Question bank

Q&A: practice questions with answers

Search questions on any topic. Filter by exam category, exam, subject and topic, try the question, then open the answer and explanation.

Free mock tests Download App

4,800 questions found.

Q1161.

X's salary is 50% more than Y's. If Y's salary increases by 30% and X's increases by p%, then X's new salary becomes 20% more than Y's new salary. What is the value of p?

X का वेतन Y से 50% अधिक है। यदि Y का वेतन 30% बढ़े और X का p% बढ़े, तो X का नया वेतन Y के नए वेतन से 20% अधिक हो जाता है। p का मान क्या है?

Show answer

Concept: Assume Y = 100 and follow each change.

$Y = 100$ → $X = 150$ .
New Y = 130; new X = $130 \times 1.2 = 156$ .
Increase in X = $156 - 150 = 6$ on 150 → $p = \frac{6}{150} \times 100 = 4 %$ .

Trick: Use multipliers: $1.5 \times (1 + \frac{p}{100}) = 1.3 \times 1.2 = 1.56$ → $1 + \frac{p}{100} = 1.04$ .

Answer: (B) 4%

अवधारणा: Y = 100 मानकर हर बदलाव लगाएँ।

$Y = 100$ → $X = 150$ ।
नया Y = 130; नया X = $130 \times 1.2 = 156$ ।
X में वृद्धि = 6, 150 पर → $p = 4 %$ ।

ट्रिक: गुणक: $1.5 \times (1 + \frac{p}{100}) = 1.3 \times 1.2 = 1.56$ → $1 + \frac{p}{100} = 1.04$ ।

उत्तर: (B) 4%

SSC CGLQuantitative AptitudeSalary comparison – successive %SSC CGL 2025 · 23 Sep Shift 1 →

Q1162.

The average of a certain number of quantities is 38. If 7 is added to each quantity, what will be the new average?

कुछ राशियों का औसत 38 है। यदि प्रत्येक राशि में 7 जोड़ दिया जाए, तो नया औसत क्या होगा?

Show answer

Concept: Adding the same k to every value raises the average by k.

Old average = 38.
New average = 38 + 7 = 45.

Trick: +k to all → average +k; ×k to all → average ×k.

Answer: (B) 45

अवधारणा: हर संख्या में k जोड़ने पर औसत भी k बढ़ता है।

पुराना औसत = 38।
नया औसत = 38 + 7 = 45।

ट्रिक: सबमें +k → औसत +k; सबमें ×k → औसत ×k।

उत्तर: (B) 45

SSC CGLQuantitative AptitudeAverage – constant addedSSC CGL 2025 · 23 Sep Shift 1 →

Q1163.

A triangular prism has a base of area 56 cm² and height 15 cm. If 20% of the prism is hollowed out for wiring, what is the volume of the solid part?

एक त्रिभुजाकार प्रिज़्म का आधार क्षेत्रफल 56 cm² और ऊँचाई 15 cm है। यदि वायरिंग हेतु प्रिज़्म का 20% भाग खोखला कर दिया जाए, तो ठोस भाग का आयतन क्या है?

A672 cm³
B680 cm³
C690 cm³
D700 cm³

Show answer

Concept: Prism volume = base area × height.

Volume = $56 \times 15 = 840$ cm³.
Solid part = $100 % - 20 % = 80 %$ .
$840 \times 0.8 = 672$ cm³.

Trick: $80 % = \frac{4}{5}$ → $840 \div 5 \times 4 = 168 \times 4 = 672$ .

Answer: (A) 672 cm³

अवधारणा: प्रिज़्म का आयतन = आधार क्षेत्रफल × ऊँचाई।

आयतन = $56 \times 15 = 840$ cm³।
ठोस भाग = 80%।
$840 \times 0.8 = 672$ cm³।

ट्रिक: $80 % = \frac{4}{5}$ → $840 \div 5 \times 4 = 672$ ।

उत्तर: (A) 672 cm³

SSC CGLQuantitative AptitudePrism volume – hollow partSSC CGL 2025 · 23 Sep Shift 1 →

Q1164.

