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Q4141.

The ratio of the total number of students scoring marks less than 50% to that of scoring marks exactly 50% is:

School	Number of students scoring marks less than 50%	Percentage of students scoring marks more than 50%	Number of students appeared
A	270	55	600
B	120	40	400
C	300	20	375
D	220	10	350
E	200	25	300

Study the above table and answer the question.

50% से कम अंक प्राप्त करने वाले विद्यार्थियों की कुल संख्या का ठीक 50% अंक प्राप्त करने वाले विद्यार्थियों की कुल संख्या से अनुपात कितना है?

विद्यालय	50% से कम अंक प्राप्त करने वाले विद्यार्थियों की संख्या	50% से अधिक अंक प्राप्त करने वाले विद्यार्थियों का प्रतिशत	परीक्षा में बैठे विद्यार्थियों की संख्या
A	270	55	600
B	120	40	400
C	300	20	375
D	220	10	350
E	200	25	300

उपर्युक्त तालिका का अध्ययन कीजिए और प्रश्न का उत्तर दीजिए।

A111 : 12
B111 : 24
C101 : 24
D101 : 12

Show answer

Concept: Exactly 50% = appeared − (less than 50%) − (more than 50%).

Less than 50%: $270 + 120 + 300 + 220 + 200 = 1110$ .
More than 50%: A $330$ , B $160$ , C $75$ , D $35$ , E $75$ .
Exactly 50%: A $0$ , B $120$ , C $0$ , D $95$ , E $25$ ; total $240$ . Ratio $1110 : 240 = 111 : 24$ .

Trick: Convert the % column to numbers first: $\frac{%}{100} \times appeared$ .

Answer: (B) $111 : 24$

अवधारणा: ठीक 50% = उपस्थित − (50% से कम) − (50% से अधिक)।

50% से कम: $1110$ ।
50% से अधिक: A $330$ , B $160$ , C $75$ , D $35$ , E $75$ ।
ठीक 50%: $0 + 120 + 0 + 95 + 25 = 240$ ; अनुपात $111 : 24$ ।

ट्रिक: पहले % कॉलम को संख्या में बदलें।

उत्तर: (B) $111 : 24$

SSC CPO Paper IQuantitative AptitudeData Interpretation – TableSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4142.

What is the total surface area of a cuboid whose length, breadth and height are 7 cm, 5 cm and 9 cm, respectively?

उस घनाभ का कुल पृष्ठीय क्षेत्रफल कितना है जिसकी लंबाई, चौड़ाई और ऊँचाई क्रमशः 7 cm, 5 cm और 9 cm है?

A $190 {cm}^{2}$
B $403 {cm}^{2}$
C $286 {cm}^{2}$
D $386 {cm}^{2}$

Show answer

Concept: TSA of a cuboid $= 2 (l b + b h + h l)$ .

$l b = 35$ , $b h = 45$ , $h l = 63$ .
TSA $= 2 (35 + 45 + 63) = 2 \times 143 = 286 {cm}^{2}$ .

Trick: TSA must be even — options are all even, so compute carefully.

Answer: (C) $286 {cm}^{2}$

अवधारणा: घनाभ का कुल पृष्ठ $= 2 (l b + b h + h l)$ ।

$l b = 35$ , $b h = 45$ , $h l = 63$ ।
$2 \times 143 = 286 {cm}^{2}$ ।

ट्रिक: $2 (l b + b h + h l)$ सूत्र याद रखें।

उत्तर: (C) $286 {cm}^{2}$

SSC CPO Paper IQuantitative AptitudeMensuration – CuboidSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4143.

The curved surface area and circumference at the base of a solid right circular
cylinder are 2200 cm² and 110 cm, respectively. Find the height of the cylinder.

एक ठोस लंब वृत्तीय
बेलन का वक्र पृष्ठीय क्षेत्रफल और आधार की परिधि क्रमशः 2200 cm² और 110 cm है। बेलन की ऊँचाई ज्ञात कीजिए।

A24 cm
B22 cm
C20 cm
D18 cm

Show answer

Concept: CSA $= 2 π r h = (circumference) \times h$ .

