Q&A: practice questions with answers

Concept: Opposite-letter pairs: a letter at position n pairs with the letter at position 27 − n.

1. Third word of the sentence = clearer.
2. Its letters: c, l, e, a … → 4th letter is a (position 1).
3. Opposite of position 1 = 27 − 1 = 26 → z.

Trick: Remember pairs with sum 27: A–Z, B–Y, C–X … just subtract from 27.

Answer: (D) z

Concept: Compare the given address with each option piece by piece.

1. (A) spells 'Saphire' – one p missing.
2. (C) has 'Gariya' instead of 'Garia'.
3. (D) expands 'Rd.' to 'Road'.
4. (B) matches every word, digit and dot.

Trick: Scan names and abbreviations first – most changes hide in spellings, not in the PIN code here.

Answer: (B) Flat 203, Sapphire building, Garia Station Rd., Kolkata, West Bengal - 600084

Concept: The 12-letter string is one 4-letter group written three times.

1. Visible letters suggest the group s _ u _.
2. Put g, b, u, s, b in order: sgub sgub sgub.
3. Result: sgub | sgub | sgub ✓

Trick: Length 12 → try blocks of 3 or 4; the first block usually reveals the pattern.

Answer: (A) g, b, u, s, b

Concept: Track each letter position separately; each moves by a fixed jump (wrap after Z).

1. 1st letter: always T.
2. 2nd: B(2)→H(8)→N(14)→T(20) : +6 → 26 = Z.
3. 3rd: D(4)→M(13)→V(22)→E(31−26=5) : +9 → 14 = N.
4. 4th: F(6)→R(18)→D(30−26=4)→P(16) : +12 → 28−26 = 2 = B. So TZNB.

Trick: After 2nd letter is fixed as Z, only TZNC and TZNB remain; +12 on P gives B, not C.

Answer: (C) TZNB

Concept: Swap each letter for its sign, then solve using BODMAS.

1. Decode: A → +, B → ÷, C → ×, D → −.
2. Inside the bracket: $\frac{0.56}{1.4}$ is 0.4, and four times that is 1.6.
3. Middle part: 4 times 5 is 20, divided by 20 leaves 1.
4. Add up: $3.2+1.6+5=9.8$, minus 1 → 8.8.

Trick: $0.56÷1.4=56÷140=\frac{2}{5}$ – drop decimals by scaling both numbers.

Answer: (B) 8.8

Concept: In each term the middle number should equal the alphabet position of the letter.

1. C = 3 → C@3C ✓
2. E = 5 → E@5E ✓; G = 7 → G@7G ✓
3. F = 6, but written 5 → F@5F breaks the rule.

Trick: EJOTY: E5, J10, O15, T20, Y25 – F is just after E, so it is 6.

Answer: (C) F@5F

Concept: Each term is twice the previous term plus 1 (terms are $2^n-1$).

1. 3 → 7 → 15 → 31 → 63: each = 2 × previous + 1.
2. Next = $2\times 63+1=127$.

Trick: Terms are one less than powers of 2: 4, 8, 16, 32, 64, 128 → $128-1=127$.

Answer: (B) 127

Concept: An assumption is what the speaker must take for granted for the claim to make sense.

1. Claim 'EVs reduce pollution' needs EVs to be cleaner than petrol/diesel cars → I is assumed.
2. 'Significantly reduce' needs vehicles to be a big source of city pollution → II is assumed.
3. III is extreme ('does not involve any pollution'); the claim works even if power plants pollute somewhat → not assumed.

Trick: Words like 'any', 'only', 'never' in an assumption usually make it non-implicit.

Answer: (A) Only I and II are implicit

Concept: A conclusion follows only if it is a reasonable, non-contradicting inference from the statement.

1. Record rainfall can overload drains; 'might have failed' is a cautious, logical inference → I follows.
2. 'Highest in 30 years' means such rain is rare → II ('happens regularly') goes against the statement.

Trick: Soft words like 'might/may' make a conclusion easier to accept; a conclusion that contradicts the data never follows.

