Q&A: practice questions with answers

Concept: Sort the letters A→Z and compare slot by slot with the original word.

1. Original: M O D U L E S
2. Sorted: D E L M O S U
3. Slot-wise pairs: M/D, O/E, D/L, U/M, L/O, E/S, S/U – no pair matches.
4. So 0 letters keep their place.

Trick: Check only the 1st and last slots first (M≠D, S≠U); then scan the middle – saves time.

Answer: (C) Zero

Concept: Each letter of the first cluster is shifted by a fixed number of places.

1. J→L, G→I, K→M, H→J: every letter +2.
2. Check: V→X, S→U, W→Y, T→V (+2) ✔
3. WTXU +2 → W→Y, T→V, X→Z, U→W = YVZW.

Trick: Option B, C, D have 'Y' as 3rd letter, but X+2 = Z – only (A) has Z.

Answer: (A) YVZW

Concept: Unfolding works like a mirror at every crease; 2 folds turn 1 punch into 4.

1. Fold 1: top half down; fold 2: left half onto right → punch sits in the bottom-right quarter.
2. Open the vertical fold: the mark is mirrored into the bottom-left quarter.
3. Open the horizontal fold: both marks are mirrored into the top half.
4. Result: 4 marks, each a mirror image of its neighbour across the crease – figure (D).

Trick: Look at the slant of the line: across a crease it must flip direction (\ becomes /). Reject options where neighbours slant the same way.

Answer: (D) Figure (D)

Concept: Treat the 1st, 2nd and 3rd letters as three separate series.

1. 1st letters: D, G, J, M → +3 → P
2. 2nd letters: M, P, S, V → +3 → Y
3. 3rd letters: W, Z, C, F → +3 (wraps after Z) → I
4. Next term = PYI.

Trick: Only one option starts with P (M+3) – pick it in 5 seconds.

Answer: (C) PYI

Concept: Fix the extreme-gap clue first; 5 people between two persons in a row of 7 means both sit at the ends.

1. H, G at ends; L is immediate left of G, so G = seat 7, L = 6, H = 1.
2. One person between L and I → I = seat 4.
3. Seats 2, 3, 5 remain for M, J, K with M < J < K → M = 2, J = 3, K = 5.
4. Row: H M J I K L G → left of J: H, M = 2 persons.

Trick: 'n−2 people between two persons' in a row of n ⇒ they occupy the two ends.

Answer: (C) Two

Concept: The same symbol string rotates by a fixed angle at each step.

1. Box 1: string vertical (reads downwards).
2. Box 2 → 3 → 4: it turns 45° anticlockwise each time (diagonal, horizontal, rising diagonal).
3. One more 45° anticlockwise turn makes it vertical again, reading from bottom to top – matching figure (D).

Trick: Track just one end symbol (e.g. the square) – see where it points next; ignore the rest.

Answer: (D) Figure (D)

Concept: A conclusion follows only if it is true in every possible diagram.

1. Cabinets ⊂ Shelves, but shelves can lie outside racks → (I) 'All shelves are racks' is not certain.
2. Drawers ⊂ Racks; the cabinet–rack overlap may miss the drawers completely → no shelf need be a drawer, so (II) fails.
3. Neither conclusion follows.

Trick: 'All A are B' never gives 'All B are A'. And two 'Some' links via a middle term give no definite result.

Answer: (A) Neither conclusion (I) nor (II) follows

Concept: Code = (sum of alphabet positions) − a constant.

1. QBYA → Q17, B2, Y25, A1; total 45, and 45 − 11 = 34 ✔
2. TZKI → T20, Z26, K11, I9; total 66, and 66 − 11 = 55 ✔
3. FWNP → F6, W23, N14, P16; total 59, so code = 59 − 11 = 48.

Trick: Use EJOTY (5, 10, 15, 20, 25) to read positions fast: W = Y−2 = 23, P = O+1 = 16.

Answer: (B) 48

Concept: Split into 4-letter groups and find the pattern inside a group and between groups.

1. Groups: _ZVR, U_TP, SV_N, QTP_, ORN_.
2. Inside each group: +3, −4, −4 (e.g. S→V→R→N).
3. Group starts fall by 2: W, U, S, Q, O → first blank W.
4. Fill: WZVR, UXTP, SVRN, QTPL, ORNJ → W X R L J.

Trick: First blank must be Z−3 = W → only (C) and (D) remain; second blank U+3 = X → (D).

