Q&A: practice questions with answers

Concept: Find the option that contains figure (X) exactly, in the same size and orientation (no rotation).

1. Key feature of (X): a right triangle whose hypotenuse goes from bottom-left to top-right, with three lines starting from the middle of that hypotenuse.
2. In option (b) the square's diagonal acts as the hypotenuse; its base and right side complete the triangle.
3. The three inner lines of (b) meet at the square's centre = mid-point of the diagonal, so (X) fits perfectly.
4. Options (a), (c), (d) have no full corner-to-corner slanting line, so (X) cannot be traced.

Trick: First locate the longest line of (X) (here the slanting side) in each option; reject options without it.

Answer: (B) Option figure (b)

Concept: The series is made of repeating 4-letter blocks; each position of the block changes by a fixed step.

1. Split into blocks: _YSX | R_QV | PU_T | NSM_ | LQK_.
2. 1st letters: ?, R, P, N, L → step −2, so first blank = T.
3. 2nd letters: Y, ?, U, S, Q → blank = W. 3rd letters: S, Q, ?, M, K → blank = O.
4. 4th letters: X, V, T, ?, ? → R, then P.
5. Blanks in order: T, W, O, R, P.

Trick: Check only the first blank: block 2 starts with R, so blank 1 = T (R+2). Options with T: (c), (d); second blank W (between Y and U) fixes (d).

Answer: (D) TWORP

Concept: If two classes are separate parts of a bigger class, draw two non-touching circles inside one large circle.

1. Hands and Eyes are both parts of the Body → both inside the Body circle.
2. A hand is never an eye → the two small circles do not overlap.
3. Option (d) shows exactly this: one big circle with two separate circles inside.

Yaad rakhein: Same pattern: Country – State – another State; Tree – Leaves – Roots.

Answer: (D) Option figure (d)

Concept: Fix the person with the most definite clue first, then place others around him.

1. 'Only L is to the right of N' → N at seat 6, L at seat 7 (seats 1–7 from left).
2. One person between M and N → M at seat 4.
3. Two people between T and M → T at 1 (seat 7 is taken).
4. Seats 2, 3, 5 left for S, B, A with order S…B…A → S = 2, B = 3, A = 5.
5. Between S (2) and A (5): B and M → 2 people.

Trick: Phrases like 'only X sits to the right' instantly fix the extreme seats – start there.

Answer: (B) Two

Concept: Arrange the letters A→Z and compare position by position with the original word.

1. Original: G L O R I F Y.
2. Sorted: F G I L O R Y.
3. Compare: G/F, L/G, O/I, R/L, I/O, F/R differ; 7th place Y = Y.
4. Only 1 letter stays in place.

Trick: The largest letter (Y) already at the end will always stay unchanged – check the first/last letters first.

Answer: (C) 1

Concept: Swap the signs as told, then solve using BODMAS.

1. Given: $72+5-42\times 7÷1$.
2. After swapping (× ↔ ÷, + ↔ −): $72-5+42÷7\times 1$.
3. $42÷7\times 1=6$.
4. $72-5+6=73$.

Trick: Rewrite the full expression with new signs before calculating – most mistakes come from swapping only one pair.

Answer: (C) 73

Concept: Differences between consecutive terms increase by 1.

1. Differences: 10, 11, 12, 13.
2. Next difference = 14.
3. 356 + 14 = 370.

Trick: Last digits: 0, 0, 1, 3, 6 → next must end in 0 (6 + 4 = 10). Only 370 ends in 0.

Answer: (D) 370

Concept: Each term is 10 more than the previous one.

1. 729 − 719 = 10, 739 − 729 = 10, 769 − 759 = 10.
2. Missing term = 739 + 10 = 749.
3. Check: 759 − 749 = 10 ✓.

Trick: Units digit stays 9 in every term – only 749 ends in 9.

Answer: (D) 749

Concept: Two 'some' (particular) statements together never give a definite conclusion.

1. (I) superstars–actors and actors–producers are both 'some' → no definite link superstars–producers.
2. (II) actors and writers are each linked only to superstars by 'some' → no definite link.
3. A valid diagram exists in which both pairs stay apart, so neither conclusion is certain.

Trick: Some + Some = No conclusion. If every statement is 'some', any new pair (not given directly) fails.

Answer: (B) Neither conclusion (I) nor (II) follows.

Concept: When facing the centre, 'right' means moving anticlockwise; build the circle by going right from one person.

1. Start at F; J is immediately right of F.
2. Three people between F and H (counting right from F) → F, J, _, _, H; L–G pair (G right of L) fills it: F, J, L, G, H.
3. Two people between K and J counting right from K → K after H, then E, then F: order F, J, L, G, H, K, E.
4. From E going right: F(1), J(2), L(3), G(4).

