Q&A: practice questions with answers

Concept: Locate the word in the passage that means 'mixtures of metals'.

Solution:

1. Para 2: 'Low-quality plating over reactive alloys …'.
2. Alloy = metal made by mixing two or more metals; here it is the base under the gold.
3. Pure = unmixed (opposite); polished/plated describe surfaces.

Yaad rakhein: Brass (copper + zinc) and bronze (copper + tin) are common alloys.

Answer: (B) Alloy

Concept: Find the word meaning 'balanced and limited use'.

Solution:

1. Para 3: '… wear them in moderation'.
2. Moderation = avoiding excess; using within limits.
3. Frequent and daily mean the opposite (too often); avoiding = not using at all.

Yaad rakhein: Moderation ↔ excess; 'moderate' = not too much, not too little.

Answer: (B) Moderation

Concept: The main idea must sum up all paragraphs, not one detail.

Solution:

1. Para 1: benefits (rich look, low cost, safer from theft).
2. Para 2: problems (tarnish, skin reaction, layer wearing off).
3. Para 3: advice – check base metal, use with care.
4. Only C combines benefits + careful use.

Trick: Reject extreme words: 'superior' (A), 'should be avoided' (B), 'only' (D) – the passage is balanced.

Answer: (C) Plated ornaments have benefits but require careful use and quality checks.

Concept: Ordinary = common, usual, nothing special. Need a word meaning unusual.

Solution:

1. Quaint = attractively unusual or old-fashioned → opposite of ordinary.
2. Normal = synonym; Courteous = polite; Gust = a sudden rush of wind.

Trick: Eliminate the synonym (Normal) and the unrelated words – the one left is the answer.

Answer: (C) Quaint

Concept: Criticise = find fault; its opposite shows approval.

Solution:

1. Praise = express approval or admiration → antonym.
2. Censure, Obloquy (strong public blame) and Condemnation all mean disapproval → synonyms.

Trick: Three options share one meaning (blame) – the odd one out is the antonym.

Answer: (B) Praise

Concept: On exchange, each person takes the other's exact seat; Total = left rank + right rank − 1.

Solution:

1. Ravi's new seat (24th from left) = Sumit's old seat, which is 15th from right.
2. Total students = 24 + 15 − 1 = 38.
3. Sumit now sits at Ravi's old seat = 10th from left → from right = 38 − 10 + 1 = 29th.

Trick: The seat that has both a left rank and a right rank gives the total in one line.

Answer: (B) 29th

Concept: Convert both ranks to the same end, then between = difference − 1.

Solution:

1. Neha from left = 50 − 24 + 1 = 27th.
2. Arjun = 18th from left.
3. Between them = 27 − 18 − 1 = 8.

Trick: Quick check: 18 + 24 = 42 < 50, so they do not overlap → between = 50 − 42 = 8.

Answer: (C) 8

Concept: Find a rule that fits both given examples, then apply it.

Solution:

1. 56 $ 20: $(56-20)÷2=36÷2=18$ ✔
2. 74 $ 30: $(74-30)÷2=44÷2=22$ ✔
3. 63 $ 18: $(63-18)÷2=45÷2=$ 22.5

Trick: Results are much smaller than the numbers → try subtraction first; decimal options hint at ÷ 2.

Answer: (C) 22.5

Concept: Test the pattern on the given pairs.

Solution:

1. $12\times 20=240$ and $720=3\times 240$ ✔
2. $15\times 20=300$ and $900=3\times 300$ ✔
3. $6\times 25=150$ → $3\times 150=$ 450

Trick: $720÷240=3$ instantly shows the multiplier; answer must be a multiple of 3 and 150 → 450.

Answer: (B) 450

Concept: Check the gaps between terms.

Solution:

1. Gaps: 9, 11, 13 → increase by 2.
2. Next gap = 15 → $52+15$ = 67.

Trick: Terms = $n^2+3$ for n = 4, 5, 6, 7, 8 → $8^2+3=67$.

Answer: (B) 67

Concept: Check the gaps between terms.

Solution:

1. Gaps: 7, 9, 11 → increase by 2.
2. Next gap = 13 → $38+13$ = 51.

Trick: Terms = $n^2+2$ for n = 3, 4, 5, 6, 7 → $7^2+2=51$.

