5}{2 \sqrt{3}}$ .

Trick: Take LCM $2 \sqrt{3}$ directly.

Answer: (C) $\frac{5}{2 \sqrt{3}}$

अवधारणा: $\sin A = \frac{1}{2} \Rightarrow A = 30^{\circ}$ ।

$\tan 30^{\circ} = \frac{1}{\sqrt{3}}$ , $\cos 30^{\circ} = \frac{\sqrt{3}}{2}$ ।
योग $= \frac{2 + 3}{2 \sqrt{3}} = \frac{5}{2 \sqrt{3}}$ ।

ट्रिक: सीधे LCM $2 \sqrt{3}$ लें।

उत्तर: (C) $\frac{5}{2 \sqrt{3}}$

SSC CPO Paper IQuantitative AptitudeTrigonometric RatiosSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3951.

Select the most appropriate synonym of the given word.
Conjure

AAppeal
BQuiet
CAppease
DContent

Show answer

Concept: ‘Conjure’ means to call upon or appeal to someone solemnly (old sense: ‘I conjure you to tell the truth’); it also means to produce something as if by magic.

In the sense ‘to beg/call upon earnestly’, conjure = appeal.
Quiet = silent; Appease = calm someone by giving in; Content = satisfied – none matches.

Yaad rakhein: Conjure (a spirit/person) = call upon → Appeal.

Answer: (A) Appeal

अवधारणा: ‘Conjure’ का अर्थ है किसी से गंभीरता से विनती करना / पुकारना (call upon solemnly); जादू से कुछ प्रकट करना भी।

‘ज़ोर देकर विनती करना’ अर्थ में conjure = Appeal (अपील/निवेदन).
Quiet = शांत, Appease = मनाना/शांत करना, Content = संतुष्ट – मेल नहीं खाते।

याद रखें: Conjure = पुकारना/निवेदन करना → Appeal.

उत्तर: (A) Appeal

SSC CPO Paper IEnglish ComprehensionSynonymsSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3952.

Select the INCORRECTLY spelt word.

ACushion
BScientist
CPosthumusly
DLaboratory

Show answer

Concept: Adverb from ‘posthumous’ (after death) keeps the ‘-ous’ ending + ‘-ly’.

Correct spelling: Posthumously (post-hu-mous-ly).
Cushion, Scientist, Laboratory are correctly spelt.

Yaad rakhein: Adjective ending -ous + ly → -ously (famously, posthumously).

Answer: (C) Posthumusly

अवधारणा: ‘posthumous’ (मृत्यु के बाद) में ‘-ous’ रहता है और फिर ‘-ly’ जुड़ता है।

सही वर्तनी: Posthumously.
Cushion, Scientist, Laboratory सही हैं।

याद रखें: -ous + ly = -ously (famously, posthumously).

उत्तर: (C) Posthumusly

SSC CPO Paper IEnglish ComprehensionSpellingSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3953.

Select the option that expresses the given sentence in passive voice.
Sugar tastes sweet.

ASugar is sweet when it has been tasted sweet.
BSugar is sweet when it is tasted.
CSugar is sweet when tastes.
DSugar is sweet when tasted.

Show answer

Concept: ‘Taste’ here is a linking verb (Sugar tastes sweet = Sugar is sweet when tasted). Such sentences are made passive as ‘Subject + is + complement + when it is + V3’.

Present simple → ‘is’ + V3 = ‘is tasted’.
Complete clause: ‘Sugar is sweet when it is tasted.’
(A) wrong tense ‘has been’, (C) no ‘is’ + V3, (D) elliptical form lacks the full clause expected.

Yaad rakhein: Feel/taste/smell + adjective → ‘… is + adj. + when it is + V3’.

Answer: (B) Sugar is sweet when it is tasted.

अवधारणा: यहाँ ‘taste’ linking verb है। ऐसे वाक्यों का passive: ‘Subject + is + complement + when it is + V3’.

Present simple → ‘is tasted’.
पूरा रूप: ‘Sugar is sweet when it is tasted.’
(A) ‘has been’ गलत काल, (C) में ‘is’+V3 नहीं, (D) अधूरा clause.