$110 \times h = 2200$ .
$h = 20$ cm.

Trick: CSA is just base perimeter × height — no need to find $r$ .

Answer: (C) $20$ cm

अवधारणा: वक्र पृष्ठ $= 2 π r h = (परिधि) \times h$ ।

$110 \times h = 2200$ ।
$h = 20$ cm।

ट्रिक: $r$ निकालने की ज़रूरत नहीं।

उत्तर: (C) $20$ cm

SSC CPO Paper IQuantitative AptitudeMensuration – CylinderSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4144.

The least common multiple of 48 and 64 is _____ times the highest common factor of 12 and 18.

48 और 64 का लघुत्तम समापवर्त्य, 12 और 18 के महत्तम समापवर्तक का _____ गुना है।

Show answer

Concept: LCM = highest powers of primes; HCF = lowest common powers.

$48 = 2^{4} \times 3$ , $64 = 2^{6}$ → LCM $= 2^{6} \times 3 = 192$ .
HCF $(12, 18) = 6$ .
$\frac{192}{6} = 32$ .

Trick: $192 \div 6 = 32$ .

Answer: (B) $32$

अवधारणा: LCM = अभाज्यों की सर्वोच्च घातें; HCF = न्यूनतम उभयनिष्ठ घातें।

LCM $(48, 64) = 192$ ।
HCF $(12, 18) = 6$ ।
$\frac{192}{6} = 32$ ।

ट्रिक: $192 \div 6 = 32$ ।

उत्तर: (B) $32$

SSC CPO Paper IQuantitative AptitudeHCF and LCMSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4145.

\cos 48^{\circ} = \frac{m}{n}

, then

\sec 48^{\circ} - \cot 42^{\circ}

is equal to:

यदि

\cos 48^{\circ} = \frac{m}{n}

है, तो

\sec 48^{\circ} - \cot 42^{\circ}

किसके बराबर है?

A $\frac{m - \sqrt{n^{2} - m^{2}}}{m}$
B $\frac{m - \sqrt{n^{2} - m^{2}}}{n}$
C $\frac{n - \sqrt{n^{2} - m^{2}}}{n}$
D $\frac{n - \sqrt{n^{2} - m^{2}}}{m}$

Show answer

Concept: $\cot (90^{\circ} - θ) = \tan θ$ , so $\cot 42^{\circ} = \tan 48^{\circ}$ .

$\cos 48^{\circ} = \frac{m}{n}$ : base $m$ , hypotenuse $n$ , perpendicular $\sqrt{n^{2} - m^{2}}$ .
$\sec 48^{\circ} = \frac{n}{m}$ , $\tan 48^{\circ} = \frac{\sqrt{n^{2} - m^{2}}}{m}$ .
Difference $= \frac{n - \sqrt{n^{2} - m^{2}}}{m}$ .

Trick: Both terms have denominator $m$ (base) — only option (D) fits.

Answer: (D) $\frac{n - \sqrt{n^{2} - m^{2}}}{m}$

अवधारणा: $\cot (90^{\circ} - θ) = \tan θ$ , अतः $\cot 42^{\circ} = \tan 48^{\circ}$ ।

आधार $m$ , कर्ण $n$ , लंब $\sqrt{n^{2} - m^{2}}$ ।
$\sec 48^{\circ} = \frac{n}{m}$ , $\tan 48^{\circ} = \frac{\sqrt{n^{2} - m^{2}}}{m}$ ।
अंतर $= \frac{n - \sqrt{n^{2} - m^{2}}}{m}$ ।

ट्रिक: दोनों का हर $m$ — केवल (D) सही।

उत्तर: (D) $\frac{n - \sqrt{n^{2} - m^{2}}}{m}$

SSC CPO Paper IQuantitative AptitudeTrigonometric RatiosSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4146.

