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Q2741.

If house tax is paid before the due date, one gets a reduction of 12% on the amount of the bill. By paying the tax before the due date, a person got a reduction of ₹2,100. The amount (in ₹) of house tax was:

यदि गृह कर नियत तिथि से पहले चुकाया जाता है, तो बिल की राशि पर 12% की छूट मिलती है। नियत तिथि से पहले कर चुकाकर, एक व्यक्ति को ₹2,100 की छूट मिली। गृह कर की राशि (₹ में) कितनी थी?

A21,000
B17,500
C25,000
D18,000

Show answer

Concept: If $12 %$ of the bill $=$ ₹2100, the bill $= \frac{2100}{0.12}$ .

$\frac{12}{100} \times Bill = 2100$
Bill $= \frac{2100 \times 100}{12} = 17500$

Trick: $1 % = 175$ , so $100 % = 17500$ .

Answer: (B) ₹ $17500$

अवधारणा: यदि बिल का $12 % =$ ₹2100, तो बिल $= \frac{2100}{0.12}$ ।

$\frac{12}{100} \times बिल = 2100$
बिल $= 17500$

ट्रिक: $1 % = 175$ → $100 % = 17500$ ।

उत्तर: (B) ₹ $17500$

SSC CPO Paper IQuantitative AptitudePercentageSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2742.

The least number which is exactly divisible by 5, 6, 8, 10 and 12 is:

वह छोटी से छोटी संख्या, जो 5, 6, 8, 10 और 12 से पूर्णतः विभाज्य है, कौन-सी है?

A180
B240
C120
D150

Show answer

Concept: Least number divisible by all $=$ LCM of the numbers.

$5$ , $6 = 2 \times 3$ , $8 = 2^{3}$ , $10 = 2 \times 5$ , $12 = 2^{2} \times 3$
LCM $= 2^{3} \times 3 \times 5 = 120$

Trick: Check options from smallest: $120$ is divisible by 5, 6, 8, 10, 12.

Answer: (C) $120$

अवधारणा: सबसे छोटी संख्या जो सबसे विभाज्य हो $=$ LCM।

$8 = 2^{3}$ , $12 = 2^{2} \times 3$ , $10 = 2 \times 5$
LCM $= 2^{3} \times 3 \times 5 = 120$

ट्रिक: सबसे छोटे विकल्प से जाँचें: $120$ सभी से विभाज्य।

उत्तर: (C) $120$

SSC CPO Paper IQuantitative AptitudeLCMSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2743.

The value of

\frac{0.325 \times 0.325 + 0.175 \times 0.175 + 25 \times 0.00455}{5 \times 0.0065 \times 3.25 - 7 \times 0.175 \times 0.025} - \frac{0.5}{1.5}

is:

\frac{0.325 \times 0.325 + 0.175 \times 0.175 + 25 \times 0.00455}{5 \times 0.0065 \times 3.25 - 7 \times 0.175 \times 0.025} - \frac{0.5}{1.5}

का मान क्या है?

A $- 3$
B $3$
C $- 1$
D $0$

Show answer

Concept: Let $a = 0.325$ , $b = 0.175$ . Check: $25 \times 0.00455 = 0.11375 = 2 a b$ ; $5 \times 0.0065 \times 3.25 = 0.105625 = a^{2}$ ; $7 \times 0.175 \times 0.025 = 0.030625 = b^{2}$ .

Expression $= \frac{a^{2} + b^{2} + 2 a b}{a^{2} - b^{2}} = \frac{(a + b)^{2}}{(a + b) (a - b)} = \frac{a + b}{a - b}$
$= \frac{0.5}{0.15} = \frac{10}{3}$
$\frac{10}{3} - \frac{0.5}{1.5} = \frac{10}{3} - \frac{1}{3} = 3$

Trick: When numbers look odd, test if they are $a^{2}$ , $b^{2}$ , $2 a b$ of the visible numbers.

Answer: (B) $3$

अवधारणा: माना $a = 0.325$ , $b = 0.175$ । जाँच: $25 \times 0.00455 = 2 a b$ ; $5 \times 0.0065 \times 3.25 = a^{2}$ ; $7 \times 0.175 \times 0.025 = b^{2}$ ।

व्यंजक $= \frac{(a + b)^{2}}{(a + b) (a - b)} = \frac{a + b}{a - b}$
$= \frac{0.5}{0.15} = \frac{10}{3}$
$\frac{10}{3} - \frac{1}{3} = 3$

ट्रिक: अजीब संख्याएँ दिखें तो जाँचें कि वे $a^{2}$ , $b^{2}$ , $2 a b$ तो नहीं।

उत्तर: (B) $3$

SSC CPO Paper IQuantitative AptitudeSimplification – Algebraic IdentitiesSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2744.

