Q&A: practice questions with answers

Concept: Letters common to both words take the digits common to both codes.

1. JACK = 9621, CALK = 6231.
2. Common letters A, C, K ↔ common digits 6, 2, 1.
3. Remaining: J ↔ 9 (in JACK) and L ↔ 3 (in CALK). So L = 3.

Trick: Eliminate common letters and common digits – the leftover pair is the answer.

Answer: (B) 3

Concept: Look for three consecutive odd digits; the middle one is counted.

1. Scan the series for odd–odd–odd runs.
2. Found: 1 1 9, 9 7 1, 7 1 3, 1 5 3.
3. Total $=4$.

Trick: Mark every even digit as a barrier; only blocks of three or more odd digits give answers.

Answer: (B) Four

Concept: Check the differences between consecutive terms.

1. Differences: $-55,-50,-45,-40,-35$.
2. Next difference $=-30$: $55-30=25$.

Trick: Differences decrease by 5 each time.

Answer: (D) 25

Concept: Draw the least possible Venn diagram for the statements.

1. All jars are boxes → Jars circle lies inside Boxes.
2. Some bottles are jars → those bottles are also boxes, so “Some boxes are bottles” is definitely true – (I) follows.
3. Boxes may contain things that are not jars, so “All boxes are jars” is not certain – (II) does not follow.

Trick: “All A are B” cannot be reversed to “All B are A”.

Answer: (B) Only conclusion (I) follows

Concept: Number seats 1 to 7 from left (all face north) and place definite clues first.

1. Only Q to the left of H → Q = 1, H = 2.
2. Four people between Q and G → G = 6.
3. Only F between L and M needs three consecutive free seats → 3, 4, 5 with F = 4. L is not next to G (6) → L = 3, M = 5.
4. O = 7. Between O (7) and H (2): seats 3–6 → 4 people.

Trick: “Only X to the left of Y” fixes both of them at seats 1 and 2.

Answer: (C) Four

Concept: Find the single operation that turns the first number into the second.

1. $78+10=88$ and $32+10=42$ → rule: add 10.
2. (A) $110+10=120$ ✓; (B) $45+11=56$ ✗; (C) $98-10=88$ ✗; (D) $90+20=110$ ✗.

Trick: Check the difference (second $-$ first) of each option: it must be exactly $+10$.

Answer: (A) 110 - 120

Concept: Compare letters position by position.

1. WTQT → VSPS: W→V, T→S, Q→P, T→S – each letter $-1$.
2. ZWTW → YVSV: each $-1$ ✓.
3. OLIL → N K H K → NKHK.

Trick: Same shift on every letter: just move each letter one step back.

Answer: (B) NKHK

Concept: Number positions 1 (bottom) to 6 (top) and fix definite clues.

1. Three boxes above F → F = 3.
2. One box between H and F → H = 1 or 5. Three boxes between H and I: H = 1 gives I = 5; H = 5 gives I = 1, but I must be above F. So H = 1, I = 5.
3. B immediately below I → B = 4. E below G among 2 and 6 → E = 2, G = 6.
4. Between G (6) and H (1): I, B, F, E → 4 boxes.

Trick: Gap between positions $p$ and $q$ $=|p-q|-1=6-1-1=4$.

Answer: (A) Four

Concept: Apply the rule to every digit: odd $+1$, even $-1$.

1. 7254136: 7→8, 2→1, 5→6, 4→3, 1→2, 3→4, 6→5.
2. New number: 8163245.
3. Digits 8, 1, 6, 3, 2, 4, 5 are all different – no digit repeats.

Trick: Odd $+1$ and even $-1$ just swap pairs (1↔2, 3↔4, 5↔6, 7↔8), so distinct digits stay distinct.

Answer: (A) None

Concept: Common letters of the two words share the common digits of the two codes.

1. GLOW = 3187, WOLF = 1273.
2. Common letters L, O, W ↔ common digits 1, 3, 7.
3. Left over: G ↔ 8 (GLOW) and F ↔ 2 (WOLF). So G = 8.

Trick: Cancel the common part; the unique letter takes the unique digit.

Answer: (B) 8

Concept: Track the change in each letter and the number.