A group of 6 friends went to a cafe. If 5 of them paid ₹250 each and the sixth paid ₹x, the average bill per person came out to be ₹270. What is the value of x?

6 मित्र एक कैफ़े गए। यदि उनमें से 5 ने ₹250 प्रत्येक दिए और छठे ने ₹x दिए, तथा प्रति व्यक्ति औसत बिल ₹270 रहा, तो x का मान क्या है?

A₹350
B₹370
C₹360
D₹380

Show answer

Concept: Total = average × count.

Bill for 6 people = $270 \times 6 =$ ₹1,620.
Paid by the five = $250 \times 5 =$ ₹1,250.
Sixth friend's share = ₹1,620 − ₹1,250 = ₹370.

Trick: Each of 5 is ₹20 below average (−100 total), so x = $270 + 100 =$ ₹370.

Answer: (B) ₹370

अवधारणा: कुल = औसत × संख्या।

6 लोगों का कुल बिल = $270 \times 6 =$ ₹1,620।
पाँचों का भुगतान = $250 \times 5 =$ ₹1,250।
छठे का हिस्सा = ₹1,620 − ₹1,250 = ₹370।

ट्रिक: पाँचों औसत से ₹20 कम (कुल −100), तो x = $270 + 100 =$ ₹370।

उत्तर: (B) ₹370

SSC CGLQuantitative AptitudeAverage – missing valueSSC CGL 2025 · 23 Sep Shift 1 →

Q1165.

A seller offers a 30% discount on an item whose cost price is ₹800. Despite the discount, the seller earns a profit of 25%. What must be the marked price?

एक विक्रेता ₹800 क्रय मूल्य वाली वस्तु पर 30% छूट देता है। छूट के बावजूद उसे 25% लाभ होता है। अंकित मूल्य क्या होना चाहिए?

A₹1,420
B₹1,430
C₹1,440
D₹1,450

Show answer

Concept: $MP \times (100 - d) % = CP \times (100 + p) %$ .

SP = $800 \times 1.25 =$ ₹1,000.
SP = 70% of MP → MP = $1000 \div 0.7 \approx$ ₹1,428.6.
Nearest option ≈ ₹1,430.

Trick: $\frac{MP}{CP} = \frac{100 + p}{100 - d} = \frac{125}{70}$ → $800 \times \frac{125}{70} \approx 1, 428.6$ .

Answer: (B) ₹1,430

अवधारणा: MP × (100 − छूट)% = CP × (100 + लाभ)%।

SP = $800 \times 1.25 =$ ₹1,000।
SP = MP का 70% → MP = $1000 \div 0.7 \approx$ ₹1,428.6।
निकटतम विकल्प ≈ ₹1,430।

ट्रिक: $\frac{MP}{CP} = \frac{125}{70}$ → $800 \times \frac{125}{70} \approx 1, 428.6$ ।

उत्तर: (B) ₹1,430

SSC CGLQuantitative AptitudeMarked price from CP, profit and discountSSC CGL 2025 · 23 Sep Shift 1 →

Q1166.

If sinA = 0.8, what is the value of tanA?

यदि sinA = 0.8 है, तो tanA का मान क्या है?

A1.50
B1.33
C1.25
D2.56

Show answer

Concept: Use the 3-4-5 right triangle.

$\sin A = 0.8 = \frac{4}{5}$ → perpendicular 4, hypotenuse 5.
Base = $\sqrt{25 - 16} = 3$ .
$\tan A = \frac{4}{3} \approx 1.33$ .

Trick: 0.8 / 0.6 / 0.75 are the 3-4-5 ratios — memorise them.

Answer: (B) 1.33

अवधारणा: 3-4-5 समकोण त्रिभुज का प्रयोग करें।

$\sin A = 0.8 = \frac{4}{5}$ → लंब 4, कर्ण 5।
आधार = $\sqrt{25 - 16} = 3$ ।
$\tan A = \frac{4}{3} \approx 1.33$ ।

ट्रिक: 0.8, 0.6, 0.75 — ये 3-4-5 के अनुपात हैं, याद रखें।

उत्तर: (B) 1.33

SSC CGLQuantitative AptitudeTrigonometry – tan from sinSSC CGL 2025 · 23 Sep Shift 1 →

Q1167.

