Q&A: practice questions with answers

Concept: Number the 8 outer cells clockwise from top-left. In each step exactly one triangle jumps two cells clockwise.

1. Fig 1→2: triangle at middle-right → bottom-middle; Fig 2→3: top-right → bottom-right.
2. Fig 3→4: top-middle → middle-right; Fig 4→5: top-left → top-right.
3. The moving cell shifts one place anticlockwise each time (MR, TR, TM, TL, …), so next the middle-left ▲ moves to top-middle.
4. Result: ▲ top-middle, △ top-right, ▲ middle-right, △ ▲ △ in the bottom row, middle-left empty.

Trick: Find which single symbol changes place between consecutive figures; the rule usually becomes visible after two steps.

Answer: (D)

Concept: The option must appear inside the main figure in the same orientation and size.

1. The main figure is a rectangle grid with vertical strips and two crossing diagonals.
2. Option (A) — a top bar with two slanting legs and a small inner rectangle — is formed by the top edge, the two diagonal-strip lines and the central cells.
3. The other options need lines (e.g. double bars or a bottom base) that are not in the figure in that position.

Trick: Match the slanting lines first; straight grid lines are easy to find anywhere.

Answer: (A)

Concept: "Some" statements can be reversed; "Some A are B" + "All B are C" ⇒ "Some A are C".

1. Some cats are rats and all rats are mice → the cats that are rats are mice → Some cats are mice (I follows).
2. Reversing I: Some mice are cats (II follows).

Trick: Some + All = Some (taking the subject of "Some").

Answer: (A) Both conclusions I and II follow.

Concept: Potato and carrot are both vegetables, but neither is the other.

1. Potato ⊂ Vegetable, Carrot ⊂ Vegetable.
2. Potato and Carrot have nothing in common.
3. So two separate circles inside one big circle.

Yaad rakhein: Two different members of the same class = two separate circles inside a bigger circle.

Answer: (D) Two separate circles inside a larger circle

Concept: Numbers seen together on one dice position are adjacent, never opposite.

1. 3 appears in all three positions, adjacent to 6, 4, 2, 1 → 3 is opposite 5.
2. 6 is adjacent to 4 (position 1) and to 1 (position 3), and also to 3.
3. Remaining number for 6 is 2 → 6 is opposite 2.

Trick: List all neighbours of the asked face; the number never seen with it is opposite.

Answer: (C) 2

Concept: Add the alphabet positions of the letters in each cluster.

1. GKDT: $7+11+4+20=42$; CQLJ: $3+17+12+10=42$.
2. DPNH: $4+16+14+8=42$.
3. BSMK: $2+19+13+11=45$ → different.

Trick: When no letter-gap pattern appears, try the sum of positions.

Answer: (A) BSMK

Concept: Assume a starting direction, trace the path, then rotate the whole picture to match the final direction.

1. Start East: 3 km E, left → North 5 km to X.
2. Right → East 4 km, right → South 4 km.
3. From there X is 4 km west and 4 km north → he moves North-West ✓.
4. So he started towards East.

Trick: Assume North first; if the final direction comes out rotated, rotate the start by the same angle.

Answer: (D) East

Concept: Each letter of the word is replaced by a fixed letter; read the replacements directly from the given example.

1. CHICANERY → DNODTHVKS gives C→D, H→N, I→O, A→T, N→H, E→V, R→K, Y→S.
2. CRANE: C→D, R→K, A→T, N→H, E→V.
3. Code = DKTHV.

Trick: All letters of CRANE occur in CHICANERY — just pick them from the pairing.

Answer: (A) DKTHV

Concept: All A are B + All B are C ⇒ All A are C. A "some" link with a third class gives no definite conclusion about the others.

1. All covers are red, all red are magazines → all covers are magazines → Some magazines are covers (II follows).
2. Books touch only magazines; they may or may not touch red → I (Some books are red) does not follow.
3. Books may or may not touch covers → III (No cover is book) does not follow.

Trick: Definite "No" or "Some" about a class linked only through "some" is never certain.

Answer: (C) Only conclusion II follows

Concept: The differences double each time.

1. Differences: $+5,+10,+20$.
2. Next difference $=+40$.
3. $43+40=83$.

Trick: Also: each term $=2\times$ previous $-3$: $2\times 43-3=83$.

Answer: (A) 83

Concept: With the mirror on the right, left and right are interchanged; top and bottom stay the same.

