Q&A: practice questions with answers

Concept: Find the common jump pattern between letter positions; the cluster that breaks it is odd.

1. LPJ = 12, 16, 10 → +4, −6
2. OSM = 15, 19, 13 → +4, −6
3. MQK = 13, 17, 11 → +4, −6
4. OIP = 15, 9, 16 → −6, +7 (pattern broken)

Trick: In the three alike clusters the last letter is always 2 places before the first (L→J, O→M, M→K). OIP fails this at once.

Answer: (A) OIP

Concept: Split the 20-letter string into equal blocks and find the rule inside each block.

1. Blocks of 4: [_OSN] [R_QL] [PK_J] [NIM_] [LGK_]
2. Inside a block: −5, +4, −5 (e.g. R→M→Q→L)
3. Block starters: T, R, P, N, L (each −2)
4. Blanks: T, M (R−5), O (K+4), H (M−5), F (K−5)

Trick: Check option C on block 1 only: T−5 = O ✓, and the first letters T, R, P, N, L drop by 2 — options with V are out instantly.

Answer: (C) TMOHF

Concept: Letters common to two words share the common digits; the leftover letter takes the leftover digit.

1. JIVE → 1597, FIVE → 5781
2. Common letters I, V, E ↔ common digits 1, 5, 7
3. Extra letter F in FIVE ↔ extra digit 8 in 5781

Trick: Cancel the common digits from the second code: 5781 − {1, 5, 7} leaves 8 = F.

Answer: (C) 8

Concept: Swap the signs as told, then solve using BODMAS.

1. Swap: − ↔ ÷ and × ↔ +
2. Expression becomes $7\times 45÷15+5-12$
3. $45÷15=3$, so $7\times 3=21$
4. $21+5-12=14$

Trick: Do division first ($45÷15=3$) to keep numbers small instead of computing $7\times 45=315$.

Answer: (A) 14

Concept: Common letters ↔ common digits; the odd letter gets the odd digit.

1. CLAP → 6452, PALM → 5428
2. Common letters L, A, P ↔ common digits 4, 5, 2
3. PALM has extra M; 5428 has extra 8

Trick: Remove 4, 5, 2 from 5428 — the digit left (8) is M.

Answer: (D) 8

Concept: Find the shift of each letter position and apply the same shifts to the new word.

1. DEATH → GLITZ: +3, +7, +8, 0, +18 (GRAVE → JYIVW confirms)
2. B(2)+3 = E, E(5)+7 = L(12)
3. N(14)+8 = V(22), C+0 = C
4. H(8)+18 = Z(26) → ELVCZ

Trick: 4th letter never changes and 5th of DEATH/GRAVE pair shows H→Z; only options with C and Z remain (B, D) — first letter E picks D.

Answer: (D) ELVCZ

Concept: Decode each symbol link from left to right and build the family chain.

1. F ! L → F is L's brother; L : A → L is A's wife
2. A < S → A is S's son; S / H → S is H's father
3. So A and H are siblings (A is H's brother)
4. From H: brother (A) → his wife (L) → her brother (F)

Trick: Trace backwards from H: H → A → L → F, naming each link — brother's wife's brother.

Answer: (B) Brother's wife's brother

Concept: While unfolding, every cut is mirrored across each fold line; a cut on a fold line opens into one full hole.

1. Fold 1: top half down → crease is the horizontal middle line
2. Fold 2: right half onto left → crease is the vertical middle line
3. The rectangular cut lies on the horizontal crease edge of the folded piece
4. Unfolding gives 2 rectangles, side by side, each sitting across the horizontal middle line

Trick: Count holes = 4 copies, but cuts touching a crease merge in pairs → 4 ÷ 2 = 2 holes, symmetric about the centre.

Answer: (A) Figure (A)

Concept: Track each letter position of the clusters separately.

1. 1st letters: B, C, D, E → F
2. 2nd letters: F, G, H, I → J
3. 3rd letter: always A
4. Next term: FJA

Trick: 1st and 2nd letters always keep a gap of 4 (B→F, E→I), so F→J; only FJA fits.

Answer: (A) FJA

Concept: Facing the centre: left = clockwise, right = anticlockwise. Fix one person and place others.

1. Put C at seat 0 (clockwise numbering). Two between, from C's left → D at seat 3
2. H second to left of D → seat 5; H is I's immediate right → I at seat 6
3. K third to left of I → seat 2
4. Seats 1, 4 left; L not next to K → L = 4, G = 1
5. Third to the right of G (anticlockwise): 1 → 0 → 6 → 5 = H

Trick: Start from the most fixed clue (D–C gap) and move only in one direction (clockwise numbers) to avoid left/right confusion.