याद रखें: taste/smell/feel + adjective → ‘… is + adj. + when it is + V3’.

उत्तर: (B) Sugar is sweet when it is tasted.

SSC CPO Paper IEnglish ComprehensionActive and Passive VoiceSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3954.

Select the most appropriate option that can substitute the underlined segment in the given sentence.
Why should I be suspect by you?

AI been suspected
BI been suspect
CI have been suspect
DI be suspected

Show answer

Concept: Passive with a modal: modal + be + V3. ‘Suspect’ is the base form; the past participle is ‘suspected’.

should + be + V3 → ‘should I be suspected by you?’
‘been’ cannot follow ‘should I’ directly; ‘have been suspect’ uses the wrong form.

Yaad rakhein: Modal + be + V3 (should be suspected, can be done).

Answer: (D) I be suspected

अवधारणा: Modal के साथ Passive: modal + be + V3। ‘suspect’ का V3 ‘suspected’ है।

should + be + V3 → ‘should I be suspected by you?’
‘should I been’ गलत; ‘have been suspect’ में V3 नहीं।

याद रखें: Modal + be + V3 (should be suspected).

उत्तर: (D) I be suspected

SSC CPO Paper IEnglish ComprehensionSentence Improvement (Passive with modal)SSC CPO Paper I 2022 · 11 Nov Shift 2

Q3955.

Select the most appropriate meaning of the underlined idiom in the following
sentence.
A wise man remains aware of fair-weather friends.

AA person from an area of pleasant weather
BA person with good knowledge of weather
CA helpful person
DA person not reliable in difficult time

Show answer

Concept: ‘Fair-weather friend’ = a friend who stays with you only in good times and leaves in trouble.

A wise man is careful about such friends because they are unreliable in hard times.
Options A and B take ‘weather’ literally; C is the opposite.

Yaad rakhein: Fair weather only → friend only in good days.

Answer: (D) A person not reliable in difficult time

अवधारणा: ‘Fair-weather friend’ = ऐसा मित्र जो केवल अच्छे समय में साथ दे, मुश्किल में छोड़ दे।

समझदार व्यक्ति ऐसे मित्रों से सावधान रहता है।
A और B ‘weather’ का शाब्दिक अर्थ लेते हैं; C उल्टा है।

याद रखें: Fair weather = सिर्फ़ अच्छे दिन → मतलबी दोस्त।

उत्तर: (D) A person not reliable in difficult time

SSC CPO Paper IEnglish ComprehensionIdiomsSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3956.

Select the option that will improve the underlined part of the given sentence. In case no improvement is needed, select 'No improvement required'.
Sheila always went to get ice cream with her dad on Tuesdays.

Ahad gotten
Bgone to get
Cwent to got
DNo improvement required

Show answer

Concept: A past habitual action (‘always … on Tuesdays’) is shown by the simple past.

‘Sheila always went to get ice cream with her dad on Tuesdays’ is correct.
‘had gotten’ (past perfect) needs an earlier past reference; ‘gone to get’ needs a helping verb; ‘went to got’ – ‘to’ takes base form.

Yaad rakhein: to + V1 always (to get, never ‘to got’).

Answer: (D) No improvement required

अवधारणा: अतीत की आदत (‘always … on Tuesdays’) simple past से व्यक्त होती है।

‘went to get’ सही है।
‘had gotten’ को पहले की past घटना चाहिए; ‘gone’ के साथ helping verb चाहिए; ‘to’ के बाद V1 आता है, ‘got’ नहीं।

याद रखें: to + V1 (to get).

उत्तर: (D) No improvement required

SSC CPO Paper IEnglish ComprehensionSentence ImprovementSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3957.

Select the most appropriate phrase for the underlined segment in the given sentence. The judgment was rejected by the Chief Justice.

ASeen through
BStand out
CSet aside
DRun in

Show answer

Concept: ‘Set aside’ (of a court decision) = to cancel/reject/overrule a judgment.

The Chief Justice rejected the judgment → set aside the judgment.
Seen through = recognise a trick; Stand out = be noticeable; Run in = arrest / break in an engine.

Yaad rakhein: Courts ‘set aside’ (= cancel) an order or judgment.

