Q&A: practice questions with answers

Concept: Check which class lies inside another and which has nothing in common with the others.

1. Fathers ⊂ Males: every father is a male → small circle inside a big circle.
2. Females share nothing with Males or Fathers → a separate, non-touching circle.
3. Required shape: one circle inside another + one detached circle.

Trick: Think of each pair: 'Is every X a Y?' (inside), 'Can X be Y?' (no → apart). Two checks fix the diagram.

Answer: (A) Figure (a): Fathers inside Males, Females separate

Concept: From only negative ('No') statements, no definite relation between two other classes can be drawn.

1. Dates are kept away from almonds, raisins and cherries – but almonds, raisins and cherries are never linked to each other.
2. (I) 'No almond is a raisin' – almonds and raisins may or may not overlap → not certain.
3. (II) 'Some cherries are raisins' – again only a possibility → not certain.

Trick: Two negative premises → no conclusion. If every statement starts with 'No', definite conclusions about other pairs fail.

Answer: (B) Neither conclusion (I) nor (II) follows.

Concept: Swap the signs as told, then solve using BODMAS (÷, × before +, −).

1. After swapping: $27+6\times 4-24÷3$
2. $6\times 4=24$; $24÷3=8$
3. $27+24-8=43$

Trick: Rewrite the full expression first on paper; most errors come from swapping only one pair of signs.

Answer: (D) 43

Concept: A word repeated in two sentences gets the code repeated in both codes.

1. Common words: 'like', 'trees'; common codes: bv, fd.
2. In 'we like trees' → 'bv mn fd', the leftover word is 'we' and the leftover code is mn.
3. So we = mn.

Trick: Strike out common words and common codes; the single leftover pair is your answer.

Answer: (C) mn

Concept: Each position of the 3-letter group moves forward by a fixed step.

1. 1st letters: O → Q → S → U → W (+2)
2. 2nd letters: A → C → E → G → I (+2)
3. 3rd letters: S → U → W → Y → A (+2, wrapping after Z)

Trick: After Z count again from A: Y + 2 = A (25 + 2 = 27 → 27 − 26 = 1).

Answer: (B) WIA

Concept: The amount subtracted grows by a constant value each time.

1. Successive drops: 20, 25, 30, 35.
2. Gap rises by 5, so next gap = −40.
3. 85 − 40 = 45

Trick: When a series falls faster and faster, check differences of differences – here a constant 5.

Answer: (A) 45

Concept: Rearrange the word alphabetically, pick the asked positions, count letters between them.

1. HARMFUL in order: A F H L M R U
2. 3rd from left = H, 3rd from right = M
3. Between H (8) and M (13): I, J, K, L → 13 − 8 − 1 = 4

Trick: Letters between two letters = difference of positions − 1.

Answer: (A) 4

Concept: Total length 20 → look for a 5-letter block repeated 4 times.

1. The block is EGLMX.
2. Write it 4 times: EGLMX EGLMX EGLMX EGLMX.
3. Fill blanks in order: G, L, M, X, E, X, G, L

Trick: Divide total letters by a small number (4, 5, 6) to guess block length, then test with given letters.

Answer: (A) GLMXEXGL

Concept: If two faces are common in both positions (same places), the remaining faces are opposite each other.

1. Common faces in both views: 10 and 8.
2. Remaining top faces: 12 (view I) and 9 (view II).
3. So 12 is opposite 9.

Trick: Two common faces in the same position → the third faces are opposite. 10-second check.

Answer: (B) 9

Concept: Decode each symbol and build the family chain step by step.

1. P + Q: P is Q's daughter.
2. Q ÷ R: Q is R's father; R − S: R is S's brother → P and S are both Q's daughters (sisters).
3. S × T: S is T's wife → P is the sister of T's wife.

Trick: Mark gender (+ male, − female) while decoding; the final link usually decides between 'sister' and 'wife's sister'.

Answer: (A) Wife's sister

Concept: Fix definite positions first (ends, exact counts), then place the rest.