At a construction site, Raju can paint a wall in 36 hours, while Angad can do the same work in 18 hours. Sumit can paint the same wall in 24 hours. In how much time can they paint the wall if they all work together?

एक निर्माण स्थल पर, राजू एक दीवार को 36 घंटे में पेंट कर सकता है, जबकि अंगद उसी कार्य को 18 घंटे में कर सकता है। सुमित उसी दीवार को 24 घंटे में पेंट कर सकता है। यदि वे सभी एक साथ मिलकर कार्य करें, तो वे दीवार को कितने समय में पेंट कर सकते हैं?

A9 hours9 घंटे
B12 hours12 घंटे
C6 hours6 घंटे
D8 hours8 घंटे

Show answer

Concept: Add the one-hour works.

$\frac{1}{36} + \frac{1}{18} + \frac{1}{24} = \frac{2 + 4 + 3}{72}$ .
$= \frac{9}{72} = \frac{1}{8}$ → 8 hours.

Trick: LCM method: total work $72$ units; rates $2 + 4 + 3 = 9$ ; $\frac{72}{9} = 8$ .

Answer: (D) $8$ hours

अवधारणा: एक घंटे के काम जोड़ें।

$\frac{2 + 4 + 3}{72} = \frac{9}{72} = \frac{1}{8}$ ।
अतः 8 घंटे।

ट्रिक: LCM विधि: कुल काम $72$ इकाई; दर $9$ ; $\frac{72}{9} = 8$ ।

उत्तर: (D) $8$ hours

SSC CPO Paper IQuantitative AptitudeTime and WorkSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4147.

Solve the following equation.

\sec^{2} θ (\sqrt{1 - \sin^{2} θ}) =

_______.

निम्नलिखित समीकरण को हल कीजिए।

\sec^{2} θ (\sqrt{1 - \sin^{2} θ}) =

_______.

Atan θ
Bcosec θ
Csec θ
D1

Show answer

Concept: $1 - \sin^{2} θ = \cos^{2} θ$ and $\sec θ = \frac{1}{\cos θ}$ .

$\sqrt{1 - \sin^{2} θ} = \cos θ$ (acute $θ$ ).
$\sec^{2} θ \times \cos θ = \frac{\cos θ}{\cos^{2} θ} = \frac{1}{\cos θ} = \sec θ$ .

Trick: $\sec^{2} θ \cdot \cos θ$ = one $\sec θ$ left.

Answer: (C) $\sec θ$

अवधारणा: $1 - \sin^{2} θ = \cos^{2} θ$ और $\sec θ = \frac{1}{\cos θ}$ ।

$\sqrt{1 - \sin^{2} θ} = \cos θ$ ।
$\sec^{2} θ \times \cos θ = \sec θ$ ।

ट्रिक: एक $\sec θ$ बचता है।

उत्तर: (C) $\sec θ$

SSC CPO Paper IQuantitative AptitudeTrigonometric IdentitiesSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4148.

In an election, a candidate secures 42% of the votes polled but is defeated by his only opponent by a majority of 3080 votes, because of 1400 invalid votes. The percentage of invalid votes is _______.

एक चुनाव में, एक उम्मीदवार डाले गए मतों का 42% प्राप्त करता है, परंतु 1400 अवैध मतों के कारण अपने एकमात्र प्रतिद्वंद्वी से 3080 मतों के बहुमत से पराजित हो जाता है। अवैध मतों का प्रतिशत _______ है।

Show answer

Concept: Here 42% is of the votes polled (including invalid). Opponent gets all valid votes except the candidate's.

Let polled $= T$ . Candidate $= 0.42 T$ ; opponent $= T - 1400 - 0.42 T = 0.58 T - 1400$ .
$0.58 T - 1400 - 0.42 T = 3080 \Rightarrow 0.16 T = 4480 \Rightarrow T = 28000$ .
Invalid $% = \frac{1400}{28000} \times 100 = 5 %$ .

Trick: Majority $+$ invalid $= 16 %$ of polled: $\frac{3080 + 1400}{16} \times 100 = 28000$ .

