airGurukul
Log in

SSC CHSL 2025 · Shift 2

SSC CHSL 18 Nov 2025 Shift 2 – Question Paper

100 questions · 200 marks · 60 minutes · +2 for a correct answer, −0.5 for a wrong one. With answer key and detailed solutions in Hindi and English.

Attempt online test Download free PDF
Test Series – airGurukul
Online testReal exam interface, timer, score, rank and review.Solved eBookEvery question with answer and step-by-step solution.Free PDFQuestion paper with answer key – no login needed.

Paper pattern

SectionQuestionsMarks
English Language2550
General Intelligence2550
Quantitative Aptitude2550
General Awareness2550

Sample questions from this paper

Q1.
Which sentence is grammatically correct?
  1. ANeither of the boys are misbehaving.
  2. BEveryone is deeply concerned about the deteriorating air quality.
  3. CMany a man has sacrificed for the safety of this nation.
  4. DThe number of emigrants has reduced significantly.
Show answer

Concept: 'Neither of + plural noun' takes a singular verb.

  1. Sentence (A) uses 'are' after 'Neither of the boys' – wrong; it should be 'Neither of the boys is misbehaving'.
  2. (B) 'Everyone is' ✔ – indefinite pronoun is singular. (C) 'Many a man has' ✔ – always singular. (D) 'The number of … has' ✔ – head word 'number' is singular.
  3. So (A) is the only faulty sentence; the keyed answer marks this sentence (the question should read 'grammatically incorrect').

Trick: Neither / Either / Each / Every / Many a / The number of → singular verb; 'A number of' → plural verb.

Answer: (A) Neither of the boys are misbehaving.

अवधारणा: 'Neither of + plural noun' के साथ singular verb आता है।

  1. (A) में 'Neither of the boys' के बाद 'are' गलत है; सही: 'Neither of the boys is misbehaving'.
  2. (B) Everyone is ✔, (C) Many a man has ✔, (D) The number of … has ✔ – तीनों में singular कर्ता के साथ singular verb है।
  3. इसलिए केवल (A) में त्रुटि है; उत्तर-कुंजी इसी वाक्य को चुनती है (प्रश्न वास्तव में 'incorrect' वाक्य पूछ रहा है)।

ट्रिक: Neither/Either/Each/Every/Many a/The number of → singular verb; 'A number of' → plural verb.

उत्तर: (A) Neither of the boys are misbehaving.

SSC CHSLEnglish LanguageSubject–verb agreement: 'Neither of'
Q26.
In a certain code language, if NOTEBOOK is written as KOOBETON, HEADPHONE is written as ENOHPDAEH, and RAINBOW is written as WOBNIAR, then according to this coding pattern, how would NEWSPAPER be coded in the same language system?
एक निश्चित कूट भाषा में, यदि NOTEBOOK को KOOBETON लिखा जाता है, HEADPHONE को ENOHPDAEH लिखा जाता है तथा RAINBOW को WOBNIAR लिखा जाता है, तो इसी कूट पद्धति के अनुसार उसी भाषा में NEWSPAPER को किस प्रकार कूटबद्ध किया जाएगा?
  1. AREPASPWEN
  2. BREPAPSWEN
  3. CREPAPWSEN
  4. DREPAPSNWE
Show answer

Concept: Each word is coded by writing its letters in reverse order.

  1. RAINBOW → W O B N I A R (read from the end) ✔ – rule confirmed.
  2. NEWSPAPER read backwards: R E P A P S W E N.
  3. Code = REPAPSWEN.

Trick: Check only the middle letters: NEWS reversed is SWEN – only option (B) ends in 'SWEN'.

