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SSC CHSL 2025 · Shift 2

SSC CHSL 19 Nov 2025 Shift 2 – Question Paper

100 questions · 200 marks · 60 minutes · +2 for a correct answer, −0.5 for a wrong one. With answer key and detailed solutions in Hindi and English.

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Paper pattern

SectionQuestionsMarks
English Language2550
General Intelligence2550
Quantitative Aptitude2550
General Awareness2550

Sample questions from this paper

Q1.
Find the incorrect part in the given sentence.
"If I was the manager, I would change the policy.*
  1. AIf I
  2. Bwas the manager
  3. CI would
  4. Dchange the policy
Show answer

Concept: An imaginary/unreal 'if' condition uses 'were' for every subject.

  1. The speaker is not actually the manager – the situation is hypothetical.
  2. Pattern: If + subject + were …, subject + would + V1.
  3. So 'was the manager' → 'were the manager'. The rest ('I would change the policy') is correct.

Trick: See 'would' in the main clause? Check the if-clause – it must have 'were' (If I were you, If he were rich).

Answer: (B) was the manager

अवधारणा: काल्पनिक (unreal) 'if' वाली शर्त में हर subject के साथ 'were' आता है।

हल:

  1. बोलने वाला सच में manager नहीं है – यह केवल कल्पना है।
  2. ढाँचा: If + subject + were …, subject + would + V1
  3. इसलिए 'was the manager' को 'were the manager' करें; बाकी हिस्सा सही है।

ट्रिक: मुख्य वाक्य में 'would' दिखे तो if-clause में 'were' देखें – जैसे If I were you.

उत्तर: (B) was the manager

SSC CHSLEnglish LanguageError spotting – 'were' in unreal condition
Q26.
If in a certain coding system, PEN is coded as 112213, INK as 181316, then how will BOOK be coded following this numerical coding pattern?
यदि किसी निश्चित कूट प्रणाली में PEN को 112213 तथा INK को 181316 लिखा जाता है, तो इसी संख्यात्मक कूट पैटर्न के अनुसार BOOK को किस प्रकार लिखा जाएगा?
  1. A25121216
  2. B24131216
  3. C25121418
  4. D25161615
Show answer

Concept: Each letter is written as the position of its opposite letter (27 − position).

  1. PEN = positions 16, 5, 14 → opposites 11, 22, 13 ⇒ 112213 ✔
  2. INK = positions 9, 14, 11 → opposites 18, 13, 16 ⇒ 181316 ✔
  3. BOOK = positions 2, 15, 15, 11 → opposites 25, 12, 12, 16 ⇒ 25121216

Trick: Opposite pairs add to 27 (A+Z = 1+26). B→25 alone matches options A, C, D; O→12 leaves only A and C; K→16 picks A.

Answer: (A) 25121216

अवधारणा: हर अक्षर को उसके विपरीत अक्षर के स्थान-मान (27 − स्थान) से लिखा गया है।

हल:

  1. PEN के स्थान 16, 5, 14 → विपरीत 11, 22, 13 ⇒ 112213 ✔
  2. INK के स्थान 9, 14, 11 → विपरीत 18, 13, 16 ⇒ 181316 ✔
  3. BOOK के स्थान 2, 15, 15, 11 → विपरीत 25, 12, 12, 16 ⇒ 25121216

ट्रिक: विपरीत अक्षरों का योग 27 होता है। O→12 और K→16 से तुरंत विकल्प A मिल जाता है।

उत्तर: (A) 25121216

SSC CHSLGeneral IntelligenceCoding – opposite letter positions
Q51.
If (a+b)2=131 and ab=8, then find a2+b2.
यदि (a+b)2=131 तथा ab=8 है, तो a2+b2 का मान ज्ञात कीजिए।
  1. A98
  2. B105
  3. C115
  4. D108
Show answer

Concept: a² + b² = (a + b)² − 2ab.

  1. a² + b² = 131 − 2 × 8
  2. = 131 − 16 = 115

Trick: Whenever (a+b)² and ab are given, just subtract 2ab – no need to find a and b.

Answer: (C) 115

अवधारणा: a² + b² = (a + b)² − 2ab

हल:

  1. a² + b² = 131 − 2 × 8
  2. = 131 − 16 = 115

ट्रिक: (a+b)² और ab दिए हों तो सीधे 2ab घटाएँ – a, b अलग से निकालने की ज़रूरत नहीं।

उत्तर: (C) 115

SSC CHSLQuantitative AptitudeAlgebraic identity – a² + b²
Q76.
Identify the renowned philosopher who was born in Kerala during the 8th century.
उस प्रसिद्ध दार्शनिक की पहचान कीजिए जिनका जन्म 8वीं शताब्दी में केरल में हुआ था।
  1. AMadhvacharyaमाधवाचार्य
  2. BVallabhacharyaवल्लभाचार्य
  3. CShankaracharyaशंकराचार्य
  4. DKabirdasकबीरदास
Show answer

Concept: Philosopher of Advaita Vedanta, born in 8th-century Kerala.

  1. Adi Shankaracharya was born at Kaladi (Kerala) and taught Advaita (non-dualism).
  2. Madhvacharya (Dvaita, 13th c.) and Vallabhacharya (Shuddhadvaita, 15th–16th c.) came much later; Kabir was a 15th-century Bhakti poet of north India.

Yaad rakhein: Shankaracharya founded four mathas: Sringeri (south), Dwarka (west), Puri (east), Jyotirmath/Badrinath (north).

Answer: (C) Shankaracharya

अवधारणा: 8वीं शताब्दी में केरल में जन्मे अद्वैत वेदांत के दार्शनिक।

हल:

  1. आदि शंकराचार्य का जन्म कालड़ी (केरल) में हुआ; उन्होंने अद्वैत दर्शन दिया।
  2. माधवाचार्य (द्वैत, 13वीं सदी), वल्लभाचार्य (शुद्धाद्वैत, 15वीं–16वीं सदी) बाद के हैं; कबीर 15वीं सदी के भक्ति कवि थे।

याद रखें: शंकराचार्य के चार मठ: शृंगेरी, द्वारका, पुरी और ज्योतिर्मठ (बद्रीनाथ)।

उत्तर: (C) शंकराचार्य

SSC CHSLGeneral AwarenessAdi Shankaracharya

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