Q&A: practice questions with answers

Concept: Track each letter position through the terms.

1. 1st: N, H, B, V, P ($-6$ each).
2. 2nd: J, D, X, R, L ($-6$ each).
3. 3rd: I, C, W, Q, K ($-6$ each).
4. Also, in each term the 3rd letter is just before the 2nd (JI, DC, XW, RQ → LK).

Trick: Inside each term the last two letters are consecutive reversed; only PLK has L-K.

Answer: (A) PLK

Concept: Look at differences between consecutive terms.

1. $391-42=349$, $349+27=376$
2. $376-42=334$, $334+27=361$, $361-42=319$
3. Next: $319+27=346$

Trick: Alternate $-42$, $+27$ (net $-15$ every two steps: $391,376,361,346$).

Answer: (D) 346

Concept: Find the letter-wise shift and apply it to each option.

1. UOM → YRK: $+4$, $+3$, $-2$. VSL → ZVJ: $+4$, $+3$, $-2$ ✓
2. INK → MQI: $I+4=M$, $N+3=Q$, $K-2=I$ ✓
3. GVS → KYR: last $-1$ ✗; FEO → JHL: last $-3$ ✗; KRX → OTV: middle $+2$ ✗

Trick: Check the unusual step ($-2$ on the 3rd letter) first to eliminate fast.

Answer: (C) INK : MQI

Concept: Apply the rule digit by digit: odd $+1$, even $-2$.

1. 4317856: $4\to 2$, $3\to 4$, $1\to 2$, $7\to 8$, $8\to 6$, $5\to 6$, $6\to 4$.
2. New number: 2428664.
3. Repeated digits: 2 (twice), 4 (twice), 6 (twice) → 3 digits.

Trick: Odd digits become even and even stay even – so all new digits are even, repeats are likely.

Answer: (A) Three

Concept: Arrange the letters of INJURED alphabetically, then count the gap.

1. Arranged: D E I J N R U.
2. 3rd from left = I (9); 2nd from right = R (18).
3. Letters between I and R: J…Q → $18-9-1=8$.

Trick: Use positions: I = 9, R = 18; gap $=$ difference $-1$.

Answer: (C) 8

Concept: Decode each symbol and draw the family tree.

1. S ÷ D: S is father of D. D + R: D is brother of R, so S is also father of R.
2. R @ Y: R is mother of Y (R is female).
3. Y × H: Y is wife of H.
4. So for H: wife Y → her mother R → her father S. S is H's wife's mother's father.

Trick: Read the chain from H backwards: wife → mother → father.

Answer: (A) Wife's mother's father

Concept: Track the net East–West and North–South movement from Y.

1. East–West: $+75-38-37=0$ → Z is directly in line with Y (north–south).
2. North–South: $+35-41-26=-32$ → Z is 32 km south of Y.
3. Turns: E → left N → left W → left S → right W → left S.
4. To return to Y he must drive 32 km towards north.

Trick: Add E/W and N/S separately; a zero in one means a straight-line answer.

Answer: (A) 32 km towards north

Concept: Use letter positions: inside each cluster and from cluster to cluster.

1. XV – NH: $X-2=V$, $N-6=H$, $X-10=N$ ✓
2. BZ – RL: $B-2=Z$, $R-6=L$, $B-10=R$ ✓; OM – EY: $O-2=M$, $E-6=Y$, $O-10=E$ ✓
3. VT – LE: $V-2=T$ and $V-10=L$, but $L-7=E$ (not $-6$) ✗

Trick: Check the second cluster's gap ($-6$): only LE gives $-7$.

Answer: (A) VT – LE

Concept: Facing the centre, left = clockwise and right = anticlockwise.

1. Fix W. T is third to the left of W; V is third to the left of T (since T is third to the right of V).
2. X is a neighbour of both U and V → X sits between U and V, on the side between T and V (the other side of V is next to W).
3. Z is second to the left of S → S sits between V and W, Z next to W, Y next to T.
4. From X going left: V, S, then W → 2 people.

Trick: “A is third to the right of B” = “B is third to the left of A”.

Answer: (C) Two

Concept: When first differences are irregular, check the second differences.

1. First differences: $4,11,20,27,36$.
2. Second differences: $7,9,7,9$ → next $7$, so next first difference $=36+7=43$.
3. Next term: $103+43=146$.

Trick: Alternating $+7$, $+9$ in the gaps.