Answer: (B) REPAPSWEN

अवधारणा: हर शब्द को उल्टे क्रम में लिखकर कोड बनाया गया है।

  1. RAINBOW → W O B N I A R ✔ – नियम पक्का।
  2. NEWSPAPER को अंत से पढ़ें: R E P A P S W E N।
  3. कोड = REPAPSWEN।

ट्रिक: NEWS उल्टा = SWEN; केवल (B) 'SWEN' पर खत्म होता है।

उत्तर: (B) REPAPSWEN

SSC CHSLGeneral IntelligenceCoding – reverse order
Q51.
A shopkeeper sells an article at a discount of 15%. Had he given only a 7% discount, he would have earned ₹768 more as profit. If the cost price of the article is ₹3,000, then find the marked price.
एक दुकानदार एक वस्तु को 15% की छूट पर बेचता है। यदि उसने केवल 7% की छूट दी होती, तो उसे ₹768 अधिक लाभ प्राप्त होता। यदि वस्तु का क्रय मूल्य ₹3,000 है, तो अंकित मूल्य ज्ञात कीजिए।
  1. A₹9,600
  2. B₹6,900
  3. C₹7,600
  4. D₹5,600
Show answer

Concept: CP is fixed, so any change in SP equals the change in profit; discount is on MP.

  1. Difference in discount = 15% − 7% = 8% of MP.
  2. 8% of MP = ₹768 → MP = 768 × 100/8 = ₹9,600.
  3. CP (₹3,000) is not needed.

Trick: 1% of MP = 768 ÷ 8 = 96 → MP = 9,600.

Answer: (A) ₹9,600

अवधारणा: CP स्थिर है, अतः SP में अंतर = लाभ में अंतर; छूट MP पर होती है।

  1. छूट का अंतर = 15% − 7% = MP का 8%।
  2. MP का 8% = ₹768 → MP = 768 × 100/8 = ₹9,600।
  3. CP (₹3,000) की आवश्यकता नहीं।

ट्रिक: MP का 1% = 768 ÷ 8 = 96 → MP = 9,600।

उत्तर: (A) ₹9,600

SSC CHSLQuantitative AptitudeDiscount – marked price from extra profit
Q76.
Which ruler of the Chahamana (Chauhan) dynasty defeated Sultan Muhammad Ghori in the year 1191 CE ?
चाहमान (चौहान) वंश के किस शासक ने 1191 ई. में सुल्तान मुहम्मद गोरी को पराजित किया था?
  1. AVigraharaja Vविग्रहराज V
  2. BVigraharaja IVविग्रहराज IV
  3. CPrithviraja IIIपृथ्वीराज III
  4. DAjayaraja IIअजयराज II
Show answer

Concept: Prithviraja III (Prithviraj Chauhan) defeated Muhammad Ghori in 1191 CE.

  1. First Battle of Tarain (1191) – Prithviraj won.
  2. Second Battle of Tarain (1192) – Ghori won, opening north India to Turkish rule.
  3. Ajayaraja II founded Ajmer; Vigraharaja IV (Visaladeva) ruled in the mid-12th century – both before Prithviraj.

Trick: Tarain: 1191 → Prithviraj; 1192 → Ghori ('1' wins first, '2' wins second).

Answer: (C) Prithviraja III

अवधारणा: पृथ्वीराज तृतीय (पृथ्वीराज चौहान) ने 1191 ई. में मुहम्मद गोरी को हराया।

  1. तराइन का प्रथम युद्ध (1191) – पृथ्वीराज विजयी।
  2. तराइन का द्वितीय युद्ध (1192) – गोरी विजयी, उत्तर भारत में तुर्क शासन की राह खुली।
  3. अजयराज द्वितीय ने अजमेर बसाया; विग्रहराज चतुर्थ (वीसलदेव) पहले के शासक थे।

ट्रिक: तराइन: 1191 → पृथ्वीराज; 1192 → गोरी।

उत्तर: (C) Prithviraja III

SSC CHSLGeneral AwarenessChauhan dynasty – First Battle of Tarain

See all 100 solutions

More SSC CHSL papers

Download our app

Study smarter with the airGurukul App

Your complete exam-prep companion - classes, practice, and progress tracking.

Learn anytime, anywhere - live classes, tests, notes, and updates in one place.

GET IT ONGoogle Play

Have a query? We’re here to help

Fill out the form and our team will get back to you as soon as possible.

  • Ask your questions related to admission, courses, fees, or facilities
  • Share your details so our team can contact you easily
  • Get accurate information from our support team
  • Quick and simple form submission process
Talk to a counsellor: +91-7042559948 info@airgurukul.com

All fields marked * are required.