RRB NTPC Graduate CBT 1 2024 PYQs

Concept: Rule: (first)${}^2$ − third = second.

1. $(19,354,7)$: ${19}^2-7=361-7=354$ ✓
2. $(9,73,8)$: $81-8=73$ ✓
3. (D) $(3,-10,19)$: $9-19=-10$ ✓
4. Others fail: ${39}^2-10=1511$, ${28}^2-5=779$, ${22}^2-2=482$.

Trick: A negative middle number hints at subtraction of a larger third number.

Answer: (D) $(3,-10,19)$

Concept: Check every condition on 7 1 6 2 8, then write the codes.

1. Condition 1: 7 and 1 are odd → not applicable.
2. Condition 2: last digit 8 is even → not applicable.
3. Condition 3: 3rd digit 6 and 4th digit 2 are even → their codes T and * interchange.
4. Codes: 7 → Z, 1 → J, then * , T, 8 → Q → Z J * T Q.

Trick: Test all conditions first; usually only one applies.

Answer: (C) Z J * T Q

Concept: Decode each symbol and draw the family tree.

1. M × N: M is the wife of N.
2. N − O: N is the brother of O; O + P: O is the sister of P → N, O, P are siblings (P male as he is a father).
3. P ÷ Q: P is the father of Q → N is Q's father's brother.
4. M, wife of N → Q's father's brother's wife.

Trick: Go step by step from Q back to M: father → brother → wife.

Answer: (A) Father's Brother's Wife

Concept: Find the rule from a pair and test the options; each letter moves by the same step.

1. Try # = KRL: K$-2$=I, R$-2$=P, L$-2$=J → KRL : IPJ means each letter $-2$.
2. Apply to NUO: N$-2$=L, U$-2$=S, O$-2$=M → LSM.
3. So # = KRL and % = LSM.

Trick: When three options share #, test the common one first, then match %.

Answer: (D) # = KRL, % = LSM

Concept: Fix the definite clues (product, sum) first, then place the pair.

1. C is on a prime floor and $C\times B=8$: only $C=2,B=4$ works ($8=2\times 4$; $1\times 8$ not possible).
2. $B+D=7\Rightarrow D=3$.
3. Free floors: 1, 5, 6. E immediately above F ⇒ F = 5, E = 6, so A = 1.
4. Between A (1) and D (3) lives only C (floor 2) ⇒ 1 person.

Trick: Product clues with floors 1–6 have very few factor pairs – start there.

Answer: (A) 1

Concept: Check each number: the element just before it must be a number and the one just after it a symbol.

1. Number 5 (7th place): preceded by 4, followed by © ✔.
2. Number 1 (18th place): preceded by 6, followed by £ ✔.
3. Others fail, e.g. 4 (6th) is preceded by #, 8 (21st) is followed by 4, and the last 4 has nothing after it.

Trick: Scan only the number-number pairs (4 5, 6 1, 9 8, 8 4) and look at what follows the second number.

Answer: (D) 2

Concept: Look at successive differences.

1. $302-300=2,300-296=4,296-290=6,290-282=8$.
2. Differences increase by 2, so next difference = 10.
3. $282-10=272$.

Trick: Even numbers subtracted: −2, −4, −6, −8, −10.

Answer: (B) 272

Concept: Compare the letter shift from first cluster to second, letter by letter.

1. BI → GN: B+5 = G, I+5 = N.
2. GN → LS: G+5 = L, N+5 = S; HO → MT: H+5 = M, O+5 = T.
3. TA → YE: T+5 = Y but A+4 = E ✘.

Trick: Use positions: T(20)→Y(25) is +5, A(1)→E(5) is only +4.

Answer: (D) TA-YE

Concept: Code = sum of reverse alphabet positions of the letters + 7 (reverse position: A = 26 … Z = 1).

1. QBOE: $10+25+12+22=69$, $69+7=76$ ✔.
2. DWIJ: $23+4+18+17=62$, $62+7=69$ ✔.
3. YAPC: $2+26+11+24=63$, $63+7=70$.

Trick: Equivalent shortcut: code $=115-(\text{sum of forward positions})$; YAPC: $115-45=70$.

Answer: (D) 70

Concept: Facing the centre: right = anticlockwise, left = clockwise.

1. Fix P. Going right of P, two people between ⇒ T is 3rd seat to P's right.
2. Two between T and V (V cannot be P) ⇒ V is immediately left of P. Three between P and Q ⇒ Q is 4th to P's right (next to T).
3. Seats left: R, U, S. R immediately left of U ⇒ R is right next to P, U next to R, S between Q and V.
4. Counting from Q's left: Q → T → U ⇒ only T between.

