Q&A: practice questions with answers

Concept: Faces that appear together with a face are adjacent to it; the one face never seen with it is opposite.

1. 4 is on top in all three views and its neighbours are 3, 2, 5 and 6, so 1 is opposite 4.
2. Turning the dice about the 4–1 axis, the side faces come round in the order 3, 2, 5, 6.
3. In this ring of four, alternate faces are opposite: 3 ↔ 5 and 2 ↔ 6.

Trick: With a common top face, the four side faces form a ring — the 1st and 3rd of the ring are opposite, as are the 2nd and 4th.

Answer: (C) 2

Concept: Trace the path step by step; a left turn while going West means facing South, and a left turn while going South means facing East.

1. From A, 6 km West.
2. Left turn → South, 8 km.
3. Left turn → East, 6 km to B. The 6 km West and 6 km East cancel.
4. So B is 8 km directly South of A.

Trick: Equal and opposite moves cancel; only the unpaired 8 km South remains.

Answer: (B) South

Concept: Read the direction of the relation carefully: the first number is related to the second.

1. $3\to 2$ and $9\to 6$: the second number is $\frac{2}{3}$ of the first.
2. We need the number $x$ that is related to 12, i.e. $\frac{2}{3}\times x=12$.
3. $x=12\times \frac{3}{2}=18$. Check: $\frac{2}{3}\times 18=12$ ✓.

Trick: Here 12 plays the role of 2 and 6, so reverse the rule: multiply by $\frac{3}{2}$.

Answer: (B) 18

Concept: Note what is added at each step; here an element is added every step, alternating between curved arcs inside the circle and vertical lines beside it.

1. Fig 1: plain circle. Fig 2: two arcs added inside.
2. Fig 3: a vertical line added on the left. Fig 4: a third arc added inside.
3. Next step should add a vertical line again, on the right, keeping the left line and all three arcs.
4. Option (D) has both lines and three arcs; (C) has only two arcs, (A) and (B) have extra lines.

Trick: Alternating additions: arc, line, arc, line — count both elements in the options.

Answer: (D)

Concept: Check each letter position separately.

1. 1st letters: H, I, J → next K ($+1$).
2. 2nd letters: M, N, O → next P ($+1$).
3. 3rd letters: W, X, Y → next Z ($+1$).

Trick: Every letter moves one step forward, so the next cluster is simply each letter $+1$.

Answer: (A) KPZ

Concept: Code = sum of alphabetical positions of the letters.

1. JAM: $10+1+13=24$ ✓.
2. GEL: $7+5+12=24$ ✓.
3. LAW: $12+1+23=36$.

Trick: Remember EJOTY: E = 5, J = 10, O = 15, T = 20, Y = 25 — W = 23 is two after U = 21.

Answer: (C) 36

Concept: Find the rule linking the three numbers of each given set.

1. $(4,12,48)$: $4\times 3=12$, $12\times 4=48$.
2. $(9,27,108)$: $9\times 3=27$, $27\times 4=108$ ✓.
3. $(13,39,156)$: $13\times 3=39$, $39\times 4=156$ ✓. (A) has 146, (B) and (D) have 36.

Trick: Third number $=12\times$ first: $13\times 12=156$.

Answer: (C) (13, 39, 156)

Concept: Decide for each pair of classes whether one lies inside the other, they overlap, or they are separate.

1. Every mother is a woman, so Mother lies completely inside Women.
2. A husband is a man, so Husband has nothing in common with Women or Mother — a separate circle.
3. Option (A) shows one circle inside a bigger one and a third separate circle.

Trick: Gender-based classes (husband vs woman) are always disjoint.

Answer: (A)

Concept: Two "All" statements in a chain give Roads ⊂ Routes ⊂ Bridges.

1. I: "Some routes are roads" — since all roads are routes, the reverse "some" is always true (conversion).
2. II: "All roads are bridges" — all roads are routes and all routes are bridges, so all roads are bridges.
3. Both conclusions are certain.

Trick: All A are B + All B are C ⇒ All A are C; and All A are B ⇒ Some B are A.

Answer: (C) Both conclusions I and II follow

Concept: Each letter is written as its reverse alphabetical position ($27-\text{position}$).

1. CITY: C = 24, I = 18, T = 7, Y = 2 → 241872 ✓.
2. DRUG: D = 23, R = 9, U = 6, G = 20 → 239620 ✓.
3. GOLF: G = 20, O = 12, L = 15, F = 21 → 20121521.

Trick: Reverse position: A ↔ 26, M ↔ 14, N ↔ 13; pairs of letters always add to 27.

