Q&A: practice questions with answers

Concept: Interchange the signs first, then solve using BODMAS.

1. Swap ÷ ↔ – and × ↔ +: $89-4984÷89+9\times 2$
2. $4984÷89=56$ and $9\times 2=18$
3. $89-56+18=51$

Trick: Rewrite the whole expression once with new signs before calculating – avoids half-swapped mistakes.

Answer: (B) $51$

Concept: Interchange the signs, then apply BODMAS.

1. Swap + ↔ − and × ↔ ÷: $405\times 2-369÷9+32$
2. $405\times 2=810$, $369÷9=41$
3. $810-41+32=801$

Trick: Do division/multiplication first; only then add and subtract left to right.

Answer: (B) $801$

Concept: Compare letter positions of the pair: each letter moves by a different step.

1. J→K ($+1$), K→M ($+2$), L→O ($+3$); PQR→QSU also $+1,+2,+3$.
2. X $+1$ = Y; Y $+2$ = A (Z, A – wrapping after Z); Z $+3$ = C (A, B, C).
3. So XYZ → YAC.

Trick: After Z, count again from A (circular alphabet).

Answer: (D) YAC

Concept: Identify the highest and lowest numbers, then pick the required digits.

1. Highest number = 884 → second digit = 8.
2. Lowest number = 316 → third digit = 6.
3. $8+6=14$

Trick: Compare only first digits to find highest/lowest quickly: 8 (884) and 3 (316).

Answer: (A) $14$

Concept: Facing the centre: right = anticlockwise, left = clockwise.

1. Fix F. C is immediate left of F, G is immediate right of F ⇒ G, F, C are together.
2. D is third to the right of C. B is not next to C and A is second to the right of B ⇒ only B with A two places right of it fits, so E takes the last seat.
3. Clockwise order: F, C, A, E, B, D, G.
4. Going left (clockwise) from G: F, C, A, then E ⇒ three persons between.

Trick: Fix the pair with "immediate" clues first, then place third/second-to clues.

Answer: (A) Three

Concept: Apply the rule to each digit separately.

1. 3762184: odd digits $+1$ → 3→4, 7→8, 1→2.
2. Even digits $-2$ → 6→4, 2→0, 8→6, 4→2.
3. New number 4840262: highest 8, lowest 0 ⇒ $8+0=8$.

Trick: Write the new digit under each old digit – no mix-ups.

Answer: (D) $8$

Concept: Track the letters and the numbers separately.

1. First letters: G, H, I, J → K ($+1$). Second: O, P, Q, R → S. Third: Q, R, S, T → U.
2. Numbers: 35, 32, 29, 26 → $26-3=23$.
3. Next term = KSU 23.

Trick: Number pattern ($-3$) alone removes the 22 options; letters $+1$ give KSU.

Answer: (A) KSU 23

Concept: Start with the fixed clues ("no one above", "immediately below"), then use gap clues.

1. No one above I ⇒ I on floor 6. Two between I and H ⇒ H on 3.
2. K odd, not 1, not 3 ⇒ K on 5; X immediately below ⇒ X on 4.
3. Two between K and G ⇒ G on 2; J on the remaining floor 1.
4. Between J (1) and X (4): G and H ⇒ two persons.

Trick: A "top" clue (no one above) is the best anchor – place it first.

Answer: (A) Two

Concept: Each letter of a pair moves back by the same step.

1. SW-NR-IM: S→N→I is $-5,-5$; W→R→M is $-5,-5$.
2. IM-DH-YC: I→D→Y and M→H→C are $-5,-5$ (wrapping after A).
3. YC-TX-OS: Y→T→O $-5,-5$; C→X→S $-5,-5$ ✔.
4. (B) P→L is $-4$ ✘; (C) H→D is $-4$ ✘; (D) A→W is $-4$ ✘.

Trick: Also each pair has the same gap (W−S = 4 letters): YC also has gap 4 (Y Z A B C).

Answer: (A) YC-TX-OS

Concept: Write basic codes first, then check each condition.

1. SEMTU → S=@, E=2, M=4, T=*, U=7.
2. Cond. 1 and 2 need the 1st letter to be a vowel – S is a consonant, so not applicable.
3. Cond. 3: 2nd letter E and last letter U are vowels ⇒ interchange their codes (2 ↔ 7).
4. Code: @ 7 4 * 2.

Trick: Check the first letter first – a consonant start kills conditions 1 and 2 instantly.

Answer: (A) @ 7 4 * 2

Concept: Decode each symbol from left to right and draw a family tree.

1. M ÷ N: M is father of N. N – O: N is brother of O.
2. O + P: O is sister of P ⇒ N, O, P are siblings, all children of M.
3. P × Q: P is wife of Q (so P is female).
4. M is father of P, who is Q's wife ⇒ M is Q's wife's father (father-in-law).