Answer: (A) $5 %$

अवधारणा: यहाँ 42% कुल डाले गए मतों (अवैध सहित) का है।

माना कुल $= T$ । प्रत्याशी $= 0.42 T$ ; विरोधी $= 0.58 T - 1400$ ।
$0.16 T - 1400 = 3080 \Rightarrow T = 28000$ ।
अवैध $% = \frac{1400}{28000} \times 100 = 5 %$ ।

ट्रिक: $\frac{3080 + 1400}{16 %} = 28000$ ।

उत्तर: (A) $5 %$

SSC CPO Paper IQuantitative AptitudeElectionsSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4149.

A man borrowed Rs.50,000 from a bank at 10% per annum, compounded annually. At the end of every year, he pays Rs.15,000 as part payment of the loan and interest. How much does he still owe to the bank after three such instalments?

एक व्यक्ति ने एक बैंक से 10% वार्षिक ब्याज दर पर, वार्षिक रूप से चक्रवृद्धि होने वाले, Rs.50,000 उधार लिए। प्रत्येक वर्ष के अंत में, वह ऋण और ब्याज के आंशिक भुगतान के रूप में Rs.15,000 का भुगतान करता है। ऐसी तीन किस्तों के बाद भी उस पर बैंक का कितना बकाया है?

ARs.16,900
BRs.15,800
CRs.15,200
DRs.16,200

Show answer

Concept: Each year: amount $= 1.1 \times$ balance, then subtract the payment.

Year 1: $50000 \times 1.1 - 15000 = 40000$ .
Year 2: $40000 \times 1.1 - 15000 = 29000$ .
Year 3: $29000 \times 1.1 - 15000 = 31900 - 15000 =$ Rs. $16900$ .

Trick: Work year by year — interest is charged only on the remaining balance.

Answer: (A) Rs. $16900$

अवधारणा: हर वर्ष: राशि $= 1.1 \times$ शेष, फिर किस्त घटाएँ।

वर्ष 1: $55000 - 15000 = 40000$ ।
वर्ष 2: $44000 - 15000 = 29000$ ।
वर्ष 3: $31900 - 15000 =$ Rs. $16900$ ।

ट्रिक: ब्याज केवल शेष राशि पर लगता है।

उत्तर: (A) Rs. $16900$

SSC CPO Paper IQuantitative AptitudeCompound Interest – InstalmentsSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4150.

Annual production of four different types of cold drinks has been tabulated below. Which of these cold-drinks has encountered maximum percentage increment in production?

Cold drink	2020 (units)	2021 (units)
Sprite	5400	5800
Coca-cola	5300	5600
Pepsi	6000	6800
Fanta	1800	2700

चार विभिन्न प्रकार के कोल्ड ड्रिंक्स के वार्षिक उत्पादन को नीचे सारणीबद्ध किया गया है। इनमें से किस कोल्ड ड्रिंक के उत्पादन में अधिकतम प्रतिशत वृद्धि हुई है?

कोल्ड ड्रिंक	2020 (इकाई)	2021 (इकाई)
Sprite	5400	5800
Coca-cola	5300	5600
Pepsi	6000	6800
Fanta	1800	2700

ACoca-Cola
BPepsi
CFanta
DSprite

Show answer

Concept: Percentage increase $= \frac{increase}{2020 value} \times 100$ .

Sprite $\frac{400}{5400} \approx 7.4 %$ ; Coca-Cola $\frac{300}{5300} \approx 5.7 %$ .
Pepsi $\frac{800}{6000} \approx 13.3 %$ ; Fanta $\frac{900}{1800} = 50 %$ .
Maximum: Fanta.

Trick: Fanta's small base with the largest rise gives the biggest %.

