RRB ALP CBT 1 2025 PYQs

Concept: Find one rule that fits both given pairs.

1. $21\times 4-1=83$ ✓
2. $33\times 4-1=131$ ✓
3. $43\times 4-1=172-1=171$

Short trick: Second number ≈ 4 × first (83 ≈ 84, 131 ≈ 132), so the answer must be just below 172 → 171.

Answer: (B) 171

Concept: Each letter moves forward by +5, +4, +3, +2.

1. 	1st	2nd	3rd	4th
   DTWM→IXZO	D+5=I	T+4=X	W+3=Z	M+2=O
   KRHF→PVKH	K+5=P	R+4=V	H+3=K	F+2=H
   SLCO→?	S+5=X	L+4=P	C+3=F	O+2=Q

2. So SLCO → XPFQ.

Short trick: Only the last letter differs between XPFR and XPFQ: O + 2 = Q, so pick XPFQ.

Answer: (B) XPFQ

Concept: Fix the definite clues first (C, then G, then D), then place the pairs.

1. Only one above C → C = 6.
2. Two between G and C → G = 3.
3. One between D and G → D = 1 or 5; D ≠ 1 → D = 5.
4. F just below E: free floors 1, 2, 4, 7 → only 1–2 are consecutive → F = 1, E = 2.
5. Two between F and B → B = 4; A = 7.

Short trick: Once F = 1 is fixed, “two persons between F and B” directly gives B = 1 + 3 = 4.

Answer: (A) Floor number 4

Concept: Track the coordinates step by step (east = +x, north = +y).

1. A(0, 0) → north 5 → (0, 5).
2. Right (east) 8 → (8, 5); right (south) 3 → (8, 2).
3. Right (west) 2 → (6, 2); left (south) 2 → B(6, 0).
4. B is 6 m due east of A, so she must walk towards west.

Short trick: Net north–south = 5 − 3 − 2 = 0, so A and B are on the same horizontal line; net east = 8 − 2 = 6 → go west.

Answer: (A) West

Concept: Look for the pattern Even – Odd – Odd (middle one is counted).

1. Scan: 4 3 1, 6 3 1, 8 9 7.
2. No other odd digit has an even digit before it and an odd digit after it.
3. Count = 3.

Short trick: First mark every even digit, then check only the two digits right after it – much faster than checking every digit.

Answer: (B) THREE

Concept: Every letter moves back 8 places (wrapping around Z→A).

1. Position	KEV	CWN	UOF	MGX	?
   1st (−8)	K	C	U	M	E
   2nd (−8)	E	W	O	G	Y
   3rd (−8)	V	N	F	X	P

2. M − 8 = E, G − 8 = Y (7 − 8 + 26 = 25), X − 8 = P.

Short trick: Check only the middle letter: G − 8 = Y (G→F→…→Y backwards); only EYP has Y in the middle.

Answer: (A) EYP

Concept: Place the fixed person, then the blocks of two consecutive days.

1. C = Friday; one between C and B → B = Wednesday (Sunday not allowed).
2. Free: Mon, Tue, Thu, Sat, Sun. Consecutive pairs available: Mon–Tue and Sat–Sun.
3. A–D cannot end on Sunday → A–D = Mon–Tue; G–F = Sat–Sun.

4. Mon	Tue	Wed	Thu	Fri	Sat	Sun
   A	D	B	E	C	G	F

5. E = Thursday.

Short trick: Two blocks of 2 need two pairs of consecutive free days; the lone free day left (Thursday) must be E’s.

Answer: (C) Thursday

Concept: Find net east–west and net north–south displacement.

1. East–west: +51 − 56 + 5 = 0.
2. North–south: −56 + 63 = +7 (P is 7 km north of A).
3. So he must drive 7 km towards south.

Short trick: Opposite legs cancel: east 51 + 5 = west 56; north 63 − south 56 = 7 → 7 km south.

Answer: (C) 7 km to the south

Concept: Letters shift +8; number is cubed.

1. DM3: D+8 = L, M+8 = U, $3^3=27$ → LU27 ✓
2. AR12: A+8 = I, R+8 = Z, ${12}^3=1728$ ✓
3. DK13: D+8 = L, K+8 = S, ${13}^3=2197$ → LS2197.

Short trick: Only option A ends in a perfect cube of 13 (2197); unit digit of ${13}^3$ = $3^3$ → 7.

Answer: (A) LS2197

Concept: Check each statement alone, then both together.

