- A5, 15, 25
- B5, 20, 25
- C5, 15, 30
- D5, 20, 30
Show answer
Concept: Each letter's code = its alphabet position multiplied by 5 ().
- Positions: A = 1, C = 3, E = 5.
- Multiply each by 5: , , .
- Code for ACE = 5, 15, 25.
Trick: A, C, E are odd positions 1, 3, 5, so the codes must jump by 10 each time (5, 15, 25). Only option (A) does this.
Answer: (A) 5, 15, 25
अवधारणा: हर अक्षर का कोड = वर्णमाला में उसका स्थान × 5 ()।
- स्थान: A = 1, C = 3, E = 5।
- 5 से गुणा: 5, 15, 25।
- ACE का कोड = 5, 15, 25।
ट्रिक: A, C, E में हर बार 2 अक्षर का अंतर है, तो कोड में हर बार 10 बढ़ेगा: 5, 15, 25।
उत्तर: (A) 5, 15, 25