Answer: (C) Fanta

अवधारणा: प्रतिशत वृद्धि $= \frac{वृद्धि}{2020 मान} \times 100$ ।

Sprite $\approx 7.4 %$ ; Coca-Cola $\approx 5.7 %$ ।
Pepsi $\approx 13.3 %$ ; Fanta $= 50 %$ ।
अधिकतम: Fanta।

ट्रिक: छोटा आधार + बड़ी वृद्धि = सबसे अधिक %।

उत्तर: (C) Fanta

SSC CPO Paper IQuantitative AptitudeData Interpretation – TableSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4151.

Select the option that expresses the given sentence in passive voice.
Jack played hide and seek.

AHide and seek was played by Jack.
BHide and seek had been played by Jack.
CHide and seek will be played by Jack.
DHide and seek is played by Jack.

Show answer

Concept: Simple Past active (Subject + V2 + Object) becomes passive as Object + was/were + V3 + by + Subject.

Subject = Jack, verb = played (simple past), object = hide and seek.
Object becomes the new subject: Hide and seek (a single game, so singular was).
Verb: was + V3 = was played; agent: by Jack.
(B) is past perfect, (C) future, (D) present – tense changed, so wrong.

Trick: Tense never changes in voice change – V2 in active means was/were + V3 in passive.

Answer: (A) Hide and seek was played by Jack.

अवधारणा: Simple Past active (Subject + V2 + Object) का passive: Object + was/were + V3 + by + Subject।

Subject = Jack, verb = played (simple past), object = hide and seek।
Object नया subject बनेगा: Hide and seek (एक खेल, इसलिए singular was)।
Verb: was + V3 = was played; अंत में by Jack।
(B) past perfect, (C) future, (D) present है – tense बदल गया, इसलिए गलत।

ट्रिक: Voice बदलने पर tense नहीं बदलता – active में V2 है तो passive में was/were + V3।

उत्तर: (A) Hide and seek was played by Jack.

SSC CPO Paper IEnglish ComprehensionActive and Passive VoiceSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4152.

Select the most appropriate synonym of the given word.
Progress

ADevelopment
BDiminishment
CHalt
DStagnation

Show answer

Concept: Progress means forward movement or improvement towards a better state.

Development = growth or advancement – same meaning.
Diminishment = reduction; Halt = stop; Stagnation = lack of movement – all opposite in sense.

Trick: Three options (diminishment, halt, stagnation) all mean 'no growth' – the odd positive word is the synonym.

Answer: (A) Development

अवधारणा: Progress का अर्थ है आगे बढ़ना / उन्नति।

Development = विकास, उन्नति – समान अर्थ।
Diminishment = कमी; Halt = रुकना; Stagnation = ठहराव – सभी विपरीत भाव।

ट्रिक: तीन विकल्प 'रुकावट/कमी' बताते हैं – अकेला सकारात्मक शब्द ही synonym है।

उत्तर: (A) Development

SSC CPO Paper IEnglish ComprehensionSynonymsSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4153.

Select the most appropriate ANTONYM of the underlined word.
My teacher asked me to compress the file.

ASearch
BTrace
CEnlarge
DTurn

Show answer

Concept: To compress a file means to reduce its size (squeeze it into less space).

The opposite of making smaller is making bigger.
Enlarge = make larger – exact opposite.
Search, Trace (find), Turn (rotate) are unrelated to size.

Yaad rakhein: compress ↔ expand / enlarge / decompress.

Answer: (C) Enlarge

अवधारणा: Compress (फ़ाइल) = आकार छोटा करना, दबाकर कम जगह में करना।

छोटा करने का विलोम है बड़ा करना।
Enlarge = बड़ा करना – सटीक विलोम।
Search, Trace (खोजना), Turn (घुमाना) का आकार से संबंध नहीं।

याद रखें: compress ↔ expand / enlarge / decompress।

उत्तर: (C) Enlarge

SSC CPO Paper IEnglish ComprehensionAntonymsSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4154.

Select the most appropriate ANTONYM of the given word.
Novel

AFormal
BAncient
CTraditional
DCustomary

Show answer

Concept: As an adjective, novel means new, original and unusual.