Answer: (C) H

Concept: Show subset as a circle inside another; unrelated classes as separate circles.

1. Every whale is a mammal → Whale circle inside Mammal
2. No reptile is a mammal or a whale → Reptile circle separate
3. Needed: one circle inside another + one detached circle = option (B)

Yaad rakhein: Whales breathe through lungs and feed milk to their young — that is why they are mammals, not fish.

Answer: (B) Figure (B)

Concept: Find how much the whole figure turns each step and keep all its parts unchanged.

1. Figure: two-headed arrow with a perpendicular stem ending in a hollow circle
2. Each step turns the whole figure 45° clockwise
3. 4th figure: arrow vertical, stem to the right → 5th: arrow on the ↗ diagonal, stem pointing down-right
4. Only (A) keeps the stem at 90° to the arrow with an empty circle

Trick: Reject options where the shape has not turned or where any part (filled circle, non-perpendicular stem) changed.

Answer: (A) Figure (A)

Concept: Find the exact shape (same size and slant) hidden inside an option, without rotating it.

1. (X) = one straight slanting line (bottom-left to top-right) with an arc on its upper-left side joining it at the lower end and the middle
2. In (B), edges of the two diamonds join into one such slanting line, and the curve in the left diamond matches the arc
3. (A) has an arrowhead, (C) meets at a centre, (D) has a horizontal main line

Trick: First match the longest line's slant; discard every option where that line is not at the same angle.

Answer: (B) Figure (B)

Concept: Two operations repeat by turns: $-8$, then $\times 3+2$.

1. $17-8=9$; $9\times 3+2=29$
2. $29-8=21$; $21\times 3+2=65$
3. $65-8=57$; next: $57\times 3+2$
4. $57\times 3=171$; $171+2=173$

Trick: Unit digit check: $57\times 3$ ends in 1, +2 → ends in 3. Only 173 ends in 3.

Answer: (C) 173

Concept: Facing north: left end = seat 1. Place the fixed people first.

1. Two people left of Y → Y = 3
2. Three between Y and W → W = 7
3. X second right of Y → X = 5; two between X and M → M = 2
4. Seats 1, 4, 6 for O < L < N → O = 1, L = 4, N = 6
5. Right of L: X, N, W = 3 people

Trick: Since 'O left of L left of N' and the free seats are 1, 4, 6, L must be the middle one — seat 4, so 7 − 4 = 3 to its right.

Answer: (B) Three

Concept: Letters between two letters = difference of positions − 1.

1. GUILDER in order: D, E, G, I, L, R, U
2. 4th from left = I (9), 1st from right = U (21)
3. Between: 21 − 9 − 1 = 11

Trick: Remember EJOTY: E5, J10, O15, T20, Y25 — I = 9 and U = 21 come instantly.

Answer: (C) 11

Concept: Find the letter-wise shift from the example pair and apply it.

1. YFOT → CIRX: +4, +3, +3, +4 (UBHW → YEKA same)
2. S + 4 = W, A + 3 = D
3. E + 3 = H, X + 4 = B (after Z, restart at A)
4. Answer: WDHB

Trick: First letter S+4 = W leaves only B and D; second letter A+3 = D confirms option D.

Answer: (D) WDHB

Concept: Each cut repeats in all four quarters; cuts on a crease join into single holes or notches.

1. Folds: bottom up, then right onto left → top-left quarter remains
2. Circle in the middle of the quarter → one circle in each quarter (4 circles)
3. Square at the corner of both creases → one square at the sheet's centre
4. Corner cut on top edge and vertical crease → V-notches at the middle of top and bottom edges; side edges stay straight

Trick: Check the edges first: only the edge touched by the cut gets notched — this removes (D) and (B) quickly.

Answer: (C) Figure (C)

Concept: Differences between terms form a simple pattern.

1. Differences: 2, 4, 6, 8
2. Next difference = 10
3. 730 + 10 = 740

Trick: Even-number gaps mean nth term = 710 + n(n−1): for n = 6, 710 + 30 = 740.

Answer: (C) 740

Concept: Two 'Some' statements together never give a definite conclusion.

1. I: chargers–batteries (some) and batteries–energies (some) → no fixed link
2. II: batteries and powers connect only through chargers (some + some) → no fixed link
3. Both can be false in a valid diagram

Trick: Some + Some = No conclusion. Spot it and skip the diagram.

Answer: (D) Neither conclusion (I) nor (II) follows