Q&A: practice questions with answers

Concept: An exact copy must agree in every part – plot, sector, locality, city, state and PIN.

1. Check part by part against the given address.
2. (A) shows Haryana in place of Delhi; (C) shows Gurugram in place of New Delhi; (D) shows Sector 16 in place of Sector 15.
3. (B) agrees in every part.

Trick: Compare numbers first (plot, sector, PIN) – they knock out options fastest; then compare place names.

Answer: (B) Plot No. 18, Sector 15, Dwarka, New Delhi, Delhi - 110078

Concept: Note only the dates of the four asked cities and sort them in ascending order.

1. Bilaspur – 10, Patna – 11, Bokaro – 12, Karimnagar – 15 April.
2. Ascending order of dates: 10 < 11 < 12 < 15.
3. Sequence: Bilaspur, Patna, Bokaro, Karimnagar.

Trick: Find only the earliest city (Bilaspur, 10th) and the second one (Patna, 11th) – only one option starts 'Bilaspur, Patna'.

Answer: (B) Bilaspur, Patna, Bokaro, Karimnagar

Concept: Each term = previous × 3 + a number that increases by 1 (2, 3, 4, …).

1. $62=(20\times 3)+2$, $189=(62\times 3)+3$, $571=(189\times 3)+4$.
2. Next addend is 5: $(571\times 3)+5=1718$.
3. Last-term check: $(1718\times 3)+6=5160$ ✓

Trick: Terms grow about 3 times each step, so the blank ≈ $571\times 3\approx 1713$+ – only 1718 / 1726 fit; the last-term check picks 1718.

Answer: (A) 1718

Concept: The terms form an arithmetic progression with common difference 11.

1. 35 − 24 = 11, 46 − 35 = 11, 57 − 46 = 11, 68 − 57 = 11.
2. Next term = 68 + 11 = 79.

Trick: Adding 11 to a two-digit number raises both digits by 1 (68 → 79) when there is no carry.

Answer: (C) 79

Concept: If a number leaves the same remainder r with several divisors, it is $(\text{LCM}\times k)+r$.

1. LCM of 4, 6, 8 = 24.
2. Smallest such number = $24+5=29$.
3. Check: $29÷4$, $29÷6$, $29÷8$ all leave 5.

Trick: Test the smallest option: $27-5=22$ is not divisible by 4; $29-5=24$ is divisible by 4, 6 and 8.

Answer: (B) 29

Concept: Each number is multiplied by its next consecutive number.

1. $6\times 7=42$ ✓, $7\times 8=56$ ✓
2. $8\times 9=72$.

Trick: $n(n+1)=n^2+n$: $8^2+8=64+8=72$. Note 64 (only $n^2$) is a trap option.

Answer: (B) 72

Concept: Put the given values into the defined rule $x\%y=x+y+xy$.

1. $x=4$, $y=5$.
2. $4+5+4\times 5=9+20=29$.

Trick: $x+y+xy=(x+1)(y+1)-1=5\times 6-1=29$.

Answer: (A) 29

Concept: Group the items by what they are used for.

1. Google Chrome, Microsoft Edge and Mozilla Firefox are web browsers (used to open websites).
2. VLC Media Player plays audio/video files – it is not a browser.

Yaad rakhein: Other browsers you may see as options: Safari, Opera, Brave; VLC is open-source software by VideoLAN.

Answer: (B) VLC Media Player

Concept: A word common to two sentences gets the code common to both.

1. Sentences 1 & 2: common word cool, common code at → cool = at.
2. Sentences 2 & 3: common word car, common code kt → car = kt; so in sentence 3, brick/clear = ct/ot. Sentences 1 & 3 share brick and ct → brick = ct, clear = ot.
3. Sentence 1 left: start, sugar = bt, mt.
4. start clear sugar = bt, ot, mt (order may vary).

Trick: The answer must contain ot (clear) and must not contain at, ct or kt – only (B) qualifies.

Answer: (B) bt, ot, mt

Concept: x% of N = $N\times \frac{x}{100}$.