Opposite of new/original = following long-established customs = Traditional.
Ancient means very old in time, not the opposite of 'original/innovative'; Customary is close but the standard pair is novel ↔ traditional; Formal is unrelated.

Yaad rakhein: novel idea = नया विचार; its opposite is a traditional (conventional) idea.

Answer: (C) Traditional

अवधारणा: Adjective के रूप में novel = नया, मौलिक, अनोखा।

नए/मौलिक का विलोम = पुरानी परंपरा पर चलने वाला = Traditional।
Ancient = बहुत पुराना (समय में), 'नवीन सोच' का विलोम नहीं; Customary निकट है पर मानक जोड़ी novel ↔ traditional है; Formal असंबंधित।

याद रखें: novel idea = नया विचार; विलोम traditional (परंपरागत) विचार।

उत्तर: (C) Traditional

SSC CPO Paper IEnglish ComprehensionAntonymsSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4155.

Select the most appropriate meaning of the underlined idiom.
Some colleagues at a workplace are really hard nuts to crack.

AHardcore traditions in a family
BAn inflexible person who is hard to convince
CSomeone showing extra concern over little things
DAn easy-goer who can be easily convinced

Show answer

Concept: A hard nut to crack = a person (or problem) that is very difficult to deal with, understand or persuade.

The sentence talks of colleagues, i.e. people who are tough to handle.
So it means an inflexible person who is hard to convince.
(D) is the opposite; (A) and (C) do not fit the idiom.

Trick: A hard nut cannot be cracked easily – similarly the person cannot be 'cracked' (convinced) easily.

Answer: (B) An inflexible person who is hard to convince

अवधारणा: A hard nut to crack = ऐसा व्यक्ति/समस्या जिसे संभालना या मनाना बहुत कठिन हो।

वाक्य में colleagues यानी लोगों की बात है जिन्हें संभालना कठिन है।
अर्थ: अड़ियल व्यक्ति जिसे मनाना कठिन हो।
(D) उलटा अर्थ है; (A) और (C) मुहावरे से मेल नहीं खाते।

ट्रिक: सख़्त अखरोट आसानी से नहीं टूटता – वैसे ही ऐसा व्यक्ति आसानी से नहीं मानता।

उत्तर: (B) An inflexible person who is hard to convince

SSC CPO Paper IEnglish ComprehensionIdioms and PhrasesSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4156.

Select the most appropriate meaning of the underlined idiom.
He was beaming from ear to ear.

APlaying
BSmiling broadly
CCriticising bitterly
DWorking

Show answer

Concept: Beam from ear to ear = to smile very broadly because of great happiness.

Beam itself means to smile radiantly.
A smile stretching 'from ear to ear' is a very wide smile.
Hence: smiling broadly. Playing, criticising or working are unrelated.

Yaad rakhein: grin / beam from ear to ear = खुशी से खिलखिलाना।

Answer: (B) Smiling broadly

अवधारणा: Beam from ear to ear = बहुत खुश होकर खुलकर मुस्कुराना।

Beam का अर्थ ही है चमकती मुस्कान देना।
'एक कान से दूसरे कान तक' मुस्कान = बहुत चौड़ी मुस्कान।
अतः smiling broadly; बाकी विकल्प असंबंधित।

याद रखें: grin / beam from ear to ear = खुशी से खिलखिलाना।

उत्तर: (B) Smiling broadly

SSC CPO Paper IEnglish ComprehensionIdioms and PhrasesSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4157.

Select the most appropriate option that can substitute the underlined segment in the given sentence.
He is a weak student and somehow pulled over the exams.

Apulled through
Bpulled down
Cpulled up
Dpulled together

Show answer

Concept: Pull through = to succeed or survive with difficulty; pull over = to stop a vehicle at the roadside, which does not fit.

A weak student 'somehow' managed to pass – success with difficulty.
So pulled through the exams is correct.
Pull down = demolish; pull up = stop / scold; pull together = cooperate.

Trick: 'somehow' + difficult situation → pull through.

