RRB NTPC Graduate CBT 1 2024 · Shift 1

RRB NTPC Graduate CBT 1 5 Jun 2025 Shift 1 – Question Paper

99 questions · 99 marks · 90 minutes · +1 for a correct answer, −1/3 for a wrong one. With answer key and detailed solutions in Hindi and English.

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Paper pattern

SectionQuestionsMarks
General Awareness4040
Mathematics2929
General Intelligence and Reasoning3030

Sample questions from this paper

Q1.
In which year did Bakshi Jagabandhu lead the Paika Rebellion to protest against the British land revenue policy?
बख्शी जगबंधु ने ब्रिटिश भू-राजस्व नीति के विरोध में पाइका विद्रोह का नेतृत्व किस वर्ष किया था?
  1. A1785
  2. B1717
  3. C1806
  4. D1817
Show answer

Concept: The Paika Rebellion was an armed uprising of the Paikas (traditional militia) of Khurda, Odisha, against British rule.

  1. It broke out in 1817 under Bakshi Jagabandhu, military chief of the Raja of Khurda.
  2. Causes: the new British land-revenue settlement, loss of Paika rent-free lands and rising salt prices.
  3. 1806 is the Vellore Mutiny year – a common trap.

Yaad rakhein: Khurda + Bakshi Jagabandhu = 1817; it is sometimes called the "first war of independence" of Odisha.

Answer: (D) 1817

अवधारणा: पाइका विद्रोह खुर्दा (ओडिशा) के पाइकों (पारंपरिक सैनिकों) का अंग्रेज़ों के विरुद्ध सशस्त्र विद्रोह था।

  1. यह 1817 में बख्शी जगबंधु के नेतृत्व में हुआ, जो खुर्दा के राजा के सेनापति थे।
  2. कारण: अंग्रेज़ों की नई भू-राजस्व नीति, पाइकों की लगान-मुक्त ज़मीनें छिनना और नमक के बढ़ते दाम।
  3. 1806 वेल्लोर विद्रोह का वर्ष है – इससे भ्रमित न हों।

याद रखें: खुर्दा + बख्शी जगबंधु = 1817।

उत्तर: (D) 1817

RRB NTPC Graduate CBT 1General AwarenessModern Indian History – Paika Rebellion
Q41.
Find the value of K if the quadratic equations 2x2+ Kx + 8 = 0 and 3x2+ 4x + 12 = 0 have both roots common.
K का मान ज्ञात कीजिए, यदि द्विघात समीकरणों 2x2+ Kx + 8 = 0 और 3x2+ 4x + 12 = 0 के दोनों मूल उभयनिष्ठ हों।
  1. A83
  2. B32
  3. C53
  4. D72
Show answer

Concept: If a1x2+b1x+c1=0 and a2x2+b2x+c2=0 have both roots common, then a1a2=b1b2=c1c2.

  1. 23=K4=812
  2. 812=23 ✓ (consistent)
  3. K4=23⇒K=83

Trick: Both roots common ⇒ the two equations are multiples of each other.

Answer: (A) 83

अवधारणा: यदि a1x2+b1x+c1=0 और a2x2+b2x+c2=0 के दोनों मूल उभयनिष्ठ हों, तो a1a2=b1b2=c1c2।

  1. 23=K4=812
  2. 812=23 ✓
  3. K4=23⇒K=83

ट्रिक: दोनों मूल समान ⇒ एक समीकरण दूसरे का गुणज है।

उत्तर: (A) 83

RRB NTPC Graduate CBT 1MathematicsQuadratic Equations – Common Roots
Q70.
If ‘+’ means ‘−’, ‘−’ means ‘×’, ‘×’ means ‘÷’ and ‘÷’ means ‘+’, then what will come in place of the question mark (?) in the following equation?
32 ÷ 14 + 16 – 8 × 4 = ?
यदि ‘+’ का अर्थ ‘−’, ‘−’ का अर्थ ‘×’, ‘×’ का अर्थ ‘÷’ और ‘÷’ का अर्थ ‘+’ है, तो निम्नलिखित समीकरण में प्रश्न चिह्न (?) के स्थान पर क्या आएगा?
32 ÷ 14 + 16 – 8 × 4 = ?
  1. A14
  2. B18
  3. C16
  4. D22
Show answer

Concept: Replace each sign by its meaning, then solve using BODMAS.

  1. Given: 32÷14+16−8×4
  2. Replace (÷→+, +→−, −→×, ×→÷): 32+14−16×8÷4
  3. 16×8÷4=32, so 32+14−32=14

Trick: Write the new expression first, then apply BODMAS – never solve before replacing signs.

Answer: (A) 14

अवधारणा: प्रत्येक चिह्न को उसके अर्थ से बदलें, फिर BODMAS लगाएँ।

  1. दिया है: 32÷14+16−8×4
  2. चिह्न बदलने पर: 32+14−16×8÷4
  3. 16×8÷4=32, अतः 32+14−32=14

ट्रिक: पहले पूरा नया व्यंजक लिखें, फिर BODMAS लगाएँ।

उत्तर: (A) 14

RRB NTPC Graduate CBT 1General Intelligence and ReasoningMathematical Operations

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