Answer: (D) WXRLJ

Concept: Swap the signs first, then solve by BODMAS.

1. Swap $+\leftrightarrow ÷$ and $-\leftrightarrow \times$: $18+15÷5-3\times 4$
2. $15÷5=3$, $3\times 4=12$
3. $18+3-12=9$

Trick: Rewrite the whole expression with new signs before calculating – most errors come from swapping in the head.

Answer: (B) 9

Concept: Find the constant shift between corresponding letters.

1. L(12)→T(20), N→V, P→X, R→Z: each +8.
2. FHJL→NPRT is also +8 ✔
3. ZBDF +8: Z→H (wraps), B→J, D→L, F→N = HJLN.

Trick: All options start with HJ; the 3rd and 4th letters must also be 2 apart (D, F) → only HJLN keeps the gap of 2.

Answer: (C) HJLN

Concept: Write positions and compare the gaps inside each cluster.

1. GID: 7, 9, 4 → +2, −5
2. PRM: 16, 18, 13 → +2, −5
3. HJE: 8, 10, 5 → +2, −5
4. DGB: 4, 7, 2 → +3, −5 ✘ – odd one.

Trick: In the three alike clusters, the 1st and 3rd letters are 3 apart (G/D, P/M, H/E); for DGB they are only 2 apart.

Answer: (D) DGB

Concept: If every pair of classes partly overlaps and none contains another, draw three intersecting circles.

1. Some employees are males, some are not (female employees).
2. Some males are engineers; some engineers are female.
3. Some engineers are not employees (self-employed).
4. All three overlap partly → three intersecting circles, figure (C).

Trick: Think of one person in each region: e.g. a male engineer-employee proves the common centre exists.

Answer: (C) Figure (C)

Concept: Letters common to two words share the digits common to their codes.

1. REST = 3149, SEAT = 4398.
2. Common letters: E, S, T; common digits: 3, 4, 9.
3. REST's leftover letter R ↔ leftover digit 1.

Trick: Just find the digit in the first code missing from the second code – that is R.

Answer: (A) 1

Concept: When first differences are irregular, check the differences of differences.

1. Differences: 3, 10, 17, 24
2. These rise by 7 → next difference = 31
3. 65 + 31 = 96

Trick: Unit digit check: 65 + 31 ends in 6 → only 96 fits.

Answer: (D) 96

Concept: Start from the person asked about (T) and climb the tree step by step.

1. S is Q's husband and T is S's daughter → Q is T's mother.
2. R is Q's father → R is T's mother's father.
3. P is R's brother → P is T's mother's father's brother.

Trick: Read from T upward: mother → her father → his brother. Write each link as you go.

Answer: (C) Mother's father's brother

Concept: The exact shape (X), same size and orientation, must be traceable inside the option.

1. (X): a base line with two peaks above it and a V below, all meeting the base at its ends and middle.
2. In figure (C), the central horizontal line acts as this base; the peaks touch the top and the V closes at the bottom.
3. No rotation is needed – every line of (X) is present in (C).

Trick: Locate the most distinctive part first (the V under the base), then verify the rest.

Answer: (C) Figure (C)

Concept: Facing the centre: immediate left = next seat clockwise, immediate right = next seat anticlockwise.

1. Clockwise links: Q→P→R (P left of Q, R left of P).
2. T is immediate left of R → T comes right after R clockwise.
3. T→S→U (S left of T, U right of S).
4. Order: Q, P, R, T, S, U and V in the last seat → V sits between U and Q.

Trick: With 7 seats and 6 people chained, the left-over person always fills the gap between the two chain ends.

Answer: (B) V

Concept: Consecutive differences form an arithmetic pattern.

1. Differences: 20, 22, 24, 26, 28
2. Next difference = 30
3. 200 + 30 = 230

Trick: Even-step differences: the answer must end in 0 and lie just above 200 → 230.

Answer: (D) 230

Concept: Each crease reflects the cut; two folds give four mirror-image cuts.

1. Folds: top onto bottom, then left onto right → cut lies in bottom-right quarter.
2. Vertical crease: bottom-left copy has the slant reversed left-to-right, line still at the bottom.
3. Horizontal crease: top copies are upside-down versions of the bottom ones.
4. The pattern of four symmetric marks matches figure (C).

Trick: The final figure must be symmetric about both creases – fold the option in your mind and see if all marks overlap.

Answer: (C) Figure (C)