Q&A: practice questions with answers

Concept: The option must be traced inside the figure exactly – same size, slope and orientation (no rotation).

1. Option A: a horizontal segment of half-width followed by a V-shape.
2. The top edge of the left half + the diagonals of the right half form exactly this shape.
3. B and C need right-angle joints and D needs a slope that the figure doesn't have.

Trick: Check angles first – the figure has only diagonal and straight lines of fixed slopes.

Answer: (A) Option figure A

Concept: The last number of each row = (sum of first three) × 2.

1. Row 1: $(8+6+4)\times 2=36$ ✓
2. Row 2: $(9+8+5)\times 2=44$ ✓
3. Row 3: $(?+6+7)\times 2=32$ → $?+13=16$ → $?=3$.

Trick: Halve the last number (32 → 16) and subtract the known numbers: $16-13=3$.

Answer: (B) 3

Concept: Count each half separately, then the triangles that cross the middle line.

1. Left rectangle (one diagonal + a short line from top-middle): 4 triangles.
2. Right rectangle with both diagonals: 4 small + 4 large = 8.
3. Crossing the middle line: 1 big triangle (top-left corner, top-right corner, bottom-middle).
4. Total = 4 + 8 + 1 = 13.

Trick: A rectangle with both diagonals always gives 8 triangles – use it as a ready block.

Answer: (A) 13

Concept: 'Caps that are socks' = region common to circle and rectangle only.

1. Circle ∩ rectangle, outside the triangle → 5.
2. 7 is inside all three (caps, socks and watches), so it is not taken here.
3. Answer: 5.

Trick: Shade the two named shapes and exclude the third – read only the number left.

Answer: (B) 5

Concept: Show whole–part relations and whether the parts overlap.

1. Red and Yellow are both colours → both inside 'Colour'.
2. Nothing is red and yellow at once → the two circles are separate.
3. Diagram: one big circle with two separate small circles inside – option C.

Trick: Same pattern as Fruit, Apple, Mango – two separate circles inside one big circle.

Answer: (C) Option figure C

Concept: Compare letter by letter until the first different letter.

1. Cre-a-… (Creation, Creative, Creature) < Cre-d-… (Credit) < Cri-… (Crisis).
2. Creat-i… vs Creat-u…: i < u, so Creature is after the other two.
3. Creati-o-n vs Creati-v-e: o < v → Creation, Creative.
4. Order: 1, 2, 3, 4, 5.

Trick: Group by common prefix first (Creat-), then sort only the differing letter.

Answer: (A) 1, 2, 3, 4, 5

Concept: The four quarters are copies of one design turned by 90° each time.

1. Each quarter has 'S' in the outer corner, two small circles and a triangle near the centre.
2. For the missing top-right quarter: S at the top-right corner, triangle at the bottom-left (near centre).
3. Only option C places the elements this way.

Trick: Check the corner nearest the centre – the triangle must point there.

Answer: (C) Option figure C

Concept: Find the change from figure 1 to figure 2 and apply it to figure 3.

1. Figure 1 → 2: every element moves one quarter turn anticlockwise (bottom-left circle goes to bottom-right, top-right line goes to top-left; the shaded half of the circle turns from bottom to right).
2. Rotate figure 3 the same way: triangle goes to the upper left pointing left, the small rectangle stands upright at the lower right, and the long diagonal changes direction.
3. Option C shows exactly this.

Trick: Follow one corner element (the circle) to confirm the direction of turn before checking options.

Answer: (C) Option figure C

Concept: The same nine symbols shift positions in a fixed pattern from figure to figure.

1. Track how each symbol moves from one figure to the next.
2. Continuing the move: square, heart, 7 in the top row; X, F, T in the middle; 3, 8, O at the bottom.
3. This grid matches option A.

Trick: Follow just 2–3 symbols (e.g. heart and 7); usually that alone eliminates three options.

Answer: (A) Option figure A

Concept: Compare word and code letter by letter to find the shift.

1. K→H, B→Y, Q→N, U→R: each moves 3 back (B−3 wraps to Y).
2. RPFY → OMCV confirms −3.
3. NTIH: N→K, T→Q, I→F, H→E = KQFE.

Trick: Just check the 2nd letter: T−3 = Q → only option D has Q second.