The given bar graph represents the number of boys and girls in five different schools. Study the graph and answer the question that follows.

What is the average number of boys in schools A, B, C, D and E?

दिया गया दंड आलेख पाँच विभिन्न विद्यालयों में लड़कों और लड़कियों की संख्या को दर्शाता है। आलेख का अध्ययन कीजिए और उसके बाद दिए गए प्रश्न का उत्तर दीजिए।

विद्यालयों A, B, C, D और E में लड़कों की औसत संख्या कितनी है?

A660
B616
C596
D569

Show answer

Concept: Average $= \frac{sum}{number of schools}$ .

Boys $= 600 + 450 + 750 + 700 + 800 = 3300$
Average $= \frac{3300}{5} = 660$

Trick: Deviation from 600: $0 - 150 + 150 + 100 + 200 = 300$ ; $600 + \frac{300}{5} = 660$ .

Answer: (A) $660$

अवधारणा: औसत $= \frac{योग}{स्कूलों की संख्या}$ ।

लड़के $= 3300$
औसत $= \frac{3300}{5} = 660$

ट्रिक: 600 से विचलन का योग $300$ ; $600 + 60 = 660$ ।

उत्तर: (A) $660$

SSC CPO Paper IQuantitative AptitudeData Interpretation – Bar GraphSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2745.

\sec 3 x = cosec (3 x - 45^{\circ})

, where

3 x

is an acute angle, then x is equal to:

यदि

\sec 3 x = cosec (3 x - 45^{\circ})

है, जहाँ

3 x

एक न्यून कोण है, तो x किसके बराबर है?

A $45^{\circ}$
B ${22.5}^{\circ}$
C $35^{\circ}$
D ${27.5}^{\circ}$

Show answer

Concept: If $\sec A = cosec B$ (both acute), then $A + B = 90^{\circ}$ .

$3 x + (3 x - 45^{\circ}) = 90^{\circ}$
$6 x = 135^{\circ} \Rightarrow x = {22.5}^{\circ}$

Yaad rakhein: $\sec θ = cosec (90^{\circ} - θ)$ .

Answer: (B) ${22.5}^{\circ}$

अवधारणा: यदि $\sec A = cosec B$ (दोनों न्यूनकोण), तो $A + B = 90^{\circ}$ ।

$3 x + 3 x - 45^{\circ} = 90^{\circ}$
$6 x = 135^{\circ} \Rightarrow x = {22.5}^{\circ}$

याद रखें: $\sec θ = cosec (90^{\circ} - θ)$ ।

उत्तर: (B) ${22.5}^{\circ}$

SSC CPO Paper IQuantitative AptitudeTrigonometry – Complementary AnglesSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2746.

The given histogram shows the frequency distribution of the speed of cars passing though at a particular spot on a highway. Study the graph and answer the question that follows.

What is the ratio of the number of cars with speed less than 60 km/h to the number of cars with speed more than 80 km/h?

दिया गया आयतचित्र (histogram) किसी राजमार्ग पर एक विशेष स्थान से गुज़रने वाली कारों की गति के बारंबारता बंटन को दर्शाता है। आलेख का अध्ययन कीजिए और उसके बाद दिए गए प्रश्न का उत्तर दीजिए।

60 km/h से कम गति वाली कारों की संख्या का 80 km/h से अधिक गति वाली कारों की संख्या से अनुपात क्या है?

A8 : 7
B4 : 5
C5 : 4
D7 : 8

Show answer

Concept: Add the class frequencies on each side and simplify the ratio.

Below 60 $km/h$ : $50 + 70 = 120$
Above 80 $km/h$ : $60 + 45 = 105$
$120 : 105 = 8 : 7$

Trick: Divide both by 15.

Answer: (A) $8 : 7$

अवधारणा: दोनों ओर की आवृत्तियाँ जोड़कर अनुपात सरल करें।

60 $km/h$ से कम: $120$
80 $km/h$ से अधिक: $105$
$120 : 105 = 8 : 7$

ट्रिक: दोनों को 15 से भाग दें।

उत्तर: (A) $8 : 7$

SSC CPO Paper IQuantitative AptitudeData Interpretation – HistogramSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2747.