1. In the figure the straight arrow runs from top-left to an arrowhead at bottom-right → in the image it runs from top-right to an arrowhead at bottom-left.
2. The curved double-headed S-arrow is laterally reversed as well.
3. Only option (D) shows both changes with top and bottom unchanged.

Trick: Vertical mirror: only the horizontal direction flips — an arrowhead stays at the bottom if it was at the bottom.

Answer: (D)

Concept: Replace + by ×, × by +, − by ÷ and ÷ by −, then evaluate with BODMAS.

1. (A) $18+6\times 24-4÷64$ becomes $18\times 6+24÷4-64$.
2. $=108+6-64=50$ ✓.
3. (B) becomes $18\times 6-24÷4+64=166$ ✗.

Trick: Interchange means both ways: + ↔ × and − ↔ ÷.

Answer: (A) $18+6\times 24-4÷64=50$

Concept: Every animal and person has one head; ducks and attendants have 2 feet, goats and cows have 4.

1. Let attendants $=x$. Heads $=48+42+10+x=100+x$.
2. Feet $=48\times 2+42\times 4+10\times 4+2x=96+168+40+2x=304+2x$.
3. Feet − Heads $=204+x=216\Rightarrow x=12$.

Trick: Each 2-legged being adds 1 to (feet − heads), each 4-legged adds 3: $48+3\times 52=204$, so attendants $=216-204=12$.

Answer: (D) 12

Concept: Look down each column: the two successive changes are always in the ratio $3:4$.

1. Column 1: $12\to 9\to 13$: changes $-3,+4$ (ratio $3:4$).
2. Column 2: $33\to 12\to 40$: changes $-21,+28$ $=7\times (3:4)$.
3. Column 3: $28\to ?\to 17$: with $?=61$, changes $+33,-44$ $=11\times (3:4)$ ✓.
4. No other option gives changes in the ratio $3:4$.

Trick: Test each option in the column — only one value keeps the same ratio of changes.

Answer: (B) 61

Concept: "My father's son", spoken by an only child, means the speaker himself.

1. Ravish is the only child → "my father's son" = Ravish.
2. So the man's father is Ravish.
3. Hence the man in the picture is Ravish's son.

Yaad rakhein: Only child + "my father's son / my mother's son" = myself.

Answer: (D) Son

Concept: Unfold step by step in reverse order; every hole is reflected across each fold line.

1. The triangle is folded three times (top flap down, then the side flaps), leaving one quarter-sized triangle in four layers.
2. Two holes are punched in it, so the opened sheet has $2\times 4=8$ holes.
3. Reflecting the holes across each fold line in turn gives them in the positions shown in option (D).

Trick: Holes after unfolding = holes punched × number of layers.

Answer: (D)

Concept: The same figure (two loops with a curved stem) rotates by a fixed angle each step.

1. Stem direction: bottom-right → bottom → bottom-left: it turns ${45}^{\circ }$ clockwise each time.
2. The next stem should point to the left, with the two loops to its right (upper-right and lower-right).
3. Of the two such options, (D) keeps the stem's curve bending the same way as in the series.

Trick: Follow one distinctive part (the stem) to find the angle of rotation.

Answer: (D)

Concept: A mirror on the right reverses the order of letters and flips each letter left to right; nothing turns upside down.

1. PQRLG read in the mirror runs G L R Q P from left to right.
2. Each letter is also laterally reversed (P faces left, L's foot points left, etc.).
3. Option (B) shows exactly this; (C) and (D) are upside-down or wrongly flipped, and (A) has normal letters.

Yaad rakhein: Mirror image = reverse the order + reverse each letter, keep top and bottom.

Answer: (B)

Concept: Compare the 1st with the 3rd letter and the 2nd with the 4th letter.

1. SHRI: S → R ($-1$), H → I ($+1$).
2. WDVE: W → V ($-1$), D → E ($+1$); UFTG: U → T ($-1$), F → G ($+1$).
3. YACE: Y → C ($+4$), A → E ($+4$) → different.

Trick: In 4-letter clusters, check alternate-letter pairs (1–3, 2–4).

Answer: (A) YACE

Concept: Unfold in reverse order; each cut appears again as a mirror image across the fold line.

1. The sheet is folded in half (right onto left) and then in half again (top onto bottom) → 4 layers.
2. Cuts: one right-pointing arrow on the left edge and two left-pointing arrows on the fold edge.
3. Opening the horizontal fold doubles them vertically; opening the vertical fold mirrors them, so arrows on the fold become double-headed arrows in the middle, giving option (A).

Trick: A cut on a fold line opens into a symmetric shape centred on that line.

Answer: (A)