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SSC CHSL 2025 · Shift 3

SSC CHSL 25 Nov 2025 Shift 3 – Question Paper

100 questions · 200 marks · 60 minutes · +2 for a correct answer, −0.5 for a wrong one. With answer key and detailed solutions in Hindi and English.

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Paper pattern

SectionQuestionsMarks
English Language2550
General Intelligence2550
Quantitative Aptitude2550
General Awareness2550

Sample questions from this paper

Q1.
Choose the one word substitute for the below sentence.
Susan asked her husband, a person who is highly knowledgeable in a particular field?
  1. AAmateur
  2. BNovice
  3. CExpert
  4. DProdigy
Show answer

Concept: Pick the word that names a person with deep, specialised knowledge.

  1. Key clue: highly knowledgeable in a particular field.
  2. Expert = a specialist who has mastered one subject.
  3. Amateur = does it as a hobby; Novice = a beginner; Prodigy = an unusually gifted child – none means 'specialist'.

Trick: Amateur and Novice are the opposites of Expert – strike them out first; Prodigy is about age + talent, not field knowledge.

Answer: (C) Expert

अवधारणा: ऐसा शब्द चुनें जो किसी एक विषय में गहरी जानकारी रखने वाले व्यक्ति के लिए हो।

हल:

  1. संकेत: highly knowledgeable in a particular field।
  2. Expert = किसी विषय का विशेषज्ञ/जानकार।
  3. Amateur = शौकिया, Novice = नौसिखिया, Prodigy = असाधारण प्रतिभा वाला बच्चा – ये अर्थ मेल नहीं खाते।

ट्रिक: Amateur और Novice तो Expert के उलटे हैं – पहले इन्हें हटाएँ; Prodigy उम्र + प्रतिभा बताता है, विषय-ज्ञान नहीं।

उत्तर: (C) Expert

SSC CHSLEnglish LanguageOne word – specialist
Q26.
In this type of questions, question is provided with substitutes for various mathematical symbols, followed by a question involving calculation of an expression or choosing the correct/incorrect equation. You have to put the real signs in the given equation and then solve the questions as required. If '*' stands for ' C ', ' $ ' stands for ' × ', '!' stands for '÷', '~' stands for '+', then find the value of: 24!9∗4∗6= ?
इस प्रकार के प्रश्नों में विभिन्न गणितीय चिह्नों के स्थान पर उनके प्रतिस्थापी प्रतीक दिए जाते हैं, और उसके बाद किसी व्यंजक का मान निकालने अथवा सही/गलत समीकरण चुनने का प्रश्न पूछा जाता है। आपको दिए गए समीकरण में वास्तविक चिह्न रखकर प्रश्न को हल करना है। यदि '*' का अर्थ ' C ' है, ' $ ' का अर्थ ' × ' है, '!' का अर्थ '÷' है, '~' का अर्थ '+' है, तो निम्नलिखित का मान ज्ञात कीजिए: 24!9∗4∗6= ?
  1. A−223
  2. B−253
  3. C−213
  4. D−273
Show answer

Concept: Replace each symbol by its real sign, then apply BODMAS (÷ before −).

  1. '!' = ÷ and '*' = − → 24 ÷ 9 − 4 − 6.
  2. 24 ÷ 9 = 8/3.
  3. 8/3 − 10 = (8 − 30)/3 = −22/3.

Trick: Combine all subtractions first (4 + 6 = 10), then one step: 8/3 − 10.

Answer: (A) −22/3

अवधारणा: हर प्रतीक की जगह असली चिह्न रखें, फिर BODMAS लगाएँ (पहले ÷, फिर −)।

हल:

  1. '!' = ÷, '*' = − → 24 ÷ 9 − 4 − 6
  2. 24 ÷ 9 = 8/3
  3. 8/3 − 10 = (8 − 30)/3 = −22/3

ट्रिक: सारे घटाव पहले जोड़ लें (4 + 6 = 10), फिर एक ही बार: 8/3 − 10।

उत्तर: (A) −22/3

SSC CHSLGeneral IntelligenceSymbol substitution – BODMAS
Q51.
An article sold for Rs. 960 after a discount of 20%. What was the marked price?
एक वस्तु 20% की छूट के बाद Rs. 960 में बेची गई। उसका अंकित मूल्य क्या था?
  1. ARs. 1250
  2. BRs. 1100
  3. CRs. 1200
  4. DRs. 1000
Show answer

Concept: After d% discount, SP = (100 − d)% of MP.

  1. 20% off → SP is 80% of MP.
  2. 80% of MP = ₹960.
  3. MP = 960 × 100/80 = 960 × 5/4 = ₹1200.

Trick: 20% = 1/5 off → SP = 4/5 MP → MP = 960 × 5/4 = 1200 in one line.

Answer: (C) Rs. 1200

अवधारणा: d% छूट के बाद विक्रय मूल्य = अंकित मूल्य का (100 − d)%।

हल:

  1. 20% छूट → SP = MP का 80%
  2. MP का 80% = ₹960
  3. MP = 960 × 5/4 = ₹1200

ट्रिक: 20% = 1/5 → SP = MP का 4/5 → MP = 960 × 5/4 = 1200।

उत्तर: (C) ₹1200

SSC CHSLQuantitative AptitudeMarked price from discount
Q76.
Among the rulers of the Chola dynasty, who is widely regarded as the most powerful and influential monarch?
चोल वंश के शासकों में, किसे व्यापक रूप से सर्वाधिक शक्तिशाली और प्रभावशाली सम्राट माना जाता है?
  1. AVijayalaya Chola
  2. BKulothunga Chola I
  3. CRajaraja I
  4. DParantaka I
Show answer

Concept: The peak of Chola power came under Rajaraja I and his son Rajendra I.

  1. Rajaraja I (c. 985–1014 CE) conquered the Cheras, Pandyas and northern Sri Lanka and built a strong navy.
  2. He built the Brihadeeswara temple, Thanjavur (UNESCO site).
  3. Vijayalaya only founded the line; Parantaka I was defeated at Takkolam; Kulothunga I came after the peak.

Trick: Founder (Vijayalaya) ≠ greatest. Remember 'Raja-raja' = 'king of kings'.

Answer: (C) Rajaraja I

अवधारणा: चोल शक्ति का चरम राजराज प्रथम और उनके पुत्र राजेंद्र प्रथम के समय रहा।

हल:

  1. राजराज प्रथम (लगभग 985–1014 ई.) ने चेर, पांड्य और उत्तरी श्रीलंका को जीता, मज़बूत नौसेना बनाई।
  2. तंजावुर का बृहदेश्वर मंदिर बनवाया (UNESCO धरोहर)।
  3. विजयालय केवल संस्थापक; परांतक प्रथम तक्कोलम में हारा; कुलोत्तुंग प्रथम बाद में आया।

ट्रिक: संस्थापक (विजयालय) ≠ सबसे महान। 'राज-राज' = राजाओं का राजा।

उत्तर: (C) Rajaraja I

SSC CHSLGeneral AwarenessCholas – greatest ruler

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