When operated separately, pipe A takes 5 hours less than pipe B to fill a cistern, and when both pipes are operated together, the cistern gets filled in 6 hours. In how much time (in hours) will pipe B fill the cistern, if operated separately?

अलग-अलग चलाए जाने पर, पाइप A किसी टंकी को भरने में पाइप B से 5 घंटे कम समय लेता है, और जब दोनों पाइप एक साथ चलाए जाते हैं, तो टंकी 6 घंटे में भर जाती है। अलग से चलाए जाने पर पाइप B टंकी को कितने समय (घंटों में) में भरेगा?

Show answer

Concept: If B takes $t$ hours, A takes $t - 5$ ; combined rate $= \frac{1}{6}$ .

$\frac{1}{t} + \frac{1}{t - 5} = \frac{1}{6}$
$6 (2 t - 5) = t (t - 5) \Rightarrow t^{2} - 17 t + 30 = 0$
$(t - 15) (t - 2) = 0$ ; $t = 2$ is impossible ( $t - 5 < 0$ ), so $t = 15$

Trick: Test options: $t = 15$ → A $= 10$ ; $\frac{15 \times 10}{25} = 6$ ✓.

Answer: (A) $15$

अवधारणा: B को $t$ घंटे लगें तो A को $t - 5$ ; मिलकर दर $= \frac{1}{6}$ ।

$\frac{1}{t} + \frac{1}{t - 5} = \frac{1}{6}$
$t^{2} - 17 t + 30 = 0$
$t = 15$ ( $t = 2$ असंभव)

ट्रिक: विकल्प जाँचें: $\frac{15 \times 10}{25} = 6$ ✓।

उत्तर: (A) $15$

SSC CPO Paper IQuantitative AptitudePipes and Cisterns – QuadraticSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2748.

The average weight of a group of 3 people A, B and C is 70 kg. When D joins this group, the average becomes 60 kg. One man E, whose weight is 5 kg more than that of D, replaces A and the average weight of B, C, D, and E now becomes 59 kg. A's weight (in kg) is:

3 व्यक्तियों A, B और C के एक समूह का औसत भार 70 kg है। जब D इस समूह में शामिल होता है, तो औसत 60 kg हो जाता है। एक व्यक्ति E, जिसका भार D के भार से 5 kg अधिक है, A का स्थान लेता है और अब B, C, D और E का औसत भार 59 kg हो जाता है। A का भार (kg में) कितना है?

Show answer

Concept: Convert every average into a total.

$A + B + C = 3 \times 70 = 210$ ; with D: $4 \times 60 = 240 \Rightarrow D = 30$
$E = D + 5 = 35$
$B + C + D + E = 4 \times 59 = 236 \Rightarrow B + C = 236 - 65 = 171$
$A = 210 - 171 = 39$

Yaad rakhein: Total $=$ average $\times$ count, at every stage.

Answer: (C) $39$

अवधारणा: हर औसत को योग में बदलें।

$A + B + C = 210$ ; $D = 240 - 210 = 30$
$E = 35$
$B + C = 236 - 65 = 171$
$A = 210 - 171 = 39$

याद रखें: योग $=$ औसत $\times$ संख्या।

उत्तर: (C) $39$

SSC CPO Paper IQuantitative AptitudeAverage – ReplacementSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2749.

If the annual rate of simple interest increases from 11% to

17 \frac{1}{2} %

, a person's yearly income increases by ₹1,071.20. The principal amount invested (in ₹) is:

यदि साधारण ब्याज की वार्षिक दर 11% से बढ़कर

17 \frac{1}{2} %

हो जाती है, तो एक व्यक्ति की वार्षिक आय में ₹1,071.20 की वृद्धि हो जाती है। निवेश की गई मूलधन राशि (₹ में) कितनी है?

A19,120
B16,480
C17,250
D10,710

Show answer

Concept: Change in yearly SI $= P \times \frac{rate change}{100}$ .

Rate change $= 17.5 % - 11 % = 6.5 %$
$P \times \frac{6.5}{100} = 1071.20$
$P = \frac{107120}{6.5} = 16480$

Trick: $1 % = \frac{1071.2}{6.5} = 164.8$ → $P = 16480$ .