Answer: (B) 20121521

Concept: Decode the expression one symbol at a time and draw the family tree.

1. M × N: M is the son of N. N + P: N is the wife of P. So M is the son of P as well.
2. P % S: P is the father of S. S – T: S is the brother of T, so T is also P's child.
3. M, S and T are all children of N and P, and M is male.
4. Hence M is the brother of T.

Trick: Siblings share the same parents; the gender of the person asked about (M) decides "brother" vs "sister".

Answer: (B) Brother

Concept: Track each of the four letter positions as a separate series.

1. 1st letters: W, S, ?, K, G → $-4$ each, so O.
2. 2nd letters: T, Y, ?, I, N → $+5$ each (Y $+5$ wraps to D), so D.
3. 3rd letters: N, H, ?, V, P → $-6$ each (H $-6$ wraps to B), so B.
4. 4th letters: M, T, ?, H, O → $+7$ each (T $+7$ wraps to A), so A.

Trick: Steps of $-4,+5,-6,+7$ — verify using the term after the gap (K, I, V, H).

Answer: (B) ODBA

Concept: Track how each symbol moves among the five positions (four corners + centre).

1. Every symbol moves one step along the same route: bottom-left → top-left → centre → top-right → bottom-right → bottom-left.
2. E.g. @: top-left → centre → top-right → bottom-right; next bottom-left. !!: centre → top-right → bottom-right → bottom-left; next top-left.
3. From Fig 4, the next figure has !! top-left, μ top-right, II centre, @ bottom-left and & bottom-right.
4. This is option (A).

Trick: Follow one symbol to find the route, then verify with a second symbol before checking the options.

Answer: (A)

Concept: Each term is twice the previous term plus 2.

1. $9\times 2+2=20$, $20\times 2+2=42$, $42\times 2+2=86$.
2. $86\times 2+2=174$ ✓.
3. Next: $174\times 2+2=350$.

Trick: Differences $11,22,44,88$ double each time → next difference 176, and $174+176=350$.

Answer: (A) 350

Concept: Replace each sign by its meaning, then solve using BODMAS.

1. $+\to -$, $-\to \times$, $\times \to ÷$, $÷\to +$: $180\times 60-30÷30+20$ becomes $180÷60\times 30+30-20$.
2. $180÷60=3$, $3\times 30=90$.
3. $90+30-20=100$.

Trick: Write the converted expression fully before computing — mixing old and new signs is the usual mistake.

Answer: (C) 100

Concept: A word common to two sentences gets the code common to both codes.

1. "stay for dinner" → px rn tf.
2. "dinner is ready" → sq mv rn.
3. Common word: dinner; common code: rn.

Trick: Compare the two lists and pick the only code that repeats.

Answer: (B) rn

Concept: Interchange the two signs given in each option and test with BODMAS.

1. Option (B), swap − and ×: $10+23\times 3-63÷7$.
2. $23\times 3=69$, $63÷7=9$.
3. $10+69-9=70$ ✓.

Trick: $63÷7=9$ is clean, so keep ÷ and look for a swap that makes $23\times 3$.

Answer: (B) − and ×

Concept: Draw the path with East as $+x$ and North as $+y$ and add the moves.

1. 5 km West, left → 6 km South, left → 11 km East, left → 6 km North, right → 6 km East to B.
2. North–South: $-6+6=0$, so B is on the same line as A.
3. East–West: $-5+11+6=12$ km East. So B is 12 km East of A.
4. To return to A he must drive 12 km towards the West.

Trick: Cancel the equal opposite legs (6 S, 6 N) first; only the East–West total is left.

Answer: (A) 12 km towards the west

Concept: Compare words letter by letter from the left until they differ.

1. All start with K. 2nd letters: Kennel, Kernel, Kettle have E; Kibble, Kicker have I → the E-words come first.
2. Among Ken-, Ker-, Ket-: N < R < T → Kennel, Kernel, Kettle.
3. Kibble vs Kicker: B < C → Kibble, Kicker. Order: 2, 5, 3, 1, 4.

Trick: Group words by the first letter that differs and sort group by group.

Answer: (B) 2, 5, 3, 1, 4

Concept: Part-to-whole relationship.

1. An episode is one part of a series.
2. In the same way, a chapter is one part of a book.
3. Author writes a book (not a part–whole link); a page is a part of a chapter, not the whole; drama is a genre.

Trick: Ask "X is a part of ___?" — the answer must be the whole that contains X.

Answer: (B) Book