Answer: (A) pulled through

अवधारणा: Pull through = कठिनाई से सफल होना/बच निकलना; pull over = गाड़ी किनारे रोकना, यहाँ ठीक नहीं।

कमज़ोर छात्र 'somehow' (किसी तरह) पास हुआ – कठिनाई से सफलता।
अतः pulled through the exams सही है।
Pull down = गिराना; pull up = रोकना/डाँटना; pull together = मिलकर काम करना।

ट्रिक: 'somehow' + मुश्किल हालात → pull through।

उत्तर: (A) pulled through

SSC CPO Paper IEnglish ComprehensionPhrasal VerbsSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4158.

Select the most appropriate ANTONYM of the given word.
Rife

AScarce
BRipe
CPopular
DSerene

Show answer

Concept: Rife = widespread, abundant, very common (usually of something bad), e.g. 'Corruption is rife'.

Opposite of abundant/widespread = Scarce (in short supply).
Ripe is a look-alike word (mature fruit); Popular is near in sense; Serene = calm.

Trick: Don't be trapped by spelling look-alikes: rife ≠ ripe.

Answer: (A) Scarce

अवधारणा: Rife = व्यापक, भरपूर, बहुत फैला हुआ (अक्सर बुरी चीज़), जैसे 'Corruption is rife'।

भरपूर/व्यापक का विलोम = Scarce (दुर्लभ, कम)।
Ripe मिलता-जुलता शब्द (पका हुआ); Popular समान भाव; Serene = शांत।

ट्रिक: मिलती-जुलती spelling के जाल से बचें: rife ≠ ripe।

उत्तर: (A) Scarce

SSC CPO Paper IEnglish ComprehensionAntonymsSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4159.

Select the INCORRECTLY spelt word.

APried
BProphet
CProdigy
DProteg

Show answer

Concept: Check each word's standard spelling.

Pried (past of pry), Prophet, Prodigy – all correct.
The correct word is Protégé (also written Protege) – a person guided by a mentor; 'Proteg' drops the final e.

Yaad rakhein: Protégé is a French word ending in -é; it is pronounced 'pro-tuh-zhay'.

Answer: (D) Proteg

अवधारणा: हर शब्द की मानक spelling जाँचें।

Pried (pry का past), Prophet, Prodigy – सभी सही।
सही शब्द Protégé (या Protege) है – किसी गुरु द्वारा मार्गदर्शित व्यक्ति; 'Proteg' में अंतिम e गायब है।

याद रखें: Protégé फ़्रेंच शब्द है जो -é पर समाप्त होता है।

उत्तर: (D) Proteg

SSC CPO Paper IEnglish ComprehensionSpellingSSC CPO Paper I 2022 · 10 Nov Shift 1 →

Q4160.

Select the option that substitutes the bracketed word-segment correctly and
completes the sentence meaningfully.
Manthan and Pranav (sang together in a concert).

Achanted together in a show
Benunciated together in a show
Cenjoined together in a show
Darticulated together in a show

Show answer

Concept: The replacement must keep the meaning 'sang together in a concert'.

Chant = sing or say in a musical, repeated tone – closest to sang; show ≈ concert.
Enunciate and articulate = pronounce words clearly (speech, not singing).
Enjoin = order or instruct – meaningless here.

Trick: Only 'chant' belongs to the family of singing; the other three are about speaking/ordering.

Answer: (A) chanted together in a show

अवधारणा: नया हिस्सा 'sang together in a concert' का अर्थ बनाए रखे।

Chant = लयबद्ध ढंग से गाना/जपना – sang के सबसे निकट; show ≈ concert।
Enunciate और articulate = शब्द साफ़ बोलना (गाना नहीं)।
Enjoin = आदेश देना – यहाँ अर्थहीन।

ट्रिक: केवल 'chant' गाने से जुड़ा है; बाकी तीन बोलने/आदेश से।

उत्तर: (A) chanted together in a show

SSC CPO Paper IEnglish ComprehensionSentence ImprovementSSC CPO Paper I 2022 · 10 Nov Shift 1 →