Answer: (B) ₹ $16480$

अवधारणा: वार्षिक ब्याज में परिवर्तन $= P \times \frac{दर परिवर्तन}{100}$ ।

दर परिवर्तन $= 6.5 %$
$P \times \frac{6.5}{100} = 1071.20$
$P = 16480$

ट्रिक: $1 % = 164.8$ → $P = 16480$ ।

उत्तर: (B) ₹ $16480$

SSC CPO Paper IQuantitative AptitudeSimple InterestSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2750.

A person travels a distance of 300 km and then returns to the starting point. The time taken by him for the outward journey is 5 hours more than the time taken for the return journey. If he returns at a speed of 10 km/h more than the speed of going, what is the average speed (in km/h) for the entire journey?

एक व्यक्ति 300 km की दूरी तय करता है और फिर प्रारंभिक बिंदु पर लौट आता है। जाने की यात्रा में उसके द्वारा लिया गया समय, वापसी की यात्रा में लिए गए समय से 5 घंटे अधिक है। यदि वह जाने की चाल से 10 km/h अधिक चाल से लौटता है, तो पूरी यात्रा के लिए औसत चाल (km/h में) कितनी है?

Show answer

Concept: Average speed $= \frac{total distance}{total time}$ .

Let outward speed $= v$ : $\frac{300}{v} - \frac{300}{v + 10} = 5$
$3000 = 5 v (v + 10) \Rightarrow v^{2} + 10 v - 600 = 0 \Rightarrow v = 20$
Times: $\frac{300}{20} = 15$ h and $\frac{300}{30} = 10$ h
Average $= \frac{600}{25} = 24 km/h$

Trick: Check: $\frac{2 \times 20 \times 30}{20 + 30} = 24$ .

Answer: (C) $24$

अवधारणा: औसत चाल $= \frac{कुल दूरी}{कुल समय}$ ।

जाने की चाल $v$ : $\frac{300}{v} - \frac{300}{v + 10} = 5$
$v^{2} + 10 v - 600 = 0 \Rightarrow v = 20$
समय: $15$ घंटे और $10$ घंटे
औसत $= \frac{600}{25} = 24 km/h$

ट्रिक: $\frac{2 \times 20 \times 30}{50} = 24$ ।

उत्तर: (C) $24$

SSC CPO Paper IQuantitative AptitudeSpeed – Average SpeedSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2751.

Identify the segment in the sentence which contains a grammatical error.
Do you earn so much to make both ends meet?

Amake both
BDo you earn
Cends meet
Dso much to

Show answer

Concept: To show that something is sufficient for a purpose we use adjective/adverb + enough + to-infinitive, not 'so much to'.

'So much' needs a result clause with that (so much that …) or 'as to'; 'so much to make' is incorrect.
The idea is sufficiency: earning sufficient money to meet expenses.
Correct sentence: Do you earn enough to make both ends meet?
'Do you earn', 'make both', 'ends meet' are correct (idiom: make both ends meet = manage expenses).

Trick: Sufficient for a purpose → enough to; result → so … that.

Answer: (D) so much to

अवधारणा: किसी काम के लिए 'पर्याप्त' बताने हेतु enough + to-infinitive आता है, 'so much to' नहीं।

'So much' के साथ परिणाम बताने के लिए that (so much that …) या 'as to' चाहिए; 'so much to make' गलत है।
यहाँ भाव 'पर्याप्त कमाई' का है।
सही वाक्य: Do you earn enough to make both ends meet?
'make both ends meet' = खर्च चला पाना – यह मुहावरा सही है।

ट्रिक: उद्देश्य के लिए पर्याप्त → enough to; परिणाम → so … that।

उत्तर: (D) so much to

SSC CPO Paper IEnglish ComprehensionError Spotting – 'enough to'SSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2752.

Select the most appropriate synonym of the given word.
CATASTROPHE

Arestraint
Bprosperity
Cexpansion
Dcalamity

Show answer

Concept: Catastrophe means a sudden event causing great damage or suffering; a disaster.

Calamity = a great misfortune or disaster – same meaning.
Restraint = self-control; prosperity = wealth/success (nearly opposite); expansion = growth.

Yaad rakhein: Catastrophe ≈ calamity ≈ disaster ≈ tragedy.

Answer: (D) calamity

अवधारणा: Catastrophe का अर्थ है – महाविपत्ति, आपदा (भारी नुकसान वाली घटना)।

Calamity = विपत्ति, आपदा – समान अर्थ।
Restraint = संयम; prosperity = समृद्धि (लगभग विपरीत); expansion = विस्तार।

याद रखें: Catastrophe ≈ calamity ≈ disaster (आपदा)।

उत्तर: (D) calamity

SSC CPO Paper IEnglish ComprehensionSynonymsSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2753.