Answer: (D) KQFE

Concept: SP at loss r% = $CP\times \frac{100-r}{100}$; SP at gain g% = $CP\times \frac{100+g}{100}$.

1. 80% of CP = ₹2000 → $CP=2000\times \frac{100}{80}=$ ₹2500.
2. Required SP = 110% of 2500 = ₹2750.

Trick: Direct ratio: new SP = $2000\times \frac{110}{80}=25\times 110=$ ₹2750.

Answer: (D) ₹2750

Concept: Profit is shared in the ratio of (capital × months).

1. P: $10000\times 12=1,20,000$.
2. Q: $12000\times 6+8000\times 6=1,20,000$.
3. R: $16000\times 6+24000\times 6=2,40,000$.
4. Ratio 1 : 1 : 2 → R = $84000\times \frac{2}{4}=$ ₹42,000.

Trick: For two 6-month halves, just add the two capitals: P 20k, Q 20k, R 40k → 1 : 1 : 2 at once.

Answer: (C) ₹42,000

Concept: Convert cosec and sec into sin and cos.

1. $\csc x·\cos x=\frac{\cos x}{\sin x}=\cot x$.
2. $\sec x·\sin x=\frac{\sin x}{\cos x}=\tan x$.
3. Sum = $\cot x+\tan x$.

Trick: Put $x={45}^{\circ }$: value = $1+1=2$; only $\cot x+\tan x$ gives 2 (option C gives $\sqrt{2}$).

Answer: (D) $\cot x+\tan x$

Concept: Equal ratio parts have equal value.

1. 5 parts = 50 shoes → 1 part = 10.
2. Socks = 3 parts = 30.

Trick: Scale the ratio: 5 → 50 is ×10, so 3 → 30.

Answer: (A) 30

Concept: Yearly compounding: full years at R%, the leftover part-year at proportional rate on the new amount.

1. Year 1: 20% → $6000\times 1.2=7200$.
2. Next 6 months: 10% of 7200 = 720 → 7920.
3. CI = $7920-6000=$ ₹1920.

Trick: Effective rate for 20% then 10%: $20+10+\frac{20\times 10}{100}=32\%$ → 32% of 6000 = 1920.

Answer: (A) ₹1920

Concept: Work year by year; the second year's interest is on the balance left.

1. Year-1 interest = 20% of 2,50,000 = 50,000.
2. Withdraws 40% of 50,000 = 20,000 → balance 2,80,000.
3. Year-2: $2,80,000\times 1.2=$ ₹3,36,000.

Trick: Keep 60% of the interest: $2,50,000+30,000=2,80,000$, then $\times 1.2$.

Answer: (C) ₹3,36,000

Concept: Numbers in ratio a : b (co-prime) = ax, bx; their LCM = abx.

1. Numbers 5x, 3x → LCM = $15x=180$ → $x=12$.
2. Numbers: 60 and 36.
3. Sum = 96.

Trick: Sum = $(5+3)\times x=8\times 12=96$ – no need to find each number.

Answer: (A) 96

Concept: Total = average × number; find the totals before and after.

1. Old total = $25\times 16=400$.
2. New total = $30\times 18=540$.
3. 5 new students: 140 → average = $\frac{140}{5}=28$.

Trick: $\text{New average}+\frac{\text{old count}\times \text{rise}}{\text{new count}}$: $18+\frac{25\times 2}{5}=18+10=28$.

Answer: (C) 28

Concept: Compute each percentage value and compare.

1. 16% of 350 = 56.
2. Others: B = 100, C = 84, D = 102.
3. Least = 56.

Trick: Option A has both the smallest % and a small base – check it first.

Answer: (A) $16\%$ of 350

Concept: Same distance both ways: total time = $\frac{d}{s_1}+\frac{d}{s_2}$.

1. $\frac{d}{7}+\frac{d}{5}=6$.
2. $\frac{5d+7d}{35}=6$ → $12d=210$.
3. $d=17.5$ km.

Trick: Average speed = $\frac{2\times 7\times 5}{12}=\frac{35}{6}$ km/h; total distance = $\frac{35}{6}\times 6=35$ → one way 17.5 km.

Answer: (C) 17.5 km