Q&A: practice questions with answers

Concept: Track each symbol separately; all five move one step along the same fixed path Centre → TR → BR → BL → TL → Centre.

1. Hook: TR, BR, BL, TL → next Centre.
2. Spiral: Centre, TR, BR, BL → next TL. Arrow: TL, Centre, TR, BR → next BL.
3. &: BL, TL, Centre, TR → next BR; s: BR, BL, TL, Centre → next TR.
4. So figure 5: spiral TL, s TR, hook in centre, arrow BL, & BR.

Trick: Find the path of one symbol (e.g. the hook); every other symbol follows the same path.

Answer: (B) Spiral top-left, s top-right, hook centre, arrow bottom-left, & bottom-right.

Concept: Find how the 2nd and 3rd numbers come from the 1st.

1. $(16,48,4)$: $16\times 3=48$ and $16÷4=4$.
2. $(24,72,6)$: $24\times 3=72$ and $24÷4=6$.
3. Check $(20,60,5)$: $20\times 3=60$, $20÷4=5$ ✓. Option (B) fails because $20÷4\ne 6$.

Trick: Second = first × 3, third = first ÷ 4 — test only the first number of each option.

Answer: (D) $(20,60,5)$

Concept: A word common to two sentences takes the code common to both coded sentences.

1. 'god is great' → 'tg so rf'; 'we love god' → 'ae rf xd'.
2. Common word: god; common code: rf.
3. So god = rf.

Trick: Common word ↔ common code.

Answer: (B) rf

Concept: Teacher, Guitarist and Lawyer are three independent groups; a person can belong to any one, two or all three of them.

1. A teacher may play the guitar, and a guitarist may be a lawyer.
2. A lawyer may also teach, and one person can even be all three.
3. So all three circles must overlap each other, with a common central region.

Yaad rakhein: Three independent professions/hobbies → three mutually intersecting circles.

Answer: (B) Three circles all overlapping one another.

Concept: Plot each move on axes (North = up, East = right) and compare P with A.

1. From A: 8 km North, right turn → 2 km East, right → 11 km South, right → 5 km West, right → 3 km North.
2. East–West: $2-5=-3$ → P is 3 km West of A's line.
3. North–South: $8-11+3=0$ → P is on the same level as A.
4. So A is 3 km East of P.

Trick: Net N–S $=0$ means the answer is a pure East/West distance.

Answer: (A) 3 km towards East

Concept: Check the gaps between consecutive letters by alphabet position.

1. TQV: $T-3=Q$, $Q+5=V$.
2. NKP: $N-3=K$, $K+5=P$; KHM: $K-3=H$, $H+5=M$.
3. QNR: $Q-3=N$ but $N+4=R$ → breaks the pattern.

Trick: Pattern $(-3,+5)$; the cluster with $+4$ is odd.

Answer: (A) QNR

Concept: Take A as origin and fix every point's position.

1. B is 35 m West of A; C is 48 m North of A; D is 23 m East of C.
2. E is 14 m South of D → E is 23 m East, 34 m North of A.
3. F is 48 m West of E → F is $48-23=25$ m West and 34 m North of A.
4. West + North → F is North-west of A.

Trick: Only signs matter for direction: (West, North) = North-west.

Answer: (D) North-west

Concept: Summon and Call are synonyms, so we need a synonym of Disperse.

1. Summon = call (someone) to come.
2. Disperse = scatter / spread over a wide area.
3. Remove and Disappear are different ideas; Surround is nearly opposite.

Trick: Pair type first: synonym → synonym.

Answer: (C) Spread

Concept: Compare each letter with its code letter.

1. MARS → KXPP: $M-2$, $A-3$, $R-2$, $S-3$.
2. BODY → ZLBV: $B-2$, $O-3$, $D-2$, $Y-3$ ✓.
3. TEST: $T-2=R$, $E-3=B$, $S-2=Q$, $T-3=Q$ → RBQQ.

Trick: Alternate $-2,-3$ shifts.

Answer: (A) RBQQ

Concept: All start with 'Bre'; compare from the 4th letter onward.