Identify the segment in the sentence which contains a grammatical error.
Nobody has ever listened to me so attentive.

Ato me
BNobody has
Cever listened
Dso attentive

Show answer

Concept: A verb is modified by an adverb, not an adjective.

The word describes how somebody 'listened' (a verb).
'Attentive' is an adjective; the adverb is 'attentively'.
Correct: Nobody has ever listened to me so attentively.
Other parts ('Nobody has', 'ever listened', 'to me') are correct.

Trick: Ask 'how?' about the verb → answer must be an -ly adverb.

Answer: (D) so attentive

अवधारणा: Verb (क्रिया) को विशेषित करने के लिए adverb चाहिए, adjective नहीं।

शब्द यह बता रहा है कि 'listened' कैसे किया – यानी verb की विशेषता।
'Attentive' adjective है; adverb रूप 'attentively' है।
सही वाक्य: Nobody has ever listened to me so attentively.
बाकी हिस्से सही हैं।

ट्रिक: Verb से 'कैसे?' पूछें → उत्तर -ly वाला adverb होगा।

उत्तर: (D) so attentive

SSC CPO Paper IEnglish ComprehensionError Spotting – Adjective vs AdverbSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2754.

Select the most appropriate ANTONYM of the given word.
IMPUDENT

Aarrant
Bbrazen
Cblatant
Dmodest

Show answer

Concept: Impudent means rude and disrespectful; shamelessly bold.

Arrant, brazen and blatant all suggest shameless or open boldness – close to impudent, not opposite.
Modest = humble, polite, not boastful – the opposite of impudent.

Yaad rakhein: Impudent ↔ modest / respectful / courteous.

Answer: (D) modest

अवधारणा: Impudent का अर्थ है – ढीठ, बेअदब, निर्लज्ज।

Arrant, brazen, blatant – सभी निर्लज्जता/खुलेपन का भाव देते हैं; ये समानार्थी जैसे हैं।
Modest = विनम्र, शालीन – impudent का विपरीत।

याद रखें: Impudent (ढीठ) ↔ modest (विनम्र)।

उत्तर: (D) modest

SSC CPO Paper IEnglish ComprehensionAntonymsSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2755.

Select the most appropriate meaning of the given idiom.
Speak one’s mind

Ato speak without thinking
Bto speak in an assembly
Cto voice one’s thoughts plainly
Dto put one’s thoughts in writing

Show answer

Concept: The idiom speak one's mind means to say openly and honestly what one thinks.

It is about frankness, not carelessness, so 'to speak without thinking' is wrong.
It has nothing to do with an assembly or with writing.
Example: She always speaks her mind, even before her seniors.

Yaad rakhein: Speak one's mind = be frank and outspoken.

Answer: (C) to voice one’s thoughts plainly

अवधारणा: Speak one's mind = अपने विचार साफ़-साफ़ और खुलकर कहना।

यह स्पष्टवादिता है, बिना सोचे बोलना नहीं।
इसका सभा या लिखने से कोई संबंध नहीं।
उदाहरण: She always speaks her mind, even before her seniors.

याद रखें: Speak one's mind = मन की बात खुलकर कहना।

उत्तर: (C) to voice one’s thoughts plainly

SSC CPO Paper IEnglish ComprehensionIdioms and PhrasesSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2756.

Select the most appropriate one-word substitution for the given group of words.
One who is easily deceived

Aplausible
Bagreeable
Ccredible
Dgullible

Show answer

Concept: A person who is easily deceived or tricked is gullible.

Plausible = seeming reasonable or believable (used for statements).
Credible = trustworthy, believable; agreeable = pleasant.
Gullible fits: A gullible buyer trusted the fake offer.

Trick: Gullible → think 'gull' = to fool someone; a gullible person is easily fooled.

Answer: (D) gullible

अवधारणा: जो आसानी से धोखा खा जाए, उसे gullible (भोला, जल्दी ठगा जाने वाला) कहते हैं।

Plausible = विश्वसनीय लगने वाला (बात के लिए)।
Credible = भरोसेमंद; agreeable = सुखद, सहमत।
अतः gullible सही है।

ट्रिक: 'gull' = मूर्ख बनाना; gullible = जो आसानी से मूर्ख बने।

उत्तर: (D) gullible

SSC CPO Paper IEnglish ComprehensionOne Word SubstitutionSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2757.