Trick: In a 7-seat circle, 4th to the right = 3rd to the left: left of E are K, H, G → G.

Answer: (B) G

Concept: Find the gaps between letters using alphabet positions.

1. KAQ: 11 → 1 (−10) → 17 (+16).
2. RHX: 18 → 8 (−10) → 24 (+16).
3. WMC: 23 → 13 (−10) → 3 (+16, wrapping after Z).
4. QEU: 17 → 5 (−12) → 21 (+16) ✗ – first gap differs.

Trick: Compare only the first gap: K−A, R−H, W−M are all 10; Q−E is 12 → odd one.

Answer: (D) QEU

Concept: Each letter shifts forward by its position number.

1. ADGI → BFJM: +1, +2, +3, +4.
2. EHLN → FJOR: same steps ✓.
3. Apply to GKPQ: G→H (+1), K→M (+2), P→S (+3), Q→U (+4) → HMSU.

Trick: First letter G+1 = H leaves (b) and (c); second letter K+2 = M picks (b).

Answer: (B) HMSU

Concept: Code = (number of letters) − 2.

1. DSBQCA has 6 letters → 6 − 2 = 4 ✓.
2. SJTB has 4 letters → 4 − 2 = 2 ✓.
3. XTPLIKAE has 8 letters → 8 − 2 = 6.

Trick: When codes are small single numbers and words are random letters, first try the letter count.

Answer: (C) 6

Concept: Every cut on a sheet folded twice appears 4 times on opening, as mirror images across each fold line.

1. Two folds (horizontal, then vertical) → 4 layers, so each cut repeats in all 4 quarters.
2. The circle cut at the folded corner → one circle near each of the 4 corners.
3. The arch → 4 arches; the two in the lower half are flipped (mirror of the upper half).
4. Only option (a) shows 4 circles and 4 correctly mirrored arches.

Trick: Count first: 2 folds = 4 copies of each cut. Reject options with fewer shapes, then check mirror direction.

Answer: (A) Option figure (a)

Concept: Treat each letter position of the term as a separate series.

1. 1st letters: D, B, Z, X → −2 each → V.
2. 2nd letter = 1st letter → V.
3. 3rd letters: I, D, Y, T → −5 each → O.
4. Next term = VVO.

Trick: All options start with VV, so only the third letter matters: T − 5 = O.

Answer: (B) VVO

Concept: Letters move by fixed steps and the number increases by a fixed value.

1. KB → SK: K+8 = S, B+9 = K; BP → JY: B+8 = J, P+9 = Y.
2. Numbers: 23 + 27 = 50, 12 + 27 = 39.
3. MH 31 → M+8 = U, H+9 = Q, 31 + 27 = 58 → UQ 58.

Trick: Number part alone: 31 + 27 = 58 leaves (a) and (d); first letter M+8 = U picks (d).

Answer: (D) UQ 58

Concept: Faces adjacent to a face can never be opposite to it.

1. 3 appears on top in both positions → same face, the dice only rotated around it.
2. 1, 2 (first view) and 4, 5 (second view) are all side faces touching 3.
3. So none of 1, 2, 4, 5 is opposite 3; the only face left, 6, is opposite 3.

Trick: List the 4 numbers seen next to a common face; the missing sixth number is opposite it.

Answer: (A) 3

Concept: $\text{Code}=4\times (\text{number of letters})$.

1. NFTBZ: 5 letters → $5\times 4=20$ ✓.
2. ZOQ: 3 letters → $3\times 4=12$ ✓.
3. GZFESITY: 8 letters → $8\times 4=32$.

Trick: Both codes are multiples of 4 and of the letter count – divide code by length to find the multiplier quickly.

Answer: (D) 32

Concept: Decode each symbol one by one and link the family members.

1. P + Q: P is daughter of Q (P is female).
2. Q × R: Q is wife of R → Q, R are P's parents.
3. R ÷ S: R is father of S → S is P's sibling.
4. S − T: S is brother of T → T is also a child of R and Q.
5. So P (female) is the sister of T.

Trick: Gender of P is fixed at the first symbol ('daughter'); siblings via the same father → sister.

Answer: (C) Sister

Concept: Track one element at a time: its position changes by a fixed turn each step.

1. The small triangle goes top → left → bottom → right: a 90° anticlockwise move each step.
2. Next step: the triangle returns to the top, with the other symbol below it.
3. The symbols themselves stay upright and a new symbol appears each time.
4. Option (d) alone matches: triangle up, fresh upright circle under it.

Trick: Fix the triangle's position first – it eliminates options (b) and (c) at once.

Answer: (D) Option figure (d)