1. LL 22 → JH 6: L(12)→J(10) $-2$, L(12)→H(8) $-4$, $22-16=6$.
2. CR 20 → AN 4: C→A $-2$, R(18)→N(14) $-4$, $20-16=4$ ✓.
3. GN 14: G(7)→E(5), N(14)→J(10), $14-16=-2$ → EJ $-2$.

Trick: Rule “$-2$, $-4$, $-16$”; only EJ has J for N.

Answer: (D) EJ −2

Concept: Apply the rule to each digit: odd $+3$, even $-2$.

1. 8254316: 8→6, 2→0, 5→8, 4→2, 3→6, 1→4, 6→4.
2. New number: 6082644.
3. First from left $=6$; second from right $=4$. Sum $=6+4=10$.

Trick: Only the two required digits need converting: 8→6 and 1→4.

Answer: (B) 10

Concept: When people face the centre, moving to their right means moving anticlockwise.

1. Fix Y; D is third to the right of Y: Y, _, _, D going anticlockwise.
2. Z is second to the right of X and B sits between X and C, so the order (anticlockwise) is C, B, X, _, Z.
3. The only fit: X, Y, Z consecutive (Y is the gap), giving Y, Z, A, D, C, B, X anticlockwise.
4. A is just after Z anticlockwise → A is to the immediate right of Z.

Trick: Facing centre: right = anticlockwise, left = clockwise.

Answer: (A) Immediate right

Concept: Decode each symbol and build the family tree.

1. C ? O: C is the wife of O. O : V: O is the father of V, so C is V’s mother.
2. V @ E: V is the mother of E. E + R: E is the daughter of R, so R is E’s father, i.e. V’s husband.
3. C is the mother of R’s wife (V) → C is R’s wife’s mother.

Trick: Two parents of the same child (V and R for E) are husband and wife.

Answer: (A) Wife's mother

Concept: Draw the minimum Venn diagram; a conclusion follows only if it is true in every possible case.

1. All chairs are trees → Chairs inside Trees. Some leaves are trees → Leaves overlap Trees.
2. The overlap of Leaves may lie outside Chairs, so “Some leaves are chairs” is not certain – (I) does not follow.
3. Trees may include things that are not chairs, so “All trees are chairs” does not follow – (II) fails.

Trick: Two statements linked through the “all” circle’s outer set (Trees) give no definite link between Leaves and Chairs.

Answer: (A) Neither conclusion (I) nor (II) follows

Concept: A LAN (Local Area Network) links devices within a small area such as a room, lab or building.

1. Classroom file sharing uses computers on the same LAN
2. Connecting servers across continents is a WAN (e.g., the Internet)
3. Bluetooth pairing forms a PAN, not a LAN

Yaad rakhein: PAN < LAN (building) < MAN (city) < WAN (country/world).

Answer: (B) Local computers within the same building

Concept: Indian classical music has two major streams: Hindustani (North India) and Carnatic (South India).

1. Hindustani — gharana tradition, forms like Dhrupad, Khayal
2. Carnatic — kriti-based, associated with Tyagaraja, Dikshitar, Syama Sastri
3. Western Classical and folk forms are not streams of Indian classical music

Yaad rakhein: Carnatic trinity: Tyagaraja, Muthuswami Dikshitar, Syama Sastri.

Answer: (D) Hindustani and Carnatic

Concept: Elections to local bodies are conducted by the State Election Commission (SEC).

1. Article 243K — SEC conducts Panchayat elections (73rd Amendment)
2. Article 243ZA — SEC conducts Municipal elections (74th Amendment)
3. The Election Commission of India handles Parliament, State Legislatures, President and Vice-President

Yaad rakhein: State Election Commissioner is appointed by the Governor.

Answer: (C) State Election Commissions

Concept: The monthly Periodic Labour Force Survey (PLFS) bulletin of MoSPI reports LFPR for persons aged 15 years and above.

1. As per the PLFS monthly bulletin for October 2025, overall LFPR (15+) rose to 55.4%
2. LFPR = share of population that is working or seeking work

Yaad rakhein: PLFS is conducted by NSO under MoSPI; monthly bulletins began in 2025.

Answer: (C) $55.4\%$

Concept: In MS Windows, Windows logo key + E opens File Explorer.

1. Win + D shows the desktop; Win + L locks the PC
2. Ctrl + E in many apps focuses the search/address bar or centre-aligns text (Word)

Yaad rakhein: E for Explorer — with the Windows key.

Answer: (C) Windows logo key + E