Trick: In a 7-seat circle, 'two between' one way means 'three between' the other way – use it to fix seats fast.

Answer: (C) 1

Concept: Place the person with a fixed position first, then fit the consecutive pairs.

1. Only two after B ⇒ B = Friday.
2. Two between B and C ⇒ C = Tuesday.
3. Left: Mon, Wed, Thu, Sat, Sun. Pairs G-H and F-E need consecutive days with H before F ⇒ G-H = Wed-Thu, F-E = Sat-Sun.
4. Remaining day Monday ⇒ D.

Trick: Only two consecutive gaps remain (Wed-Thu, Sat-Sun) – the order clue decides which pair goes where.

Answer: (B) Monday

Concept: Number the letters 1-2-3-4 and track their positions.

1. BORE → EOBR = 4-2-1-3; EOBR → ORBE = 2-4-3-1. RUST → TURS → USRT follows the same.
2. JUSL → 4-2-1-3 = LUJS ✔; LUJS → 2-4-3-1 = USJL ✔.
3. TORN → NOTR fits, but NOTR → 2-4-3-1 gives ORTN, not ROTN, so (A) fails; (C), (D) fail at the first step.

Trick: Test only step 1 (4-2-1-3) first – it eliminates most options.

Answer: (B) JUSL - LUJS - USJL

Concept: Change each digit by the rule, then add the required digits.

1. 7135624: odd digits +2 (7→9, 1→3, 3→5, 5→7), even digits +3 (6→9, 2→5, 4→7).
2. New number: 9357957.
3. First two: $9+3=12$; last two: $5+7=12$; total $=24$.

Trick: Only the four end digits matter: 7, 1 and 2, 4 → 9, 3 and 5, 7.

Answer: (A) 24

Concept: Track each letter position of the 3-letter groups separately.

1. 1st letters: T → Z → F → L → R (+6 each, wrapping Z → F).
2. 2nd letters: C → I → O → U → A (+6).
3. 3rd letters: L → R → X → D → J (+6).

Trick: All three letters move +6 – shift the last term LUD by 6: RAJ.

Answer: (A) RAJ

Concept: Replace each sign by its meaning, then apply BODMAS.

1. $45-2÷9+16\times 8$ becomes $45\times 2+9-16÷8$.
2. $=90+9-2$.
3. $=97$.

Trick: Do the swap carefully in one go: $-\to \times$, $÷\to +$, $+\to -$, $\times \to ÷$.

Answer: (C) 97

Concept: Apply the rule digit by digit, then pick the even digits of the new number.

1. 753814: 7→8, 5→6, 3→4, 8→7, 1→2, 4→3.
2. New number: 864723.
3. Even digits: $8+6+4+2=20$.

Trick: Odd +1 always becomes even and even −1 becomes odd – so the even digits are just (old odd digits + 1).

Answer: (A) 20

Concept: Treat the two letters and the number as three separate series.

1. 1st letter: K, L, M, N → O (+1).
2. 2nd letter: P, Q, R, S → T (+1).
3. Number: 23, 32, 41, 50 → 59 (+9).

Trick: Number +9 each time and letters +1 each – OT59.

Answer: (C) OT59

Concept: Place the extreme positions first.

1. No box below G ⇒ G at the bottom (7th from top). Only C above E ⇒ C = 1st, E = 2nd.
2. Two boxes between B and G ⇒ B = 4th.
3. Left: 3rd, 5th, 6th for F, D, A with F above D above A ⇒ F = 3rd, D = 5th, A = 6th.
4. Below F: B, D, A, G ⇒ 4 boxes.

Trick: 'Only X above Y' means X is at the top and Y second.

Answer: (B) 4

Concept: Draw the towns on a grid step by step.

1. K is east of L and M is east of L ⇒ L, K, M lie on one east–west line.
2. J is north of K; N is north of M; J is south-west of N ⇒ J (and so K) is to the west of N's line, i.e. west of M.
3. Hence K is to the West of M.

Trick: South-west of N means 'left and below' – that fixes K to the left of M.

Answer: (D) West

Concept: Check each symbol: the element before must be a number and the element after a symbol.

1. & (7th): preceded by 7, followed by € ✔.
2. * (10th): preceded by 9, followed by % ✔.
3. © (20th): preceded by 2, followed by % ✔. Others fail (e.g. © at 14th is followed by 5; @ is followed by 2).

Trick: Look only at number→symbol pairs and check the next element.

Answer: (B) 3