If cosecA + cotA = r, then what is cosecA in terms of r?

यदि cosecA + cotA = r है, तो cosecA का मान r के पदों में क्या होगा?

A $\frac{r ² + 2}{2 r}$
B $\frac{r ² - 1}{2 r}$
C $\frac{r ² + 1}{2 r}$
D $\frac{2 r ² + 1}{r}$

Show answer

Concept: $\csc^{2} A - \cot^{2} A = 1 \Rightarrow (\csc A + \cot A) (\csc A - \cot A) = 1$ .

$\csc A + \cot A = r$ → $\csc A - \cot A = \frac{1}{r}$ .
Add: $2 \csc A = r + \frac{1}{r} = \frac{r^{2} + 1}{r}$ .
$\csc A = \frac{r^{2} + 1}{2 r}$ .

Trick: Put $A = 90^{\circ}$ : $\csc = 1$ , $\cot = 0$ → $r = 1$ ; only $\frac{r^{2} + 1}{2 r}$ gives 1.

Answer: (C) $\frac{r ² + 1}{2 r}$

अवधारणा: $\csc^{2} A - \cot^{2} A = 1 \Rightarrow (\csc A + \cot A) (\csc A - \cot A) = 1$ ।

$\csc A + \cot A = r$ → $\csc A - \cot A = \frac{1}{r}$ ।
जोड़ें: $2 \csc A = r + \frac{1}{r} = \frac{r^{2} + 1}{r}$ ।
$\csc A = \frac{r^{2} + 1}{2 r}$ ।

ट्रिक: $A = 90^{\circ}$ रखें: $\csc = 1$ , $\cot = 0$ → $r = 1$ ; केवल $\frac{r^{2} + 1}{2 r} = 1$ देता है।

उत्तर: (C) $\frac{r ² + 1}{2 r}$

SSC CGLQuantitative AptitudeIdentity – cosec + cotSSC CGL 2025 · 23 Sep Shift 1 →

Q1168.

A circular jogging track has a radius of 60 m. A runner covers a curved path that subtends an angle of 150° at the centre. What is the length of the arc she runs?

एक वृत्ताकार जॉगिंग ट्रैक की त्रिज्या 60 m है। एक धाविका ऐसा वक्र पथ तय करती है जो केंद्र पर 150° का कोण बनाता है। वह जो चाप दौड़ती है उसकी लंबाई क्या है?

A70π m
B120π m
C100π m
D50π m

Show answer

Concept: Arc $= 2 π r \times \frac{θ}{360^{\circ}}$ .

Arc $= 2 π \times 60 \times \frac{150}{360}$ .
$= 120 π \times \frac{5}{12} = 50 π$ m.

Trick: Shortcut in radians: arc $= r \times θ = 60 \times \frac{5 π}{6} = 50 π$ .

Answer: (D) 50π m

अवधारणा: चाप $= 2 π r \times \frac{θ}{360^{\circ}}$ ।

चाप $= 2 π \times 60 \times \frac{150}{360}$ ।
$= 120 π \times \frac{5}{12} = 50 π$ m।

ट्रिक: रेडियन में: चाप $= r \times θ = 60 \times \frac{5 π}{6} = 50 π$ ।

उत्तर: (D) 50π m

SSC CGLQuantitative AptitudeArc lengthSSC CGL 2025 · 23 Sep Shift 1 →

Q1169.

Which of the following is true for all acute angles A?

निम्न में से कौन-सा संबंध सभी न्यून कोणों A के लिए सत्य है?