Trick: Siblings share the parent – once N, O, P are siblings, M is father of all three.

Answer: (D) Wife's Father

Concept: Letters and numbers follow separate patterns.

1. First letters: D, G, J, M → P ($+3$).
2. Second letters: K, N, Q, T → W ($+3$).
3. Numbers: 26, 33, 40, 47 → 54 ($+7$).
4. Next = PW54.

Trick: Number ($+7$ ⇒ 54) leaves PW54 / PV54; letter $+3$ after T is W.

Answer: (B) PW54

Concept: Check the differences between consecutive terms.

1. Differences: $55-46=9$, $78-55=23$, $87-78=9$, $110-87=23$, $119-110=9$.
2. Pattern $+9,+23$ alternates; next is $+23$.
3. $119+23=142$

Trick: Alternating differences – just continue the pair ($+9,+23$).

Answer: (B) $142$

Concept: Track coordinates: North/South change y, East/West change x.

1. Start A $(0,0)$; 8 km North → $(0,8)$.
2. Left (West) 12 → $(-12,8)$; left (South) 11 → $(-12,-3)$.
3. Left (East) 14 → $(2,-3)$; left (North) 3 → P $(2,0)$.
4. P is 2 km East of A ⇒ he must drive 2 km to the West.

Trick: North–South: $8-11+3=0$, so only East–West matters: $-12+14=2$ East ⇒ go back West.

Answer: (B) 2 km to the west

Concept: Compare the letters by their alphabet positions in each triad.

1. NK-RO-VX: $N(14)\to R(18)\to V(22)$ is $+4,+4$; $K(11)\to O(15)\to X(24)$ is $+4,+9$.
2. LI-PM-TV: $L\to P\to T$ is $+4,+4$; $I(9)\to M(13)\to V(22)$ is $+4,+9$.
3. JG-NK-RT: $J(10)\to N(14)\to R(18)$ is $+4,+4$; $G(7)\to K(11)\to T(20)$ is $+4,+9$ ✓
4. JG-NK-RU fails ($K\to U$ is $+10$); IG options fail ($I\to N$ is $+5$).

Trick: Check the first letters ($+4,+4$) first – it removes both IG options at once.

Answer: (A) JG-NK-RT

Concept: Every digit (even or odd) increases by 1.

1. 7142568 → each digit $+1$ → 8253679
2. First digit from left $=8$; first digit from right $=9$
3. Sum $=8+9=17$

Trick: Only the two end digits matter: $(7+1)+(8+1)=17$.

Answer: (C) $17$

Concept: Find the step between consecutive letters (backward counting wraps from A to Z).

1. AWRP: $A\stackrel{-4}{\to }W\stackrel{-5}{\to }R\stackrel{-2}{\to }P$
2. RNIG: $R\stackrel{-4}{\to }N\stackrel{-5}{\to }I\stackrel{-2}{\to }G$; JFAY: $J\stackrel{-4}{\to }F\stackrel{-5}{\to }A\stackrel{-2}{\to }Y$
3. HDVW: $H\stackrel{-4}{\to }D$, but $D\to V$ is $-8$ and $V\to W$ is $+1$ ✗

Trick: Fix the pattern $-4,-5,-2$ from two clusters, then test the rest.

Answer: (C) HDVW

Concept: Look for the pattern Number – Number – Symbol and count the middle number.

1. … 3 2 $ … → 2 preceded by 3, followed by $ ✓
2. … 9 2 @ … → 2 preceded by 9, followed by @ ✓
3. … 5 3 % … → 3 preceded by 5, followed by % ✓
4. No other number fits (e.g. the 9s are followed by numbers), so the count is 3.

Trick: Scan only the symbols: for each symbol, check whether the two places just before it are both numbers.

Answer: (A) $3$

Concept: Look for the pattern Number – Symbol – Symbol and count the middle symbol.

1. 3 € & → € preceded by 3, followed by & ✓
2. 1 $ € → $ preceded by 1, followed by € ✓
3. 1 € 4 → followed by a number ✗; 4 © at the end → nothing follows ✗
4. Count = 2

Trick: List every number, then check the next two places: symbol + symbol.

Answer: (D) $2$

Concept: Track the position on a grid (East +x, North +y); a right turn while facing South points West.

1. A(0, 0) → 11 km South → (0, −11)
2. Right (West) 9 km → (−9, −11); right (North) 12 km → (−9, 1)
3. Right (East) 12 km → (3, 1); right (South) 1 km → P(3, 0)
4. P is 3 km East of A, so he must drive 3 km to the West.

Trick: Net East = 12 − 9 = 3 km; net North = 12 − 11 − 1 = 0 → move 3 km West.

Answer: (A) 3 km to the west