1. (I): I is 3rd from the bottom. L, D adjacent with L above → (D, L) at positions 1–2 or 4–5. Tallest unknown.
2. (II) alone says only M > D – not enough.
3. Together: if D = 4, L = 5 then M > D is impossible → D = 1, L = 2. Positions 4 and 5 go to M and O in either order → tallest still unknown.

Short trick: After combining, two poles (M, O) still have no relation between them – so the tallest cannot be fixed.

Answer: (A) Data in both statements I and II together are not sufficient to answer the question.

Concept: Pattern needed: Vowel – Consonant – Consonant.

1. Check the letter after every vowel: U N M ✓, E C S ✓, U M U → M followed by U ✗, U T E ✗, E W X ✓, E Q A ✗, A Z S ✓, I O → O is vowel, O P L ✓.
2. Count = 5.

Short trick: Start only at vowels (U, U, U, E, E, A, I, O) – 8 checks instead of 33.

Answer: (A) 5

Concept: All A are B + All B are C ⇒ All A are C; “All B are C” also gives “Some C are B”.

1. All farmers ⊂ graduates ⊂ employees.
2. (I) Some employees are graduates – conversion of “All graduates are employees” ✓
3. (II) All farmers are employees ✓

Short trick: In an “All–All” chain, the outermost circle contains everything inside → both follow.

Answer: (B) Both conclusions (I) and (II) follow

Concept: Decode symbol by symbol, left to right.

1. W − Q: W is the daughter of Q (W is female).
2. Q * F: Q is the father of F → W and F are siblings.
3. F * E: F is the father of E.
4. So W is the sister of E’s father.

Short trick: W is a female of the generation just above E (father’s side) → father’s sister; “Mother” is ruled out since W is F’s sibling.

Answer: (D) Father's sister

Concept: Swap the signs first, then apply BODMAS.

1. After interchange: 18 + 36 × 10 ÷ 20 − 34.
2. 36 × 10 ÷ 20 = 18.
3. 18 + 18 − 34 = 2.

Short trick: Rewrite the whole expression once with new signs before calculating – avoids sign errors.

Answer: (B) 2

Concept: Facing north: left = left end, right = right end. Fix absolute positions first.

1. 3 to the right of J → J = 4. 2 to the left of P → P = 3.
2. K third to the right of P → K = 6. M immediately left of P → M = 2.
3. Remaining 1, 5, 7: L–O with three between → (1, 5). O ≠ 1 (immediate left of M) → O = 5, L = 1, N = 7.

Short trick: The question is answered by one clue: “M sits to the immediate left of P”.

Answer: (B) M

Concept: Decode each symbol from left to right.

1. D # M: D is the daughter of M.
2. M + S: M is the wife of S → D is S’s daughter.
3. S @ P: S is the brother of P.
4. P − R: P is the father of R.
5. D = daughter of R’s father’s brother (cousin).

Short trick: Go from R upward: R → father P → P’s brother S → S’s daughter D.

Answer: (B) Father's brother's daughter

Concept: Each position follows its own step.

1. 1st: T U V W → X (+1).
2. 2nd: K L M N → O (+1).
3. 3rd: B G L Q → V (+5).
4. Answer XOV.

Short trick: First two letters must be X, O → only XOV.

Answer: (D) XOV

Concept: Check each statement alone.

1. (I): C is taller than only two poles; I < C and N < I ⇒ these two are N and I, so N < I < C ⇒ N is the shortest ✓
2. (II): H > L says nothing about the others ✗

Short trick: “Taller than only two” + two poles named below it → those are the bottom two; the lower of them is the shortest.

Answer: (A) Data in statement I alone is sufficient to answer the question while data in statement II is not

Concept: Pattern needed: Consonant – Vowel – Vowel.

1. Vowels in the series: U (N U Y), O (R O N), A (W A at the end).
2. U is followed by Y (consonant), O by N, and A is the last letter.
3. No vowel is followed by a vowel → count = 0.

Short trick: Only 3 vowels exist and none sits next to another vowel → None.

Answer: (A) None

Concept: Find the common operation in both pairs.

1. 14 + 12 = 26; 32 + 12 = 44 → rule: add 12.
2. 29 + 12 = 41 ✓; 40 → 52 (not 54); 56 → 68 (not 69); 70 → 82 (not 83).

Short trick: Just subtract: only 41 − 29 = 12.

Answer: (A) 29 - 41