Answer: (A) Only Conclusion I follows

Concept: Pick the letters at the asked positions, then look for meaningful four-letter words.

1. P-L-A-N-E-T → 1st P, 3rd A, 4th N, 6th T.
2. Letters available: P, A, N, T.
3. Only one meaningful word can be formed: PANT.

Trick: With one vowel (A) fixed in the middle, try each consonant pair around it – only P_NT works.

Answer: (A) One

Concept: Each letter is replaced by its position in the alphabet; the × sign stays.

1. M = 13, O = 15 → 13 × 15 ✓
2. G = 7, I = 9.
3. So G × I → 7 × 9.

Trick: G and I are 2 apart, just like M and O – the numbers must also differ by 2; only 7 × 9 does.

Answer: (A) 7 × 9

Concept: Letters move backward from Z after the first term; numbers rise by 1.

1. Letters: A, Z, Y, X → next W (one step back).
2. Numbers: 1, 2, 3, 4 → next 5.
3. Term = W5.

Trick: A then Z = wrap-around: think of the alphabet as a circle running backward.

Answer: (A) W5

Concept: Group the articles by the Part of the Constitution they belong to.

1. Art. 15 (no discrimination), 16 (equal opportunity in public jobs), 18 (abolition of titles) – all Right to Equality, Part III.
2. Art. 352 – proclamation of National Emergency, Part XVIII.
3. So Article 352 is the odd one.

Yaad rakhein: Right to Equality = Articles 14–18; Emergency provisions = Articles 352–360.

Answer: (D) Article 352

Concept: Place each person in a generation and connect them.

1. R and S are husband–wife; Q is their son.
2. P is Q's daughter → one generation below Q.
3. S is the mother of P's father → paternal grandmother.

Trick: Count generations: S is two levels above P and female → grandmother.

Answer: (C) Grandmother

Concept: Find the hidden rule that turns a + b into the given result.

1. 4 + 5: 4×5 = 20, 4+5 = 9 → 29 ✓
2. 3 + 6: 18 + 9 = 27 ✓
3. 1 + 6: 6 + 7 = 13.

Trick: $ab+a+b=(a+1)(b+1)-1\to (2)(7)-1=13$.

Answer: (B) 13

Concept: Each letter has one fixed digit; read the digits from the given words in order.

1. Match letter by position in the first word: E = 1, F = 5, Q = 3, T = 8.
2. From the second word: M = 6, P = 2, D = 9.
3. Reading T-D-P-P-Q with these digits gives 89223.

Trick: TDPPQ ends in Q = 3 and has a repeated P (22) – only 89223 fits both.

Answer: (C) 89223

Concept: The result is the sum of the squares of the two numbers.

1. 5 ∗ 3: squares are 25 and 9, total 34 ✓
2. 6 ∗ 4: squares are 36 and 16, total 52 ✓
3. 7 ∗ 2: squares are 49 and 4, total 53.

Trick: Results 34 and 52 are not products/sums – near-square numbers hint at $a^2+b^2$.

Answer: (C) 53

Concept: Same letters, same codes – the code only reorders with the word.

1. Pair READ with T2#3 letter by letter: D = 3, A = #, R = T, E = 2.
2. DEAR gives 32#T with the same pairs – rule confirmed.
3. DARE is simply D, A, R, E in that order → 3#T2.

Trick: DARE starts with D (3) – only option (A) begins with 3.

Answer: (A) 3#T2

Concept: For numbers in equal steps, average = middle term.

1. Numbers: 11, 13, 15, 17, 19.
2. Middle (3rd) term = 15.
3. Check: sum $75÷5=15$.

Trick: Average = first $+(n-1)=11+4=15$ for consecutive odd numbers.

Answer: (B) 15

Concept: Replace every symbol as told, then apply BODMAS.

1. 30 × 5 ÷ 32 + 16 − 2 → 30 − 5 + 32 ÷ 16 × 2.
2. 32 ÷ 16 = 2; 2 × 2 = 4.
3. 30 − 5 + 4 = 29.

Trick: Rewrite the whole line first – changing signs mid-calculation causes most errors.

Answer: (C) 29