Atan(90° − A) = sinA
Bcos(90° − A) = sinA
Csin(90° − A) = tanA
Dcot(90° − A) = cosA

Show answer

Concept: For 90° − A, each ratio changes to its co-ratio: sin↔cos, tan↔cot, sec↔cosec.

cos(90° − A) = sin A ✓
sin(90° − A) = cos A, tan(90° − A) = cot A, cot(90° − A) = tan A — so (A), (C), (D) are wrong.

Trick: A ratio and its 'co'-partner always pair up — check that one side has 'co' and the other doesn't.

Answer: (B) cos(90° − A) = sinA

अवधारणा: 90° − A पर हर अनुपात अपने सह-अनुपात में बदलता है: sin↔cos, tan↔cot, sec↔cosec।

cos(90° − A) = sin A ✓
sin(90° − A) = cos A, tan(90° − A) = cot A, cot(90° − A) = tan A — अतः (A), (C), (D) गलत।

ट्रिक: जोड़ी में एक तरफ 'co' हो और दूसरी तरफ न हो — तभी सही।

उत्तर: (B) cos(90° − A) = sinA

SSC CGLQuantitative AptitudeComplementary angle identitiesSSC CGL 2025 · 23 Sep Shift 1 →

Q1170.

The compound interest on a certain sum for 2 years at 25% per annum is ₹625. Find the simple interest on the same sum at the same rate and period.

किसी राशि पर 25% वार्षिक दर से 2 वर्ष का चक्रवृद्धि ब्याज ₹625 है। उसी राशि पर उसी दर और अवधि का साधारण ब्याज ज्ञात कीजिए।

A₹480.25
B₹520.75
C₹555.55
D₹600.50

Show answer

Concept: For 2 years, $C I = S I + S I \times \frac{R}{200}$ , i.e. $\frac{C I}{S I} = \frac{200 + R}{200}$ .

$\frac{C I}{S I} = \frac{200 + 25}{200} = \frac{225}{200} = \frac{9}{8}$ .
SI = $625 \times \frac{8}{9} = \frac{5000}{9} \approx$ ₹555.55.

Trick: Check: $P = \frac{625}{0.5625} =$ ₹1,111.11 → SI = P × 50% = ₹555.55.

Answer: (C) ₹555.55

अवधारणा: 2 वर्ष में $\frac{C I}{S I} = \frac{200 + R}{200}$ ।

$\frac{C I}{S I} = \frac{225}{200} = \frac{9}{8}$ ।
SI = $625 \times \frac{8}{9} = \frac{5000}{9} \approx$ ₹555.55।

ट्रिक: जाँच: $P = \frac{625}{0.5625} =$ ₹1,111.11 → SI = P का 50% = ₹555.55।

उत्तर: (C) ₹555.55

SSC CGLQuantitative AptitudeCI to SI – 2 yearsSSC CGL 2025 · 23 Sep Shift 1 →

Q1171.

What is the distance between the centres of two circles having radii 7 cm and 4 cm such that exactly three common tangents exist?

7 cm और 4 cm त्रिज्या वाले दो वृत्तों के केंद्रों के बीच कितनी दूरी हो कि ठीक तीन उभयनिष्ठ स्पर्श रेखाएँ बनें?

A11 cm
B3 cm
C7 cm
D14 cm

Show answer

Concept: Exactly 3 common tangents ⇔ circles touch externally ⇔ d = r₁ + r₂.

d = 7 + 4 = 11 cm.

Trick: Tangents: d > r₁+r₂ → 4; d = r₁+r₂ → 3; between → 2; d = r₁−r₂ → 1; inside → 0.

Answer: (A) 11 cm

अवधारणा: ठीक 3 उभयनिष्ठ स्पर्श रेखाएँ ⇔ वृत्त बाहर से स्पर्श करें ⇔ d = r₁ + r₂।

d = 7 + 4 = 11 cm।

ट्रिक: स्पर्श रेखाएँ: d > r₁+r₂ → 4; d = r₁+r₂ → 3; बीच में → 2; d = r₁−r₂ → 1; अंदर → 0।

उत्तर: (A) 11 cm

SSC CGLQuantitative AptitudeCommon tangents of two circlesSSC CGL 2025 · 23 Sep Shift 1 →

Q1172.