Answer: (A) 146

Concept: Compare each letter of the first cluster with the matching letter of the second.

1. LX – HT: $L-4=H$, $X-4=T$ ✓
2. QE – MA: $Q-4=M$, $E-4=A$ ✓; NV – JR: $N-4=J$, $V-4=R$ ✓
3. BK – XF: $B-4=X$ but $K-5=F$ ✗

Trick: Every pair should be the first cluster moved back by 4; one letter breaks it.

Answer: (C) BK – XF

Concept: Track each position; here every letter moves $+8$.

1. 1st: K, S, A, I, Q ($+8$, wrapping S → A).
2. 2nd: F, N, V, D, L.
3. 3rd: P, X, F, N, V.

Trick: Inside each term letters are 5 apart (K→F is $-5$, F→P is $+10$); QLV keeps that.

Answer: (C) QLV

Concept: Decode the chain and build the tree from M down to R.

1. M + N: M is father of N. N ÷ O: N is mother of O (N female).
2. O – P: O is sister of P, so N is mother of P too.
3. P × Q: P is husband of Q. Q ÷ R: Q is mother of R, so P is R's father.
4. From R: father P → his mother N → her father M. M is R's father's mother's father.

Trick: Write the path from R upward: father → mother → father.

Answer: (D) Father's mother's father

Concept: “All A are B” + “No B is C” ⇒ “No A is C”.

1. All hats are carpets → Hats circle inside Carpets.
2. No carpet is a locket → Lockets lie completely outside Carpets, hence outside Hats → (I) ‘No hat is a locket’ follows.
3. (II) ‘Some lockets are carpets’ directly contradicts ‘No carpet is a locket’ → does not follow.

Trick: All + No ⇒ No (in the same order of terms).

Answer: (B) Only conclusion (I) follows

Concept: Total $=$ rank from top $+$ rank from bottom $-1$ (the person is counted twice).

1. Rank from top $=28$, from bottom $=65$.
2. Total $=28+65-1$
3. $=92$ students.

Trick: Never forget the $-1$; $93$ is the trap option.

Answer: (C) 92

Concept: 2025 World Aquatics Championships were held in Singapore (July–August 2025).

1. Kate Douglass (USA) won the women's 200 m breaststroke in 2:18.50 — a championship record and a new American record.
2. Evgeniia Chikunova took silver; Torri Huske and Claire Curzan are US swimmers known for butterfly/backstroke events.

Yaad rakhein: Kate Douglass — Paris 2024 Olympic champion in 200 m breaststroke too.

Answer: (D) Kate Douglass

Concept: Article 240 lets the President make regulations for peace, progress and good government of certain Union Territories.

1. It covers Andaman & Nicobar Islands, Lakshadweep, Dadra & Nagar Haveli and Daman & Diu (and Ladakh).
2. Puducherry has a legislature, so this power applies to it only when its Assembly is dissolved or suspended; Delhi and J&K have Assemblies.

Yaad rakhein: Article 240 = President's regulations for UTs without legislatures (island UTs and DNH&DD).

Answer: (C) Andaman & Nicobar Islands, Lakshadweep, Dadra & Nagar Haveli and Daman & Diu

Concept: Section 4 of the Citizenship Act, 1955 deals with citizenship by descent.

1. A child born outside India to an Indian citizen parent gets citizenship by descent if the birth is registered at an Indian consulate within one year of birth.
2. Registration after one year needs special permission of the Central Government.

Yaad rakhein: Descent = birth abroad + registration at consulate within 1 year.

Answer: (B) One year

Concept: Sleep mode keeps the current session in RAM at very low power.

1. Work resumes within seconds when a key is pressed — no reboot needed.
2. Shutdown closes everything and needs a full boot; reinstalling OS or formatting disk erases data.

Yaad rakhein: Sleep → RAM (fast resume); Hibernate → hard disk (no power used).

Answer: (B) Sleep mode

Concept: Baba Ramchandra led the Awadh peasant movement (1920–21) in Pratapgarh–Rae Bareli region of UP.

1. Peasants protested against high rents, illegal cesses (nazrana) and begar imposed by taluqdars and landlords.
2. The Awadh Kisan Sabha was formed in 1920 with Jawaharlal Nehru's support.

Yaad rakhein: Baba Ramchandra = Awadh Kisan Sabha = against taluqdars.

Answer: (C) A rural uprising against exploitative landlords