1. 30% of 680 = $680\times \frac{3}{10}=204$.
2. 25% of 840 = $840÷4=210$.
3. Sum = $204+210=414$.

Trick: $25\%=\frac{1}{4}$, so just divide by 4; $30\%=3\times 10\%$: $3\times 68=204$.

Answer: (D) 414

Concept: Both pairs are perfect squares whose bases differ by 2.

1. $324={18}^2$, $400={20}^2$ (base +2).
2. $196={14}^2\to {16}^2=256$.

Trick: Squares ending in 6 come from bases ending in 4 or 6: 196 (14), 256 (16).

Answer: (A) 256

Concept: A palindrome reads the same from left and from right.

1. 789987 → reverse 789987 ✓
2. 98765 → reverse 56789 ✗
3. 5005 ✓ and 4321234 ✓
4. Total palindromes = 3.

Trick: Just compare the first and last digit: 98765 starts with 9 but ends with 5 – rejected instantly.

Answer: (C) 3

Concept: All A are B + All B are C ⇒ All A are C; also 'All B are C' gives 'Some C are B'.

1. Fruits ⊂ Nutritious ⊂ Healthy ⇒ all fruits are healthy – I follows.
2. 'All nutritious are healthy' converts to 'Some healthy are nutritious' – II follows.

Trick: An 'All' statement can always be converted into 'Some' with the terms swapped.

Answer: (C) Both I and II follow

Concept: Some A are B + No B is C ⇒ Some A are not C.

1. Some hardworking are successful; no successful is lazy ⇒ those hardworking are not lazy – I follows.
2. Students are inside hardworking, but they may lie outside the successful part, so they may all be lazy – II does not follow.

Trick: Some + No = Some Not (in the same order). Students are not linked to 'successful', so nothing definite about them.

Answer: (A) Only I follows

Concept: Use alphabet positions; the backward gap increases by 1 each step.

1. W = 23, S = 19, N = 14, H = 8.
2. Gaps: −4, −5, −6 → next gap −7.
3. 8 − 7 = 1 = A.

Trick: Remember EJOTY = 5, 10, 15, 20, 25 to get positions fast (S = 19, N = 14).

Answer: (A) A

Concept: Each term should be 3 times the previous term.

1. 2 → 6 → 18 → 54 ✓
2. $54\times 3=162$, but the series shows 172 ✗
3. $162\times 3=486$ ✓, so 172 is the wrong number.

Trick: In a ×3 series every term after 2 is even and divisible by 3; $1+7+2=10$ is not divisible by 3, so 172 fails.

Answer: (D) 172

Concept: Rearrange the 11 letters into a real word, then count the letter's place.

1. Letters N I F O R T M I O N A → INFORMATION.
2. I(1) N(2) F(3) … ⇒ F is 3rd from the left.

Trick: Letters like -TION (T, I, O, N) usually go at the end; the rest forms the stem INFORMA.

Answer: (A) 3

Concept: Each term is the sum of the two terms just before it.

1. 5 = 2 + 3; 8 = 3 + 5; 13 = 5 + 8.
2. Next = 8 + 13 = 21.

Trick: If the differences (1, 2, 3, 5) repeat the series itself, it is Fibonacci-type.

Answer: (C) 21

Concept: Every letter is shifted two places backward (Z comes before A cyclically).

1. O→M, B→Z, A→Y, M→K, A→Y ✓
2. LINCOLN: L→J, I→G, N→L, C→A, O→M, L→J, N→L.
3. Code = JGLAMJL.

Trick: LINCOLN has L at positions 1 and 6 and N at 3 and 7 – the code must repeat letters at the same places (J…J, L…L); only (A) and (B) do, and O−2 = M picks (A).

Answer: (A) JGLAMJL

Concept: Treat the first and second letters as two separate series.

1. First letters L, M, N (+1) → O.
2. Second letters I, H, G (−1) → F.
3. Next pair = OF.

Trick: The two letters move in opposite directions, so their positions always add to the same total: L+I = 12+9 = 21, O+F = 15+6 = 21 ✓

Answer: (C) OF