Fill in the blank with the most appropriate word.
______! What have you done to your hair? You are looking so odd.

AHurrah
BBother
CBravo
DGoodness gracious

Show answer

Concept: An interjection must match the emotion of the sentence – here surprise/shock at an odd hairstyle.

'Goodness gracious!' expresses surprise or shock – fits 'What have you done to your hair?'
Hurrah and Bravo express joy or praise – unsuitable for 'looking so odd'.
Bother expresses annoyance at one's own trouble, not surprise at someone's look.

Trick: Match the interjection with the feeling: surprise → Goodness gracious / Oh my God; joy → Hurrah; praise → Bravo.

Answer: (D) Goodness gracious

अवधारणा: Interjection वाक्य की भावना से मेल खाना चाहिए – यहाँ अजीब बाल देखकर आश्चर्य/हैरानी है।

'Goodness gracious!' आश्चर्य/हैरानी दिखाता है – सही।
Hurrah (खुशी) और Bravo (शाबाश) – 'looking so odd' के साथ नहीं जमते।
Bother झुंझलाहट दिखाता है, आश्चर्य नहीं।

ट्रिक: आश्चर्य → Goodness gracious; खुशी → Hurrah; प्रशंसा → Bravo।

उत्तर: (D) Goodness gracious

SSC CPO Paper IEnglish ComprehensionFill in the Blank – InterjectionSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2758.

Select the most appropriate one-word substitution for the given group of words.
A person with the same name as another

Aalias
Bimposter
Cnamesake
Dancestor

Show answer

Concept: A person having the same name as another is a namesake.

Alias = a false or assumed name.
Imposter = one who pretends to be someone else; ancestor = forefather.
Example: My namesake in the class often gets my marks.

Yaad rakhein: Name + sake → same name.

Answer: (C) namesake

अवधारणा: किसी दूसरे के समान नाम वाला व्यक्ति namesake (हमनाम) कहलाता है।

Alias = उपनाम/झूठा नाम।
Imposter = धोखे से किसी और का रूप धरने वाला; ancestor = पूर्वज।
अतः namesake सही है।

याद रखें: Namesake = हमनाम।

उत्तर: (C) namesake

SSC CPO Paper IEnglish ComprehensionOne Word SubstitutionSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2759.

Fill in the blank with the most appropriate word.
She has inherited her fondness ______ tennis from her parents.

Ato
Bat
Cfor
Dby

Show answer

Concept: The noun fondness (like the adjective fond) takes the preposition for.

Fixed usage: fondness for something; but fond of something.
Correct: She has inherited her fondness for tennis from her parents.
'to', 'at', 'by' are not used with fondness.

Yaad rakhein: fond of but fondness for (love for, liking for, passion for).

Answer: (C) for

अवधारणा: संज्ञा fondness के साथ preposition for आता है।

निश्चित प्रयोग: fondness for; परन्तु fond of।
सही वाक्य: She has inherited her fondness for tennis from her parents.
'to', 'at', 'by' इसके साथ नहीं आते।

याद रखें: fond of लेकिन fondness for (love for, liking for जैसे)।

उत्तर: (C) for

SSC CPO Paper IEnglish ComprehensionPrepositionsSSC CPO Paper I 2020 · 23 Nov Shift 3 →

Q2760.

Fill in the blank with the most appropriate word.
The doctor often made his patients ______ for long.

Awaited
Bwaiting
Cto wait
Dwait

Show answer

Concept: Causative make + object + bare infinitive (verb without 'to').

Pattern: made + his patients + wait.
'To wait' is used only in the passive: patients were made to wait.
'Waited' and 'waiting' do not fit this pattern.
Correct: The doctor often made his patients wait for long.

Trick: make / let / have + object + V1 (no 'to') in active voice.

Answer: (D) wait

अवधारणा: Causative make + object + bare infinitive (बिना 'to' वाला V1)।

संरचना: made + his patients + wait।
'to wait' केवल passive में आता है: patients were made to wait।
'waited', 'waiting' यहाँ गलत हैं।
सही वाक्य: The doctor often made his patients wait for long.

ट्रिक: Active में make / let / have + object + V1 (बिना 'to')।

उत्तर: (D) wait

SSC CPO Paper IEnglish ComprehensionCausative Verb 'make'SSC CPO Paper I 2020 · 23 Nov Shift 3 →