Answer: (D) 51

Concept: Unfold in reverse order; every unfolding mirrors the holes across that fold line.

Solution:

1. Fold 1 (left onto right) + Fold 2 (top onto bottom) leave only the bottom-right quarter.
2. That quarter has 3 square holes and 1 circle.
3. Two unfoldings → each hole appears 4 times: 12 squares and 4 circles, symmetric about both centre lines.

Trick: $\text{Holes after opening}=\text{holes punched}\times 2^{\text{number of folds}}=4\times 2^2=16$; pick the option with full left-right and top-bottom symmetry.

Answer: (D) Option D

Concept: A cut on a fold line becomes a full hole; a cut on a free edge becomes a notch copied across each fold.

Solution:

1. Fold 1 is along the main diagonal; fold 2 is a vertical fold of the triangle.
2. Cut on the folded edge → a diamond hole after opening fold 2; cut on the bottom edge → two symmetric notches.
3. Opening the diagonal fold copies this bottom pattern onto the right edge.

Trick: Diagonal fold acts like a mirror that swaps 'bottom edge' with 'right edge' – look for the option with identical patterns on these two edges.

Answer: (C) Option C

Concept: $\text{Bottom number of each column}=(\text{sum of the three numbers above}{)}^2$.

Solution:

1. Column 1: $11+5+3=19,{19}^2=361$ ✔; Column 2: $17+3+7=27,{27}^2=729$ ✔
2. Column 3: $1225={35}^2$, so $8+15+?=35$
3. $?=35-23$ = 12

Trick: When the bottom row has big numbers like 361, 729, 1225, think of perfect squares first.

Answer: (C) 12

Concept: In each figure: $(\text{top-left}\times \text{top-right})+\text{bottom-right}=\text{bottom-left}$.

Solution:

1. Figure 1: $4\times 7+2=30$ ✔; Figure 3: $3\times 5+4=19$ ✔
2. Figure 2: $4\times 5+?=22$ → $?=22-20$ = 2

Trick: Bigger number in one corner usually comes from multiplying the two smaller ones; the leftover is the missing value.

Answer: (A) 2

Concept: A rectangle with both diagonals has 8 triangles; then count triangles spanning both halves.

Solution:

1. Left half: 4 small + 4 half-rectangle triangles = 8; right half: 8.
2. Spanning triangles: top edge with apex at bottom-middle, and bottom edge with apex at top-middle = 2.
3. Total = 8 + 8 + 2 = 18.

Trick: Memorise: a rectangle/square with both diagonals = 8 triangles.

Answer: (C) 18

Concept: Triangle = bags, circle = leather, rectangle = brown. Take only regions that satisfy every condition.

Solution:

1. Statement I: inside circle, outside rectangle → only the region with 5 → 5 items, not 14 ✘.
2. Statement II: inside rectangle and triangle but outside circle → no such numbered region → 0, not 4 ✘.
3. Both statements are false.

Trick: 'Not X' means stay completely outside the X-shape – the 2 and 1 sit inside the rectangle, so they are excluded in I.

Answer: (D) Neither I nor II

Concept: Convert each clue into an inequality chain.

Solution:

1. Q is less than only P → P first, Q second.
2. R > S > T.
3. Order: P > Q > R > S > T → below R are S and T = 2.

Trick: 'Less than only X' = rank 2 directly; fill the rest below it.

Answer: (B) 2

Concept: Fix the top position first using 'second highest' and 'not maximum'.

Solution:

1. W, U > Z > X, Y. V is 2nd and U is not 1st → W must be the heaviest.
2. So W > V > U > Z > X/Y.
3. Lighter than U: Z, X, Y = 3.

Trick: With 6 people, if U is 3rd, people below U = 6 − 3 = 3.

Answer: (C) 3

Concept: Count the sides of each figure.

Solution:

1. Triangle (3 sides) → rectangle (4 sides): +1 side.
2. Third figure: house shape = pentagon (5 sides).
3. Answer must have 6 sides → hexagon.

Trick: In shape analogies, counting sides/lines is the first test to try.

Answer: (B) Option B (hexagon)