1. 4th letter: a (Breacher, Breakfast, Breakthrough, Breathable) before v (Brevetting, Breviaries).
2. Brea-c < Brea-k < Brea-t: Breacher, then Breakfast (break-f) before Breakthrough (break-t), then Breathable.
3. Breve-t before Brevi-a (e before i): Brevetting, Breviaries.
4. Order: 5, 3, 6, 1, 2, 4.

Trick: Strip the common prefix and compare the first differing letter only.

Answer: (D) 5, 3, 6, 1, 2, 4

Concept: Swap the two signs and evaluate using BODMAS.

1. Interchange ÷ and −: $6+3\times 8÷12-4$.
2. $3\times 8÷12=24÷12=2$.
3. $6+2-4=4$ ✓.

Trick: Try the option that makes a clean division first ($24÷12$).

Answer: (A) ÷ and −

Concept: Look at the differences between terms.

1. $192-7=185$, $185-14=171$.
2. Differences are multiples of 7: $7,14,21,28,35$.
3. $171-21=150$, $150-28=122$, $122-35=87$ ✓.

Trick: Differences $7\times 1,7\times 2,7\times 3,\dots$

Answer: (D) 150

Concept: When two conclusions about the same pair are 'Some A are B' and 'No A is B', and neither is definite alone, exactly one must be true.

1. All cards are plastics; some plastics are woods → no definite link between cards and woods.
2. I (Some cards are woods) is only possible; II (No card is wood) is only possible.
3. I and II are opposite (complementary), so one of them must hold → Either I or II.

Trick: Same subject + same predicate + 'Some' vs 'No' → Either-Or.

Answer: (D) Either conclusion I or II follows

Concept: Each fold line acts like a mirror: on unfolding, the cut design is reflected across it.

1. The paper is folded right-half onto left, then top-half down, so the cut part is the bottom-left quarter.
2. Cut there: a cross and a slanting slit with a dot near the corner.
3. Opening the horizontal fold mirrors them into the top-left quarter; opening the vertical fold mirrors both into the right half.
4. So 4 crosses and 4 slits appear, each slit pointing to its own corner dot — symmetric about both fold lines.

Trick: Unfold in reverse order; the final pattern is symmetric about every fold line.

Answer: (A) The figure with all four quarters mirror-symmetric about both centre lines.

Concept: Track each letter position separately.

1. 1st letters: Y, B, E, H, K ($+3$, cyclic).
2. 2nd: F, J, N, R, V ($+4$).
3. 3rd: J, E, Z, U, P ($-5$, cyclic); 4th: W, C, I, O, U ($+6$, cyclic).
4. Missing term: E N Z I.

Trick: Four separate series with shifts $+3,+4,-5,+6$.

Answer: (D) ENZI

Concept: Track the first and second letters separately.

1. First letters: A, D, G, J → $+3$ → M.
2. Second letters: M, K, I, G → $-2$ → E.
3. Next term: ME.

Trick: First $+3$, second $-2$.

Answer: (D) ME

Concept: Decode each symbol from left to right and draw the family tree.

1. N × M: N is the wife of M.
2. M − K: K is the sister of M; K ÷ L: K is the mother of L.
3. L + P: L is the father of P → L is male.
4. So L is K's son.

Trick: Gender of the asked person usually comes from the last relation (here 'father').

Answer: (D) Son

Concept: Replace letters by signs and apply BODMAS.

1. $8\times 9+49÷7-25$.
2. $=72+7-25$.
3. $=54$.

Trick: Do ÷ and × first, then + and −.

Answer: (B) 54

Concept: If one face is common and in the same position in two views, the faces in corresponding positions are opposite.

1. View 1: V top, R left, M right; View 2: S top, T left, M right.
2. M is common and in the same place.
3. So V ↔ S and R ↔ T are opposite; remaining M ↔ Q.

Trick: Common face in same position → match the other positions directly.

Answer: (C) S

Concept: Compare each letter with its code.

1. GOOD → HMPB: $G+1$, $O-2$, $O+1$, $D-2$.
2. HALL → IYMJ: $+1,-2,+1,-2$ ✓.
3. TOOL: $T+1=U$, $O-2=M$, $O+1=P$, $L-2=J$ → UMPJ.

Trick: Alternate $+1,-2$.

Answer: (D) UMPJ