Q&A: practice questions with answers

Concept: Compare every part of the address piece by piece; even one changed digit makes it different.

1. Original: Flat 31A, PIN 411038.
2. (A) PIN reads 411048 – mismatch.
3. (B) PIN starts with 5 – mismatch; (C) flat is 31B – mismatch.
4. (D) has 31A and 411038 – identical.

Trick: Check the most "error-prone" parts first – numbers (flat no., PIN). Text is rarely changed.

Answer: (D) Flat No. 31A, Maple Residency, Thane, Maharashtra - 411038

Concept: Days after = later date − earlier date (same month).

1. Lucknow → 12 Feb.
2. Vadodara → 16 Feb.
3. Gap = 16 − 12 = 4 days.

Trick: Ignore the other six cities – pick only the two dates asked and subtract.

Answer: (A) 4 days

Concept: A conclusion follows only if it is a reasonable, direct result of the statement.

1. Skill training makes youth more employable → I (more job opportunities) is a natural outcome – follows.
2. II uses "immediately" and "drastically" – training needs time; such a sharp claim is unsupported – does not follow.

Trick: Words like immediately, drastically, only, always in a conclusion usually make it invalid.

Answer: (A) Only I follows

Concept: Find the hidden rule from the given examples, then apply it.

1. $8-3=5$, and $5\times 3=15$ ✓
2. $9-2=7$, and $7\times 3=21$ ✓
3. $7-3=4\to 4\times 3=12$

Trick: All answers are multiples of 3 → think "×3" at once.

Answer: (B) 12

Concept: Constant ratio series: each term = previous × 1.5 (i.e. $\times \frac{3}{2}$).

1. $\frac{6}{4}=1.5$, $\frac{9}{6}=1.5$, $\frac{13.5}{9}=1.5$
2. Missing = $13.5\times 1.5=20.25$
3. Check: $20.25\times 1.5=30.375$ ✓

Trick: If a series has decimals like .5, .25, .375 – test the ratio $\frac{3}{2}$ first.

Answer: (C) 20.25

Concept: Each input is mapped to twice its value.

1. 6 → 12, 5 → 10, 4 → 8: output = 2 × input.
2. 12 → $12\times 2=24$

Trick: Output ÷ input is the same (2) every time – a one-glance check.

Answer: (C) 24

Concept: Word value = sum of alphabet positions (A=1 … Z=26).

1. T(20), R(18), A(1), I(9), N(14) → total 62 ✓
2. P(16), A(1), N(14), T(20) → total 51 ✓
3. C(3), A(1), T(20) → total 24

Trick: Remember EJOTY = 5, 10, 15, 20, 25 to get positions fast (T = 20).

Answer: (B) 24

Concept: Join the statements through common letters; the chain gives a definite relation only if the signs do not oppose.

1. I: U > S > K = L → U > L, true.
2. II: K > N = Q ≥ T → K > T, so K ≥ T is also true.
3. Both are true, so none is false.

Trick: If the chain gives ">", then a conclusion with "≥" is still true (">" is part of "≥").

Answer: (D) Neither conclusion I nor II is false

Concept: Find the common property shared by three options.

1. Lucknow – capital of Uttar Pradesh; Jaipur – Rajasthan; Patna – Bihar.
2. Pune is a big city of Maharashtra, but the capital is Mumbai.

Yaad rakhein: Pune was the seat of the Peshwas and is called the "Oxford of the East".

Answer: (C) Pune

Concept: Find a rule linking the three numbers, then test each option.

1. Given: $87-65=22=2\times 11$ ✓
2. $49-35=14=2\times 7$ ✓; $58-42=16=2\times 8$ ✓; $83-55=28=2\times 14$ ✓
3. $40-28=12$, but $2\times 5=10$ ✗

Trick: Third − second should be an even number (2 × first). $40-28=12\ne 10$ – spot it in seconds.

Answer: (C) (5, 28, 40)

Concept: Siblings have the same father.

1. P is Q's sister → P and Q are siblings.
2. R is P's father → R is Q's father too.

Trick: Q's gender is unknown, but "father" does not depend on it.

Answer: (B) Father

Concept: In SI, interest grows equally each year; amount n times → interest = $(n-1)\times P$.

1. Triples: interest = 2P in 15 years → P in 7.5 years.
2. 9 times: interest = 8P.
3. Time = $8\times 7.5=60$ years.

Trick: ${\text{Time}}_2={\text{Time}}_1\times \frac{n_2-1}{n_1-1}=15\times \frac{8}{2}=60$.

Answer: (A) 60

Concept: 215 is just below $216=6^3$, so the rule is $n^3-1$.

1. $6^3=216\to 216-1=215$ ✓
2. $8^3=512\to 512-1=511$

Trick: Know cubes up to 15: numbers like 215, 511, 999 shout "cube − 1".

Answer: (A) 511

Concept: Fix the sure positions first, then fill the rest.

1. Equal boxes above and below brown → brown at 4.
2. Teal above brown, below violet; violet not top → teal 5, violet 6.
3. Blue just below cyan, neither at ends → blue 2, cyan 3; yellow not bottom → yellow 7, maroon 1 (two boxes between maroon and brown ✓).
4. Maroon 1, Teal 5, Yellow 7 are odd positions; Brown 4 is even.

Trick: "Equal above and below" in 7 boxes always means the middle box, 4.

Answer: (B) Brown

Concept: An assumption is the unstated belief behind a decision.

1. Police add patrols only if they believe patrolling will curb rash driving → I implicit.
2. That belief works only if drivers behave better on seeing police → II implicit.

Trick: Ask "Why would they do this?" – every honest answer is an implicit assumption.

Answer: (C) Both I and II are implicit

Concept: Each term is one-fifth of the previous term.

1. 625 → 125 → 25 → 5 (÷5 each time).
2. Next = $5÷5=1$

Yaad rakhein: $625=5^4$, $125=5^3$, $25=5^2$, $5=5^1$ → next $5^0=1$.

Answer: (B) 1

Concept: Each letter moves 4 places forward.

1. E5 → I9 → M13 → Q17 → U21
2. 21 + 4 = 25 → Y

Trick: Use EJOTY: Y = 25 directly.

Answer: (B) Y

Concept: Each pair is two consecutive letters, and the pair shifts by one.

1. CD, DE, EF, FG, GH – first letter C, D, E, F, G.
2. Next first letter H → pair HI.

Trick: Second letter of a pair = first letter of the next pair.

Answer: (C) HI

Concept: Every letter is replaced by the next letter.

1. SWEET → TXFFU (each +1).
2. LIGHT: L→M, I→J, G→H, H→I, T→U
3. Code = MJHIU

Trick: Check only the 3rd–4th letters: G→H, H→I must give "HI" – only (B) has it.

Answer: (B) MJHIU

Concept: Make each swap, then solve using BODMAS.

1. Swap + ↔ × and 5 ↔ 9: $9\times 3+5$ becomes $5+3\times 9$.
2. $3\times 9=27$; $5+27=32$ ✓

Trick: Since + and × swap in every option, first write $9+3\times 5$ form and just try the number swaps.

Answer: (C) + and ×, 5 and 9