Q&A: practice questions with answers

Concept: Two moves alternate between boxes: (i) row-ends swap with middle column shifting, (ii) each row slides one place right.

1. Box 2 → Box 3 used the row-slide move; Box 3 → Box 4 used the swap move.
2. So Box 4 → ? is a row-slide: top U,★,B → B,U,★; bottom A,S,○ → ○,A,S; centre T fixed.
3. This matches option (B).

Trick: Track one symbol (e.g. B) across boxes – its path reveals the rule.

Answer: (B)

Concept: One symbol changes per step, alternately at top (from left) and bottom (from right).

1. 1→2: first top square → star; 2→3: last bottom star → square; 3→4: second top square → star.
2. Next: second bottom star → square.
3. Figure: top ★ ★ ■, bottom ★ ■ ■ – option (B).

Trick: Spot which position changed in each step; the pattern of positions predicts the next.

Answer: (B)

Concept: A = +, B = ÷, C = ×, D = −; then BODMAS.

1. $48+12÷3-5\times 2$
2. $=48+4-10=42$.

Trick: Handle ÷ and × first, then +/− left to right.

Answer: (A) 42

Concept: Substitute each option's signs and solve with BODMAS.

1. Option (B): $42+18-36÷3\times 2$.
2. $36÷3=12$, $12\times 2=24$.
3. $60-24=36$ ✔.

Trick: RHS 36 is close to $42+18=60$ → look for '+' then '−' with a 24-making tail.

Answer: (B) ,,,$+-+\times$

Concept: Number: ×2 in all; letters: first +1, second +3.

1. ES→FV: S+3 = V; BI→CL: I+3 = L; QV→RY: V+3 = Y ✔.
2. DY→EC: Y(25)+4 = C(3) – second letter moves +4 ✘.

Trick: When numbers agree everywhere, check letters with position values.

Answer: (A) DY108 - EC216

Concept: Number × 1.5 in all; letters: first +2, second +5.

1. AX→CC: X(24)+5 = C; BC→DH: C+5 = H; KV→MA: V+5 = A ✔.
2. SQ→UW: Q(17)+6 = W(23) ✘.

Trick: ×1.5 = add half: 120 + 60 = 180 – quick check.

Answer: (A) SQ120 - UW180

Concept: Each group falls by 30, then 30.

1. 315, 285, 255; 492, 462, 432; 678, 648, 618 – all −30, −30.
2. 754 − 724 = 30 but 724 − 700 = 24 ✘.

Trick: Check just the last gap of every group – the odd one shows up.

Answer: (D) (754, 724, 700)

Concept: $\text{Second}=2\times \text{first}+3$; $\text{third}=\text{first}+\text{second}$.

1. 120→243→363; 155→313→468; 182→367→549 ✔.
2. $145\times 2+3=293$, not 292 ✘.

Trick: Quick check: third − first should equal second ($437-145=292$ ✔), so test the ×2+3 step.

Answer: (C) (145, 292, 437)

Concept: Both letters −3 (with wrap-around); number −210.

1. T→Q, C→Z; B→Y, S→P ✔.
2. GL → D I; 840 − 210 = 630.
3. Answer: DI630.

Trick: Fix the number first (630) – leaves only (C) and (D); then G−3 = D, L−3 = I.

Answer: (C) DI630

Concept: Number: ×3 − 1. Letters: each −2, then the two letters swap places.

1. $72\times 3-1=215$; $93\times 3-1=278$ ✔ → $103\times 3-1=308$.
2. MX: K, V → VK; DB: B, Z → ZB ✔.
3. GY: E, W → WE.

Trick: Number 308 cuts options to (A) and (B); then check the first letter Y − 2 = W.

Answer: (B) WE308

Concept: $\text{Sum}=\text{average}\times \text{count}$; the $\text{middle number}=\text{total}-(\text{first group}+\text{last group})$.

1. $\text{Total of }9=9\times 83=747$.
2. $\text{First }4=4\times 89=356$; $\text{last }4=4\times 80=320$.
3. $5\text{th}=747-356-320=71$.