In a circle, the angle subtended by chord AB at the centre is 100°. What is the measure of ∠ACB, where C lies on the circle?

एक वृत्त में जीवा AB केंद्र पर 100° का कोण बनाती है। यदि C वृत्त पर स्थित है, तो ∠ACB की माप क्या है?

A40°
B45°
C50°
D60°

Show answer

Concept: Angle at the centre = 2 × angle at the circumference (same arc).

∠ACB = 100° ÷ 2 = 50° (C on the major arc).

Trick: If C were on the minor arc, ∠ACB = 180° − 50° = 130° — not in options, so 50°.

Answer: (C) 50°

अवधारणा: केंद्र पर कोण = परिधि पर कोण × 2 (एक ही चाप पर)।

∠ACB = 100° ÷ 2 = 50° (C दीर्घ चाप पर)।

ट्रिक: C लघु चाप पर हो तो 180° − 50° = 130° — विकल्प में नहीं, अतः 50°।

उत्तर: (C) 50°

SSC CGLQuantitative AptitudeInscribed angle theoremSSC CGL 2025 · 23 Sep Shift 1 →

Q1173.

In a circle with centre O, two chords AB and CD cross each other at right angles at the point P. If the distance from the centre O to chord AB is 6 cm and the distance from O to chord CD is 8 cm, what is the length of OP?

केंद्र O वाले एक वृत्त में दो जीवाएँ AB और CD बिंदु P पर परस्पर समकोण पर काटती हैं। यदि केंद्र O से जीवा AB की दूरी 6 cm और O से जीवा CD की दूरी 8 cm है, तो OP की लंबाई क्या है?

A11 cm
B7 cm
C9 cm
D10 cm

Show answer

Concept: Perpendiculars from O to two perpendicular chords form a rectangle with P.

Feet of perpendiculars M (on AB) and N (on CD): $O M = 6$ , $O N = 8$ .
OMPN is a rectangle, so OP is its diagonal.
OP = $\sqrt{6^{2} + 8^{2}} = \sqrt{100} = 10$ cm.

Trick: 6-8-10 is a Pythagorean triplet (2 × 3-4-5).

Answer: (D) 10 cm

अवधारणा: O से दोनों लंबवत जीवाओं पर डाले गए लंब P के साथ आयत बनाते हैं।

लंबपाद M (AB पर) और N (CD पर): $O M = 6$ , $O N = 8$ ।
OMPN आयत है, OP उसका विकर्ण।
OP = $\sqrt{36 + 64} = 10$ cm।

ट्रिक: 6-8-10 पाइथागोरस त्रिक है (3-4-5 का दुगना)।

उत्तर: (D) 10 cm

SSC CGLQuantitative AptitudePerpendicular chords – distance OPSSC CGL 2025 · 23 Sep Shift 1 →

Q1174.

If the angle subtended by a chord at the centre is 120°, what is the angle subtended at a point on the circle in the same segment?

यदि कोई जीवा केंद्र पर 120° का कोण बनाती है, तो उसी वृत्तखंड में वृत्त पर स्थित बिंदु पर वह कितना कोण बनाएगी?

A60°
B75°
C90°
D80°

Show answer

Concept: Angle at circumference = half the angle at the centre (same segment).

Angle = 120° ÷ 2 = 60°.

Trick: Just halve the central angle.

Answer: (A) 60°

अवधारणा: परिधि पर कोण = केंद्र पर कोण का आधा (उसी खंड में)।

कोण = 120° ÷ 2 = 60°।

ट्रिक: केंद्रीय कोण को बस आधा करें।

उत्तर: (A) 60°

SSC CGLQuantitative AptitudeAngle at centre vs circumferenceSSC CGL 2025 · 23 Sep Shift 1 →

Q1175.

In a triangle PQR the sides are p, q and r, and the area of the triangle is T. What is the radius of the inscribed circle (inradius)?

