Q&A: practice questions with answers

Concept: Letters are rearranged and the 2nd and 5th letters are replaced by their opposite letters (pair sum $=27$).

1. ACTION: output = 3rd (T), opposite of 2nd C (X), 1st (A), 6th (N), opposite of 5th O (L), 4th (I) → TXANLI.
2. Check DEBATE: B, opp(E)=V, D, E, opp(T)=G, A → BVDEGA ✓.
3. CHANGE: 3rd A, opp(H)=S, 1st C, 6th E, opp(G)=T, 4th N → ASCETN.

Trick: Opposite letters: $\text{position}+\text{position}=27$ (C–X, H–S, G–T).

Answer: (D) ASCETN

Concept: Alternate (two interleaved) series.

1. Odd terms: $38,40,42$ (each $+2$).
2. Even terms: $57,59,?$ (each $+2$).
3. So $?=59+2=61$.

Trick: If the series goes up-down-up, split it into odd and even places.

Answer: (D) $61$

Concept: Differences increase by a constant.

1. Differences: $17,21,25,29$ (each $+4$).
2. Next difference $=33$.
3. $?=204+33=237$.

Trick: Second differences constant ($4$) → add the next difference.

Answer: (C) $237$

Concept: First letter is moved $5$ steps back; the remaining four letters are swapped in pairs.

1. COACH: $C-5=X$; (O,A)→(A,O), (C,H)→(H,C) → XAOHC.
2. BERTH: $B-5=W$; (E,R)→(R,E), (T,H)→(H,T) → WREHT ✓.
3. TRAIN: $T-5=O$; (R,A)→(A,R), (I,N)→(N,I) → OARNI.

Trick: Check the first letter separately when the rest is just a pair-swap.

Answer: (A) OARNI

Concept: Replace each sign as given, then use BODMAS.

1. After replacing: $121÷11+28\times 3-46$.
2. $=11+84-46$
3. $=49$

Trick: Rewrite the whole expression first, then solve — never solve with the old signs.

Answer: (A) $49$

Concept: Each letter position of the 4-letter groups forms its own series.

1. 1st letters: L, N, ?, R, T → $+2$ → P.
2. 2nd letters: D, G, ?, M, P → $+3$ → J.
3. 3rd letters: E, I, ?, Q, U → $+4$ → M.
4. 4th letters: A, F, ?, P, U → $+5$ → K.

Trick: Read the groups column-wise: here the steps are $+2,+3,+4,+5$.

Answer: (D) PJMK

Concept: Replace each sign as given, then use BODMAS.

1. After replacing: $30-5\times 2÷10+2$.
2. $=30-10÷10+2=30-1+2$
3. $=31$

Trick: Rewrite the whole expression first, then solve — never solve with the old signs.

Answer: (B) $31$

Concept: Unfold in reverse order; every cut is mirrored across each fold line.

1. The paper was folded bottom-to-top, then right-to-left, so the cuts lie in the top-left quarter: square, dot, cross and circle along a slant, with the circle next to the vertical fold.
2. Opening the right fold mirrors them: the two circles meet near the top centre.
3. Opening the bottom fold mirrors again: the two squares meet at the middle of the left and right edges, circles appear at the top and bottom centre — a ring of 16 cuts.

Trick: A cut touching a fold line becomes a pair side by side after unfolding.

Answer: (B) Option (B) figure

Concept: Code = sum of letter positions $+2\times$(number of letters).

1. HORSE: $8+15+18+19+5=65$; $65+2\times 5=75$ ✓.
2. MOVE: $13+15+22+5=55$; $55+2\times 4=63$ ✓.
3. RACE: $18+1+3+5=27$; $27+2\times 4=35$.

Trick: Subtract the alphabet-sum from the code; the leftover ($10$, $8$) is twice the word length.

Answer: (D) $35$

Concept: "Alas" is an exclamation that expresses woe (sorrow); the second word is the quality/feeling linked with the first.

1. Alas → woe: the word and the feeling it conveys.
2. Beauty → charm: beauty is associated with charm (attractiveness).
3. Inelegance and crudeness are opposites of beauty; expunge (erase) is unrelated.