Answer: (C) Set aside

अवधारणा: ‘Set aside’ (अदालत के संदर्भ में) = किसी निर्णय को रद्द/निरस्त करना।

Chief Justice ने judgment reject किया → set aside.
Seen through = चाल समझ जाना, Stand out = अलग दिखना, Run in = गिरफ़्तार करना।

याद रखें: अदालत का आदेश रद्द = set aside.

उत्तर: (C) Set aside

SSC CPO Paper IEnglish ComprehensionPhrasal VerbsSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3958.

Identify the sentence that correctly uses the indefinite article.

AA taco is a traditional Mexican dish consisting of a tortilla topped with a filling.
BA taco is a traditional Mexican dish consisting of an tortilla topped with filling.
CAn taco is a traditional Mexican dish consisting of tortilla topped with filling.
DA taco is traditional Mexican dish consisting of a tortilla topped with an filling.

Show answer

Concept: ‘A’ is used before a consonant sound, ‘an’ before a vowel sound.

taco, tortilla, filling begin with consonant sounds → ‘a’.
(A) uses ‘A taco’, ‘a traditional … dish’, ‘a tortilla’, ‘a filling’ – all correct.
(B) ‘an tortilla’, (C) ‘An taco’, (D) ‘an filling’ and missing ‘a’ before ‘traditional’ – wrong.

Yaad rakhein: Article depends on the first sound, not letter.

Answer: (A) A taco is a traditional Mexican dish consisting of a tortilla topped with a filling.

अवधारणा: Consonant sound से पहले ‘a’, vowel sound से पहले ‘an’.

taco, tortilla, filling – सब consonant sound → ‘a’.
(A) में सभी articles सही हैं।
(B) ‘an tortilla’, (C) ‘An taco’, (D) ‘an filling’ – गलत।

याद रखें: Article पहली ध्वनि (sound) पर निर्भर है, अक्षर पर नहीं।

उत्तर: (A) A taco is a traditional Mexican dish consisting of a tortilla topped with a filling.

SSC CPO Paper IEnglish ComprehensionArticlesSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3959.

Select the most appropriate meaning of the given idiom.
To throw caution to the wind

ATo do something carefully
BTo do something with caution
CTo do something without worrying about the risk
DTo do something after thinking about the result

Show answer

Concept: ‘Throw caution to the wind’ = act boldly without caring about the risks.

Caution (carefulness) is thrown away → no worry about danger.
A, B and D describe careful action – the opposite.

Yaad rakhein: Caution gone with the wind → risk ignored.

Answer: (C) To do something without worrying about the risk

अवधारणा: ‘Throw caution to the wind’ = जोखिम की परवाह किए बिना कुछ करना।

Caution (सावधानी) को हवा में फेंक देना = लापरवाही से साहस करना।
A, B, D सावधानी दिखाते हैं – उल्टा अर्थ।

याद रखें: सावधानी हवा में उड़ा दी → जोखिम की चिंता नहीं।

उत्तर: (C) To do something without worrying about the risk

SSC CPO Paper IEnglish ComprehensionIdiomsSSC CPO Paper I 2022 · 11 Nov Shift 2

Q3960.

Select the INCORRECTLY spelt word.

AWhorle
BWinch
CWeird
DWench

Show answer

Concept: A ‘whorl’ is a spiral/coil pattern (e.g. on fingerprints).

Correct spelling: Whorl – no final ‘e’.
Winch (lifting device), Weird (strange), Wench (old word for a young woman) are correct.

Yaad rakhein: Whorl rhymes with ‘curl’ – no extra e.

Answer: (A) Whorle

अवधारणा: ‘Whorl’ = घुमावदार/सर्पिल आकृति (जैसे उँगलियों के निशान)।

सही वर्तनी: Whorl – अंत में ‘e’ नहीं।
Winch, Weird, Wench सही वर्तनी हैं।

याद रखें: Whorl (curl जैसा) – अतिरिक्त e नहीं।

उत्तर: (A) Whorle

SSC CPO Paper IEnglish ComprehensionSpellingSSC CPO Paper I 2022 · 11 Nov Shift 2