त्रिभुज PQR की भुजाएँ p, q और r हैं तथा उसका क्षेत्रफल T है। अंतःवृत्त की त्रिज्या (अंतःत्रिज्या) क्या होगी?

A $\frac{T}{p + q + r}$
B $\frac{2 T}{p + q + r}$
C $\frac{p + q + r}{2 T}$
D $\frac{T}{2 (p + q + r)}$

Show answer

Concept: Area = inradius × semi-perimeter ( $T = r \times s$ ).

$s = \frac{p + q + r}{2}$ .
Inradius = $\frac{T}{s} = T \div \frac{p + q + r}{2} = \frac{2 T}{p + q + r}$ .

Trick: Check with an equilateral side 2: $T = \sqrt{3}$ , $r = \frac{\sqrt{3}}{3} = \frac{2 \sqrt{3}}{6}$ ✓.

Answer: (B) $\frac{2 T}{p + q + r}$

अवधारणा: क्षेत्रफल = अंतःत्रिज्या × अर्धपरिमाप ( $T = r \times s$ )।

$s = \frac{p + q + r}{2}$ ।
अंतःत्रिज्या = $\frac{T}{s} = \frac{2 T}{p + q + r}$ ।

ट्रिक: जाँच: भुजा 2 वाला समबाहु: $T = \sqrt{3}$ , $r = \frac{\sqrt{3}}{3} = \frac{2 \sqrt{3}}{6}$ ✓।

उत्तर: (B) $\frac{2 T}{p + q + r}$

SSC CGLQuantitative AptitudeInradius of a triangleSSC CGL 2025 · 23 Sep Shift 1 →

Q1176.

Select the most appropriate antonym of the given word.
Innocuous

AHarmless
BPernicious
CInoffensive
DInnocent

Show answer

Concept: Innocuous = causing no harm.

Its opposite is a word meaning 'harmful'.
Pernicious = very harmful, often in a slow, hidden way → antonym.
Harmless, Inoffensive, Innocent are near-synonyms, not opposites.

Trick: Three options mean the same thing as the given word — the odd one out is the antonym.

Answer: (B) Pernicious

अवधारणा: Innocuous का अर्थ है 'हानि न पहुँचाने वाला'।

इसका विलोम 'हानिकारक' अर्थ वाला शब्द होगा।
Pernicious = बहुत हानिकारक (अक्सर धीरे-धीरे) → विलोम।
Harmless, Inoffensive, Innocent समानार्थी जैसे हैं।

ट्रिक: तीन विकल्प दिए गए शब्द जैसे अर्थ के हों, तो बचा हुआ विकल्प विलोम है।

उत्तर: (B) Pernicious

SSC CGLEnglish ComprehensionAntonym – InnocuousSSC CGL 2025 · 23 Sep Shift 1 →

Q1177.

Select the correct indirect/direct form of the given sentence.
He stated that he was feeling much better that day.

AHe stated, "I had been feeling much better that day."
BHe stated, "I was feeling much better that day."
CHe stated, "He is feeling much better today."
DHe stated, "I am feeling much better today."

Show answer

Concept: Going back to direct speech, undo all the changes of reported speech.

'he' (speaker) → 'I'.
Past continuous 'was feeling' → present continuous 'am feeling'.
'that day' → 'today'. Result: He stated, "I am feeling much better today."

Trick: In direct speech the speaker refers to himself as 'I' and the time words are 'today/now' — reject any option with 'he' or 'that day'.

Answer: (D) He stated, "I am feeling much better today."

अवधारणा: प्रत्यक्ष कथन बनाते समय अप्रत्यक्ष कथन के सभी बदलाव उलट दें।

'he' (वक्ता) → 'I'।
'was feeling' → 'am feeling'।
'that day' → 'today'। सही: He stated, "I am feeling much better today."

ट्रिक: प्रत्यक्ष कथन में वक्ता स्वयं को 'I' कहता है और समय-शब्द 'today' होता है — 'he' या 'that day' वाले विकल्प हटाएँ।

उत्तर: (D) He stated, "I am feeling much better today."