Trick: Make a sentence: "Alas expresses woe" → "Beauty shows charm".

Answer: (D) Charm

Concept: Trace the path and cancel opposite movements.

1. North $40$, then right → East $60$.
2. Right again → South $40$: back on the home line (north–south cancels).
3. Facing South, a left turn → East $60$.
4. Net: $60+60=120\text{km}$ East of home.

Trick: Facing South, "left" means East.

Answer: (D) East, $120\text{km}$

Concept: The differences follow an alternating multiply–add pattern.

1. Differences: $2,2,5,25,32,288,299$.
2. $2\times 1=2$, $2+3=5$, $5\times 5=25$, $25+7=32$, $32\times 9=288$, $288+11=299$.
3. So the next difference is $299$: $?=357+299=656$.

Trick: When differences jump wildly, check the differences themselves for $\times$ / $+$ alternation.

Answer: (A) $656$

Concept: Draw the least-overlap Venn diagram and test each conclusion.

1. Plains lie inside Mountains; Seas lie fully outside Mountains.
2. So no Sea can be a Plain → III follows.
3. Valleys touch Seas, but need not touch Plains or avoid Mountains → I and II are only possibilities.

Trick: A definite "No" (No sea is a plain) follows when one set is inside a set that is disjoint from the other.

Answer: (A) Only conclusion III follows.

Concept: Find the repeating block.

1. The block "PQRRS" repeats four times.
2. PQRRS | PQRRS | PQRRS | PQRRS.
3. Blanks in order: Q, S, R, R, P, R, Q.

Trick: Count the total letters ($20$) — a 5-letter block repeating 4 times fits.

Answer: (D) Q S R R P R Q

Concept: Replace each sign as given, then use BODMAS.

1. After replacing: $16\times 5+112÷8-32$.
2. $=80+14-32$
3. $=62$

Trick: Rewrite the whole expression first, then solve — never solve with the old signs.

Answer: (C) $62$

Concept: Join the neighbour clues into a chain; facing the centre, "right" is anticlockwise.

1. Shree sits between Dayal and Tripti; Shrishti sits between Tripti and Manju → chain Dayal–Shree–Tripti–Shrishti–Manju.
2. The 6th seat (Sharda) lies between Manju and Dayal.
3. Check: Manju is second to the right of Dayal (Dayal → Sharda → Manju) ✓.
4. Sharda’s neighbours: Dayal and Manju.

Trick: Build the chain from "neighbour of both" clues first.

Answer: (A) Dayal

Concept: Second term $=n\times (n+11)$.

1. $2\times 13=26$ ✓.
2. $27\times 38=1026$ ✓.
3. $8\times 19=152$ → the missing term is $8$.

Trick: Check the options: only $8\times 19$ gives $152$.

Answer: (B) $8$

Concept: Five symbols sit on five fixed positions; the whole order shifts by two places each step.

1. Reading positions in order, figure 1 is ○ □ △ ◇ ▽.
2. Each next figure starts from the old 3rd symbol (cyclic shift by 2).
3. Figure 5: ◇ ▽ ○ □ △ — diamond top-left, triangle-down beside it, circle in the middle, square on its right, triangle-up at the bottom.

Trick: Track one symbol: ○ goes P1 → P4 → P2 → P5 → P3.

Answer: (A) Option (A) figure

Concept: Each shape moves one step along a fixed cycle of the five positions.

1. Triangle: TL → TR → BL; Square: TR → BL → BR; Ellipse: BR → C → TL — all follow C → TL → TR → BL → BR → C.
2. Next step: hexagon C → TL, ellipse TL → TR, square BR → C, diamond TR → BL, triangle BL → BR.
3. So: hexagon top-left, ellipse top-right, square centre, diamond bottom-left, triangle bottom-right.

Trick: Follow one shape for two steps to discover the path, then apply it to all.

Answer: (B) Option (B) figure

Concept: Replace each sign as given, then use BODMAS.

1. After replacing: $83+12\times 65÷13-47$.
2. $=83+780÷13-47=83+60-47$
3. $=96$

Trick: Rewrite the whole expression first, then solve — never solve with the old signs.

Answer: (B) $96$