Trick: Deviation method: first 4 give $+6\times 4=+24$, last 4 give $-3\times 4=-12$ → $5\text{th}=83-12=71$.

Answer: (B) 71

Concept: To keep expenditure fixed, $\text{cut in consumption}=\frac{R}{100+R}\times 100\%$.

1. $R=50\Rightarrow \frac{50}{150}\times 100\%=33.33\%$.

Trick: Fraction method: $50\%=\frac{1}{2}$ rise → $\text{consumption cut}=\frac{1}{2+1}=\frac{1}{3}=33.33\%$.

Answer: (D) 33.33%

Concept: After 30% discount, price paid = 70% of original.

1. $70\%\text{ of }x=700\Rightarrow x=\frac{700\times 100}{70}=$ ₹1000.

Trick: 70% ↔ 700 means 100% ↔ 1000 – just shift the zeros.

Answer: (D) Rs. 1000

Concept: When only water is added, the quantity of acid stays the same.

1. $\text{Acid}=60\%\text{ of }88=52.8\text{ L}$.
2. For acid to be 40%: $\text{total}=52.8÷0.4=132\text{ L}$.
3. $\text{Water to add}=132-88=$ 44 L.

Trick: $\text{Water added}=V\times (\text{old\%}-\text{new\%})÷\text{new\%}=88\times 20÷40=44\text{ L}$.

Answer: (A) 44 liters

Concept: Take total work = LCM of days.

1. $\text{Total}=\text{LCM}(40,60)=120$ units; $A=3$, $B=2$ units/day.
2. 10 days together = $5\times 10=50$ units.
3. $\text{Left}=\frac{70}{120}=\frac{7}{12}$.

Trick: Direct: $10\times (\frac{1}{40}+\frac{1}{60})=10\times \frac{5}{120}=\frac{5}{12}$ done → $\frac{7}{12}\text{ left}$.

Answer: (C) $\frac{7}{12}$

Concept: $\text{Number of boxes}=\text{carton volume}÷\text{box volume}$ (edges must divide exactly).

1. $60÷15=4,35÷7=5,30÷10=3$.
2. $\text{Boxes}=4\times 5\times 3=60$.

Trick: Pair each carton edge with the box edge that divides it evenly.

Answer: (C) 60

Concept: Similar triangles have equal corresponding angles.

1. Second sign has the same angles: 40°, 80°, 60°.
2. Given 60°, the others are 80° and 40° (sum 180° ✔).

Trick: Similarity changes size, never angles.

Answer: (A) 80° and 40°

Concept: Each exterior angle of a regular n-gon = 360°/n; interior = 180° − exterior.

1. Hexagon: exterior = 360°/6 = 60°.
2. Interior = 180° − 60° = 120°.

Trick: Exterior-angle route is faster than (n − 2) × 180°/n.

Answer: (B) 120°*

Concept: Use the given ratio of quantities (2 : 1).

1. ₹28 part $=x$, ₹20 part $=2x\Rightarrow 3x=600\Rightarrow x=200$ kg.
2. Check: $\text{CP}=400\times 20+200\times 28=13,600$; $\text{SP}=600\times 25=15,000$; profit = ₹1,400 ✔.

Trick: The ratio alone gives the answer; the profit only confirms it.

Answer: (D) 200 kg

Concept: $\text{Volume of prism}=\text{base area}\times \text{length}$; $\text{equilateral triangle area}=\frac{\sqrt{3}}{4}{a}^2$.

1. $\text{Base}=\frac{\sqrt{3}}{4}\times 64=16\sqrt{3}{\text{cm}}^2$.
2. $\text{Volume}=16\sqrt{3}\times 30=480\sqrt{3}=480\times 1.732=831.36{\text{cm}}^3$.

Trick: $480\sqrt{3}\approx 480\times 1.73\approx 830$ → only 831.36 is close.

Answer: (C) $831.36{\mathrm{cm}}^3$