SSC CGLEnglish ComprehensionNarration – indirect to directSSC CGL 2025 · 23 Sep Shift 1 →

Q1178.

Choose the correct one-word substitute for the sentence below:
A word or phrase used to avoid saying an unpleasant or offensive word.

AHyperbole
BEulogy
CEpithet
DEuphemism

Show answer

Concept: Euphemism = a soft, polite word in place of a harsh one (e.g. 'passed away' for 'died').

Hyperbole = exaggeration.
Eulogy = speech praising someone, often after death.
Epithet = a descriptive title added to a name.

Trick: 'Eu' = good (Greek): euphemism = 'speaking well' of something unpleasant.

Answer: (D) Euphemism

अवधारणा: Euphemism = कठोर शब्द की जगह प्रयुक्त नरम/शिष्ट शब्द (जैसे 'died' की जगह 'passed away')।

Hyperbole = अतिशयोक्ति।
Eulogy = प्रशंसा भाषण (प्रायः मृत्यु के बाद)।
Epithet = नाम के साथ जुड़ा विशेषण/उपाधि।

ट्रिक: 'Eu' = अच्छा (ग्रीक): euphemism = अप्रिय बात को अच्छे ढंग से कहना।

उत्तर: (D) Euphemism

SSC CGLEnglish ComprehensionOne-word substitution – EuphemismSSC CGL 2025 · 23 Sep Shift 1 →

Q1179.

Sentences of a paragraph are given below in jumbled order. Arrange the sentences in the correct order to form a meaningful and coherent paragraph.
1. Climate change poses a serious threat to global ecosystems and human livelihoods.
2. Rising temperatures have led to melting glaciers and unpredictable weather patterns.
3. These effects highlight the urgency of reducing carbon emissions worldwide.
4. International cooperation is therefore vital to mitigate its long-term impact.

A2-1-3-4
B1-2-3-4
C1-3-2-4
D3-1-2-4

Show answer

Concept: Opening statement → details → inference → conclusion.

1 introduces the topic (climate change as a threat).
2 gives its effects; 3 begins 'These effects', so it must follow 2.
4 starts with 'therefore' → conclusion. Order: 1-2-3-4.

Trick: Linkers fix the order: 'These' needs a previous sentence; 'therefore' closes.

Answer: (B) 1-2-3-4

अवधारणा: आरंभिक कथन → विवरण → निष्कर्ष की ओर।

1 विषय प्रस्तुत करता है।
2 प्रभाव बताता है; 3 'These effects' से शुरू होता है, इसलिए 2 के बाद आएगा।
4 में 'therefore' है → अंत। क्रम: 1-2-3-4।

ट्रिक: 'These' से पहले कोई वाक्य चाहिए; 'therefore' अंत में आता है।

उत्तर: (B) 1-2-3-4

SSC CGLEnglish ComprehensionPara jumble – climate changeSSC CGL 2025 · 23 Sep Shift 1 →

Q1180.

Select the most appropriate option to substitute the underline/Bold segment in the given sentence.
Each of the candidates were asked to submit his document before noon.

Awas asked
Bwere being asked
Chas asked
Dare asked

Show answer

Concept: 'Each of + plural noun' takes a singular verb.

The subject is 'Each', not 'candidates'.
Singular past passive: 'was asked'.
Correct: Each of the candidates was asked to submit his document before noon.

Trick: Each / Every / Either / Neither + of + plural → singular verb.

Answer: (A) was asked

अवधारणा: 'Each of + बहुवचन संज्ञा' के साथ एकवचन क्रिया आती है।

कर्ता 'Each' है, 'candidates' नहीं।
एकवचन भूतकाल passive: 'was asked'।
सही: Each of the candidates was asked to submit his document before noon.

ट्रिक: Each / Every / Either / Neither + of + बहुवचन → एकवचन क्रिया।

उत्तर: (A) was asked

SSC CGLEnglish ComprehensionSubject–verb agreement – EachSSC CGL 2025 · 23 Sep Shift 1 →