1. E at seat 1 (no one to its left); G at seat 6 (four between).
2. Three to the right of F → F at seat 4.
3. L–M together → seats 2, 3. K not next to F → K at seat 7, H at seat 5.
4. Order: E L M F H G K → rightmost is K.

Trick: Number seats 1–7 left to right and convert every clue into a seat number.

Answer: (C) K

Concept: Find the shift for each letter position and apply it to the new word.

1. NAVI → QCYK: +3, +2, +3, +2 (ZIHQ → CKKS confirms).
2. IOQW with the same +3/+2 steps gives L, Q, T, Y in turn.
3. Result: LQTY

Trick: Once the first two letters give L and Q, only (c) and (d) remain; the 3rd letter T decides.

Answer: (C) LQTY

Concept: The series alternates between two designs.

1. Figures 1 and 3 are the same; figures 2 and 4 are the same (dot shifted to the bottom-left).
2. Figure 5 is an odd position → it must match figures 1 and 3.
3. Only option (c) has that design.

Trick: In figure series always compare 1st with 3rd and 2nd with 4th – alternate repetition is very common.

Answer: (C) Figure (c)

Concept: Convert letters to positions and compare the internal steps.

1. HEI = 8, 5, 9 → −3, +4
2. QNR = 17, 14, 18 → −3, +4; GDH = 7, 4, 8 → −3, +4
3. DBE = 4, 2, 5 → −2, +3 → odd one.

Trick: Another quick view: 3rd letter is always 1st letter + 1 (H→I, Q→R, G→H, D→E); then the middle letter decides.

Answer: (C) DBE

Concept: Unfold step by step; each opening creates a mirror image of the holes across the fold line.

1. Two folds → 4 layers → the punch gives 4 holes.
2. Open the second (vertical) fold: hole mirrored left ↔ right.
3. Open the first (horizontal) fold: both holes mirrored top ↔ bottom → option (b).

Trick: Count first: holes = punches × 2^{number of folds}; eliminate options with the wrong count, then check mirror symmetry.

Answer: (B) Figure (b)

Concept: Facing the centre: left = clockwise, right = anticlockwise.

1. Seat Y; U immediately anticlockwise of Y.
2. R three places clockwise of Y; Q two places clockwise of Y.
3. Empty seats: next to Y (clockwise) and between R and U. S not next to Y → S between R and U; T next to Y.
4. From S going right (anticlockwise): R, Q, then T → two people between.

Trick: Draw 6 dots, fix one person, and turn every 'left/right' into clockwise/anticlockwise before placing.

Answer: (A) Two

Concept: Look for the exact figure – same size, same direction – hidden inside an option.

1. Key parts: a vertical line, a right-then-up slanting branch from its middle, and a base line ending in a small circle.
2. Options (a), (b), (c) have the circle but not the full joined shape in this orientation.
3. Option (d) contains all three parts exactly.

Trick: Pick the most unusual part (here the slanting branch) and scan options for it first – fastest elimination.

Answer: (D) Figure (d)

Concept: Every letter moves forward by the same number.

1. E→H, W→Z, H→K, O→R: each +3 (OPQM → RSTP also +3).
2. LTOG: L→O, T→W, O→R, G→J
3. Result: OWRJ

Trick: First letter L+3 = O leaves (a) and (b); second letter T+3 = W picks (a).

Answer: (A) OWRJ

Concept: Two series are mixed: odd places and even places follow separate rules.

1. Odd places: 901, 902, 903, 904 (+1 each).
2. Even places: 888, 887, 886 (−1 each).
3. 8th term is in the even series: 886 − 1 = 885

Trick: Numbers jumping up and down around a value usually mean two interleaved series.

Answer: (A) 885

Concept: Each letter's code = 30 − its alphabet position.

1. X (24) + 6 = 30, E (5) + 25 = 30 → code = 30 − position (UBHW fits too).
2. Q is 17 → 13; C is 3 → 27
3. J is 10 → 20; R is 18 → 12 → code 13-27-20-12

Trick: Add a letter's position to its code; if every sum is the same (30), use subtraction directly.

Answer: (C) 13-27-20-12